Introduction of Hamming Code

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[@Crazytesseract]

Hamming codes can be understood using logic (maths is not required). However, maths is useful.
There are 4 data bits. Now you add 3 parity bits so you get 7 bits. So max 7 possible locations where errors can happen. And 7 is 2^3 - 1. So 3 bits needed to define 7 positions (plus 0, for no error)
m=4,p=3. so 2^p-1>= p+m.
(Remember I am going backwards, you need to fit the equation or solve).
Similarly for 15 bit codeword.
2^4-1=4+11. 4 parity bits, 11 data bits.
Also watch Hamming codes on 3b1b channel.

[@sallauddin1]

Extremely easily explained, great job.

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[@Neopolitan_Illusion]

I understood this better than the module laid to us.
Thank you 😊

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Great effort madam ji, thanks for making your lectures in English

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good explanation mam...
thank you !

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thank you madam it helps us lot ........................

[@sureshpendram1977]

Thank you for better understanding

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[@khwahishsinha6799]

Helpful video thank u mam :)

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Thank you mam.. you are a life saver 🙏

[@muskaanmittal296]

Maam tysm for this video u cleared all my doubts I was so confused

[@avsubbareddy9653]

Thanks mam I have so helpful for sem exams

[@shihansajeed2110]

great video. very well explained.

[@Av6Hamza]

Thank you so much!! Finally I understood how it works

[@Tigertagwar]

Easy explanation thanks 😊

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[@fakerdxx]

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[@devasaikumarpeddiboina4662]

Nice teaching..,tq

[@factworldshorts3101]

mam but this parity formula give wrong ans if we give 7 bit
by above formula there should be 3 parity bit but ans is 4 parity bit

[@mohitchandel2002]

I need help to solve this problem...A 4-bit data 1100 is received as 1101.
How will the Hamming error correcting
code detect and correct the error ?

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Thank you mam ❤️

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AWSOME lectures thank u so much mam......

[@abdulaminkhan3275]

thank u mam mca 1st yr

[@aadrshptel]

My teacher has taught to count bit from right side and you're counting from left side .. which one is correct??

[@TheCommentCommander]

Our teacher told us both are correct. Just make sure to stick to one all the time and avoid silly mistakes from being confused.

[@shantanutekale6199]

Good explain👍

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Happy teacher's day

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Where I can find more videos related to information theory

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Yes

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Digital electronics

[@haadbajwa7565]

Well explained

[@Gb-kg5mq]

Hello madam...u showed the formula 2^p>=p+m+1...can u plz tell why 1 is used for & why in (7,4) hamming code there is 4 message & rest r parity bits then where is 1 amount...or anyone can plz answer me this...thank u

[@Crazytesseract]

There are 4 data bits. Now you add 3 parity bits so you get 7 bits. So max 7 possible locations where errors can happen. And 7 is 2^3 - 1. So 3 bits needed to define 7 positions (plus 0, for no error)
m=4,p=3. so 2^p-1>= p+m.
Similarly for 15 bit codeword.
2^4-1=4+11. 4 parity bits, 11 data bits.

[@praise6265]

great mam :)

[@krzysztofkwietniewski9100]

Mam where did you get the formula 2^p >= p + m + 1. Isn't it supposed to be 2^p - 1 >= m ?

[@sudhanshunautiyal6765]

you can use both the equation to solve it but more accurate one is 2^p>=p+m+1

[@arifahmedbarbhuiya5141]

Very helpful your lecture

[@fasnamusharaf6458]

Very very helpful...

[@nikhilchourasiya4720]

Nice lecture thanks mam

[@shrur3527]

Thanks mam

[@lima7145]

redundant bit?

[@Omer-es7wo]

appreciated job.

[@jillellamounika4408]

Determine the single bit error correcting code or Hamming code for information bits 10110 using odd parity please solve this one mam

[@Smart_farming79]

Hello medam
Kya aap odd even parity ke bare me hindi me bata sakti ho

[@mukhtiarlaghari654]

Why we are use hamming code

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Nyc

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Helpful

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Thanks

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Even our teachers are copying this madam lectures

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Angrejan

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😂hii mam

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WHY IS EVERY SINGLE YT VIDEO ON THE HAMMING CODE BY AN INDIAN

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Exam ke akhiri 4 min waste kiya 😢kuch bhi samjh nhi aaya

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Thank U Mam