Visualizing Directional Derivatives and the Gradient

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  • Опубліковано 16 гру 2024

КОМЕНТАРІ • 15

  • @BEEP640
    @BEEP640 Місяць тому

    Thank you so much! This helped me understand directional derivatives a lot more with the visualizing.

    • @DrMcCrady
      @DrMcCrady  Місяць тому

      Glad it was helpful!

  • @MathPhysicsEngineering
    @MathPhysicsEngineering 2 роки тому +1

    How did you do the animation?

    • @DrMcCrady
      @DrMcCrady  2 роки тому +1

      I used Geogebra. It’s crazy how much it can do for free.

  • @chiai6562
    @chiai6562 7 місяців тому +1

    I found this video is really helpful for my studying about calculus 2 in uni. Could you share that geogebra animation, I really want to learn more about animating in geogebra! After all, thank you so much for your work!

    • @DrMcCrady
      @DrMcCrady  7 місяців тому +1

      Glad it was helpful! Sure here’s the Geogebra link.
      www.geogebra.org/m/e7vztr4d

  • @remivarine4
    @remivarine4 6 місяців тому

    If the directional derivative is the scalar product with a turning unitary vector, it's mean that 2 points which have the same gradient on 2 different curve will have necessarly the same directional derivative in each direction at that given point ? Probably because the 2 different curve are the same LOCALLY ? -- altough intuitively I would think it could be different and depend on the law of evolution of it's own curve.

    • @DrMcCrady
      @DrMcCrady  6 місяців тому

      Yes looks like you’re on the right track. If gradient f at (a,b) has the same value as gradient g at (c,d), then locally f and g look the same, and if u is any unit vector, then the directional derivative for f at (a, b) in the direction of u will match the directional derivative for g at (c,d) in the direction of u. This is because the directional derivative is just the scalar product of the gradient with u.

  • @gary1679
    @gary1679 Рік тому

    thanks man

  • @saduzi6498
    @saduzi6498 9 місяців тому

    thank you!!!!!

    • @DrMcCrady
      @DrMcCrady  9 місяців тому

      Glad it was helpful!

  • @Timmy-zl1gu
    @Timmy-zl1gu 4 місяці тому

    😀

  • @gary1679
    @gary1679 Рік тому

    spend 2 hours trying to figure out why gradient is perpendicular to slope

    • @DrMcCrady
      @DrMcCrady  Рік тому

      Not bad, sucks when you’ve got other stuff to do, but putting that time in will pay off. Glad to hear the video was helpful!

    • @remivarine4
      @remivarine4 6 місяців тому

      Is the gradient vector really perpendicular to slope ? He is in the plane X-Y and his magnitude is the slope of the surface curve at the given point ? if we take this magnitude for the component in Z, we have a vector perpendicular, let's say rather normal, to the surface curve ?