In this video Mohit Goenka Sir discusses all 22 questions asked on Current Electricity July Attempt JEE main 2022. 😍 Just in Rs 99 get all Physics Concepts, Chapter wise PYQs (2019 to 2022), Tests and How use web version - ua-cam.com/video/G8NPmayT3L8/v-deo.html 👉July Attempt Chapter Wise Solutions Playlist Link - bit.ly/3LeU4zB 👉June Attempt Chapter Wise Solutions Playlist Link - bit.ly/3AHXgjJ
It's 4:22 am and I'm done for the day (or night). This will be my last late night study session and I'll try to change my sleep cycle, but I'll surely remember these days.....
@@DARKRAI-i5j mera bhi change hogya subah subah thand me half shirt aur lower pahenke running krne jata hu ab 6:30 baje se 7 tk maja aaa jata ha pure body me 🔥🔥
Q2 3:23 silly mistake Q9 18:17 do once again Q10 20:01 once again Q12 23:35 concept Q14 29:15 Q15 30:26 current sensitivy Q17 34:43 do once again Q18 36:36 formula Q22 46:02 confusing #learnlikeneverbefore
for my revision: 17:56 Great Standard Ques which was asked in my institute test and didn't knew how to solve lol 22:49 Great Conceptual and Controversial Ques but the explanation here is(sir ne nhi bataya) that if we write I = V/R then write R=rhoL/A then Area cut ho jaata hai, which only leaves us with L in denominator. 26:40 Great Conceptual Ques 28:14 Great ques and confusing coz BLUNDER KRDIYA BHAI MAINE 35:05 Easy ques but follow the calculation the way sir showed 39:26 Good ques 42:25 Fact Based Ques(remember this) 44:14 Great ques
Q4 7:19 SM - (diff likha hai) Q8 13:40 - potentiometer Q9 17:56 CM - (emf mei pd zero ka mtlb ye ni ki poore circuit mei no current) Q12 22:50 - drift vel Q14 28:00 SM - (increase by likha hai bhai) Q15 29:35 - Concept (galvanomter sensitivtiy) Q18 35:07 - solve smartly , put values in end Q21 42:25 - concept Q22 44:10 - bdhiya ques
25:57 sir, V = I T by ohms law V directly proportional to I .......(Eq 1) And I = n A V(d) e I directly proportional to V(d) ..... (Eqn2) Therefore by 1 and 2, V(d) directly proportional to V
potentiometer rev 17:00 and 9:00, meter bridge wala 11:13 ( wheatstone), 40:14 effective conduvtivity is resistance offered are same 43:10 fact based 47:18 patience question
Current Electricity-REVISE💥 42:27[Conceptual] 18:24[Most Repeated] 20:15[AC] 26:20[Remember IMP] 28:23[Increased BY] 47:07[Length doubles then Area halves] 30:43[Current Sensitivity] 31:46[Potentiometer Resistance and RB in Series] 34:36[V const due to parallel so take v^2/R] 39:00[Bulbs] Thank You Very Much Sir❤
*Timestamps* CURRENT ELECTRICITY Q10 19:43 Peak value wala problem Ac pdho Q14 28:18 language problem Maine length 2x leliya woh 2L + L hogi Q15 29:30 concept problem Current sensitivity = Theta / current and NIAB = C theta Q19 39:27 Easy tha dhyaan rkhna next time R = R1 + R2 Q22 45:20 ye ban gaya tha answer galat tick hogya but acha question tha to ek baar phirse krlena
litteraly telling this man is like someone god has sent in these last days for first attempt ab 1st ka toh pta ni dusra attempt toh fod hi denge sir like litterally hats off to ur revision series as well as pyq solvings uh r damnnnnnn awesome sir thankuu soo much
35:00 rem❗inv ratio 39:07 redo 41:28 cond inv res 42:18 1 st mrk the pot 47:19 ✅ 43:03 mang cons -R 30:37 NIAB=ctheta c is torsial const,I SENSITIVITY IS THETA/I 29:10 elongatn q me volm ∆ ni krte A*L=v 29:10 r pe R depend nhi krta 24:00 vd =eE/mTou I =nAvd. E -v/l 19:29 chk🚫 1:36 ye yad rkh, 5:10 re chk 20:17 ac me peak i =i./√2 Heat prod-h =i^2Rt
[2:03] o or vo ke beech me to pura hai [9:58] re do [17:57] re do must late concept [19:05] irms =io/root2 [21:51] do again silly mistake [25:02] repeat silly mistake learn sare formule khol lena contro [26:00] repeat [28:00] drawn out and increased by repeat [30:00] niab=c theta theta /i currrent sensitivity [37:00] common khechna [41:00] repeat new {43:00] length and area volume constant
Sir what if in 44:14 , we take both length as L1 and L2 for X and Y respectively, Then when we stretch the wire X to W, the Area and Length both will change but volume will remain constant, So we use LA=V which gives A=V/L and when we put it in Resistance of W we get (L)^2 which is basically (L1)^2 and then we equate it with Resistance of Y and then we write the terms in expression of Resistance of X(R1) and Resistance of Y(R2), where we get the expression 4R1=2R2, so we get R1/R2 = 1/2 which is the answer. Sir is this approach correct?
