How to Find Range of Rational Function PreCalculus

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  • Опубліковано 8 тра 2023
  • #globalmathinstitute Multiple Choice Question Bank: • 5 Rational Functions M...
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    Reciprocal functions may not be rational functions.
    Rational function can be continuous and in some cases the graph of the curve may pass through the horizontal asymptote. Understand all this from the playlist of videos.
    Characteristics of f(x) = (ax+b)/(cx+d) and related functions
    x-intercept
    y-intercept
    Vertical Asymptote and holes
    Horizontal and Oblique Asymptote
    Domain/Range
    Equation from Conditions
    Sketch Graph
    / @mathematicstutor
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    Horizontal, vertical, oblique asymptotes, hole, domain and range along with x-intercepts, y-intercepts and equation from the graph are discussed in this video

КОМЕНТАРІ • 9

  • @shittycatto
    @shittycatto 6 місяців тому +3

    i've been losing my mind for the past 4 hours trying to solve this, didn't find a video that helped my case, all the websites required me to pay to get the steps, i was about to give up but you saved my exam, thank you so much

    • @MathematicsTutor
      @MathematicsTutor  6 місяців тому +1

      Happy to see you here. Feel free to post questions. We try to provide FREE solutions. All the Best!

  • @vickyytofficial7817
    @vickyytofficial7817 Рік тому +3

    Amazing 😍😊😊

  • @GilbertSisso
    @GilbertSisso 8 місяців тому +3

    There is a little mistake here with replacing "c" in Sir. C= -( 3y+3), therefore b^2-4ac= ( 2y+2)^2+4(y-1)( 3y+3)= 8 ( y^2+y-1)
    Range ={ y/y €R, y is less or equal to ( -1-√5)/2 and y is greater or equal to ( -1+√5)/2 }

    • @MathematicsTutor
      @MathematicsTutor  8 місяців тому

      Please check again. It looks correct to me. Thanks for the feedback

  • @eccentrico5965
    @eccentrico5965 11 місяців тому +1

    Thank you very much sir. It helps a lot. I am actually advancing my lessons to General mathematics, Pre-calculus, and Calculus 1(at the same time). And i've encounter that topic as you are talking about yesterday and Im still stuck of finding the range of rational functions with a degree of 2. I did the same approach you did sir and the only thing that I didn't know is just the quadratic discriminant. I mean... I thought I need to solve the entire quadratic in order to find the inverse function of the original rational function(with a degree of 2) and then look for the denominator of the inverse function and set it not equal to zero. Until I found your video sir.

  • @user-rh3sb7uq4g
    @user-rh3sb7uq4g 4 місяці тому +1

    what about if the denominator and nominator are above the two degree

  • @abrhamshibru
    @abrhamshibru 4 місяці тому +1

    How do the solution y+1 greater than or equals to zero could be y_ -1

    • @MathematicsTutor
      @MathematicsTutor  4 місяці тому

      PLAYLIST for you: ua-cam.com/video/3SMoDd7cg5A/v-deo.html
      Thanks