I would really appericiate if you can upload solution of questions from remaining A2 topic as well (eg Nuclear phys etc...). They are the most beneficial stuff I have come across on the youtube!!! My exam is in May 2022. Thank you Sir!
Hey can you plz drop some tips for me I also have my exam in may and I'm struggling with physics alot cus our teacher ain't v helpful unluckily .and ain't got no friends with whom I could study in groups .
24:21, why doesn't the elastic (po) at the min all get transferred to just elastic (po) at the max. I get that the height increases at so it gains gpe but just talking about the spring, if we imagine a spring horizontally, that is what would happen so why doesnt it here due to being c compressed?
Nope, all about direction and thinking about the magnitude. Acceleration can be positive and negative and displacement can be positive or negative. So when x is positive (say on the left of the equlibrium), a is negative, i.e. opposite way towards the origin. When x is negative, a is positive, and once again they are in opposite directions, i.e. a is again pointing towards the equlibrium. Maybe I should do a further video on this.
you would have full marks for the negative as well, because acceleration changes direction constantly the acceleration is always going between positive and negative values. The mark scheme I am pretty sure accepts both
this was super helpful thank you!
Anytime!
I would really appericiate if you can upload solution of questions from remaining A2 topic as well (eg Nuclear phys etc...). They are the most beneficial stuff I have come across on the youtube!!! My exam is in May 2022.
Thank you Sir!
I will be uploading a lot of those during the Easter break to aid revision. Best of luck revising! : )
Hey can you plz drop some tips for me I also have my exam in may and I'm struggling with physics alot cus our teacher ain't v helpful unluckily .and ain't got no friends with whom I could study in groups .
For 5:29 should velocity time graph not be drawn as the inverse? As at points where x is decreasing v should instead be increasing?
v is maximum at the equilibrium so max v is when x is 0, and when x is max, v is 0
24:21, why doesn't the elastic (po) at the min all get transferred to just elastic (po) at the max. I get that the height increases at so it gains gpe but just talking about the spring, if we imagine a spring horizontally, that is what would happen so why doesnt it here due to being c
compressed?
for the first question can u say net force instead of resultant force
Yep!
is this for Pearson Edexcel international ial ?
these questions are from OCR A however applicable to most exam boards as the physics is the same regardless of exam boards.
If acceleration is proportional to -x, surly it is true that when displacement decreases acceleration increases?
Nope, all about direction and thinking about the magnitude. Acceleration can be positive and negative and displacement can be positive or negative.
So when x is positive (say on the left of the equlibrium), a is negative, i.e. opposite way towards the origin.
When x is negative, a is positive, and once again they are in opposite directions, i.e. a is again pointing towards the equlibrium. Maybe I should do a further video on this.
@@zhelyo_physics Thank you for your comment, I think I was just thinking too linearly here.
lovely tutorial, extremely helpful
thanks for the comment! Glad to hear!
at 22:14 why didnt u put the negative sign in the answer since the exact value i got when i calculated it was -0.9869...
you would have full marks for the negative as well, because acceleration changes direction constantly the acceleration is always going between positive and negative values. The mark scheme I am pretty sure accepts both