1:03, 19:50( use i rms in ac source for heat calc), 35:12( lengthy calc se bacho), 40:26 (eff conductivity ke liye equivalent system draw karo then proceed
Bhai wo shi h dekh Drift velocity = I / (neA). me sir current ka dependency check ni kiye .... I=V/R. aur kyuko R=pl/A to area cut jayega aur inverse relation with L hi aayega
@@themicahbell woh sab toh thik hai, Lekin i noticed that only original drift velocity formula was used to find ans.(Vd=eEτ/m) Ig we have to ignore I=neAVd ones.
1:00 rev 5:00 dont panic and apply basic conc 10:35 meter bridge 19:00 basics pe khelna hai 20:00 DC to AC rev 22:00 units ka khel 24:00 27:00 aata tha but still rev 29:30 current sensitivity 40:00 aise ques mein diagrams bana liya karo agar atko 42:30 theory 44:03 good ques
q1 1:51 used eq emf but used v= e-ir instead of just using v = 4 (doubt) q9 18:50 similar type q13 27:17 solved but conceptual q19 41:13 forgot the 2 q22 44:18 good ques
Thanks sir ❤. Sir no error by nta Q12 25:35 , you proved it in 2023 jan vid at 59:09 by substituting 'I'. #learnlikeneverbefore Q. 18 # 35:10 revisit Q. 19 # 39:26 silly
In Q.12, I=neAVd...then V/R=neAVd....now write R as (rho into length)/area.....u have VA/(rho into length)= neAVd.....now Area from both sides get cancelled....so drift velocity is independant of area.....I think this is the solution
For 2nd revision - Question - 22 ( good question) Question - 18 ( good methid for less calculation) Question -10 silly mistake on peak current Question - 5 silly mistake thankyou sir #learnlikeneverbefore
25:25 Sir B wala galat hoga cuz when we put I=V/R then put R=rho*l/A , A will get cancelled and we get the expression Vd=V/rho*lne hence we can say Vd is independent of the area of cross section
At 25:35, B Sahi nahi hoga sir. Agar A badlega to resistance kam hoga jiske karan current bhi same amount mei badh jayega to no effect. E ko V/l wala isliye valid hai kyuki source same hai
1:44 did it but a good question 17:54 wasn't able to solve good question kind off new type (to me) 20:29 take rms not peak 23:03 controversial question 26:39 did it but maybe i will forget this if i don't revise 28:17 length is increased by twice not length became twice 35:26 too calculative 39:37 got it wrong 45:39 did it but a good question language wise wasn't able to solve 6 questions out of 22 questions
3:34 parallel h toh divide ker dena yad seh direct multiply nhi 18:09 silly mistake 22:53 controversial q 26:31 depends on lenght not on radiu 28:53 increased by its original length... Not increase to its original length 29:33 silly mistake 35:09 repeat 42:40 repeat 21:00 rms use kero 45:31 repeat again
1✅ 2✅ 3✅ 4❌ new concept( potentiometer) 5✅ 6✅ 7✅ 8✅ 9✅ 10✅ 11✅ 12✅ 13❌ balancing length doesn't depend on area 14❌INCREASED by twice(read question carefully 15✅ 16✅ 17✅ 18❌calculation mistake(reduce equation as much as possible before doing numerical) 19❌ length of new wire will be 2l 20✅ 21✅ 22✅ Thankyou for this session sir❤
For personal revision ques.12 ( just see the relation) ques.13 ( balancing length does not depend on radius if area is uniform) ques.14 (just revise once) ques.18 (put the values at last)
