Questions ranging from 3 to 11 are a bit confusing during first time... But when you will do it again and again you will get to know the concept behind...
same que. of me also sirr...... subset toh tbb hoyega jbb 'A' k sarre elements 'B' m honge apn sirff ekk hi element le rhe h na..... toh woh True bhi toh ho skta h na sirr????
Sir but in Q2 (v) if we take x=1 A={1,3,5} and B={1,6,7,8} then x will belong to A, A is not the subset of B but x will belong to B. So this should be true
Sir you are great teacher of mathematics. I have started 11th class from maths chapter no 1 sets from your videos. Sir ,your teaching style is very very great .I hope your channel will go to top of list in few days.Sir please start making videos for new session of 11th (i.e 2021-2022)
SIR I WAS TOTALLY CONFUSED IN QUESTION NUMBER 3....................I REQUEST YOU TO MAKE A SEPERATE VIDEO ON Q 3 AND ITS CONCEPT......sir you teaching style is very good during lockdown i am only preffering your video....and really your video are very helpful....but still i request you to make seperate video on this question..
Sir your videos not only help school students also college students in real analysis basics. Please make videos of higher class mathematics and definitely your channel will reach at maximum heights because you clears the doubt from basic 🙏❣️
3rd question: AUB=AUC On applying the formulas x{A}+x{B}-x{A intersection B}=x{A} +x{C}-x{A intersection C}. (i)eq As {A intersection B}= {A intersection C} So on equating (i) equation x{B}=x{C} As elements in both sets are same So B=C Give it as much as likes you can so that it goes through sir eyes
Sir you are the best U explain and clear concepts so well and u also clear doubts even though u don't teach individually cause u urself know what doubts will noobs face and u clear them. Thanks u are simply great
@@shivammahajan6995 firstly by noob I meant the first time learners of the topic Including me cause when I watched I could relate the doubts which he cleared and I wrote that when I revisited the video..... Hope u got it
Sir, in question 2 part 5 8:59 if we take example as following A={1,2} B={2,3,4,5} Then, here, x(which is 2) belongs to both the sets So, the answer should be true
Sir no. 3 ka explaination thoda mere dimag me uper se nikal lekin mai aise solve kia simple way me Solution: A U B = A U C A+B-(AΠB) = A+C-(AΠC) B-(AΠB) = C-(AΠC) It is given that Its is given in question that (AΠB)=(AUC) so this will cancel out So B=C hence proved..🤓😎
UA-cam saying skip the video if u know a how to solve UA-camr saying don't watch video first try yourself He is not UA-camr he is real teacher Real gem
You did not understand the question, we can write true only if the statement is true for any possible values. If it becomes false for any value, it is false. Hope you understood it.
Bhai mujhe v yahi problem he Let A={1,2} , B={2,3} Definitely A is not the subset of B But x belongs to A i.e 2 And here x belongs to B also i.e 2 Then why this statement is false???? even all the given conditions are true
You did not understand the question, we can write true only if the statement is true for any possible values. If it becomes false for any value, it is false. Hope you understood it.
*In Question 2. and Roman v) I have an issue with that!! It could be like this too. Let x=1; since x belongs to A; Let's define A = {1,2} and the question says A is NOT the SUBSET of B. that means I could define B = {1,3,5}; IN THIS ONE It clearly accepts the condition that A is NOT SUBSET of B; and x DOES belong to both A and B; What's up with that????*
See , only one example is capable to make a sentence false . Even if it accepts other cases still one example can make the whole sentence false. You can also give examples for making other options ( 1.2.4.5) true but still one example is capable of making the statement false. You should understand this concept as it would help you in solving questions based on syllogism in ntse stage ll . By the way do you study in class 11 ?
Q.2 (iv)-- solution. A={1,2} B={3,4,5} C={6,7,8} Then, A(doesn't belongs to)B B(doesn't belongs to)C A(doesn't belongs to)C . . From my side it is true. . . Please explain me it can be or not Please reply.
Listen bro in true and false questions a statement will be declared true only if it satisfies all the conditions and if you get even one condition or one set which is not satisfying then the condition becomes false.
