Dear Sir You are so great in teaching mechanical courses why dont you make complete descriptive lecture series on the course of statics, dynamics, Mechanics of materials, Fluid mechanics, Design of machinery, etc You videos help a lot please share your knowledge with others too. Regards From Pakistan
Dear Dr. Faysal. When you calculate the acceleration, you have considered only the tangential acceleration (which is the product of the angular acceleration (alpha) and the arm between the IC (instantaneous center) and the point of interest (the arm for 60 degree angle is L). Should not you consider the acceleration in the perpendicular direction due to the centripetal force (which is equal to v2/r or w2r, in both equations the number 2 are in square form)? Thanks.
This question is impossible, both angles cannot be 60 degrees (phi and theta) when all lengths from ab bc and ac are L There cannot be a difference of height between ab and bc mfw you go against the laws of physics to "solve" an impossible question 💀💀💀
So what? When both angles equal to 60⁰, that means the triangle has 3 equal sides and 3 equal angles. And both of points A and C are gonna be at the same height. Also, the piston is gonna be inside the cylinder, which is very logical! 🤔
@@nourdarwish4277 You're right. Now that I'm watching this again a few month later, I don't see anything wrong. I don't know how I ever saw anything wrong lol. It all makes perfect sense to me.
@@nourdarwish4277 I was just doing a little side project where I needed to design a lever that can move something up and down. I graduated from Aerospace Engineering earlier this year tho.
thank you very much for explaining so good
Dear Sir
You are so great in teaching mechanical courses
why dont you make complete descriptive lecture series on the course of statics, dynamics, Mechanics of materials, Fluid mechanics, Design of machinery, etc
You videos help a lot please share your knowledge with others too.
Regards From Pakistan
Dear Dr. Faysal. When you calculate the acceleration, you have considered only the tangential acceleration (which is the product of the angular acceleration (alpha) and the arm between the IC (instantaneous center) and the point of interest (the arm for 60 degree angle is L).
Should not you consider the acceleration in the perpendicular direction due to the centripetal force (which is equal to v2/r or w2r, in both equations the number 2 are in square form)? Thanks.
السلام عليكم استاذي الكريم الحل معقد واايد
This question is impossible, both angles cannot be 60 degrees (phi and theta) when all lengths from ab bc and ac are L
There cannot be a difference of height between ab and bc
mfw you go against the laws of physics to "solve" an impossible question
💀💀💀
I was thinking the exact same thing lol
So what? When both angles equal to 60⁰, that means the triangle has 3 equal sides and 3 equal angles. And both of points A and C are gonna be at the same height. Also, the piston is gonna be inside the cylinder, which is very logical! 🤔
@@nourdarwish4277 You're right. Now that I'm watching this again a few month later, I don't see anything wrong. I don't know how I ever saw anything wrong lol. It all makes perfect sense to me.
@@1stcomment700 That's great! What are you studying?
@@nourdarwish4277 I was just doing a little side project where I needed to design a lever that can move something up and down. I graduated from Aerospace Engineering earlier this year tho.