Fun fact: On the hide and seek mini-game, it is more benefitial for you to hide on the horses (provided none of your teamates hide there and you are the only one doing so, which is guaranteed when playing against the CPU since it will never choose that spot). That is because you are allowing for an extra spot to hide. Yes, you will always be found inmediately, however, this changes things and actually benefits you. If you play normally, that is, nobody hides on the horses, then the finder has 5 chances, and 6 places you hide, to find 3 people. That means that there will always be one spot that he won't be able to search. So effectively, the hiders (i don't know if that's a real word sorry, english is not my first language) win if one of them chooses to hide on the spot that the finder doesn't search. What are the odds of that? Well, it is easier to calculate the chances of all three not picking that spot. That is, we are gonna calculate the chances of the hiders loosing, we will call it P, so the chances of them winning is 1-P. What are the chances of them loosing? For them to loose everybody needs to pick the wrong one, the chances of picking the wrong one are 5/6 (5 spots of the 6 will be wrong, that is, the finder will search them). So the chances of all 3 picking a wrong one are (5/6)^3=0.58. So the odds that the hiders win are 1-0.58=0.42 (42%). So we can see that the game is slighly biased towards the finder. However, if you are playing with friends, so you know where everybody else is hiding, and can make sure that everybody picks a different spot, then the chances of the hiders winning are (1/6)*3=3/6=1/2=0.5 (50%). So this game is slighly biased towards the finder if you are playing with CPUs, and perfectly fair if you are playing with friends and everybody chooses a different spot. Now let's see how the game changes if we pick the horse. In that case, we will be found inmediately, but the finder has 4 chances, accross 6 spots, to find 2 people. That means that there will be two spots that the finder is not gonna be able to check. And the hiders win if one of the other two choses either of the two spots. What are the odds of that? We calculate it the same way, we calculate first the probability of the hiders loosing, that is, that two of them pick the wrong spot, what are the chances of picking the wrong spot? 4/6 (now there are only 4 wrong spots since he will only be able to search 2 spots), so the odds that both of them pick a wrong spot are (4/6)^2 = (2/3)^2 = 0.44. Which means that the chances of the hiders winning in this case are 1-0.44=0.55 (55%) so we can see that their chances significatly increased and now, the game is slightly biased towards the hiders. For anyone interested, if you are playing with friends and everybody can pick a different spot. Then the odds of the hiders winning jump up to 1-(4/6)*(3/5)=1-(2/5)=3/5=0.6 (60%). So to sum it all up, if you are playing with the CPU, the chances of the hiders winning NOT picking the horses are 42%, and they jump up to 55% if you DO pick it (the game is actually slighly biased towards the hiders if you play this way). If you are playing with friends and everybody can choose a different spot, then, the odds of the hiders winning if you DON'T pick the horses are 50%, and 60% if you DO pick it. Once again, sorry for my bad english, and for such a lenghty post. And sorry if you actually already knew this, I figured you didn't because you never pick them.
Clocc gives main character energy
A Tomodachi Life series with all of Josh’s Miis would be awesome and crazy to watch!
omg this is such a great idea 😭
Fun fact: On the hide and seek mini-game, it is more benefitial for you to hide on the horses (provided none of your teamates hide there and you are the only one doing so, which is guaranteed when playing against the CPU since it will never choose that spot). That is because you are allowing for an extra spot to hide. Yes, you will always be found inmediately, however, this changes things and actually benefits you. If you play normally, that is, nobody hides on the horses, then the finder has 5 chances, and 6 places you hide, to find 3 people. That means that there will always be one spot that he won't be able to search. So effectively, the hiders (i don't know if that's a real word sorry, english is not my first language) win if one of them chooses to hide on the spot that the finder doesn't search. What are the odds of that? Well, it is easier to calculate the chances of all three not picking that spot. That is, we are gonna calculate the chances of the hiders loosing, we will call it P, so the chances of them winning is 1-P. What are the chances of them loosing? For them to loose everybody needs to pick the wrong one, the chances of picking the wrong one are 5/6 (5 spots of the 6 will be wrong, that is, the finder will search them). So the chances of all 3 picking a wrong one are (5/6)^3=0.58. So the odds that the hiders win are 1-0.58=0.42 (42%). So we can see that the game is slighly biased towards the finder. However, if you are playing with friends, so you know where everybody else is hiding, and can make sure that everybody picks a different spot, then the chances of the hiders winning are (1/6)*3=3/6=1/2=0.5 (50%). So this game is slighly biased towards the finder if you are playing with CPUs, and perfectly fair if you are playing with friends and everybody chooses a different spot. Now let's see how the game changes if we pick the horse. In that case, we will be found inmediately, but the finder has 4 chances, accross 6 spots, to find 2 people. That means that there will be two spots that the finder is not gonna be able to check. And the hiders win if one of the other two choses either of the two spots. What are the odds of that? We calculate it the same way, we calculate first the probability of the hiders loosing, that is, that two of them pick the wrong spot, what are the chances of picking the wrong spot? 4/6 (now there are only 4 wrong spots since he will only be able to search 2 spots), so the odds that both of them pick a wrong spot are (4/6)^2 = (2/3)^2 = 0.44. Which means that the chances of the hiders winning in this case are 1-0.44=0.55 (55%) so we can see that their chances significatly increased and now, the game is slightly biased towards the hiders. For anyone interested, if you are playing with friends and everybody can pick a different spot. Then the odds of the hiders winning jump up to 1-(4/6)*(3/5)=1-(2/5)=3/5=0.6 (60%).
So to sum it all up, if you are playing with the CPU, the chances of the hiders winning NOT picking the horses are 42%, and they jump up to 55% if you DO pick it (the game is actually slighly biased towards the hiders if you play this way).
If you are playing with friends and everybody can choose a different spot, then, the odds of the hiders winning if you DON'T pick the horses are 50%, and 60% if you DO pick it.
Once again, sorry for my bad english, and for such a lenghty post. And sorry if you actually already knew this, I figured you didn't because you never pick them.
I though I was the only one who knew this. Glad you mentioned it!
Started to see your vids recently. Really like em, and the miis are pretty cool too! ❤
ayyy im always happy to see u post a video playing my favourite gamemode 🎉
Nice Video Josh!