6th HLF - Lecture: Sir Michael Francis Atiyah

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  • Опубліковано 2 лис 2024

КОМЕНТАРІ • 473

  • @franzfakka1417
    @franzfakka1417 6 років тому +355

    1:06 Introduction
    2:30 Who is Riemann and what is the Riemann Hypothethis
    4:28 History of the Zeta Function/Euler Product Formula
    7:11 Why is the Hypothethis interesting/difficult
    9:09 History of Prime Numbers, Little drivel about Ramanujan, Hardy's Umbrella Problem
    14:22 Introduction to Quarternions
    17:45 Euler and Complex Numbers
    19:28 Tribute to Von Neumann
    21:52 Generalization of Eulers formula to the Quarternions (Euler-Hamilton Formula)
    24:50 Todd polynomials/function
    27:55 Infinite iteration of exponentials
    30:21 Connection to the Hypothethis
    31:48 Fine Structure Constant (preceeded the claimed proof) and Feynmans Elaboration on it
    35:55 His Proof of the Riemann Hypothethis (Proof by contradiction)
    39:47 "Where do we go from here?"
    42:12 Question Time
    43:10 "Have you really solved the problem?" -> Unless you dont believe proof by contradiction, then yes. Generalizations have not been solved.
    45:05 "When will your proof will be made available?" -> Fine Structure Constant Paper is available, Riemann is basically the slide.
    46:28 "You said people dont believe proofs. How high are the stakes for you?" -> Of course he does care. People will not believe proofs unless they involve new ideas.
    48:28 Vague attempts at bribery to find the answer to Hardy's Umbrella Problem

  • @shreyasingh5992
    @shreyasingh5992 6 років тому +18

    Whether his proof is correct or not, this man is a genius! He's 89 & he remembers his numbers and theorems despite having dementia. His wit is on point. Salute to you Sir for having the courage to attempt the problem nobody less than half your age would have the courage to even comment on. It's not disgrace. This lecture is courage, dream, love, hope and belief personified. Who are we to judge this man? We are all just students of nature (at the very best, we are still not as good as him, far alone being nature's favorite student which he and likes of him are) and we'd be lucky if we were half of his genius, if we could do half of what he did, if nature loved us half of how much it loves him. Kudos Sir, keep rocking and dreaming.
    None of us are ever perfectly correct. Any idea, wrong or right, only helps form a better understanding and that's the reason, the backbone, the thrill that truly curious minds live for. This lecture is an inspiration. Thank you Sir. Amen.

  • @Edekje
    @Edekje 5 років тому +8

    Rest In Peace Michael Atiyah. A friend of mine spoke to him in December two weeks before his death. He had just sent the manuscript of his final proof to several leading mathematicians. My logical side tells me that it can't be right. My heart however keeps hoping!

  • @ccppurcell
    @ccppurcell 6 років тому +181

    Why is the video of him so big, and the slides so small? Should be the other way round!

    • @yourlordandsaviouryeesusbe2998
      @yourlordandsaviouryeesusbe2998 6 років тому +1

      Exactly.

    • @guyfsone3403
      @guyfsone3403 6 років тому +4

      Christopher Purcell they don't want you to see 🤣🤣🤣

    • @LaureateForum
      @LaureateForum  6 років тому +7

      perfect, thanks, the same we suggest.

    • @randomrant3886
      @randomrant3886 6 років тому +3

      The man is in his 90s.
      Here is his paper.
      drive.google.com/file/d/17NBICP6OcUSucrXKNWvzLmrQpfUrEKuY/view

    • @SvobodovaEva
      @SvobodovaEva 6 років тому +1

      @@randomrant3886 the man didn't shoot the video not uploaded it to UA-cam 😂 you're silly

  • @thelastcipher9135
    @thelastcipher9135 6 років тому +32

    he is 89. why can't we let it slide if he's wrong and celebrate if he's correct.

  • @rositaledesmamataromenorca1361
    @rositaledesmamataromenorca1361 6 років тому +21

    I am almost done with my own version of RH proof. Just checking the calculations. If only those damn margins are a little bit wider...