Yaad ho gya - "chalte he next question ki taraf, before that students please pause the video to note it down" And the style of telling "check kr looo" 🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏
Sir agar x= 1,A={1, 2} B={1,3,4,5} Is case me x is the element of A A is not subset of B kyunki pura set B me nahi hai But X set B ka element to ho sakta hai
Sir i have one doubt: if x belongs to A and x belongs to B how can A be the subset of B. Because x is only common in both sets but all the elements of A are not in B.
In question no 3 X is the element of B and X is the element of C To aap.kaise keh sakte hai ki B is the subset of C. This is big confusion please sort out it.
prasant kumar Same, I also got confused by it. At 15:11 he wrote that if x ∈ B and x ∈ C then B ⊂ C but the statement is false because - _If x belongs to set A and set B, does it imply that A is a subset of B?_ Absolutely not. Sets A and B can share one elements but still have more elements that are not shared. *Proof* There is an element x, x ∈ A and x ∈ B. Suppose another element c, c ∈ A but c ∉ B. Then, it is not always true that A is a subset of B or A ⊂ B since x ∈ A ∩ B but c ∉ A ∩ B
Ok but in that case if x belongs to both B and C then we can prove that both B and C have same cardinality so they should be equal. n (A ∪ B) = n (A ∪ C) ⇒n(A) + n(B) - n(A ∩ B) = n(A) + n(C) - n(A ∩ C) But (A ∩ B) = (A ∩ C) [ Given ] ⇒n(A) + n(B) - n(A ∩ B) = n(A) + n(C) - n(A ∩ B) Cancelling n(A) and n(A ∩ B) from both sides ⇒n(B) = n(C) so B and C have same cardinality However the above proof still isn't helpful since it only proves that the sets are *equivalent* and not necessarily *equal* . Anyway, I have another proof for anyone who is stuck on this question (You can refer to a Venn Diagram to understand it better) B = (A ∩ B) ∪ (B - A) ⇒B = (A ∩ B) ∪ (A` ∩ B) ⇒B = (A ∩ B) ∪ (A` ∩ (A ∪ B)) But (A ∩ B) = (A ∩ C) and (A ∪ B) = (A ∪ C) [Given] ⇒B = (A ∩ C) ∪ (A` ∩ (A ∪ C)) ⇒B = (A ∩ C) ∪ ((A` ∩ A) ∪ (A` ∩ C)) Now (A` ∩ A) = Φ ⇒B = (A ∩ C) ∪ (Φ ∪ (A` ∩ C)) ⇒B = (A ∩ C) ∪ (A` ∩ C) Now (A` ∩ C) = C - A ⇒B = (A ∩ C) ∪ (C - A) ⇒B = C , *hence proved* .
Sir in q.2:5 (8:50)...u stated it false...but i can prove that it is true... Let x=2 A={2,3,4} B={2,5,6,9} Here, x is element of A and A is not a subset of B... But x still is element of B. Am i wrong?? Please clarify 🙏
You did not understand the question, we can write true only if the statement is true for any possible values. If it becomes false for any value, it is false. Hope you understood it.
Sir in 9:30 min in video x=1.. Then A={1,2} in your video.. Then it is not important to let B={4,5,6,7} we can also let B={1,3,4,5}in that case also A is not a subset of B but X belongs to B then it is true...... Please answer my question sir
Sir aap Q6 ki 3rd line par dhyan dejiye kyonki koi bhi set doosare set ko belong nahi karta hai balki uska subset ho sakta hai Isiliye X subset P(B) hoga
Sir 3rd question chote tarike se bhi ho sakta tha (A U B) = A + B - (A intersection B) (A U C) = A + C - ( A intersection C) As (A U B) = (A U C) A + B - (A intersection B) = A + C - ( A intersection C) B - (A intersection B) = C - ( A intersection C) Because, (A intersection B) = ( A intersection C) ( given) B = C
sir in 4th part of q.2 ,why did u take 1 and 2 as the elements of set C ?? u could have taken C=(7,8,9) instead. if u had C=(7,8,9), then A would not have been a subset of C and the statement would subsequently had been true . plz check :/
In Mathematics a example that shows the given statement is TRUE does not prove that given Statement is TRUE But an Example that shows the given statement is FALSE proves that it is false For example:- 2×2 =4 and 2+2 =4 So from here we can't say that a×a = a+a But, 3×3 = 9 3+3 = 6 So this example shows that a×a ≠ a+a, So it proves that a×a = a+a is a False Statement. I hope you will understand.
