What is d ans if the options are given in mullikens trms . 3T1g or 3T2g ... $ what is in case of configurations d^5 low spin . Bcoz for high spin i get it by orgel diag.
Sir had you not taken CF splitting concept the ml value comes to be 6,i.e, 2 electrons in +2 and 2 electrons in +1 orbitals. So should we always use cfse concept in such cases?
इसका आंसर cr[CN]6 3G nahi hoga kya kyuki t2g orbitals ke liye l value +2 +1 -1 hoti hain dz2 to eg orbital h iske liye l value 0 hoti h dz2 orbital me to strong field lingand ke karan electron jayega hi nahi Please confirm sir in gate 2017 question ground state term symbol dx2 dx2y2 0. -2 dxy dxz dyz +2 +1 -1
DINESH KUMAR SAINI, Is question me already maine mention kia h ki option ³G nhi hoga qki question me sirf electronic state ya metal cation na de k poora complex dia h, ye ek trick question tha, aur poora complex hone ki wajah se hme ligand k effect ko bhi consider krna hoga... Isliye strong feild ligand hone ki wajah se electronic configuration change hogi aur answer ³H hoga...
All 'Bout Chemistry Strong Field ki vajah se electron dz2 orbital me jayega hi nahi isiliye Sigma L value {+2×2+1+(-1)=4 4 ke liye G hi hota hain Sir dz2 orbital eg orbital hone ke karan dz2 me electron nahi jaayega Please confirm Sir please
DINESH KUMAR SAINI, I think you're confused in ml values of d-orbitals. The ml values are -2, -1, 0, 1, 2 for dx²-y², dz², dxy, dxz, dyz respectively. Now I think it'll be clear yo you...
All 'Bout Chemistry OK Sir thanks I confirmed Kuch book me dz2 ki ml value 0 de rakhi hain Yeh ml values jo apne batai hain wo hi fix h na d orbitals ke liye dz2 orbital ki ml value kuch book me 0 de rakhi hain likely that jaise pz orbital ki ml value 0 hoti h
IN this question complex is given thats why we have taken effect of ligands in it. if it is simple ion then we dont have to worry about the splitting and alll..
Hey they asked about the ground state term not the first excited state term..for d4 system pentate D is a ground state term..triplet H is first excited term
Noor Fathima, check out GATE 2017 Question Paper and Answer Key on GATE Official website. This is an exceptional case asked in exam and it should be done like this.
No, it's not like that, Cr+2 with strong feild ligand is given, now whenever you have question like this where you're given with complex then your ligand will also play role in deciding term symbol. That's why the effect of CN ligand is taken over here. For reference you can see James E Huhyee, or Meissler and Tarr there many examples like this are given.
The filling of electron would be different for tetrahedral arrangement as T2 will go up and E will come down, Now it depends on question that what will be value of sigma ml there.
Sir u should make a playlist taking JAM and GATE questions one by one. That would be greatly appreciated
Nice suggestion, I'll try to follow that... Thank you 😊
What is d ans if the options are given in mullikens trms . 3T1g or 3T2g ... $ what is in case of configurations d^5 low spin . Bcoz for high spin i get it by orgel diag.
Learned many things from you sir thank you🙏 so much
Excellent job sir...we want more like this
Thank you, I'm making more videos 😊
How you calculate the l value ..pls reply...sir..
Sir is there video for mulliken symbol?
Sir had you not taken CF splitting concept the ml value comes to be 6,i.e, 2 electrons in +2 and 2 electrons in +1 orbitals. So should we always use cfse concept in such cases?
Vishal Roy, this concept is applicable only if you're given with complex in the question
All 'Bout Chemistry ok👍 thank you for quick reply 😊
You're most welcome 😇
you mean the above answer is wrong?
No answer is correct, check yourself from GATE 2017 answer key
This made it so simple, thanks :)
Sir . What about the -4charge given in complex
That was so helpful..keep up the good work sir..