    • @LaureateForum
      @LaureateForum  6 років тому +2

      This video is also available on another stream:
      hitsmediaweb.h-its.org/Mediasite/Play/35600dda1dec419cb4e99f706197a3951d?autoStart=false&popout=true

    • @chandraponnusamy3526
      @chandraponnusamy3526 4 роки тому +1

      Keep it up mate do wonders👏💪

    • @surplusvalue3271
      @surplusvalue3271 3 роки тому

      fermat

  • @ej3281
    @ej3281 6 років тому +141

    What are these, slides for ants?

    • @Jim6593
      @Jim6593 6 років тому +12

      No bacteria

    • @sheenapunky
      @sheenapunky 6 років тому +1

      you need laser vision to appreciate maths???

    • @RedCarnage1
      @RedCarnage1 6 років тому +1

      It would be great if there was a way to download the slides. When lectures are being recorded I could careless about looking at the speaker. The slides should be the larger screen.

    • @gaborandomvlog9112
      @gaborandomvlog9112 6 років тому +2

      if you enter the link below, you can zoom into it

    •  6 років тому +3

      Click to "Swap Media Elements" in the following link:
      hitsmediaweb.h-its.org/Mediasite/Play/35600dda1dec419cb4e99f706197a3951d

  • @prateek2849
    @prateek2849 6 років тому +32

    Why are the slides so big, I want to see his face too!

  • @srw6772
    @srw6772 6 років тому +17

    Yes, he's completely wrong (according to most credible mathematicians) but I admire his tenacity. He's still trying to make an impact. Still trying to ignite minds. This is not someone who should be mocked. It is someone who should be revered. He may not be the mathematician he once was (that's an understatement) but he's still fairly articulate and I'm sure that he is still capable of being a great ambassador for math.
    "It is not the critic who counts; not the man who points out how the strong man stumbles, or where the doer of deeds could have done them better. The credit belongs to the man who is actually in the arena, whose face is marred by dust and sweat and blood; who strives valiantly; who errs, who comes short again and again, because there is no effort without error and shortcoming; but who does actually strive to do the deeds; who knows great enthusiasms, the great devotions; who spends himself in a worthy cause; who at the best knows in the end the triumph of high achievement, and who at the worst, if he fails, at least fails while daring greatly, so that his place shall never be with those cold and timid souls who neither know victory nor defeat."
    - Teddy Roosevelt

    • @theultimatereductionist7592
      @theultimatereductionist7592 6 років тому +3

      Love how hypocrites who use TR's quote NEVER apply it to powerless political groups in every nation on earth, fighting & struggling, killing people if necessary, to make the world be more fair & just in their view.

    • @terrywilder9
      @terrywilder9 6 років тому

      Credible Mathematicians? Who for instance?
      Surely not Lubos Motl!
      Those idiots over there don't even know why the C is adjuncted to ZF!

  • @jorgejimenez4325
    @jorgejimenez4325 6 років тому +115

    The lecture slides are so small in the video they're unreadable. Please put the slides in the description. Thanks.

  • @rule8744
    @rule8744 6 років тому +83

    Please someone put the subtitles in this video, thank you

    • @thomasdam9916
      @thomasdam9916 6 років тому +5

      At first I couldn't understand him at all, but eventually (after ~10 mins) I got somewhat used to his accent. Still, subtitles would be nice

    • @heliocentric1756
      @heliocentric1756 6 років тому

      Play the video at speed 2x

  • @tommyrjensen
    @tommyrjensen 6 років тому +9

    The viewer is supposed to be able to toggle between a close-up view of the speaker or of the slides. You should only have to click on the view that you prefer. It does not seem to work here on youtube.

  • @alfred144
    @alfred144 6 років тому +3

    For all of you looking for a version where you can actually read the slides, you can watch it on the HLF website: www.heidelberg-laureate-forum.org/blog/video/lecture-monday-september-24-2018-sir-michael-francis-atiyah/ and click the symbol in the top right hand corner that says 'Swap Media Elements'.

  • @bachjs2696
    @bachjs2696 6 років тому +26

    another victim of prime number.

