Trigonometry Top-10 सवाल🔥 एक सवाल पक्का Gagan Pratap Sir

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[@MathsConceptKing_]

Trigonometry ke top 10 sawal kaise lage mere bhai😊😊😊 videos ko jyada se jyada share kare , dosto se subscribe bhi karwaye ☺️☺️
Aur kis chapter ke top 10 questions solve karna chahte hai ??? Comments me batao🙂

[@MausamRaj-kz3tt]

Bahut hi laa jabab question the guru jii

[@officialchoudhary__mahakal9700]

Algebra ke guru ji

[@tarungupta2429]

Bhut badhiya solution karwaya sir apne sir please number system ke har ek topic ke bhi top 10 questions Kara do

[@onkar-MEA]

Mixture allegation ~~ multiplying factor wala

[@Pacific_phoenix]

Guruji har chapter k hi kra dijiye concept k sath. Bhot productive h accha revision ho rha hai.

[@twinaspirants]

SecA+tan³A.CosecA= SecA(1+tan²A)= Sec³A
▶️tan²A=3+Q²
▶️1+tan²A=4+Q²
▶️Sec²A=4+Q²
▶️SecA= (4+Q²)½
▶️Sec³A= (4+Q²)³/²
Option D ✅

[@himanshubajaj4605]

Bahi aapne ye type kaise kiya hai ?

[@poojachauhan6294]

D

[@chandrakantchouksey9896]

Bahut sahi bro

[@jaishreeram3753]

Opt d

[@shubhampawar4304]

Thanks brother 😊

[@Bolt-ek7nm]

Q11 option d (4+q2)3/2
sec +tan3a coseca
1/c + sin3/cos3 *1/sin3
1/c + sin2a/cos3a
On solving = sec3a
And put Value from below
Tan2a +1= 3+Q2 +1
Sec2a = 4+q2
(sec2a)3/2 or sec3a = (4+q2)3/2 ans

[@riyansh_0019]

*_"अतीत पर रोने से बेहतर है नए भविष्य का निर्माण कीजिए.,क्योंकि अतीत एक सबक है भविष्य नहीं..😊......!_*
जय हिन्द गुरुदेव,,❤️🔥🇮🇳

[@SSCASPIRANT7187]

Q.11- 42:10 Ans. (D)❤ chlo ab to sir ke ashirbad se CGL nikal jayga

[@rolexsir..8052]

1/c3=sec3
Sec2-1 =tan2
Put in eq and solve it
option d is coreect

[@user-sb1bl5mz3y]

11.Ans-D (4+Q^2)3/2

[@DeepakKumar-kc7nx]

Seca+tan^3a.coseca
Seca+sin^3a/cos^3a.coseca
Seca+tan^2a.seca
Seca(1+tan^2a)
Sec^3a
(√1+tan^2a)^3
(4+Q^2)^3/2

[@DeepakTiwariThenewAmbitionstar]

ANS. (D) (4+Q^2)^3/2 JAI JAI SHIYA RAM SIR JI

[@RimjhimSingh-xt8bg]

Main jb. Kam time m questions ko slove lar leti huu to apnne ap pe gurv hone lagta hhh......because of sir

[@anarghashome87]

Option D is the absolute answer. As we see from the given expression, it could be reduced to sec a(1+tan²a), or (1+tan²a)½(1+tan²a)= (1+tan²a)^1.5. Thus, the answer is, (1+3+a²)^1.5= (4+a²)^1.5.