Sir question no. 12 me....Vd=i/neA Ishme agar i = V/R put krnge...uske baad R ki value resistivity×length/area put krnge to .....to Vd= i/neA me ....A cancel out ho jayega...aur drift velocity independent of area ho jayega...👍
Q.2 Revise Q.5 Answer sahi aaya but Still Mujhe Str. Redraw krne meh Dikkat aarahi hai Q.8 aise Ques. Exam ke last Meh Solve krna hota hai Tough Ques. for me Q.9 Repeated Ques. Two sources honge Emf same hogi Series meh Honge Aur ak external Resistance bhi laga Hoga Series Meh So iski Value batao Jisper Potential Difference Zero aaye and that will be ****(r1-- r2)**** Q.13 Good Ques. Here Resistance is Depending on Length Only Not on radius So their will be No Change in Length After doubling the radius😂 Q.14 Literally English Grammar Per Focus krna padega increased by likha hai so it means addition hoga l + 2l hoga😢 Q.16 Repeated Ques. but Uhh also repeat this ques 🔁 Q.18 Ak Tagda Sawal EXAM PRESSURE MEH TOUGH MEH COUNT KR SAKTE HAI DUE TO CALCULATION Q.19 Conceptual Hai Ak bar revise Krna Banta hai
Solved in time bound manner (50 min) Wrong Qn- 1(Absent minded, in E equivalent did not divide by r) Qn10( In case of A.c current I rms is used) Qn 18( stuck in calculation) Qn 19( Did not take effective length as 2L
I think sir in q:12 Drift velocity should be independent of A in case of conductor, because it has electron cloud or charges spread on surface Maybe isiliye nta ne.. nhi rakha ho 25:42
Sir in 1 question me parellel combination me Req bhe to aayega and fir vo potential se earth wale jagha tak current bhe flow karega to effective emf alag hoga plzz reply sir 1:51 ❤
Day 9 Day6,7,8 - completed wpe revision with imp pyqs will do 2022-2024 after revising com, rbd + completed current electricity module + lecture + imp pyq Day 9- Wrong - 9,17,22 Rest done
In this video Mohit Goenka Sir discusses all 22 questions asked on Current Electricity July Attempt JEE main 2022.
😍 Just in Rs 99 get all Physics Concepts, Chapter wise PYQs (2019 to 2022), Tests and How use web version - ua-cam.com/video/G8NPmayT3L8/v-deo.html
👉July Attempt Chapter Wise Solutions Playlist Link - bit.ly/3LeU4zB
👉June Attempt Chapter Wise Solutions Playlist Link - bit.ly/3AHXgjJ
Sir I take your paid course and it is very fantastic and distraction free that you said. THANK YOU SO MUCH FOR THIS EFFORT!! 😊
😊
It's 4:22 am and I'm done for the day (or night). This will be my last late night study session and I'll try to change my sleep cycle, but I'll surely remember these days.....
Kaise change Kiya bhaiya 😢😊
Hmm batayeye
@@DARKRAI-i5j mera bhi change hogya subah subah thand me half shirt aur lower pahenke running krne jata hu ab 6:30 baje se 7 tk maja aaa jata ha pure body me 🔥🔥
@@AyushKumar-eh2bs bro I mean to say that ki late night jaise 4 baje tak kaise padh lete hoo
Mera toh 2:30 avg jata hai
@@DARKRAI-i5jsame bro 2:30-3:00 avg hota h
4:30 baje tk padhunga toh burn out ho jayega
mai video like karna bhool gai thi phir vapas aayi like karne .....because I thought itna toh kar hi sakti hu,like toh banta hai....he deserves it.
