Consider two vertices as 1+i,2+2i. They lie on the line x=y. So perpendicular line is y=-x ie 1-i/√2 direction. Height of equilateral triangle is √3/2 a. Therefore we transport the midpoint 1.5+1.5i by √3/2 *a=√6/2. Therefore, 1.5+1.5i+√6/2(1-i)/√2=(3+√3)/2+(3-√3)/2 i there is one more solution if we instead take (-1+i)/√2
Sir homework Question Answer is 3rd vertex - *{[ 3 + √3 ]/2 , [ 3 - √3 ]/2}* Full solution below : - Solved using the concept of rotation - Solution link : drive.google.com/file/d/191Oh5vo6JWvZWbiDONYrv9WcSlUObBQe/view?usp=drivesdk + Sir please take my solution in the next video . I watch your videos on the next day morning so i am late and i have also described the solution properly also i solve and post every problem you give ( at least I try) Thank you sir and physics wallah team for teaching pacians 🧡
Sir, aap kiske liye kya hain ye hum nahin jaante but aap hain to hum hain, aapki mehnat sarvopari hai. Sir we are always with you 🙏🙏🙏 . Don't mind on the negative 😡 comments.
sir most of the students want the pace batch continue for 12th class. please sir even take the fee for 12th but please teach us class 12 also. Because the level of education provide by all teachers in pace batch is very high
We sir we have Z1=(1+i) and Z2=(2+2i) and we have to find Z3 So,by diagram Z3-Z2 = Z1-Z2.e^i( thita) Z3= Z1-Z2.e^i(thita) +Z2 Putting values of Z1 and Z2 respectively. -(1+i).e^30° +2+2i -(1+i).(cos30°+isin30°) +(2+2i) -(1+i).(root3/2 +i 1/2) +(2+2i) 1/2-root3/2+2 + (- 1/2 - root3/2+2)i 5-root3/2 - (3+root3/2)i = answer Hope that i did right.
Let vertices are A = 1+i and B = 2+2i. And angle= pi/3 and there are two possibilities one clockwise angle and other anti clockwise. So angle=pi/3 and - pi/3. C= A + |C-A|/|B-A| × (B-A)× e^(i × pi/3) Now since |C-A| and |B-A| represent sides of equilateral triangle,so they are equal. So C= A+ (B-A)e^(i×pi/3). => C = (1+i) + [ (2+2i) - (1+1i) ] e^(i×pi/3). => C = (1+i) + [ 1+i ] e^(i×pi/3) => C = (1+i)[ 1 + cos(pi/3)+ i×sin(pi/3) ] And for other point D we can put (- pi/3) instead of pi/3 => C = (1+i)(1+1/2+root3 ×i) and D =(1+i)(1 +1/2 - root3 × i). => C = [1×(1+1/2) - (1×(root3/2)] + [1×root3/2 + (1×(1+1/2)] × i. And D =[(1+1/2) - (- root3/2)] +[ - root3/2+ 1×1/2] × i. => C = [(3-root3)/2] + [(3+root3)/2] × i. And D = [(3+root3)/2] + [(3-root3)/2]× i. (ANSWER).
@@prasadphad7115 use formula of previous question Z3-Z2/|Z3-Z2|=Z1-Z2/|Z1-Z2|×e^ipie/3 And here |Z3-Z2|=|Z1-Z2| so you can cancel out it And then put Z3=x+it Z2=2+2i Z1=1+1i Then convert whole in quadratic form and then after comparing you get the answer
This topic I learn Today but I can't understand & now I watch this video... During this video I understand all things... Thank you Physicswallah Platform & Also Thanks To Alakh sir& Aman sir.... 🔥🔥🔥🔥🔥BHANNAT🔥🔥🔥🔥🔥
sir ek doubt hai aap geometry k lessons nhi padhaoge mene lectur plan dekha toh usme koi mention nhi tha geometry k lectures k baare plzz sir bataona Straight lines Conic Sections Introduction to Three Dimensional Geometry Limits and Derivatives Mathematical Reasoning Statistics Probability ye sab chapters mention nhi hai sir lecture plan me toh kya khud se padhne padega
Hello sir. I have watched whole playlist of complex no. I am not here to object or to spread hate , but I just wanted you to know that the content was incomplete. Though it covered mostly all the topics but few topics were not there. Which I think is important to do question more quickly. No offence. I truly whole heartedly enjoyed the playlist, but I didn't get the satisfaction of completion . I think sir thaught well and I really mean it. Thank you.