Sir mujhe ek baate nahi smjh aya ki 2 que ke 5 part me if we assume that X=1and A={1,2} and B={1,3,5} in this case A is not subset of A situation satisfying but X also belongs to B😕😕🤔
You did not understand the question, we can write true only if the statement is true for any possible values. If it becomes false for any value, it is false. Hope you understood it.
the question says every assumption is like that so it will be false because sir's example make it false and ur is true but the question says every should be true i hope you got it but my english is really poor..
You did not understand the question, we can write true only if the statement is true for any possible values. If it becomes false for any value, it is false. Hope you understood it.
Sir, hum question 2(iv) me ye kr skte hai kya: A={1, 2} [A not subset B] B={4,5,6} [B not subset C] C={7,8,9,10} And also, A is not subset C True (Ans.)
Respected sir, Please clear my doubt. In the fourth subdivision of the second sum, you had taken A={1,2}; B={4,5,6}; C={1,2,7,8} . so that you got the answer as A is a subset of C. But what if you take C={7,8,9,10}, now, how can the set A be the subset of C. I request you to clear my doubt sir, please consider my request
@@jacquelinefernandez1868 ....thanks for the reply....but still I don't get this....All the questions of 2nd sum are general true or false type question and .........the thing is the answer may change depending on the values he take for the respective sets ie. A , B , C....so how can he assure that whether it is true or false.....
People like u are helping those people who do not have tutions thanx sir
Hi
hindi me
No shit
Iske continuously part ni milte kya tm send kr skte ho link
Please watch this video on youtube-examination in life never give up mufti menk by merciful servant
Questions ranging from 3 to 11 are a bit confusing during first time...
But when you will do it again and again you will get to know the concept behind...
i think this was the only concept on which the students are getting messed up like me
Me too....
👆😔
Please watch this video on youtube-examination in life never give up mufti menk by merciful servant
Yes bro
True af
great job sir....... salute to such teachers👍👍👍👍
Question no.2-v : x=1 and A={1,2} here x belong to A if B={1,5,7} then A is not subset of B. But x belongs to B.
same que. of me also sirr...... subset toh tbb hoyega jbb 'A' k sarre elements 'B' m honge apn sirff ekk hi element le rhe h na..... toh woh True bhi toh ho skta h na sirr????
Ya i have same doubt
U r correct
Same daught
We need only one possibility for it to be true
Same question
today I come to know that my maths teacher also follows you😂😂
😅😅
Very nice sir ji thanks
😂😂😂😂
wow😂😂😂😂😂🤣🤣🤣🤣🤣
@@piyushchander09 wow
@@seeyouatthetop7 😌
Thankyou so much sir i thought ki lockdown me main nhi padh paungi maths kyunki doubts hi clear nhi ho rahe the but you sorted it all
Sir but in Q2 (v) if we take x=1
A={1,3,5} and B={1,6,7,8}
then x will belong to A, A is not the subset of B but x will belong to B. So this should be true
Yahi doubt hai Mera bhi sir batado
Wow Sarika tatiwar
Same doubt
@@Rahul_Raj__ As x€A therefore we can take x = 1
Same doubt
Sir you are great teacher of mathematics. I have started 11th class from maths chapter no 1 sets from your videos. Sir ,your teaching style is very very great .I hope your channel will go to top of list in few days.Sir please start making videos for new session of 11th (i.e 2021-2022)
SIR I WAS TOTALLY CONFUSED IN QUESTION NUMBER 3....................I REQUEST YOU TO MAKE A SEPERATE VIDEO ON Q 3 AND ITS CONCEPT......sir you teaching style is very good during lockdown i am only preffering your video....and really your video are very helpful....but still i request you to make seperate video on this question..
Me too .. I m also confuse in question number 3 and due to this question I left whole exercise 😫😫
Sir this statement is true sir please help me and our students
Plz plz plz plZ
Please watch this video on youtube-examination in life never give up mufti menk by merciful servant
If x €B and x€c then it's not sure to say that B is subset of C...it's not a concept
@@piyushmodi8067 yes you are right
Sir your videos not only help school students also college students in real analysis basics.