[@ShashiPrakash-er4jx]

Mind blowing question❤❤

[@bhupendrajoshi5618]

(d) (4+Q^2)^3/2

[@Income_Tax_Officer_1718]

Jai shree Ram sir ji ❤❤❤

[@ankitgoswami2358]

D

[@RjsportsAdda]

Super Sir

[@radheshyamkumaryadav3581]

D will be the ans using value putting concept
Put a=60 degree

[@prateekyadav5349]

Like for Gagan sir ❤❤❤❤

[@Shiva---1729---]

Putting Q=0
Tana=√3
A=60⁰
Now sec60⁰+tan³60.cosec60⁰
=1/2+3√3×2/√3 =8
Satisfying option 4. At Q=0✅✅✅

[@onlineknowledgepoint9519]

Question no. 11 , Ans - D

[@hpdongre]

Q. No. 11 answer - d - (4+Q²)³/²

[@Sachinsirop21]

Pahle math se dar lagta tha per aab sab se jayada interest hi math me ho Gaya

[@allexams7611]

Batch liya bhai aapne

[@matabhai2]

Sir Mera Selection Hone ke baad Main apne Salary ka 25 ℅ Aapko Donate karunga / Yearly❤

[@skmishra6701]

Achcha joke tha bhai

[@4everyone75]

Brother selection only maths se nhi hoga

[@pridishgupta3796]

Behtareen sir

[@Nb_783]

Truly amazing class ❤ we need more classes like this 😊😊😊😊 always thank ful of you sir😊😊😊🎉❤❤😂😂😂

[@SONU...RAJPOOT]

Kon kon sir ko dil se pasand karta hai ❤❤

[@Shanu0184]

Tere andar bhi kaun kaun wala bhut ghus gaya k

[@Anuragsingh-fh5yz]

Tumera bhi fefda dhadakta hh kya..❤❤

[@rkfullfun]

hmare pass dil hi nahi h😂😂tut chuka h😂😂

[@Satendra_Kumar18-10]

Hum toh gurde se pasand karte hain dil toh kisi or ko de diya hai n isliye

[@Ckyadav-ahir]

Let, Q=0,
Then, a=60°
2+3√3•2÷√3
=8
So, option d is correct 💯
😊

[@nitish6239]

Nice class sir ji ...
by the way answer is option D: Thank you.

[@ndaaspirant9473]

Superb session sir maja aa gya. But end me majboor hokar swal ko solve karna pada (4+Q^2)^3/2 d option answer hoga

[@ankit_ku_singh]

Seca +tan3a. Coseca
=Seca(1+tan2a)
=Seca.sec2a
=Sec3a
=(4+Q2)3/2

[@Arjun-cx7kt]

Bahut majedar hey sir questions

[@bijoydas7171]

Option -d : (4+Q²)³/²

[@Mohit-bc3jb]

Ans d hoga after solving given equation we get - sec^3 , we can find out its value using tan^2 =3+Q^2

[@Ranjeetkumari911]

Concept lajwab tha sir ji.....❤❤❤❤❤

[@smitasarkar9864]

Option -d (4+Q^2)^3/2

[@Bhaktidarshan909]

(D). (4+Q^2)^3/2

[@Rahul_roy_abhi]

Q11-ans option d from value putting if a=60°

[@rajankashyap3452]

First try to make tan²a into sec²a then then on solving we tan²a.seca hence the answer is option (d)

[@SonuSingh-vr9wm]

By value putting
a=60° and Q=0
Correct ans. Option D

[@HIMANSHUKUMAR-dz6zy]

Ans : option D

[@diliptejra6167]

Sir bahut shandar

[@Rockstarabhifactz]

Option D is the Right Answer ❤️❤️🙏🙏

[@AKsharma-np6qb]

Option - (D)

[@DefencewithOPSIR]

option D correct answer of question no, 11 (4+Q^2)^3/2

[@AJEETKUMAR-py3ex]

Ye series daily chalao sir jee
Very helpful series

[@ravisahani3587]

Easy concept ❤❤❤

[@Niru719]

Thanks a lot guru ji & lot of love❤
Ans d

[@dheerajmahor2836]

Ans D - (4+Q^2)3/2

[@rahulkrishna640]

Q11--option D

[@SabitaKumari-pl9od]

Majedaar sir ji 🥰🥰

[@vishalsinghsingh8361]

Put q=0. a=60⁰ ( 2+3root3×2/root 3=8 that is in option D

[@SSC_CGL_02]

D
Es question को पहले long method se करता था but जब से आपका पहले के video me इस question ka solution dekha hai tab se short me hi ho जाता hai
Thank you sir ❤

