Evaluating Inverse Trigonometric Functions
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- Опубліковано 24 лип 2024
- This trigonometry video tutorial provides a basic introduction on evaluating inverse trigonometric functions. It has plenty of examples such as inverse sine, cosine, and tangent functions.
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Full 47 Minute Video:
• Evaluating Inverse Tri...
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You should note that tan^-1 does not include the pi/2 or -pi/2 for the range, since you would technically be dividing by a zero which is undefined. Therefore, your range for inverse tan is (pi/2, -pi/2), not [pi/2, -pi2].
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*Domain of inverse trig functions*
arcsin [-1, 1]
arccos [-1, 1]
arctan (-∞, ∞)
arccsc (-∞, -1] and [1, ∞)
arcsec (-∞, -1] and [1, ∞)
arccot (-∞, ∞)
*Range of inverse trig functions*
arcsin [-π/2, π/2]
arccos [0, π]
arctan (-π/2, π/2)
arccsc [-π/2, π/2]
arcsec [0, π]
arccot (0, π)
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I was so confused, and then you answered my frustration within the first 2 minutes of this video (the arcsin range). THANK YOU!!!! Love your videos.
is there a video on evaluating inverse trig functions of csc,sec,cot ?
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They threw inverse trig equations at me in ACT Math and I wasn't ready! Your video helped me a lot thank you
The explanation for range was extremely helpful. I was confused on what was right and what was wrong when there are two answers that look like they could work, but the automated teaching system my college used just said "That's right because it is!" and I was like "but why though?" Thanks for the vid.
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MR. Organic Chemistry tutor, thank you for a well explained and define lecture on the Evaluation of Inverse Trigonometric Functions. These functions pop up in all areas on Mathematics and Engineering.
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Thanks much! This is what I'm looking for-range of inverse trig..
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How do you get 5pi/6 in the first example
why is the range for arcsin -pi/2 to pi/2?
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I just saw a video called "a year's worth of calculus in 1 minute" then as I read the comments, many suggests him trying inverse trigonometry and substitution.
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how do i solve for a function with more than one trig operation in the function. for example, cos(sin^-1(1/2))
Keep order of operations in mind. Evaluate sin^-1(1/2) first...pi/6. Then evaluate cos(pi/6)=sqrt{3}/2.
sin^1(1/2) is pi/6, then you do cos(pi/6), which is root 3/2
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Is there a regular trig functions (not the inverse) video like evaluating sin(-1/2) and answering with the radian value?
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