Please make videos of higher class mathematics and definitely your channel will reach at maximum heights because you clears the doubt from basic 🙏❣️
3rd question:
AUB=AUC
On applying the formulas
x{A}+x{B}-x{A intersection B}=x{A} +x{C}-x{A intersection C}. (i)eq
As {A intersection B}= {A intersection C}
So on equating (i) equation
x{B}=x{C}
As elements in both sets are same
So B=C
Give it as much as likes you can so that it goes through sir eyes
😸 that proves number of elements in set B = number of elements in set C 😹😹
It doesn't mean set B = set C
Bro number of elements does not mean ki set equal honge vo equivalent hota h
Sir you are the best
U explain and clear concepts so well and u also clear doubts even though u don't teach individually cause u urself know what doubts will noobs face and u clear them.
Thanks u are simply great
@AviSan damn bro you really need to understand the trend of the word noob
😑😑
@@shivammahajan6995 firstly by noob I meant the first time learners of the topic
Including me cause when I watched I could relate the doubts which he cleared and I wrote that when I revisited the video..... Hope u got it
@@AviSanX bro I literally can do that now! Oh it's true, it's DAMM true
@@shivammahajan6995 also a noob refers to the person who is new to a concept or idea or a game. So Pls think before u react!
@@rishavsingh6728 maybe you need to check that i have referred avi san really bro dont you think un should scheck who i tagged
Who all are watching in 2020?
Hmm
Watching in 2021 after exam for retest.. LoL
@@subhrabehera9147 fail hogya kya bhai🤡
In 2030
Sir, in question 2 part 5 8:59 if we take example as following
A={1,2}
B={2,3,4,5}
Then, here, x(which is 2) belongs to both the sets
So, the answer should be true
Sir plzz ek chiz smjh nii aarhi ki kyu AP miscellaneous k ques ,2 ke (i) me set B it's complicated le rhe ho sirf simple {1,2,3} kyu nii le rhe??
Wow sirr
Pahle mujhe ye tough lagta tha
But now all these questions becomes so easy
*_Real toughness starts from _**_11:30_**_ ...try it guys 🤔_*
Sir no. 3 ka explaination thoda mere dimag me uper se nikal lekin mai aise solve kia simple way me
Solution:
A U B = A U C
A+B-(AΠB) = A+C-(AΠC)
B-(AΠB) = C-(AΠC)
It is given that
Its is given in question that
(AΠB)=(AUC) so this will cancel out
So B=C hence proved..🤓😎
UA-cam saying skip the video if u know a how to solve
UA-camr saying don't watch video first try yourself
He is not UA-camr he is real teacher
Real gem
great work sir.... salute
2nd Q 5th one-
A={1,2} b={1,3} then if x=1
x belongs to A
A is a subset of b
Also now x belongs to B.
So statement can be TRUE.
You did not understand the question, we can write true only if the statement is true for any possible values. If it becomes false for any value, it is false.
Hope you understood it.
14:28 .... If same element belongs to two different sets, it's not necessarily true that 1st set will be the subset of 2nd set......check it....
Yes bro you are true I'm with you
9:20 sir hm agr B set ko {1,4,5,6,7 } lete to ....condition 1st A is not subset of B set hota and x(1) B set se belong krta. There is confusion. ??
Bhai mujhe v yahi problem he
Let A={1,2} , B={2,3}
Definitely A is not the subset of B
But x belongs to A i.e 2
And here x belongs to B also i.e 2
Then why this statement is false???? even all the given conditions are true
@@2005ashishsingh yaa bro.
You did not understand the question, we can write true only if the statement is true for any possible values. If it becomes false for any value, it is false.
Hope you understood it.
*In Question 2. and Roman v) I have an issue with that!!
It could be like this too. Let x=1; since x belongs to A; Let's define A = {1,2} and the question says A is NOT the SUBSET of B. that means I could define B = {1,3,5}; IN THIS ONE It clearly accepts the condition that A is NOT SUBSET of B; and x DOES belong to both A and B; What's up with that????*
See , only one example is capable to make a sentence false . Even if it accepts other cases still one example can make the whole sentence false.
You can also give examples for making other options ( 1.2.4.5) true but still one example is capable of making the statement false. You should understand this concept as it would help you in solving questions based on syllogism in ntse stage ll .
By the way do you study in class 11 ?
@@dt8332 no.. I'm 24. I need some revision sort of thing.!
Gr8 sir 👍👍
Quality of teaching maths in school to the power infinite plus one is equal to quality of teaching of these sir
Q.2
(iv)-- solution.
