When the pulleys have the same radius R and are separated by a distance D, the belt length is simply L = 2D + 2πR. When the pulleys have different radii r1 and r2, the length is then L = 2D + (r1 + r2) π + a correction term that accounts for the asymmetry. Note that the asymmetry causes the straight lengths to become shorter, and the sum of the circular lengths to become larger, so that the two effects offset each other, but do not cancel. Because the arc length increase is greater than the straight length decrease, the correction term will be positive. Now the correction term has to depend on the difference (r2 - r1) and the distance D. It must have dimensions of length, so the most likely candidate is ((r2 - r1)^2) / D, to within a constant. To a first approximation, take the constant to be 1. This yields a result L = 2D + (r1 + r2) π + ((r2 - r1)^2) / D. This is exactly the result obtained by Aryan, without having drawn a diagram or doing any geometry.
Subasini Sahoo u just have to make a change at the length of perpendicular line in this open belt a perpendicular line is made inside of the circle but for cross u have to extend the line on which the perpendicular is drawn and should draw the perpendicular on the extended line
derivation of Alpha is wrong. If you consider sin (alpha) = (r1-r2)/l means. alpha should be sin-1((r1-r2)/l). And how did you applied binomial theorem. please explain...
Sir aap to pura doubt hi clear kar diye thank you so much sir ❤❤❤❤
Great video sir. Thank you!
I hope you are a university lecture. you are good man❤
super explanation sir.....
...👍👌🌝🙏👏
When the pulleys have the same radius R and are separated by a distance D, the belt length is simply
L = 2D + 2πR.
When the pulleys have different radii r1 and r2, the length is then
L = 2D + (r1 + r2) π + a correction term that accounts for the asymmetry.
Note that the asymmetry causes the straight lengths to become shorter, and the sum of the circular lengths to become larger, so that the two effects offset each other, but do not cancel. Because the arc length increase is greater than the straight length decrease, the correction term will be positive.
Now the correction term has to depend on the difference (r2 - r1) and the distance D. It must have dimensions of length, so the most likely candidate is ((r2 - r1)^2) / D, to within a constant. To a first approximation, take the constant to be 1.
This yields a result
L = 2D + (r1 + r2) π + ((r2 - r1)^2) / D.
This is exactly the result obtained by Aryan, without having drawn a diagram or doing any geometry.
Great teaching ......
This is what we expect....
perfect,this is what i was searching .
thanks :)
ok thanks for this man
really helpful
So beautiful explain
Super
It's very helpful!!!!
Pls do more videos on gears sir
Need a video for cross belt system :)
very nice...plz provide length of cross belt drive
Subasini Sahoo u just have to make a change at the length of perpendicular line in this open belt a perpendicular line is made inside of the circle but for cross u have to extend the line on which the perpendicular is drawn and should draw the perpendicular on the extended line
Best one..
Thank you so much
how to find the centre to centre distance of the pulleys?
That's a given. It's a function of your installation constraints. Measure it
how did you apply binomial theorem please explain that
We should consider two terms in binomial expansion. Kindly go through the expansion which is Maths subject.
Just accept n mug up the change made by binomial theorem
amol kumar 😂😀
derivation of Alpha is wrong. If you consider sin (alpha) = (r1-r2)/l means. alpha should be sin-1((r1-r2)/l). And how did you applied binomial theorem. please explain...
V M K bewakoff when angle is very small sin x is nearly equal to x . Engg m a gya itna bhi ni pta 😂
Rip😂😂
thankyou,
Sir please cross belt drive pe ek video bna do
Nice
Kekaaa👌
Language problem
Great video sir. thank you!