20:29 samjh ahgya case 1 super bannnnatttlyyyyy.........mera ek sapna h sir alakh sir ke city se hi m belong karta hu....to jabm top 100 m aauna to main sir se face to face mil sakho and sir mera interview le dill ki wish aj commment box m likh raha hu phele baar..bas sir se milne ke liye m mehnat karne ko taiyaar hu....aur jis din mera naam paper m ayega aur sir se milunga us din ye comment publically sab ko share karunga...
Sir yaha par sab ke rahe he ki course kab complete hoga me aapse kehna chahta hu ki course kabhi bhi complete kare pr saara jee mains and advanced level tak ke concept kara dijiye 11 ki exam me hame jarurat nhi kyuki ye exam ki percentage ya marks kuch kaam nhi aata lekin jee se hume achhi college milti he jese ki IITs NITs IIITs etc aap in logo ki baat sunke course bhagayega mat or please hame saare concepts jee main and advanced level tak ke kara dijiyaga jisse hame aage takleef na ho. Bhale hi February me course complete na ho or april tak chalaa jaye hame koi takleef nhi he. Thank you very much
i have subscription of accelerate batch , i can easily watch this video on physics wallah app but i am watching on youtube so that alakh sir can get revenue from the ads in the video !!!!!!
sir case 1 kya ab tak jitna aapne padhaya h sab bhannatali samajh aa gya h aur sabhi formulae bhi learned kar liye h 😎😎 *sir kuch tips bta do maths ke jee advance prep ke liye* Sir homework q ans is( 3 - root 3) / 2 , y = (3 + root3 ) / 2 Hw --jamboard.google.com/d/1j8j1b-J5N8QBvqb-WnVLq3nMTOmamYxwFk3lGNCVIIY/edit?usp=sharing
Sir homework question m mene rotation concept ka phla case lagaya third wale ko (x,y) manke equations banayi fir vectors ka istemaal kiya sir last m aakr calculation thodi complicated hogi prr sir I tried my best but answer nhi nikal paya....
Rati shankar sukla best dialogue 🤣🤣🤣🤣🤣🤣
Consider two vertices as 1+i,2+2i. They lie on the line x=y. So perpendicular line is y=-x ie 1-i/√2 direction. Height of equilateral triangle is √3/2 a. Therefore we transport the midpoint 1.5+1.5i by √3/2 *a=√6/2. Therefore, 1.5+1.5i+√6/2(1-i)/√2=(3+√3)/2+(3-√3)/2 i there is one more solution if we instead take (-1+i)/√2
🙂
aapka jee ka exam ho gaya kia
Sir homework Question Answer is
3rd vertex - *{[ 3 + √3 ]/2 , [ 3 - √3 ]/2}*
Full solution below :
- Solved using the concept of rotation
- Solution link : drive.google.com/file/d/191Oh5vo6JWvZWbiDONYrv9WcSlUObBQe/view?usp=drivesdk
+ Sir please take my solution in the next video . I watch your videos on the next day morning so i am late and i have also described the solution properly also i solve and post every problem you give ( at least I try)
Thank you sir and physics wallah team for teaching pacians 🧡
Learning Mathematics with this energy is amazing 🔥🔥🔥
Sir, aap kiske liye kya hain ye hum nahin jaante but aap hain to hum hain, aapki mehnat sarvopari hai.
Sir we are always with you 🙏🙏🙏 . Don't mind on the negative 😡 comments.