  • @rehsetjhrjktr
    @rehsetjhrjktr 6 років тому +20

    The slides are for Ant-Man.

    • @LaureateForum
      @LaureateForum  6 років тому +4

      This video is also available on another stream:
      hitsmediaweb.h-its.org/Mediasite/Play/35600dda1dec419cb4e99f706197a3951d?autoStart=false&popout=true
      If you open the link, in the upper right-hand corner you will see a few icons (see screenshot attached):
      · Select the middle icon ‘Slide by Slide’
      · Then select the last icon - ‘Swap media elements’

  • @BareClause
    @BareClause 5 років тому +1

    Rest in peace, Sir Michael Atiyah. He was the best of the best.

  • @therealAQ
    @therealAQ 6 років тому +6

    *drops a RH proof*
    - Any questions?
    ...
    - Well... how do you feel about that?

  • @markjulian7874
    @markjulian7874 6 років тому +33

    Shall be a step of the history, or just a dementia's coffin.

  • @Duhans700
    @Duhans700 2 роки тому +2

    Rest In Peace Michael Francis Atiyah.

  • @MusicEngineeer
    @MusicEngineeer 6 років тому +41

    i think, he should have spent less time on history and more on explaining what this mysterious todd function is and what the stuff about iterating exponentials is about. when i iterate exponentials, it either diverges to infinity (for x > 1) or converges to 1 (for x < 1)......but maybe this works only with quaternions? ...no idea. i'm just baffled but i surely hope, the proof holds up

    • @yourlordandsaviouryeesusbe2998
      @yourlordandsaviouryeesusbe2998 6 років тому +6

      This is a seminar for laymen, not mathematically trained people.

    • @maxg3372
      @maxg3372 6 років тому +1

      Only if you iterate using the same number. Same thing for addition and multiplication, right?

    • @MusicEngineeer
      @MusicEngineeer 6 років тому

      aahh...yes! of course!

    • @randomrant3886
      @randomrant3886 6 років тому

      Enjoy: drive.google.com/file/d/17NBICP6OcUSucrXKNWvzLmrQpfUrEKuY/view

    • @letstalkaboutmath2121
      @letstalkaboutmath2121 6 років тому

      I think that for iterating exponential he means for example x^(x^(x^(x^(...)))). In this case the function is convergent for x greater than 0 and less than e^(1/e), at least on the real line. Maybe there exist a complex extension of the function

  • @jaidenrichard99
    @jaidenrichard99 6 років тому +3

    I will solve The Riemann Hypothesis.Atiyah, your sprit of mathematics is inherited to me.

    • @primenumbers2383
      @primenumbers2383 6 років тому

      R H isn't true. I can show that by using a general rule for prime numbers.

    • @modhartorki2756
      @modhartorki2756 6 років тому

      @@isaacm.3535. Yes, I can show most of zeros for zeta function are existing but the rest of zeroes not exist on critical line . You can see this fact by using a general rule for prime numbers

    • @holofech9744
      @holofech9744 6 років тому

      You're forgetting that RH talks about NON-TRIVIAL zeros, so reread Isaac Newtons question

    • @modhartorki2756
      @modhartorki2756 6 років тому

      @@holofech9744 I know that. There is existing a relation between the distribution of prime numbers with non trivial zeroes of the Zeta function .I can shwo that.

  • @MoctarAbeidi
    @MoctarAbeidi 6 років тому

    تحية للأستاذ عطية!. تحية من موريتانيا
    Greetings for you from mauritania!
    Atiyah is a legend!.

    • @AmbientMorality
      @AmbientMorality 6 років тому

      this proof isn't correct, unfortunately.

    • @UPAKHOSALA
      @UPAKHOSALA Рік тому

      At Mauritania 🇲🇷 u have university?

  • @josephmathmusic
    @josephmathmusic 5 місяців тому +1

    Reminds me the proof of Goldbach conjecture by Uncle Petros. RIP

  • @mrnarason
    @mrnarason 6 років тому +16

    He appealed to authority wayy too blatantly, it makes his arguements and talk feel like a sham. Yes von Neumann was a genius, but that fact that he was genius doesn't make the proof or some fact of the proof validate itself.

