I also blog on Medium medium.com/@seetharam.anand. I write on data science, AI, machine learning and computer science in general. Please FOLLOW me on Medium for more articles.I also provide FREE courses on Udemy on these topics www.udemy.com/user/anand-seetharam/. Check it out!
I'm surprised you don't get more comments but, your videos explaining computer networks are amazing and informative. Thank you very much for sharing your knowledge : )
thank you anand I had an oral for the subjrect of sattelite and i was preparing i saw your video which was very hrelfull thanks a lot fir easy explanation
One point to add is that in TCP reno, if a duplicate acks is received; the cwnd cuts to half which is TCP's Reno threshold(SSH) after loss due to 3 duplicate acks.
@@anandseetharam I meant to ask how is it decided in general(the initial ssthresh value). Also, is it a parameter where I can check from the OS?Like going /proc/sys/net/ipv4.
At later slides its being explained that the window size is increased exponentially ( to twice) when "each and every ack of previous sent segments has been received" while in previous slides it was told that when the first ack of the 2 segments arrives , the MSS is increased to twice. Please can you explain the same. In general cwnd is max number of segments that are sent before the sender waits for the acknowledgments - that is fine. The question that remains is that does the sender doubles the cwnd when the first ack has come or all the acks for all the previous segments have arrived?
I also blog on Medium medium.com/@seetharam.anand. I write on data science, AI, machine learning and computer science in general. Please FOLLOW me on Medium for more articles.I also provide FREE courses on Udemy on these topics www.udemy.com/user/anand-seetharam/. Check it out!
Saw the video once and already it's in my memory...great explanation..
Thank you
Thank a lot, it really helped me to figure out the most difficult part of my course in such a simple way, you're the boss
I'm surprised you don't get more comments but, your videos explaining computer networks are amazing and informative. Thank you very much for sharing your knowledge : )
You are welcome
It's because he's trying to use accents which is hard to understand, just use a neutral accent then more people will listen to you speaker.
I've watched like 4 videos on this and read so many articles, this is the first one that makes sense
I'm watching this on the day of exam hahaah thank you so much I don't need to study from a book now.
Good luck with your exam
You're a beauty man!! You explained it so cleanly
thank you anand I had an oral for the subjrect of sattelite and i was preparing i saw your video which was very hrelfull thanks a lot fir easy explanation
Simple and straightforward! thanks
It’s really helpful I suggest you to make more videos sir!
One point to add is that in TCP reno, if a duplicate acks is received; the cwnd cuts to half which is TCP's Reno threshold(SSH) after loss due to 3 duplicate acks.
Very good explanation.
Very precise and clear explaination, thanks for making the video
Super clear,, thank you so much
amazingly explained, thank you!
Glad it was helpful!
Those slides belong to Professor Kurose, right? I can't find where you are quoting him.
this is a perfect explanation!
subscribed, you explain really well!
Thanks
Very well explained!
Thank you
Best on youtube 💯
Thank you
Hey thanks for the great explanation. One question: How do we decide the initial Slow Start Threshold at 8?
Thanks! That is used here for explanation purposes.
@@anandseetharam I meant to ask how is it decided in general(the initial ssthresh value). Also, is it a parameter where I can check from the OS?Like going /proc/sys/net/ipv4.
Very well explained. Thanks for making this video.
You are welcome
Very well explained. It helped a lot. Subscribed the channel also to support the good cause.
Glad it helped
Brilliant
Thank you
At later slides its being explained that the window size is increased exponentially ( to twice) when "each and every ack of previous sent segments has been received" while in previous slides it was told that when the first ack of the 2 segments arrives , the MSS is increased to twice. Please can you explain the same. In general cwnd is max number of segments that are sent before the sender waits for the acknowledgments - that is fine. The question that remains is that does the sender doubles the cwnd when the first ack has come or all the acks for all the previous segments have arrived?
What all cases does the threshold(ssthresh) increase here?
very well explained thank you
Glad it was helpful!
So good!
Thank you
GOOD EXPLANTION
Thanks!
Why the Ack of the seg 2 is 4 ansvthen 8 I cant get it please
I have one doubt this question and open loop and closed loop congestion control techniques are same ahh
Tcp rano min 6.30
your explanation is good but your accent makes it worst
Slang👎
is this slide stolen from my uni XD
These slides are from Kurose and Ross (made publicly available with their textbook).