@Universal Cricket kai log negative comments likhte hain bahut bure hai vo
@@adityabute2107 yes vo log likhte he ki course khatam kab hoga karne ki taakat na ho to mat karao
Aisa aisa bolte he bawle haters
0:43 sec
Physics ki watt laga diya sir ne 🤣🤣🤣🤣🤣🤣🤣🤣🤣
😀😀😀😀
Thumbnail ek dam bhannat💣 hit like if u guys feel the same
z1 = 2+2i,z2 = 1+1i,z3 = x+iy
wkt,
z1 - z2 = z1-z3(e^i(π/3))(for an equilateral triangle)
1+1i = (2-x/2 - √3(2-y)/2)+((2-x)√3/2 + 2-y /2)
Equating real and imaginary parts,
√3y - x = 2√3 ...(1)
√3x + y = 2√3....(2)
From 1 and 2,
x = (3-√3)/2, y = (3+√3)/2
flawless teaching by a flawless teacher
every thing is crystal clear..............
Case 1 bhannnnnatly yad🤩💯💥✌👍🙆♂️💁♂️
Me too
Mai bhi ashu🤣😂
@@ashusingh7273 😃
👍
All cases. ❤❤❤😄😄😄👌👌👌👌
20:27; case 1 samajh aa gya hai bhannatly ✅😊🙂 .Or sir ek baat to te h ki Aap or R.G sir ek doosre k lectures bhi dhekhte h.....🤭🤭😄😄
Correct
Rg sir
And aman sir active hokr padate hai
But chemistry ke ser 🙄
Chemistry ke sir bolenge bs
,,I hope..samj aa hi gaya hoga 😉😁
But acha padate hai..
@@ndaandairforcecadets1913 he is also very energetic.
@@ndaandairforcecadets1913 he is also a genius.
Solution for 38:31 :
z1 = 2+2i,z2 = 1+1i,z3 = x+iy
wkt,
z1 - z2 = z1-z3(e^i(π/3))(for an equilateral triangle)
1+1i = (2-x/2 - √3(2-y)/2)+((2-x)√3/2 + 2-y /2)
Equating real and imaginary parts,
√3y - x = 2√3 ...(1)
√3x + y = 2√3....(2)
From 1 and 2,
x = (3-√3)/2, y = (3+√3)/2
Nice 👍
Bro there will be 2 solutions for that question
The intro bhannat gives me energy🔥
sir most of the students want the pace batch continue for 12th class. please sir even take the fee for 12th but please teach us class 12 also. Because the level of education provide by all teachers in pace batch is very high
Answer of home work question.....
(3+root3)/2 + (3-root3/2 )i
Please tell me how you did solve?
Kash me iss saal 12th ki jagah 11th me hota 😩😩😩😭😭😭😖😖😖😖
Kyu ?
Q vai ?
Bhai aaisa koi 12 ka series nhi he ? I'm in also 12th maine 11 k saare dekh liya
Bhai fail karne ka icha hai kya?🙂
Bohot achha hua .ab khud ka gand ghis. I am in 11 and I am studying sincerely 😊
Carry. : Toh kaise h aap loog 1:00
Aman sir : i m Carry’s Fan
No Carry is Aman sir's Fan
Padhai par comments karne mein mann nahi lagta
We sir we have Z1=(1+i) and Z2=(2+2i) and we have to find Z3
So,by diagram
Z3-Z2 = Z1-Z2.e^i( thita)
Z3= Z1-Z2.e^i(thita) +Z2
Putting values of Z1 and Z2 respectively.
-(1+i).e^30° +2+2i
-(1+i).(cos30°+isin30°) +(2+2i)
-(1+i).(root3/2 +i 1/2) +(2+2i)
1/2-root3/2+2 + (- 1/2 - root3/2+2)i
5-root3/2 - (3+root3/2)i = answer
Hope that i did right.
Let vertices are A = 1+i and B = 2+2i. And angle= pi/3 and there are two possibilities one clockwise angle and other anti clockwise.
So angle=pi/3 and - pi/3.
C= A + |C-A|/|B-A| × (B-A)× e^(i × pi/3)
Now since |C-A| and |B-A| represent sides of equilateral triangle,so they are equal.
So C= A+ (B-A)e^(i×pi/3).
=> C = (1+i) + [ (2+2i) - (1+1i) ] e^(i×pi/3).
=> C = (1+i) + [ 1+i ] e^(i×pi/3)
=> C = (1+i)[ 1 + cos(pi/3)+ i×sin(pi/3) ]
And for other point D we can put (- pi/3) instead of pi/3
=> C = (1+i)(1+1/2+root3 ×i) and
D =(1+i)(1 +1/2 - root3 × i).