A={1,2}
B={3,4,5}
C={6,7,8}
Then,
A(doesn't belongs to)B
B(doesn't belongs to)C
A(doesn't belongs to)C
.
.
From my side it is true.
.
.
Please explain me it can be or not
Please reply.
Subset h question me belongs to nhi h??
Listen bro in true and false questions a statement will be declared true only if it satisfies all the conditions and if you get even one condition or one set which is not satisfying then the condition becomes false.
Always solve these types of questions with an intend of proving it wrong..
Yes it will be true 👍
A may or may not be the subset of C
Which means we consider it as False
And Question is telling it as false
That's why answer will be true
Thankuu sir, this tutorial help me a lot 🙂🙂
Please watch this video on youtube-examination in life never give up mufti menk by merciful servant
Are bhai aisi bhi condition bn skti h ki q 3 me x belong hi na kre c se to
Bhai ache se smjhao 13:50 pr apne kaise x ko belong kra diya c se
Yaad ho gya - "chalte he next question ki taraf, before that students please pause the video to note it down"
And the style of telling "check kr looo"
🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏
Best maths teacher on UA-cam 👍👍.
App ke jaisa koi nahi samjhata
Sir haven't you done the video of that miscellaneous example part
Sir, x€ B
And x€ C
How can be B subset of C
Eg.
X = 2
B ={ 2, 4}
C={2, 5}
But, B is not a subset of C
If the example is true then A U B would not be equal to A U C
GOD OF HELL ᎪᏒᎽᎪᏁ agreed
Here x is reffered as every element of set B
@@BhaveshKumar-is1co exactly
Sir,your teaching,your voice and offcourse you, all are awesome.
Sir agar x= 1,A={1, 2} B={1,3,4,5}
Is case me x is the element of A
A is not subset of B kyunki pura set B me nahi hai
But X set B ka element to ho sakta hai
Same doubt sir
Can you clear it?
sir, @7:29 we can take elements of set C other than{1,2,7,8} so why you have taken it to forcefully prove it false.
Thanks a million times Sir .😘
Sir Kya hm question 3 se 12 tk venn's diagram se solve KR skte hai???
Please reply sir..
Yes you do it
Sir l like your tone of# check kar loooo.....your teaching is marvelous
Kya jab Ek set ke sabhi elements dusra mai hote hai jabhi vo subset hota hai
ya
Kuch elements mil jaye tab bhi set subset ho jata hai
Thank you very much sir g,, my favorite teacher👍👍👍 I like you sir
That's pretty gay...
There is no word to thanks you sir .
Thankyou for help 😊😲
Hats off to u sir...
Great Hard Work
सर question no. 2 के 4 part में अगर हम c ={3,7, 9,10} ले तो क्या यह गलत हो जायेगा ।
Ha Bhai it becomes wrong but it must obey in all cases......when we take c={1,2,3,7} it becomes true....so statement is false
@@hanamantaraoinamdar1320 good
Sir at 5:20 ..B={{1,2},3} hona chahiye jaise aapne C ke liye likha hai
Thnx sir 🔥 great content
Very useful video.Thank you so much
Sir i have one doubt: if x belongs to A and x belongs to B how can A be the subset of B. Because x is only common in both sets but all the elements of A are not in B.
Yessss question 5 of Of Question 2 has this same concept .....
Here x is a variable for all elements of A and does not denote a single element
Sir miscellaneous exercise k examples bhi samjha dijiye
In question no 3
X is the element of B and
X is the element of C
To aap.kaise keh sakte hai ki
B is the subset of C.
This is big confusion please sort out it.
Exactly I completely agree with you. It's a wrong concept.
prasant kumar Same, I also got confused by it.
At 15:11 he wrote that if x ∈ B and x ∈ C then B ⊂ C but the statement is false because -
_If x belongs to set A and set B, does it imply that A is a subset of B?_
Absolutely not. Sets A and B can share one elements but still have more elements that are not shared.
*Proof*
There is an element x, x ∈ A and x ∈ B.
Suppose another element c, c ∈ A but c ∉ B.