Sir it is an example d3 term symbol??
d4 low spin complex
इसका आंसर cr[CN]6
3G nahi hoga kya kyuki t2g orbitals ke liye l value +2 +1 -1 hoti hain dz2 to eg orbital h iske liye l value 0 hoti h dz2 orbital me to strong field lingand ke karan electron jayega hi nahi
Please confirm sir in gate 2017 question ground state term symbol
dx2 dx2y2
0. -2
dxy dxz dyz
+2 +1 -1
DINESH KUMAR SAINI,
Is question me already maine mention kia h ki option ³G nhi hoga qki question me sirf electronic state ya metal cation na de k poora complex dia h, ye ek trick question tha, aur poora complex hone ki wajah se hme ligand k effect ko bhi consider krna hoga... Isliye strong feild ligand hone ki wajah se electronic configuration change hogi aur answer ³H hoga...
All 'Bout Chemistry
Strong Field ki vajah se electron dz2 orbital me jayega hi nahi isiliye
Sigma L value {+2×2+1+(-1)=4
4 ke liye G hi hota hain
Sir dz2 orbital eg orbital hone ke karan dz2 me electron nahi jaayega
Please confirm Sir please
DINESH KUMAR SAINI, I think you're confused in ml values of d-orbitals.
The ml values are -2, -1, 0, 1, 2 for dx²-y², dz², dxy, dxz, dyz respectively.
Now I think it'll be clear yo you...
All 'Bout Chemistry OK Sir thanks I confirmed
Kuch book me dz2 ki ml value 0 de rakhi hain
Yeh ml values jo apne batai hain wo hi fix h na d orbitals ke liye dz2 orbital ki ml value kuch book me 0 de rakhi hain likely that jaise pz orbital ki ml value 0 hoti h
DINESH KUMAR SAINI,
Follow standard books... JD Lee me dekho, Huhyee me, Shivers and Atkins me... Ye sb standard books h... Inke data reliable hote h
Sir what will the value of "J"
In that case
Sir jha aapne n+1 likha h wha pe 2S+1 mtlb spin multiplicity likhte h na
Plz reply
Haan baat ek hi Hai qki spin of electron is 1/2 to chahe n+1 kr lo jaha n means number of unpaired electrons honge.
If there is ground state term symbol asked den also is same answer??? If J value is not given in answer
IN this question complex is given thats why we have taken effect of ligands in it. if it is simple ion then we dont have to worry about the splitting and alll..
Hey they asked about the ground state term not the first excited state term..for d4 system
pentate D is a ground state term..triplet H is first excited term
Noor Fathima, check out GATE 2017 Question Paper and Answer Key on GATE Official website.
This is an exceptional case asked in exam and it should be done like this.
@@AllBoutChemistry but how it is an exceptional case?chromium is in +2 state..no one files the objection at dat time for this answer i guess...
No, it's not like that, Cr+2 with strong feild ligand is given, now whenever you have question like this where you're given with complex then your ligand will also play role in deciding term symbol. That's why the effect of CN ligand is taken over here.
For reference you can see James E Huhyee, or Meissler and Tarr there many examples like this are given.
Sir how to solve multi step reaction constant
ok sure
Ty sir .....and what is the term symbol of V3+ ion .....can u plzz tell me
Sir What will sigma ml value if it were tetrahedral arrangement
The filling of electron would be different for tetrahedral arrangement as T2 will go up and E will come down, Now it depends on question that what will be value of sigma ml there.
sir ²s+1L. ?????
sorry.. i didn't get you...???
is this wrong answer?.someone commented like that know
No answer is 100% correct
Thank you for clear explanation.
Sir esse hi video ...regular dal digiye
Thankyou so much sir😊😊😊
thank you for the solution
Vry nice explantion sir ... Thank you
nice .. really it is very conceptual nd important
The ground state for[co(H2o) 6]+2 solve sir please🙏
Thank U So Much....
Very nice😎😍🤩
Thank u Bro for neat explanation
Thank you sir
Thank u so much sir🙏
Very well explained sir thnku so much
Thank you so much
good explination sir thanks.....
If it's not for complex dn d5 is correct
Great explanation... please give quantum mechanics lectures
Thank you... I'll sure make videos on Quantum soon.. :)
Thanks a lot Sir
Thanks 😊 sir
Ok thank you sir
Thanks sir
you're welcome :)
3F
👌👌👌👌
Thanks
Thank u
Its answer should be B
Hand's up to you sir
But electron shld get singly occupied first....
But in the case strong field ligand is there , hence in the octahedral splittings t2g electrons first fill
great sir
Rly btfl expltn
thank you
L value comes out to be 6 I think all the options r inorrect
Thank you sir
Thanks
thanks sir