=> C = [1×(1+1/2) - (1×(root3/2)] + [1×root3/2 + (1×(1+1/2)] × i.
And D =[(1+1/2) - (- root3/2)] +[ - root3/2+ 1×1/2] × i.
=> C = [(3-root3)/2] + [(3+root3)/2] × i.
And D = [(3+root3)/2] + [(3-root3)/2]× i. (ANSWER).
Sir ji ab nhi chalti hampe math ki marzi...AAP ho hamare concepts ke darzi..
38:13
ANS:-
third vertex
(3+underroot3/2,
3-underroot3/2)
Can you tell steps
@@prasadphad7115 use formula of previous question
Z3-Z2/|Z3-Z2|=Z1-Z2/|Z1-Z2|×e^ipie/3
And here |Z3-Z2|=|Z1-Z2| so you can cancel out it
And then put Z3=x+it
Z2=2+2i
Z1=1+1i
Then convert whole in quadratic form and then after comparing you get the answer
@@anitaprajapati2412 thanks
@@anitaprajapati2412 I done with case 1 method
@@prasadphad7115 ya that method is also applicable
38:17 the coordinates are (3 - v3)/2 , (3 + v3)/2
How to solve plz tell
Yup
plz explain
Naagin tune is awesome.🔥🔥🔥🔥
This topic I learn Today but I can't understand & now I watch this video... During this video I understand all things...
Thank you Physicswallah Platform & Also Thanks To Alakh sir& Aman sir....
🔥🔥🔥🔥🔥BHANNAT🔥🔥🔥🔥🔥
1:09 RIP fir headphone users 😂
G faat gyi thi
@@KunalKumar-zs6ii bhai g nhi kan gat gay tha
👍
@@KunalKumar-zs6ii Tum G se sunte ho kya? 🤣🤣🤣
@@KunalKumar-zs6ii kaan me g hai ky??
.
1:00 Carryminati
1:09 Aman Sir❤️❤️
ua-cam.com/video/tOd6hqdaHBQ/v-deo.html
Coordinates are (1,1) and (2,2).
Let the vertices are A = 1+i and B = 2+2i.
sir ne ye question complex no my diya ha par ye question complex no ka lag nahi raha
maybe you are correct
sir ek doubt hai aap geometry k lessons nhi padhaoge mene lectur plan dekha toh usme koi mention nhi tha geometry k lectures k baare plzz sir bataona
Straight lines
Conic Sections
Introduction to Three Dimensional Geometry
Limits and Derivatives
Mathematical Reasoning
Statistics
Probability
ye sab chapters mention nhi hai sir lecture plan me
toh kya khud se padhne padega
Full clear with Bhannat way!
Thankyou very much sir🙏🙏🙏🔥🔥🔥
Don't scroll down, watch lecture with full concentration 👍🏻👍🏻👍🏻
Sir please assure us that we can clear jee advance level question with your video lectures 🙏🙏🙏👆👆👆 please 🙏🙏🙏🙏🙏
Sir, Please start regular exams(or unit tests) for Class 11 also(Doesn't matter even if we have to pay for that)
Please Sir Please
😭😭😭😭😭😭
nice
Pichle 2 week se yahi spam kiye jaarha hai tu 😡😡😡😡😡😠😠😠🤬🤬
Bhannately solved the question at 32:56
Majaa aaa gya
Bhanattt feel ho rha h❤️❤️😍😍✌️✌️
Bannnnnnnnnnnbnnaaaattt😁
Ekdum bhanatt
Brother aap khaaha se ho....
Jara mai bhi janu..alak sir ka revolution khaha tk faila hai😉
I m from bihar
Aur ye revolution and unka parakram india k hr kone m fela hua h
Hm bro mai up se
Third vertex = (√3+1/2, √3+3/2)
And, (√3+3/2, √3+1/2)
One of the best resources to prepare for jee
Hats off!
Ans of hw is (3-√3/2 ) +(3+√3) i/2
35:00 sir sum mujhse hua nhi pr apka solution dekhr ekdum bhannat tareeke se samajh aagya thankyou sir
humbhi yhi h ek hafta phele sir dale h video apan log abhi bhi tahl rahe h
Yes !!! Case-1 Understood very Effectively !!!