3 . 5:53
9. 18:00
14 . 28:58 (remember increases BY twice means 3l not 2l)
18. 35:10(from not revised part)
21. 42:34( theory)
22. 42:20
👍
Q2 3:23 silly mistake
Q9 18:17 do once again
Q10 20:01 once again
Q12 23:35 concept
Q14 29:15
Q15 30:26 current sensitivy
Q17 34:43 do once again
Q18 36:36 formula
Q22 46:02 confusing
#learnlikeneverbefore
2. 3:42 (revise again)
9. 17:55(Va-Vb=E-ir)
15. 29:27(current sensitivity (theta / I)
22. 44:22 ( draw diagram step wise become easier)
very good dear
keep learning and solving
for my revision:
17:56 Great Standard Ques which was asked in my institute test and didn't knew how to solve lol
22:49 Great Conceptual and Controversial Ques but the explanation here is(sir ne nhi bataya) that if we write I = V/R then write R=rhoL/A then Area cut ho jaata hai, which only leaves us with L in denominator.
26:40 Great Conceptual Ques
28:14 Great ques and confusing coz BLUNDER KRDIYA BHAI MAINE
35:05 Easy ques but follow the calculation the way sir showed
39:26 Good ques
42:25 Fact Based Ques(remember this)
44:14 Great ques
well done for completing it
keep learning and solving
Q4 7:19 SM - (diff likha hai)
Q8 13:40 - potentiometer
Q9 17:56 CM - (emf mei pd zero ka mtlb ye ni ki poore circuit mei no current)
Q12 22:50 - drift vel
Q14 28:00 SM - (increase by likha hai bhai)
Q15 29:35 - Concept (galvanomter sensitivtiy)
Q18 35:07 - solve smartly , put values in end
Q21 42:25 - concept
Q22 44:10 - bdhiya ques
well done on completing it
keep learning and solving
25:57 sir,
V = I T by ohms law
V directly proportional to I
.......(Eq 1)
And
I = n A V(d) e
I directly proportional to V(d)
..... (Eqn2)
Therefore by 1 and 2,
V(d) directly proportional to V
potentiometer rev 17:00 and 9:00, meter bridge wala 11:13 ( wheatstone), 40:14 effective conduvtivity is resistance offered are same 43:10 fact based 47:18 patience question
Current Electricity-REVISE💥
42:27[Conceptual]
18:24[Most Repeated]
20:15[AC]
26:20[Remember IMP]
28:23[Increased BY]
47:07[Length doubles then Area halves]
30:43[Current Sensitivity]
31:46[Potentiometer Resistance and RB in Series]
34:36[V const due to parallel so take v^2/R]
39:00[Bulbs]
Thank You Very Much Sir❤
*Timestamps*
CURRENT ELECTRICITY
Q10 19:43 Peak value wala problem Ac pdho
Q14 28:18 language problem Maine length 2x leliya woh 2L + L hogi
Q15 29:30 concept problem
Current sensitivity = Theta / current and NIAB = C theta
Q19 39:27 Easy tha dhyaan rkhna next time R = R1 + R2
Q22 45:20 ye ban gaya tha answer galat tick hogya but acha question tha to ek baar phirse krlena
litteraly telling this man is like someone god has sent in these last days for first attempt ab 1st ka toh pta ni dusra attempt toh fod hi denge sir like litterally hats off to ur revision series as well as pyq solvings uh r damnnnnnn awesome sir thankuu soo much
35:00 rem❗inv ratio
39:07 redo
41:28 cond inv res
42:18 1 st mrk the pot
47:19 ✅
43:03 mang cons -R
30:37 NIAB=ctheta c is torsial const,I SENSITIVITY IS THETA/I
29:10 elongatn q me volm ∆ ni krte A*L=v
29:10 r pe R depend nhi krta
24:00 vd =eE/mTou I =nAvd. E -v/l
19:29 chk🚫
1:36 ye yad rkh,
5:10 re chk
20:17 ac me peak i =i./√2
Heat prod-h =i^2Rt
[2:03] o or vo ke beech me to pura hai
[9:58] re do
[17:57] re do must late concept
[19:05] irms =io/root2
[21:51] do again silly mistake
[25:02] repeat silly mistake learn sare formule khol lena contro
[26:00] repeat
[28:00] drawn out and increased by repeat
[30:00] niab=c theta theta /i currrent sensitivity
[37:00] common khechna
[41:00] repeat new
{43:00] length and area volume constant
2. 3:26 (revise again
9 18:03 (Va-Vb=E-ir)
14. 28:23(increase by - length become 3l)
18. 35:06(put values at last)
19. 44:13( revise again)
very good dear
keep learning and solving
Sir what if in 44:14 , we take both length as L1 and L2 for X and Y respectively, Then when we stretch the wire X to W, the Area and Length both will change but volume will remain constant, So we use LA=V which gives A=V/L and when we put it in Resistance of W we get (L)^2 which is basically (L1)^2 and then we equate it with Resistance of Y and then we write the terms in expression of Resistance of X(R1) and Resistance of Y(R2), where we get the expression 4R1=2R2, so we get R1/R2 = 1/2 which is the answer. Sir is this approach correct?