[@nikitadas5589]

Option . D

[@studyadda5080]

Option D { Sec³A=( 4+Q²)³/2}

[@hrgaming8403]

answer option D (4+Q^2)^3/2

[@theearthclasses24]

Tan²a= 3+Q².............................. seca+tan³a×coseca= 1/ cos³a = sec³a
1+tan²a = 1+3 + Q²
Sec² = 4 + Q²
Sec = ( 4+Q²)1/2
Sec³a = (4+Q²)3/4

[@educationtutorial5860]

3/4 😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂pagal

[@tkseries6643]

Ans. D (4+Q^2)^3/2

[@lovemeena4817]

(4+Q^2)^3/2 option D

[@mansi5719]

Q.11...Ans-D (4+Q^2)^3/2.

[@sakshigehlot6470]

Ans. Option D

[@imyadavvipul5892]

41:55 (4+Q²) ³/²

[@amankeshav6652]

d option (4+Q^2)^3/2

[@statuscreater......]

Ans (d).I have solved it by using value putting.😊

[@swetatiwari873]

D. (4+Q²)3/2

[@GaneshPatil-io2gu]

Q)11-D

[@lalitkumarsahu942]

SecA+ tan ^2A*CosecA=Sec^3A.
tan^2A=3+Q^2.
Sec^2-1=3+Q^2.
Sec^2A=4+Q^2.
SecA=(4+Q^2)^1/2.
Sec^3A= (4+Q^2)^3/2.
Correct answer is :-. D.
Thank you so much sir ji 🙏❤️

[@Gauravchaturvediji]

Tnq gurudev 😊

[@rahulvishwakarma207]

Q11 -ansD

[@GargiJadaun-sq4gr]

Ques 11. Option D

[@Kashmir-kf3xo]

option D(4+Q²)³/²

[@abhijeetkumawat8502]

Let Q=0 then a=60
2+3√3*2/√3=8
Byoption d is ans

[@RahulRaj-tj2cp]

Ans :- D

[@NikitaSharma-rn1cf]

Ques 11-Option d

[@shantanu_nath]

Ans : Option D

[@user-ik9tz2qc9i]

Question 11-- option d

[@stayaway258]

Ans - D

[@AdarshYadav-cu8rj]

42:03 (d) (4+Q^2)^3/2

[@BASNTIMEENA2006]

Kese aaya

[@neetukumari2986]

Option --- ddd ((4+Q²) ³/²)

[@Pacific_phoenix]

d) (4+Q^2)^3/2

[@ashvanigupta1502]

Options..(d)

[@shivamkumarsingh420]

Gjb 👍🏼

[@PRIYANKATIWARI-nu5rm]

Ans .option (d)( 4+Q^2)^3/2

[@abhishekanand2616]

D.(4+Q)^3/2

[@rohan98M]

D (4+Q^2)^3/2

[@ArjunYadav-rv5pn]

Super sir ❤❤

[@satyamsharma8006]

option : D

[@ASHWANI.PAL.JE2748]

d (4+Q^2)^3/2

[@user-zx6md9tt1w]

D >ans

[@golupatel8822]

ans. - D

[@ShishupalKumar-zo9ws]

Option -(d)

[@AjayKumar-eg2un]

11 Ans option D

[@hariom-it3qw]

(D)(4+Q^2)^3/2

[@shikshapathshalawithmasti5470]

Great sir ji

[@Megha0120]

Option D is correct ..... (4+Q²)³/²....
Thanku so mch sir for this amazing class 🥰🤗......
#Mathsguru🤞🏻

[@ravipratap___]

Jay ho gurudev ki 🙏🔱

[@deepu7493]

((4+Q^2)^3/2 Ans d

[@priyarani1179]

Last question -D

[@rawatcreative96]

Ans D

[@Satyam-pl2fe]

Speechless...
Ans option D

[@KhesariRecordsBhojpuri]

Ans-D hoga

[@shikhaverma7820]

Ans.11 (d) (4+Q²)³/²