Your teaching amezing sir. And last lecture is a very super sir . Thanks for you sir.
kaka
*amazing 🌚
Hello sir.
I have watched whole playlist of complex no.
I am not here to object or to spread hate , but I just wanted you to know that the content was incomplete.
Though it covered mostly all the topics but few topics were not there. Which I think is important to do question more quickly.
No offence. I truly whole heartedly enjoyed the playlist, but I didn't get the satisfaction of completion .
I think sir thaught well and I really mean it.
Thank you.
Case 1 ekdum bhannattttt tarike s yad ho gya.
❤️❤️😍😍
Any bio student here...?
Like me ..😝😆😆😂
Im here kyunki mujhey sir ke bolne ka style bohot achha lga....😆😁
maths bhi pdh lo kaam krega😛
@@avanishkumar7817 pdh leti pr drr lgta hai....😅🤣🤣
@@shyamkanojia6925 yr insan hoke ek maths jaise chote subj se dr gai🤣🤣
@@shyamkanojia6925 maths se drne ka nii hmne maths ko banaya maths ne hmko nii banaya😂😂😜😄
@@avanishkumar7817 maths ek khatrnaak sub or mein pyari si ladki drr toh lgega hi ....😝🤣🤣
Complex number ekdam bannnat samaj aa gaya ❤️ thanks 😊 sir
sir pls start coordinate geometry after complex no.its my humble request....thanks for ur efforts sir
Sir you are a magician ...literally...🤩
Case 1: understood bhannatly
20:29 samjh ahgya case 1 super bannnnatttlyyyyy.........mera ek sapna h sir alakh sir ke city se hi m belong karta hu....to jabm top 100 m aauna to main sir se face to face mil sakho and sir mera interview le dill ki wish aj commment box m likh raha hu phele baar..bas sir se milne ke liye m mehnat karne ko taiyaar hu....aur jis din mera naam paper m ayega aur sir se milunga us din ye comment publically sab ko share karunga...
Two video in one day that's great
My favourite scene is at 1 : 15 ...aaj ye last lecture h for comples no.
I feel them as school
Hw ans (1-root3/2,1+root3/2)
Homework answer :)
Coordinates are ([3+√3]/2. ,[3-√3]/2)
Edit: i used coordinate geometry 😅😅
@Anirudh R 😅😅
Answer of last question is
[(3/2+√3/2),(1+√3)] and [(3/2-√3/2),(1-√3)]...
3/2,3/2. Hamara aya by using
How
Jee crash course 2021 ..
Today is 5 .
🙏🙏🙏
Jee 2021
Plz announce / hint 🙏🙏🙏
Sir answer is...,..(3+√3/2) , (3-√3/2)
How
सर का तो अपना स्वैग ही अलग है ।।😂😂😂
Sir yaha par sab ke rahe he ki course kab complete hoga me aapse kehna chahta hu ki course kabhi bhi complete kare pr saara jee mains and advanced level tak ke concept kara dijiye 11 ki exam me hame jarurat nhi kyuki ye exam ki percentage ya marks kuch kaam nhi aata lekin jee se hume achhi college milti he jese ki IITs NITs IIITs etc aap in logo ki baat sunke course bhagayega mat or please hame saare concepts jee main and advanced level tak ke kara dijiyaga jisse hame aage takleef na ho. Bhale hi February me course complete na ho or april tak chalaa jaye hame koi takleef nhi he. Thank you very much
ua-cam.com/video/tOd6hqdaHBQ/v-deo.html
Well said bro
@@sudhasharma9413 thanks
Exactly
Right bro
Aaj ka bhannaaat🔥🔥🔥🔥1:09
Thugesh jyse lag rahe ho sir 😂
Wahi
Thugesh sir ki tarah lagta hai...naki sir Thugesh ki tarah
@@pankajkumari9566 ek hi baat hai be
Case one samajh me aa gaya hai sir भन्न्नाटली 😎
Sir last Hw qt. ka answer
x=3- root3/2
y=3+ root3/2
aa raha
Kaise aaya
plz explain kro yaar
Eq of ray And arc locus
thankyou sir................i understood the concept very nicely
Sir the lecture was amazing but we are going a lot slower than our schedule, pls acknowledge this and reply ⚡⚡
Are sir aaj ka intro dekh ke toh mazzaa hi aagya bilkul👊👊
Ekdum bhannaatttttttt🔥🔥😎😎
Alakh pandey sir is the best. 😊😊
Yes,I understood case 1.