0:40 silly
18:06 repeating
19:44 AC
28:18 language
30:53
35:08 calc
42:28 correct but gq
PM 7:17 13:45
Q2 - silly mistake
Q9 - 19:30
Q10 - 20:50 (use Irms to calculate heat )
Q12 - asesertion
Q22 - (redo)
Good
For revision
4:40 ( resistance)
17:55 ( same ques in previous session)
20:33 ( peak rms i)
24:09 ( drift velocity)
27:35 ( metre bridge concept clear)
28:22 ( 🫡)
29:59 ( galvanometer)
35:30 ( power rating)
40:00 (conducting)
44:44 ( beautiful question on resistivity)
very good dear
keep learning and solving
for revision
8:30 potentiometer
13:50 potentiometer
24:25 drift velocity
bina=k theta implies theta/i= bna/k = current sensitivity
31:00 potentiometer
33:50 ratings of a bulb
conductivity (sigma) inv proportional to resistivity (rho)
43:00 facts
Revise later:
11:44 Q6 (Remember) R+x
19:46 Q10 RMS concept AC
23:20 Q12 Formulae
26:04 Q13 unable to solve
28:56 Q14 (L+2L) not simply 2L
(note: Need to read question more carefully.)
29:41 Q15 formula
35:31 Q18 Easy calculations
42:42 Q21 Conceptual
very good dear
keep learning and solving
1 2:07 easy but see
3 5:45 easy but weak
9 18:06 nice q
10 20:24 AC ke badh
12 23:27 nice
13 26:30 nice concept
15 29:36 new concept
18 39:20 batman cocept + caclution
19 39:44 batman
20 41:52 improve concept
22 47:12 batman
qno.2 5:10 be careful about multiplying by a constant based on series or parallel connection
qno.22 47:15 do again
well done on completing it
keep learning and solving
1:03, 19:50( use i rms in ac source for heat calc), 35:12( lengthy calc se bacho), 40:26 (eff conductivity ke liye equivalent system draw karo then proceed
very good dear
keep learning and solving
26:00
NTA should be serious about this 😓😓
5 marks can make huge difference in rank
Bhai wo shi h dekh
Drift velocity = I / (neA). me sir current ka dependency check ni kiye .... I=V/R. aur kyuko R=pl/A to area cut jayega aur inverse relation with L hi aayega
yes@@themicahbell
@@themicahbellyes same ques asked in 2023 also
@@themicahbellCorrect Explanation
@@themicahbell woh sab toh thik hai, Lekin i noticed that only original drift velocity formula was used to find ans.(Vd=eEτ/m) Ig we have to ignore I=neAVd ones.
3:27 re🔥
15:59 core❤
20:06 for ac source Irms=i0/root2🤔
22:50 conceptual try once more🥲
27:20 core ❤
28:28 English wali cheezein dhyan se padho! ⚠️
30:01 current sensitivity (theta/i)🕸
32:07 dhyaan do🦔
33:36 re🦭
35:16 practice once🦋
43:56 conceptual guess😂
44:14 ek baar aur🐌
26:24 q13 independent of radius
28:43 increased by 2x not increased to 2x
29:52 magnet q
34:40 q17 silly mistake
38:08 q18
39:32 q19 property write the equations
44:26 q22
20:31 e rms lena h. Also try to solve again
23:09 important based on drift velocity
38:00 calculation mistake
41:27 retry
1:00, 19:09,20:47,23:07,27:38,28:36 mistake,30:18,36:30 kim, 39:32,40:41mistake,43:28kim,44::11imp
19:39
27:13 Independent of area
29:36 Conceptual
37:16
40:32 New variety
42:57 Factual
REVISION QUES. OF JULY 2022 :-
●QUES. NO. 15 [ CURRENT SENSITIVITY]
●QUES. NO. 22 [ 44:00 ]
TYSM ❤❤ FOR UR LOVE & SUPPORT 😊❤🔥..