  • @kylokat
    @kylokat 6 років тому +7

    GREAT JOB ON MAKING THE SLIDE SO SMALL

  • @Astro_Rohan
    @Astro_Rohan 6 років тому +1

    *If you can't read the slides. Click on the link in the description to pick which part to see. You tube can't do that yet.*

  • @MichaelTiemann
    @MichaelTiemann 6 років тому +2

    "The first step [solving the Riemann Hypothesis] is a first step on a long road, but yes! The first step is the solution to the problem, period. I can retire now." LOL!

  • @hanshaun1350
    @hanshaun1350 6 років тому +31

    I was expecting the audiences to ask some techinical questions, not these dumb questions LOL

    • @AmbientMorality
      @AmbientMorality 6 років тому +18

      To be honest, the actual content here was far too weak to ask anything technical. I think people were generally nervous too - the expectation is this proof would be quite incorrect.

    • @diatomsaus
      @diatomsaus 6 років тому +2

      A good mathematician asks a lot of questions, no matter how "dumb" one may think they are.

  • @powt0wn
    @powt0wn 6 років тому +48

    what the hell are these “666 sofa” comments about

    • @Svabhava
      @Svabhava 6 років тому +17

      chinese internet popular way of saying: well done, i am amongst the first ones to comment.
      so 666, sofa!

    • @etbadaboum
      @etbadaboum 6 років тому +31

      OK let's go then
      777 couch

    • @abbysmother
      @abbysmother 6 років тому +14

      Hahaha. 6, sounds like a Chinese word that means "smooth sail". Thus 666, the more the better. Sofa means "front seat".

    • @powt0wn
      @powt0wn 6 років тому +1

      thank you!

    • @RW19T
      @RW19T 6 років тому +1

      Ha, chinese internet subculture, meaning some of the first ones to say it seems great

  • @ShawnLeee
    @ShawnLeee 6 років тому +11

    Alright I'm in for a 50 minute rollercoaster ride

  • @lilbuninio451
    @lilbuninio451 6 років тому +40

    I'm hoping that he's right

    • @niteolabs
      @niteolabs 6 років тому +4

      Lil Buninio I am hoping he leaves the million dollar prize for me☺️😅

    • @OtiumAbscondita
      @OtiumAbscondita 6 років тому +3

      he is wrong I read the paper and I found a couple of mistakes...

    • @GawblyOG
      @GawblyOG 6 років тому +48

      @Mathedidasko
      Just imagine how fucking delusional he must be, if a random guy on the internet "found a couple mistake" in the paper.

    • @christianmartinez4858
      @christianmartinez4858 6 років тому +1

      Maybe you're wrong and he's so smart that you cannot understand his ideas:)

    • @gizatsby
      @gizatsby 6 років тому +10

      From what I understand, the errors in the proof are understandable to anyone familiar with complex analysis, and many people are angry with HLF for allowing him to give a whole lecture on this before looking over the preprint. Everyone makes mistakes, but most people are given the courtesy of honest review before being thrown up on a live broadcast. I hope he's right for his sake but that no longer seems likely.

  • @A.i.priest
    @A.i.priest 10 місяців тому

    To solve the equation 3x + 1, we can find the value of x that makes the equation true.
    To solve for x, we need to isolate the variable on one side of the equation.
    Let's start by subtracting 1 from both sides of the equation:
    3x + 1 - 1 = 0
    This simplifies to:
    3x = -1
    Now, to isolate x, we divide both sides of the equation by 3:
    (3x)/3 = (-1)/3
    Simplifying further, we get:
    x = -1/3
    So the solution to the equation 3x + 1 = 0 is x = -1/3.

  • @TerryPilling
    @TerryPilling 6 років тому +11

    I really like Atiyah. I hope there are no issues with the definition of the Todd function. I will definitely be reading his fine structure constant paper. Fun and interesting lecture!