Then, it is not always true that A is a subset of B or A ⊂ B
since x ∈ A ∩ B but c ∉ A ∩ B
Ok but in that case if x belongs to both B and C then we can prove that both B and C have same cardinality so they should be equal.
n (A ∪ B) = n (A ∪ C)
⇒n(A) + n(B) - n(A ∩ B) = n(A) + n(C) - n(A ∩ C)
But (A ∩ B) = (A ∩ C) [ Given ]
⇒n(A) + n(B) - n(A ∩ B) = n(A) + n(C) - n(A ∩ B)
Cancelling n(A) and n(A ∩ B) from both sides
⇒n(B) = n(C) so B and C have same cardinality
However the above proof still isn't helpful since it only proves that the sets are *equivalent* and not necessarily *equal* .
Anyway, I have another proof for anyone who is stuck on this question
(You can refer to a Venn Diagram to understand it better)
B = (A ∩ B) ∪ (B - A)
⇒B = (A ∩ B) ∪ (A` ∩ B)
⇒B = (A ∩ B) ∪ (A` ∩ (A ∪ B))
But (A ∩ B) = (A ∩ C) and (A ∪ B) = (A ∪ C) [Given]
⇒B = (A ∩ C) ∪ (A` ∩ (A ∪ C))
⇒B = (A ∩ C) ∪ ((A` ∩ A) ∪ (A` ∩ C))
Now (A` ∩ A) = Φ
⇒B = (A ∩ C) ∪ (Φ ∪ (A` ∩ C))
⇒B = (A ∩ C) ∪ (A` ∩ C)
Now (A` ∩ C) = C - A
⇒B = (A ∩ C) ∪ (C - A)
⇒B = C , *hence proved* .
@@balwan4679 thanx I got it t
@@rajat3398 in second proof check third step 😂😂 he wrote B = A union B 😂😂😂 lol that's enough to laugh on him
Thanks for for telling me this / sir please make a video on temperature and area
Thnku so much sir.I am really confused in this exercise,but you cleared all doubts.Great explanation☺💯💯❤👍
very helpfull vedio in lock dowm
owesome.... sir
explanation of question 4 was really owesome
Sir mujhe apke explication wale hi example krne h ap acha pda te ho🙏🙏🙏🙏🙏🥰
uuuuuummmmmmmmaaaaa teaching😘
itna badia expalanation dete ho ki koi tuition lagane ki jarurat nhi😀😃
Sir, you are the best teacher.
Sir in q.2:5 (8:50)...u stated it false...but i can prove that it is true...
Let x=2
A={2,3,4}
B={2,5,6,9}
Here, x is element of A
and A is not a subset of B...
But x still is element of B.
Am i wrong?? Please clarify 🙏
You did not understand the question, we can write true only if the statement is true for any possible values. If it becomes false for any value, it is false.
Hope you understood it.
Thank you so much dear genius sir😊
Awesome 👍🏻👍🏻
Mazaa aa gyaa sir G
thank you ❤️ sir... i have no words more to thankful you
MAN! you look like abish matthew. Also, nice explanation
brilliant sir . it is easy to understand.👌👌👍👍👍
Sir in 9:30 min in video x=1.. Then A={1,2} in your video.. Then it is not important to let B={4,5,6,7} we can also let B={1,3,4,5}in that case also A is not a subset of B but X belongs to B then it is true...... Please answer my question sir
If X belongs to A n X=1 then A sld be {{1}2} shouldn't it be?
Sir aap Q6 ki 3rd line par dhyan dejiye kyonki koi bhi set doosare set ko belong nahi karta hai balki uska subset ho sakta hai
Isiliye X subset P(B) hoga
Sir 2 iv me C={7,8,9} A={1,2} and B={4,5,6}le lijiye tab bhi to B is not the sunset of C tab
Hamare pura statement true Ho jayega
Plzzz respones
ya i also think like that .....both possibility can happen
Hence answer will be correct right
@@arsh6842 i am not shure about that but both the posibility we can see in it...😊😊
Sir 3rd question chote tarike se bhi ho sakta tha
(A U B) = A + B - (A intersection B)
(A U C) = A + C - ( A intersection C)
As (A U B) = (A U C)
A + B - (A intersection B) = A + C - ( A intersection C)
B - (A intersection B) = C - ( A intersection C)
Because, (A intersection B) = ( A intersection C) ( given)
B = C
no , u r using wrong given condition
@@akshat2735 and what is wrong ??
