How to calculate number of base pairs in a DNA fragment
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- Опубліковано 19 сер 2024
- Deoxyribonucleic acid is a molecule composed of two polynucleotide chains that coil around each other to form a double helix carrying genetic instructions for the development, functioning, growth and reproduction of all known organisms and many viruses. DNA and ribonucleic acid are nucleic acids.
The video I very good. Pls I need more on how to calculate length, number of base paire, number of turns etc.
Just check my playlist "DNA structure".
Thank you sir
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Sir, there are 10 %adenine among the bases in a DNA fragment measuring 10.2 nanometres length.The no. Of H-bonds in the DNA fragment.
Answer is
3.4 nm - 10 bp
10.2 nm -?
=30 base pair (bp)
10% of A means
20% of A+T in 30 bp
So, 20/100*30=6
So, 6 base pairs of A+T
So, no of H-bonds of A+T is
6*2=12
So, 12 H-bonds of A+T
80%Of G+C bp's in 30bp's
So, 80/100*30=24bp's of G+C
So, 24*3=72 H-bonds of G+C.
So, 72+12=84 H-bonds.
Now, if the answer for that question becomes a question like this.
A DNA contains 84 H-bonds. It contains 12 Guanine bases. Find the no. Of Adenine, Cytosine bases.
The answer will be like this.
=12+12 base pairs of G+C
So, 24*3=72 H-bonds of G+C
84-72=12 H-bonds Of A+T
So, 12/2=6 bp's of A+T
6/2=3
3 means 3 Adenine and 3 Thymine bases.
In the same way if I solve the below question.
If a fragment of ds-DNA has 135 H-bonds. It contains 23G-bases. Find the no. Of Adenine and Thymine bases.
Answer is
=23+23
=46 bp's of G+C
No. Of H-bonds of G+C
=46*3
=138 H-bonds of G+C.
But this is wrong .
But I don't know where I am going wrong . Please explain me, where I am going wrong.
Here is calculations to your earlier posted problem on DNA length calculations - use the same logic: ua-cam.com/video/xF93IIyK1Mw/v-deo.html
23 pairs of G-C x triple bond = 69 bonds
135-69=66 bonds between A-T/2 bonds per pair = 33 base pairs A-T
The answer: this dsDNA contains 33 base pairs A-T
@@GeneticsLessonsThank you sir.
good
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Sir pleAse help me . How can i solve the average number of nucleotide pairs
Sorry, I do not understand your question,
Thank u
Welcome
iam not able to solve this problems.if A has sequence GAACC.if B has sequence GAATTCC.WHICH AMONG THE FOLLOWING IS TRUE.anwser is A cuts dna at 2500 nucleotides.B cuts at 4096 nucleotides.explain me.
Please give me the problem exactly as it is in the text.
looks like word "endonuclease" is missing or "recognition site" and "DNA strand" = I know the answer but I want to make a video so I need exact word problem in order to use in the video.
I modified your problem and here is a solution ua-cam.com/video/v6Rx4lEaLKk/v-deo.html
(and you will see that your problem stated wrong)
If in a cell the amount of DNA is 2c in metaphase then what will be the amount of DNA in anaphase , G1 phase, and after M phase.?
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Thank you for your videos. Base pair length is my biggest problem now. I still don't understand how to determine base pair and size. The samples of the kit i use give the base pair of the gel around 118bp however the marker/ladder i use range from 50-10,000 bp. Now on my result, the DNA bands are little below the lowest marker band. How can i determine the base pair length and size of such a result. Thank you in advance!
Oh, that is simple - you have to run a polyacrylamide gel (not agarose) and reference-ladder between 100-150 bases, then you could find the size of DNA fragment exactly. Good luck!
Thank you for your prompt reply sir!
Is it not 19118 bp? and with 2 sig figs 1.9 x 10(power of 4)?
Yes.
If the n=8 in plant cell, what is the no. of tetrads, no. of sister chromatids, no. of centromeres in pachytene of meiosis...?
if n=8 than 2n=16 and during prophase I chromosome number will double 4n=32
number of tetrads 32:4=8 number of sister chromatids 8+8 and 8+8 or 16 of one kind and 16 of the different kind (this question is tricky you can answer 16 of one kind or 16 of one and 16 of the other) number of centromeres 16 - one per a pair of sister chromatids.
Спасибо вам за видео.
Если можно у вас спросить, как посчитать наиболее вероятное число пар оснований в последовательности узнавания, если при расщеплении ферментом образуются фрагменты средней длинны 1,048,500 bp.
When DNA is digested by this particular enzyme, fragments are average 1,048,500 bp in length are produced, what is the most likely number of base pairs in the recognition sequence of this enzyme.
Хорошо я сделаю видео.
@@GeneticsLessons hooray!!! ☺️☺️☺️God bless you!!! I'm already a week trying to find the answer! It looks like there is not enough income data to solve this problem. Waiting for your video 🙏🙏🙏 (Student from Canada)
@@GeneticsLessons the name of this particular enzyme is endonuclease, but the name didn't helped me to solve the problem 🤷🏻 I just found that usually it has 4 to 6 bp, rarely 8bp. But no concrete solution.. and not in the textbook either...
Here is a solution: ua-cam.com/video/fo8G-0pcPck/v-deo.html
@@GeneticsLessons You are amazing 😍 you made a video in few hours!🙏🙏🙏
Sir, please help me in solving the problem
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Is 0.34 nm a constant number?
More or less. There can be different types of DNA left handed and right handed.
Hello sir in bdna the total length of a Turn is 3.4nm and each turn contain 10 base pairs. How could be The length between concecutive base pairs is 0.34? Is it 0.37 Right? If we divide 10 base pairs conatian 9 equal division so 3.4 divide by 9. 0.37 so 0.37 is the distance between consecutive base pairs?
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How many turns are in a double helix? I am not a scientist but just a layman.
10.5 base pairs per one turn of B-DNA.
@@GeneticsLessons Thank you very much, Sir!
Respected sir
If i send you the picture of my ran gel of dna....will you be able to determine the size and no. of amplified DNA and no. of polymorphism and monophorphic bands... If yes pls send me ur email id
You can send me email though contact option.
Sir
Sir i couldnt find your email
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