well done dear
keep solving & learning
#learnlikeneverbefore
1:00 rev
5:00 dont panic and apply basic conc
10:35 meter bridge
19:00 basics pe khelna hai
20:00 DC to AC rev
22:00 units ka khel
24:00
27:00 aata tha but still rev
29:30 current sensitivity
40:00 aise ques mein diagrams bana liya karo agar atko
42:30 theory
44:03 good ques
21:00 rms use kro
27:52 repeat
37:08 revise
41:28 blunder
43:28 goof assertion reasioning
45:31 repeat
well done dear
keep solving, learning and revising
#learnlikeneverbefore
q1 1:51 used eq emf but used v= e-ir instead of just using v = 4 (doubt)
q9 18:50 similar type
q13 27:17 solved but conceptual
q19 41:13 forgot the 2
q22 44:18 good ques
very good dear
keep learning and solving
Thnq sir ❤
Done 🙂
For rev
0:36 gud ques 🔥
18:01 gud ques 🔥🔥
19:40 silly mistake
26:13 gud ques 🔥
28:02 silly mistake
39:26 silly mistake
42:33 gud ques 🔥
44:12 gud ques 🔥🔥
very good dear
keep learning and solving
Bro your comment when translated in hindi😂😂😂
5:31 redooo
12:23
20:24 alternating source or peak source m i rms values
27:55 ❌
29:19
39:16
46:56
19:20 Khela Khatam Supremacy by Mohit Sir
Thanks sir ❤. Sir no error by nta Q12 25:35 , you proved it in 2023 jan vid at 59:09 by substituting 'I'.
#learnlikeneverbefore
Q. 18 # 35:10 revisit
Q. 19 # 39:26 silly
Very good
18:14
20:35 imp becoz of my mistake
44:49
26:19
29:22 silly mistake by many
38:17
39:36 imp
35:07(calculation), 39:30 (new length =2l),44:04
41:21 good 😊
47:10 beautiful question 🎉
0:42, 20:01, 26:10, 28:06 (increased by not increased to!), 29:33, 35:12 (easier calculation), 39:32 (silly error), 42:30
in 12th question 25:00 B will not come becoz it is given area of crossection of conductor but actually it should be only area .......
Sir Looked Kind Of Sleepy But Still He Did The Entire 47 Min Video...
Dedication 🔥🔥🔥🔥
In Q.12, I=neAVd...then V/R=neAVd....now write R as (rho into length)/area.....u have VA/(rho into length)= neAVd.....now Area from both sides get cancelled....so drift velocity is independant of area.....I think this is the solution
👏👏👏
woh sab toh thik hai, Lekin i noticed that only original drift velocity formula was used to find ans.(Vd=eEτ/m) Ig we have to ignore I=neAVd ones.
got 18/22 correct
Thank you Sir for this beautiful session ❤️
19:00
47:11 very good q
22:55
26:11 check
28:10 galat ho gaya
35:41
38:14 very good q
42:30 Factual
44;008
For 2nd revision -
Question - 22 ( good question)
Question - 18 ( good methid for less calculation)
Question -10 silly mistake on peak current
Question - 5 silly mistake thankyou sir #learnlikeneverbefore
30/09/2024
Attempted - 18/19
Correct - 15/18
Can't attend 21th assertion reason question 😢
Thank you sir 😊❤ 47:08
very good dear
keep learning and solving
5:34 26:41 44:48 ( 39:26 solid mai bhi aise) 35:13
20:30
27:30
29:00
41:00
45:30
circuit analysis and potentiometer not strong
25:25 Sir B wala galat hoga cuz when we put I=V/R then put R=rho*l/A , A will get cancelled and we get the expression Vd=V/rho*lne hence we can say Vd is independent of the area of cross section
Same😊
Q01
Q09 *REPEATED*
Q12 *CONTROVERSIAL*
Q13 *CONCEPTUAL*
Q14 *GOOD* *WAY* *SOLVING*
Q15 *STATEMENT* *BASED*
Q17
Q18 *SMART* *CALCULATION*
Q19 *PURE* *CONCEPT*
Q21 *FACT's*
Q22 Long Que. *But* *very* *Conceptual*
26:00 Sir, if we write I as V/R and then open R as Rho.L/A, then Area will be eliminated from drift velocity , so how does it depend on area then?