    • @Czeckie
      @Czeckie 6 років тому +3

      have you read it? it's rubbish and crackpoty. He gone senile, there's nothing wrong in that - except for HLF to exploit the poor old man.

    • @TerryPilling
      @TerryPilling 6 років тому +2

      @@Czeckie Ya I just read it yesterday :(

  • @AdityaKumar-ij5ok
    @AdityaKumar-ij5ok 6 років тому +1

    Just one more request, please make the slide available for free online, so that I can see what was he trying to convey when he was in conference, my happiness overflowed when I heard Hamilton, Ramanujan and ofcourse Euler

    • @HarshSharma-wj8mc
      @HarshSharma-wj8mc 6 років тому

      You can read the paper here:drive.google.com/file/d/17NBICP6OcUSucrXKNWvzLmrQpfUrEKuY/view

  • @ulisespachecosanchez5058
    @ulisespachecosanchez5058 6 років тому

    It is excellent but if you can expose the larger slides in the video that the Dr. represents, the data that explains the sequence is hardly visible. if they are so kind, thank you. to see in more detail what the Dr. exposes. Thank you.

    • @LaureateForum
      @LaureateForum  6 років тому

      This video is also available on another stream:
      hitsmediaweb.h-its.org/Mediasite/Play/35600dda1dec419cb4e99f706197a3951d?autoStart=false&popout=true

  • @gl312
    @gl312 6 років тому

    不管怎么样,这老头儿引发了我们普通人对数学的热情,虽然只是吃瓜群众但还是很有意义的

  • @chrisyoung9186
    @chrisyoung9186 6 років тому

    It can be done other way around; enlarge the PPT slide while put the speakers in the small section (we mainly need to hear him), the current format is not informative.

  • @lokoepoco7143
    @lokoepoco7143 3 роки тому +2

    Mas ganhou ou não???
    Se não tem mais o prêmio de 1 milhão, não tem motivo nenhum para começar a estudar matemática.
    Justo agora q tava animado pra isso.

  • @springkiang
    @springkiang 6 років тому +4

    PPT里的内容太小了,看不清啊

  • @enlongchiou
    @enlongchiou 6 років тому

    His infinite iteration function is Euler product of (p-1)/p, which 1st zero of zeta function contain 2nd zero which contain 3rd zero ....to last zero, in physics is ch=2*3.14*gm^2 vacuum energy of Chern-Simons 2 dimensional space on surface of sphere of quantum black hole by gravity,strong, EM force at Planck, proton, atom scale, plus one dimensional time which oscillate between Planck, proton scale produce strong force(2.17*10^-8/(1.67*10^-27))^2=1.69*10^38.

    • @starlight8260
      @starlight8260 6 років тому

      Interesting. But how exactly do you arrive to that conclusion?

    • @enlongchiou
      @enlongchiou 6 років тому

      from realization of sieve of Eratosthenes prove Riemann hypothesis, vacuum energy ch, detail on google search.

  • @jacoboribilik3253
    @jacoboribilik3253 6 років тому +2

    This is how you prove RH in an easy way. We basically add a sixth postulate to Euclid's list which states the following: "Riemann Hypothesis is true".
    Done, I want my million dollars

  • @RSFB17
    @RSFB17 6 років тому +18

    In the proof, it doesn't seem to me that he used any of the Zeta function's properties!! UH OH!!

    • @Rotem_S
      @Rotem_S 6 років тому +2

      He did use zeta(0) = -1/2 != 0
      He presumed all the non real zeros are on the critical strip (I think)
      I think the Todd function thing is only valid for the zeta function or something

    • @C00Cker
      @C00Cker 6 років тому +1

      He used the fact the zeta function is analytic which itself is pretty strong property (infinitely differentiable, easily approximable on small areas)

    • @C00Cker
      @C00Cker 6 років тому

      @TheNumberZero yeah sure, just said that he uses at least some nontrivial properties of the function, but you are right, he didn't speak about a single zeta function specific property...

    • @suesheification
      @suesheification 6 років тому

      @@theocannon8141 well then he did solve it. Like he says riemann is just a happy byproduct of the bigger idea that all analytic functions have real part .5

  • @atsutomaeda5390
    @atsutomaeda5390 6 років тому +1

    The PC he uses is FMV!!
    I’m very surprised with that.