sir plx tell how to approch questions bhannatly like you
😥😥
Mujhe bhi pta karna h
@@princevegeta315 mughe questions ko approach karne ma bohad difficulty hoti h
1-root 3/2,1+root3/2 answer for homework question
20:19 case 1 done👍👍👍
HOMEWORK QUESTION----->
Z1=(1+i) Z2=(2+2i) Z3=?
now,
as, ( Z3-Z1)=(Z2-Z1).e^i60°
Z3-(1+i)=(1+i)(1/2+√3/2i)
Z3=(1+i)(1/2+√3/2i+1)
on solving..
Z3=(3-√3/2)+(3+√3/2i)
therefore
Z3=( 3-√3)/2 , (3+√3)/2
#Bhannnnnnnnnnatttttt💖💖💖💖💖💖
37:50
(3,1) or (0,2)
i have subscription of accelerate batch , i can easily watch this video on physics wallah app but i am watching on youtube so that alakh sir can get revenue from the ads in the video !!!!!!
Today intro was amazing 😎😎😎😎😎😎😎😎😎😎
Sir mujhe case1 bhannatly samajh as gays hai aapki kripa see dhanyavad
yes sir case 1 samjh me aaa gaya hai thanks for explaning in bhannat way.
concept of rotation done 👍👍 bannatly 😎😎
2:22 sir sab kuch tamej se seekha hai par abhyas series mein thodi problems hai usme kch kch sums nahi bante
20:18 sir aa gaya case 1 smjh me
20:25 sir samjh mae aaa Gaya hai
I am feeling like that you are infront of me
Answer to homework is coming:
3 plus-minus root3, plus minus root 3
plz explain
sir kvpy 2021 ke liye maths ka course jan 31 tk ho jaayega kya sir?..(plz take this on sawal jawab session)
20:29 case 1 yaad hogya ekdum bannat tarike se ......👍👍👍👍👍👍👍👍
I am addictive of his bhannaat
acha bhai mai bhi
Case 1 clearly understood!!
I understood case 1
*sir mere sawaal hai , ki sir next topic complex number ke badd kya suru hoga,dusra sir sigma bala lecture kab aayega*
Thanks sir for lecture 🙏 🙌 👌 👍 🙂 😊 🙏 🙌
18:00 sir math ki gf Physics hai
To math me Physics Ka fanda Hoga hi 😂😂
aaga samajh mei case 1 sir
1 minute silence for chacha😥😥😥😥😥
Is accelerate batch enough for jee mains 2021??am going to purchase pls tell me😭😭😭
No bro.. Accelerate is only for boards... Boards oriented hoga
MAIN BOARDS
But thode bohut concepts mains ke bhi hote hai
Bhai ruk ja most probably kal ya parso tak jee ka crash course aa jae ga
sir case 1 kya ab tak jitna aapne padhaya h sab bhannatali samajh aa gya h aur sabhi formulae bhi learned kar liye h 😎😎
*sir kuch tips bta do maths ke jee advance prep ke liye*
Sir homework q ans is( 3 - root 3) / 2 , y = (3 + root3 ) / 2
Hw --jamboard.google.com/d/1j8j1b-J5N8QBvqb-WnVLq3nMTOmamYxwFk3lGNCVIIY/edit?usp=sharing
Awesome teaching sir
Case1 understood bhanaatly
0:39 Ratishankar Sir😂😂😂😂😂
20:21 case 1 samaj me aa gya bhannatly
Sir homework question m mene rotation concept ka phla case lagaya third wale ko (x,y) manke equations banayi fir vectors ka istemaal kiya sir last m aakr calculation thodi complicated hogi prr sir I tried my best but answer nhi nikal paya....
Love from 2g network of Kashmir
all cases understood...😊
Does he teach deleted course also ????
(3-√3/2,3+√3/2)