Exactly current is a dependent quantity
U r ryt
Sir , with the help of eduniti i am in nit Srinagar (ece) now once again going to follow this channel for get into nit Trichy ❤️
Love you sir 💝
is nit srinagar any good? i haven't heard anything good about it
Revise 26:26
35:17
Theory 42:41
44:19
well done dear
keep solving & learning
#learnlikeneverbefore
At 25:35, B Sahi nahi hoga sir. Agar A badlega to resistance kam hoga jiske karan current bhi same amount mei badh jayega to no effect. E ko V/l wala isliye valid hai kyuki source same hai
Yes we can also put I=V/R then put R=rho*l/A in the formula and we will see that A gets cancelled hence we can say Vd is independent of A
4:38 19:25 20:23 24:33 30:09 36:01 37:10
41:10 44:12 44:59 47:14
very good dear
keep learning and solving
1:44 did it but a good question
17:54 wasn't able to solve good question kind off new type (to me)
20:29 take rms not peak
23:03 controversial question
26:39 did it but maybe i will forget this if i don't revise
28:17 length is increased by twice not length became twice
35:26 too calculative
39:37 got it wrong
45:39 did it but a good question language wise
wasn't able to solve 6 questions out of 22 questions
33:18 lagging in this concept must ⌚ 39:19 calculation 🧮
24:42 theory
43:27 theory
Sir in at 25:20 min in ques no. 12 option B is also wrong B'coz there we can write I=V/R and then R=rho(L/A) so in the final expression Vd=V/rho×n×e×L
44:10 amazing question
Completed now 🫡
3:34 parallel h toh divide ker dena yad seh direct multiply nhi
18:09 silly mistake
22:53 controversial q
26:31 depends on lenght not on radiu
28:53 increased by its original length... Not increase to its original length
29:33 silly mistake
35:09 repeat
42:40 repeat
21:00 rms use kero
45:31 repeat again
well done dear
keep solving, learning & revising
#learnlikeneverbefore
Yaay completed the pyqs of current electricity!!
Enjoyed solving these questions with you sir!
forever grateful.
❤
revision Q: 9,16,18,19,22...Thank you so much sir!
1✅
2✅
3✅
4❌ new concept( potentiometer)
5✅
6✅
7✅
8✅
9✅
10✅
11✅
12✅
13❌ balancing length doesn't depend on area
14❌INCREASED by twice(read question carefully
15✅
16✅
17✅
18❌calculation mistake(reduce equation as much as possible before doing numerical)
19❌ length of new wire will be 2l
20✅
21✅
22✅
Thankyou for this session sir❤
QUE 18 ;22 constain and magnenian used for making coils becoz of low temp coficient ..NIAB = thita×c sensitivity
For personal revision
ques.12 ( just see the relation)
ques.13 ( balancing length does not depend on radius if area is uniform)
ques.14 (just revise once)
ques.18 (put the values at last)
very good dear
keep learning and solving
Sir question no. 12 me....Vd=i/neA
Ishme agar i = V/R put krnge...uske baad R ki value resistivity×length/area put krnge to .....to Vd= i/neA me ....A cancel out ho jayega...aur drift velocity independent of area ho jayega...👍
12:00,19:00 ,25:00 27:00,40:00,42:00 redo
28:00 made the same mistake stated by sir
38:00 put data in last
45:00 good qs
well done dear
keep solving and learning
#learnlikeneverbefore
revise 39:32 35:08 40:08
well done on completing it
keep learning and solving
Revise
0:34 22:51 26:17 35:12 39:41
well done dear
#learnlikeneverbefore
Thank you so much sir for this beautiful video 😊
We will make u proud in jee 2023 😊❤️
What happen bro
Q.2 Revise
Q.5 Answer sahi aaya but Still Mujhe Str. Redraw krne meh Dikkat aarahi hai
