Dude thank you so much. I was stuck on a problem for an hour scratching my head. Within 10 min of your video I figure it out and learned something! God bless you brother!
expansion/contraction (change in volume) of the same mass would be the third case. i like to think of it as an accordion. if we expand the mass (say 3 kg) the volume goes up but the density decreases -- volume and density are inversely proportional. the volume becomes less dense in an effort to keep the mass the same. think of stretching a sponge.
Thank you for the comprehensive explanation. I have a question regarding your solution of (b). I did not get the whole explanation of multiplying the change of time by the change in flow rate to get the change of mass. Why did not you simply multiply the 106 by 600 (10 minutes) and you will get the same solution 63 600 as simple as this. I would love to know your justification
I wish my Thermo class was this straight forward, but no we have to find all this crap at different temperatures and pressures not on the tables and use that to find energy leaving after some time, never given a mass or density just find everything from 2 temps and 1 pressure.
so it's either an increasing/decreasing mass in a given imaginary volume (rho increases/decreases) or and increasing/decreasing mass in an increasing/decreasing imaginary volume (rho remains constant)
so either a given imaginary volume becomes more dense (more massive) or the volume expands and collects mass, keeping the density the same as it doesn't change with position
I have a question.. if mfr= vfr * D then why in the 2nd question is vfr NOT = mfr/D ? you never divided the mass f rate by density .. can you please explain?
I think for most cases temperature is disregarded. The volume, mass and velocity will be supplied and are sufficient to solve the mass and volume flow rate in almost any problems. But if we are the one to solve the rate of flow ( velocity or speed )of liquid or substance then we might use temp. and pressure especially on gases (pv=rt or pv=nrt)to solve the volume then use to calculate the rate.
Temperature directly affects density at the same pressure, so when you plug the density into your mass flow equation, you are also including temperature.
If 106kg flow at 1 sec ..... Then it would be 6360kg for 1 min right .... So i can easily say it by multiplying 250000 × 1 then devide by 6360kg so answer is 39.30min so easy.... why he complicate it hun ?
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Dude thank you so much. I was stuck on a problem for an hour scratching my head. Within 10 min of your video I figure it out and learned something! God bless you brother!
I study Engineering, but sometimes I forget basic materials, and you are a lifesaver, thanks for your all work ❤️🙏.
Thank you so much! You have helped me get through engineering school
the real GOAT
In the second problem, with 7.65 hrs as time basically means 8 hr and 5 minutes right? Given the fact that for every 1 hr = 60 m.
Well, if you have 7.65 hours, you have 7 hrs + 0.65 hr. So 0.65 hr x 60 min/1 hr = 39 minutes. Add to 7 hrs, you have 7 hrs, 39 min.
He is clearing my further maths while teaching me physics as well real goat
expansion/contraction (change in volume) of the same mass would be the third case. i like to think of it as an accordion. if we expand the mass (say 3 kg) the volume goes up but the density decreases -- volume and density are inversely proportional. the volume becomes less dense in an effort to keep the mass the same. think of stretching a sponge.
Thank you for the comprehensive explanation. I have a question regarding your solution of (b). I did not get the whole explanation of multiplying the change of time by the change in flow rate to get the change of mass. Why did not you simply multiply the 106 by 600 (10 minutes) and you will get the same solution 63 600 as simple as this. I would love to know your justification
1111q
You are excellent a intructor. Appreciate thanks.
It's excellent, from what book do you get these problems?
how do u find the time given the hight and diameter
What reaction the flow rates in fluid.
I wish my Thermo class was this straight forward, but no we have to find all this crap at different temperatures and pressures not on the tables and use that to find energy leaving after some time, never given a mass or density just find everything from 2 temps and 1 pressure.
by any chance were you able to find a good video that would help a thermo student understand flow rate?
so it's either an increasing/decreasing mass in a given imaginary volume (rho increases/decreases) or and increasing/decreasing mass in an increasing/decreasing imaginary volume (rho remains constant)
so either a given imaginary volume becomes more dense (more massive) or the volume expands and collects mass, keeping the density the same as it doesn't change with position
the latter is Q
thank you so much
HEY , so for number 2.(b) how do you know if they want the time in hours or mins
I love you and your channel ❤👍😘
I have a question.. if mfr= vfr * D then why in the 2nd question is vfr NOT = mfr/D ? you never divided the mass f rate by density .. can you please explain?
coz
there is not mfr given in question, also
Av is easier than finding first mfr & then dividing by D to find vfr
thank you
thank you sir
Maybe I don't understand exactly what you're doing, but isn't temperature an integral component of mass flow?
I think for most cases temperature is disregarded. The volume, mass and velocity will be supplied and are sufficient to solve the mass and volume flow rate in almost any problems. But if we are the one to solve the rate of flow ( velocity or speed )of liquid or substance then we might use temp. and pressure especially on gases (pv=rt or pv=nrt)to solve the volume then use to calculate the rate.
Temperature directly affects density at the same pressure, so when you plug the density into your mass flow equation, you are also including temperature.
Awesome!
how did you get 106 kg/s ? its really frustrating :(
he just calculated the equation at 03:30
The density of water multiplied by the volume flow rate
the area in number 2 is 0.0314 m^2
I fucken love you😤🙌
If 106kg flow at 1 sec ..... Then it would be 6360kg for 1 min right .... So i can easily say it by multiplying 250000 × 1 then devide by 6360kg so answer is 39.30min so easy.... why he complicate it hun ?
What?
thank you so much