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Sir very nice explanation I am impressed excellent 😍😍😍😍😍😍❤❤
Jab sequence s=1/2 k liye not converge then P(A)=1 how
"this here this and this so this becomes this" that's all he can teach. WASTE OF TIME.
Please provide the proof of WLLN, SLLN & CLT
At 23:46 I don’t understand why we can discard the 0 case?
For s = 0.5, limXn(0.5) != X(0.5), so for all s € [0,1] the P{ w: lim(Xn(w)) = X(w)} is not equal to 1 right? Then how can you conclude Xn converge almost surely to X?
It is equal to 1 at every point in between (0,1].
🙏🙏🙏 no word for ......
U have lost me
Sir can u make a video on hajek reyni inequality proof
12 tk probablity kitni acchi thi...engineering ne iski bhi chod di
🤣🤣🤣🤣🤣🤣🤣🤣🤣🤣🤣🤣🤣🤣🤣🤣🤣
For real 😭
Sir please can you explain the inequality at 14:52?
Note thatP(|X1| =1) = 1P(|X2| = 1/2) =1,.....P(|Xn| =1/n) =1. Not being probabilistic any longer.For large n, x_n epsilon) = Sum[1;1/epsilon] P(|Xn| >epsilon) + Sum[1/epsilon; inf] P(|Xn| >epsilon)= Sum[1;1/epsilon] 1 + Sum[1/epsilon; inf] 0
Kch smj m nh aaya 😑😑😑
Maybe you can try teaching in Hindi?
-1
may be he must not teach
Sir very nice explanation I am impressed excellent 😍😍😍😍😍😍❤❤
Jab sequence s=1/2 k liye not converge then P(A)=1 how
"this here this and this so this becomes this" that's all he can teach. WASTE OF TIME.
Please provide the proof of WLLN, SLLN & CLT
At 23:46 I don’t understand why we can discard the 0 case?
For s = 0.5, limXn(0.5) != X(0.5), so for all s € [0,1] the P{ w: lim(Xn(w)) = X(w)} is not equal to 1 right? Then how can you conclude Xn converge almost surely to X?
It is equal to 1 at every point in between (0,1].
🙏🙏🙏 no word for ......
U have lost me
Sir can u make a video on hajek reyni inequality proof
12 tk probablity kitni acchi thi...engineering ne iski bhi chod di
🤣🤣🤣🤣🤣🤣🤣🤣🤣🤣🤣🤣🤣🤣🤣🤣🤣
For real 😭
For real 😭
Sir please can you explain the inequality at 14:52?
Note that
P(|X1| =1) = 1
P(|X2| = 1/2) =1,
.....
P(|Xn| =1/n) =1. Not being probabilistic any longer.
For large n, x_n epsilon)
= Sum[1;1/epsilon] P(|Xn| >epsilon)
+ Sum[1/epsilon; inf] P(|Xn| >epsilon)
= Sum[1;1/epsilon] 1
+ Sum[1/epsilon; inf] 0
Kch smj m nh aaya 😑😑😑
Maybe you can try teaching in Hindi?
-1
may be he must not teach