Q.8 aise Ques. Exam ke last Meh Solve krna hota hai Tough Ques. for me
Q.9 Repeated Ques. Two sources honge Emf same hogi Series meh Honge Aur ak external Resistance bhi laga Hoga Series Meh So iski Value batao Jisper Potential Difference Zero aaye and that will be ****(r1-- r2)****
Q.13 Good Ques. Here Resistance is Depending on Length Only Not on radius So their will be No Change in Length After doubling the radius😂
Q.14 Literally English Grammar Per Focus krna padega increased by likha hai so it means addition hoga l + 2l hoga😢
Q.16 Repeated Ques. but Uhh also repeat this ques 🔁
Q.18 Ak Tagda Sawal EXAM PRESSURE MEH TOUGH MEH COUNT KR SAKTE HAI DUE TO CALCULATION
Q.19 Conceptual Hai Ak bar revise Krna Banta hai
Solved in time bound manner (50 min)
Wrong Qn- 1(Absent minded, in E equivalent did not divide by r)
Qn10( In case of A.c current I rms is used)
Qn 18( stuck in calculation)
Qn 19( Did not take effective length as 2L
28:20 this question had my brain bawling, I was so confused, thank you for the explanation
very good dear
keep learning and solving
I think sir in q:12
Drift velocity should be independent of A in case of conductor, because it has electron cloud or charges spread on surface
Maybe isiliye nta ne.. nhi rakha ho
25:42
15/18 correct
Incorrect ~ 3 ~ 22,14,12
3 out of syllabus
Doing pyqs consistently and trying ❤️✨
very good dear
keep learning and solving
@@mohitgoenka99 thank you sir ❤️
Bhai ques 1 ma v° -0=4 kese ho skta hai bich ma ek resistance bhi toh ayega 1/3 ka?? Pls btado bhai
@@absharahmad6847 U CAN SOLVE THIS QUES BY USING KCL (CURRENT LAW)
0:45 , 3:30 , 10:30 , 17:55 , 19:45 , 22:52 , 26:10 , 28:05 , (29:30) , 33:30 , 35:10 , 39:30 , 42:30 , 44:05
It's 2:46 am and july 2022 current electricity pyqs done ✅
Thank you so much sir for this amazing session ☺️
In question no.12 we have to also considered the change in resistance when cross section area changes so current will also change
To do
37:18
40:25
47:15
well done dear
#learnlikeneverbefore
2:39 alternative
22:58
28:12
42:35
44:08
Q-1, 2, 8, 12, 15, 18, 19
25:00 sir second equation me I ko V/R likhe aur R ko rho(l)/A likhe to A cancel out ho jayega
Q 18 35:11
Q 19 39:25
well done dear
keep solving, learning & revising
#learnlikeneverbefore
In Q 12 :-only option A and D are correct, B is incorrect as Drift velocity is independent of areal change
24:05 but in thermodynamics relaxation time is directly proportional to temperature then it should increase with temperature
Sir in 1 question me parellel combination me Req bhe to aayega and fir vo potential se earth wale jagha tak current bhe flow karega to effective emf alag hoga plzz reply sir 1:51 ❤
39:11 last me calcul kre 39:11
16:30 Q8
42:27,20:15,26:20,30:43
27:56,36:05 ,44:10(uljahu sawal),
very good dear
keep learning and solving
23:00 (Q.12)
well done dear
keep solving, learning and revising
#learnlikeneverbefore
5:53
15:00
18:00
35:01
40:00
Day 9
Day6,7,8 - completed wpe revision with imp pyqs will do 2022-2024 after revising com, rbd
+ completed current electricity module + lecture + imp pyq
Day 9-
Wrong - 9,17,22
Rest done
very good dear
keep solving and learning
2:22 SIR AGAR QUESTION 1 ME YE CAPACITOR PARALLEL KE BAJAY SERIES ME HO TO KONSA FORMULA LAGEGA??
Sir 35:00 que 17 me H=I^ 2 R t bhi hota hai na to uske hisab se 2nd statement right honi chahiye pls explain if possible thanku❤️