@@minalduggal9174 how can u add sets a and b
@@akshat2735 by overlapping formula ;- n(A u B) = n(A) + n(B) -n(A intersection B) and n(A u C) = n(A) + n(C) -n(A intersection C)
@@minalduggal9174 in q3 it is not applicable because it is an application formula of sets which is used in word prob not in proving
thanks sir 👍
sir in 4th part of q.2 ,why did u take 1 and 2 as the elements of set C ??
u could have taken C=(7,8,9) instead.
if u had C=(7,8,9), then A would not have been a subset of C and the statement would subsequently had been true .
plz check :/
In Mathematics a example that shows the given statement is TRUE does not prove that given Statement is TRUE
But an Example that shows the given statement is FALSE proves that it is false
For example:- 2×2 =4
and 2+2 =4
So from here we can't say that a×a = a+a
But,
3×3 = 9
3+3 = 6
So this example shows that a×a ≠ a+a, So it proves that a×a = a+a is a False Statement.
I hope you will understand.
Sir ak case ye bhi to hai kii koi match hii naa krta ho tbhii empty araha ho Q 4 KA 2 PLZZ SOLVE MY DOUBT
Sir u r best teacher in universe
Sir miscelaneous examples ka video kaha hai?
Sir question 4 ko example ke through solve kar sakte hai kya? Please reply kijiega.
@@riapandit5547 why not
that question contains various conditions which you have avoided
Yes, true
Yaa u have to assume certain things to proof
Sir mujhe ek baate nahi smjh aya ki 2 que ke 5 part me if we assume that X=1and A={1,2} and B={1,3,5} in this case A is not subset of A situation satisfying but X also belongs to B😕😕🤔
Great answer bro!!! Really highly beneficial
Your teaching method is so fantastic sir.Thanks for give me a strategy to solve mathematical problem.
Superb way of teaching sir
I like your way of teaching
2.(V). If A= {1,2}
B= {1,3,5}
Here A is not a subset of B.. but 1 belongs to B😐!!!
How sir!
You did not understand the question, we can write true only if the statement is true for any possible values. If it becomes false for any value, it is false.
Hope you understood it.
Sir at 7:50 we can also take c ={7,8,9} then the statement can become true please clear this to me
the question says every assumption is like that so it will be false because sir's example make it false and ur is true but the question says every should be true i hope you got it but my english is really poor..
Sir in Q2 (iv) if we take C={5, 6} then A is not a subset of C so it should be true. Correct me if i am wrong🙏
You did not understand the question, we can write true only if the statement is true for any possible values. If it becomes false for any value, it is false.
Hope you understood it.
Exactly what he said
Very nice way of explanation sir, Thank you very much.
In q2(v)
if,x=1
A={1,2}
B={1,3.4,5}
IN THIS CASE -
x€A AND A₡B then, x€B.
Am i correct ???please reply sir..............
sir
Your videos are so helpful for us
Great video very helpful
Nice bhaiya
Awesome sir 👌👌🙏🙏🙏🙏
Just amazing sir
Salam sir kia aap ecat preparation kara sakte hain fast uni k liye
sir ..ques 5th mein aisa bhi to ho sakta h ki x belongs to B but other elements does not belong to B ..then in that case ye to true hona chahiye
Then a is subset of b
@@shantanujha15 ek element same hone se subset nhi hota
Sir, hum question 2(iv) me ye kr skte hai kya:
A={1, 2} [A not subset B]
B={4,5,6} [B not subset C]
C={7,8,9,10}
And also, A is not subset C
True (Ans.)
iska ans pta lga merko bhii ye doubt hai
Sir question no.3 ko assume karke kar sakte h kya??????
Respected sir,
Please clear my doubt. In the fourth subdivision of the second sum, you had taken A={1,2}; B={4,5,6}; C={1,2,7,8} . so that you got the answer as A is a subset of C. But what if you take C={7,8,9,10}, now, how can the set A be the subset of C. I request you to clear my doubt sir, please consider my request
But there are chances that A is a subset of C. But in question, it is given that A is not a subset of C which is wrong.
Ji
@@jacquelinefernandez1868 ....thanks for the reply....but still I don't get this....All the questions of 2nd sum are general true or false type question and .........the thing is the answer may change depending on the values he take for the respective sets ie. A , B , C....so how can he assure that whether it is true or false.....
4:12 sir kya x ek set ni h..... Plz reply
Thank you very much sir
And net as well
Explanation is really good! Thank you sir..