Series Parallel Combination Circuit #19
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- Опубліковано 6 вер 2016
- An additional Series Parallel Combination Circuit to ensure that you have mastered this topic.
Sources cited in video:
PDF's of all 19 Circuits: wyedelta.wixsite.com/html_can...
How to Solve Any Series and Parallel Circuit Problem
• How to Solve Any Serie...
Resistors in Series and Parallel
www.electronics-tutorials.ws/r...
i have been struggling with redrawing circuits for a while now but thanks to the explanation in this video redrawing circuits seems really simple to me.
Thanks!
Glad it helped!
Wow. I really couldn't believe I could redraw circuits after watching yr video. Thanku so much! It means alot and am so relieved I can understand it now.
I understand second half of your tutorial. The first half was tricky. I am re-watching it. Many thanks for your tutorials.
Hope it was more clear on your second try. That's what is so cool about learning from the videos... you can go back and go over something that wasn't clear.
Awesome video. You did a great job. You simplified something that was killing me.Ty
So glad to hear that the video helped out. All the best Roger.
Pete
do you have any idea how much you just helped me???..... DAMN THANK YOU SO MUCH MAN. SINCERELY FROM THE BOTTOM OF MY HEART!
Thanks so much Hussein. All the best. Pete
Hey Pete, It's been a few years since I was at GB. I needed to brush up on some calculations and appreciated these videos. I hope things are going well!
Everything is going well Jon. All the best and enjoy the upcoming holidays.
Thank you for Tutor, I need to learned my lesson that. I will wrote my notebook.
You saved me from losing my mind. Thanks!
Excellent, thanks Pete.
Great video, but I'm wondering, can you find Req by using the Delta-Wye Transformation?
i really learned how to be methodical watching this video great tutorial much appreciated
Thanks for watching John. All the best. Pete
This circuit has been around long before the internet. It was used back when I went through school as a training aid to learn series/parallel circuits.
It's a great circuit that really challenges the students.
Now I understand the break it down but the build it up is somehow complicated but I got it from the recommended video. Thanks so much
No problem. I find I often have to go to a number of sources to fully understand each topic as well. Thanks for the comment.
Pete
In fact, he doesn't need us...we just know that he's having fun solving the problem on his own and that it's really his passion! ahah
Thanks a million Pete. i had watched Mason's vid previous to stumbling on this vid but yours really helped me sort out the more complicated circuits. I feel like I can deconstruct just about any circuit now which of course is the key to not making mistakes. keep up the good work brother
Thanks for the nice comment.
10th grade from Turkey, thanks a lot, you saved me!
Thx！！it is really helpful for me！！
it was amaizing loved it . thank you so much
Who knew Series Parallel Circuits would have such rave reviews! Thanks AashuU
thank you very much
very useful , i understand every thing s thanks
THANK YOU SO MUCH
Can someone please explain how I can get the I in the 5th resistor?
Thanks bro
R1,7,10 are series connected in with the parallel rest R 2,3,4,5,6,8,9. through addition i felt
Whats the total resistance of the circuit? I have 23,897 ohms
Chona Pardo round it up. The decimals made the difference. But it should be the same.
Isn't there 2 wheat-stones bridge like connections in the circuit so that we needn't take R6 and R9?
From what I understand of Wheatstone bridges, you could place a voltmeter where R9 is and look at the proportional voltage drops across R8, R10 vs R6, R7. However, as soon as you place R9 back into the
circuit it effects the current flows. Send me a diagram to vree.peter2@gmail.com if you want to discuss further.
Hi Pete, I think I noticed a mistake at the end? If R5 has 0.3A and 0.2 A comes from R6, doesn't that mean the current through R7 has to be 0.1A due to the jxn rule?
That seems to be the value (0.1A) that I have written at R7 @ 34:23
Thank u so much very helpful
Good job and well done
Could u please upload problems of symmetrical and unsymmetrical problems?
Could u please upload problems over current protection, batteries and of (differential, directional and pilot) relays please
These are beyond my expertise... but you've definitely given me new topics to explore. Here is a link to symmetrical vs. unsymmetrical faults. Thanks for the comment. www.chegg.com/homework-help/definitions/unsymmetrical-faults-and-symmetrical-components-4
Sir this video helped me a lot...sir i have a question regarding circuit problem..can u please help me??
thx a lot
it is bit confusing
At 29:23 on the junction between R7 and R5 - By the current rule the total current entering must equal the total current exiting. However, .2 A (entering from R6) plus .06 A (entering from R7) does not equal .3 A (exiting towards R5). So the assumption that 2.4 V/(R8 + R10 + R7) = .06 A must be invalid...
nvm, mistake caught later on in the video
Yes. At 35:00 , this is changed.
Uhm, hello Pete! This vid helped me a lot. Can I have the link you mentioned?
Link is now available in the comments section: wyedelta.wixsite.com/html_canada-electrical/series-parallel-resistive-circuit-review
got it right using different way
Excellent video 😉
This is the best way thank you very much
God bless
Anybody elese in school learn how to do this by heart but then you get a very simple version of it a couple months after for a different class and the realize you forgot how to do it🤣
What the answer of this circuit
R4 should be in parallel with R2,R3 ...but how did u put it...i don't understand 🤔
It might be trivial to solve this question but wouldn't current flow from positive to the negative electrode(19:40)??
Most electronic textbooks do use the Conventional Current flow model (+ to -), however in my class we use Electron Flow model (- to +). I use the same rule throughout the course because I make use of Flemings Right Hand rule later for Generators which uses the same - to + notation.
Am I correct that your school follows the International Baccalaureate Curriculum? How do you like it? My daughter is applying to a local school that follows the IB Curriculum.
@@PeteVree IB is great!!
what is the answer??
equilavalent resistance?
Its really very confusing
I Easily do the simpleones but I get hang up on complicated ones
I agree. The main reason we start our Intermediate Theory class with these circuits is just to see patterns within the circuits. Once you have an eye for the patterns and can distinguish series and parallel connections, it makes further topics easier to comprehend.
Having struggling drawing it, I understand that in parallel, current is equal and that in series voltage is equal, its still pretty confusing
Might be confusing because the relationships are that current/flow is the same in series and voltage/pressure is the same in parallel.
Very helpful
mobile liye hai ka
plz tell me if u have a video about loops and nodes ? if u don't plzzz make a one
Hi Jolonar. Loops and nodes are not my specialty. Check out Michel's video here for more info. on that topic. ua-cam.com/channels/iGxYawhEp4QyFcX0R60YdQ.html
thank u sooo much for help
ua-cam.com/users/ilectureonline should work for you.
thank u so much
jolonar jojo pleace contac me.
getting 21.6 ohm Req
WHATS THE TOTAL RESISTANCE?
24 volts / 1.2 A = __________
We can use star delta method to solve this easily
Thanks for the comment. Here is a video if anyone is interested: ua-cam.com/video/pQRvIPvABKI/v-deo.html
ily
Ohm my gosh you should try this application! Search: 'PhasorSystems' on Google Play.
It is a cool App.
Here is the link:
play.google.com/store/apps/details?id=summersedge23.com.circuitbreaker.lite&hl=en
your R3 ,you do not series in R4 because your r4 0.3 while your r3 0.6....explaine me how you determine that
If you stop the video at 36:11 you will see that the 0.6A flowing through R3 then branches off to a number of parallel rungs. So R4 is just one of the parallel branches in series with R3. You will notice as well that the currents from all the parallel branches recombine to give us the 0.6A that was flowing through R3. Hope this helps. Pete
R3 and R2 are connected in parallel. why the voltage are not same. explaine please
Have a look again around 25:26 R3 and R2 are in parallel, but R3 is actually in Series with a whole bunch of other resistors. The overall voltage on both rungs is equal, but R3 and R2 do not have the same voltage.
pinahirapan pa ko lalo😡😂
You make a series parallel combination too complicated .Solving from back to forth it's way easier to solve and explain. Malvino reference is excellent for this combinations. R8+R10 parallel to R9 find equivalent .R6 parallel to equivalent+R7 find equivalent .... and come up with only one sum to 20 Ω total.
This method has worked well to allow students to take a complicated circuit and reconfigure in a different manner. I'll take a look at the Malvino's books though. Thanks for the comment.
Hey pete odds u answer before tmrw lol?
What would you like answered?
@@PeteVree damn u rly did answer,
I had a question about power dissipation in a series circuit
do u have a email or perhaps twitter i can msg you on?
@@BertskiThe3rd vree.peter2@gmail.com
who the hell disliked this?
Grass man I did
I agree. This vid makes things so handy. Anyone who disliked it needs a slap
Տᑌᑭᗴᖇ
This was so confusing. Didn’t help at all
Try Jesse Mason's video then... ua-cam.com/video/-PiB2Xd3P94/v-deo.html
Irritating
Glad you enjoyed it.