  • @diatomsaus
    @diatomsaus 6 років тому

    Would be really nice if we can download the slides. They are beyond unreadable, I'm not an ant.
    Surely I can recognise Riemann... except it would be hard given the resolution of those tiny nokia-brick-screen sized slides >.>

    • @diatomsaus
      @diatomsaus 6 років тому

      hitsmediaweb.h-its.org/Mediasite/Play/35600dda1dec419cb4e99f706197a3951d?autoStart=false&popout=true
      At this link, the slides can be viewed at 100%. Small box doesn't help, I'm sure there's a way to download them.
      Edit: click on swap media elements on the RHS ribbon, slides can be viewed as full!

  • @EsquineroN
    @EsquineroN 6 років тому +2

    It's very simple! What do you think?

  • @sqqs3023
    @sqqs3023 5 років тому

    May Sir Atiyah rest in peace.

  • @chandraponnusamy3526
    @chandraponnusamy3526 4 роки тому +1

    Where is gauss the teacher of riemann

  • @kevinldonnelly
    @kevinldonnelly 6 років тому +2

    Great Lecture
    I've been interested in the solution to "The Riemann Hypothesis" as a path to greater understanding of stuff like the "Fine Structure Constant" and String Theory.
    Reciprocally Id would expect some discovered greater understanding of the Fine Structure Constant would have implications for RH.
    What you be said about one of my other favorite subjects Quaternions is also interesting, thanks

  • @pseudopathicus2524
    @pseudopathicus2524 6 років тому +15

    With all due respect to his earlier work, but now i know the feeling of having grandpa...
    Utter waste of time by talking about irrelevant things.

  • @davidcao4060
    @davidcao4060 6 років тому

    it is not easy for a man nearly 90 to stand so long to give a lecture for us.

  • @lsbrother
    @lsbrother 5 років тому

    Whether he's right or wrong its surely remarkable that an 89 year old has the ability to even attempt this.

  • @etbadaboum
    @etbadaboum 6 років тому +3

    'The proof is in the pudding'
    I don't get it.

  • @maxalexviolao
    @maxalexviolao 6 років тому

    If his proof is incorrect, at least, it is puting the Riemann Hipoteses in highlights.

  • @postbodzapism
    @postbodzapism 6 років тому

    Does anyone have his powerpoint slides?

  • @FaiThWii
    @FaiThWii 6 років тому +16

    F(2s) = 2F(s) is homogeneous of degree 1, not 2.

    • @Derrota4e6f
      @Derrota4e6f 6 років тому +2

      What?

    • @FaiThWii
      @FaiThWii 6 років тому +6

      I just looked at the paper, I see it was a typo.

    • @jacoboribilik3253
      @jacoboribilik3253 6 років тому

      Then the proof is already wrong

  • @michaelaristidou2605
    @michaelaristidou2605 6 років тому +3

    He didn't know what the RH was?? Kidding me???

  • @luckysharma5438
    @luckysharma5438 6 років тому

    anyone please tell me the name of movie he is talking about...

  • @nadinekhoury7754
    @nadinekhoury7754 6 років тому

    more info regarding the Todd function please?

    • @MegaMetang
      @MegaMetang 6 років тому

      drive.google.com/file/d/1WPsVhtBQmdgQl25_evlGQ1mmTQE0Ww4a/view
      This is the paper referenced where the Todd function was supposedly constructed as stated in his 'proof'.

    • @nadinekhoury7754
      @nadinekhoury7754 6 років тому

      thanks

  • @StarzzLAB
    @StarzzLAB 6 років тому

    Don't you think that ratio of slide screen size should be switch with camera? Jesus...

  • @sakispetropouleas4308
    @sakispetropouleas4308 6 років тому

    Firsly the great greek mathematician Fokas solves the Lindelhof hypothesis and now this!

  • @happyman_smiling
    @happyman_smiling 6 років тому

    Riemann hypothesis is not solved till now because arithmetic and algebraic rules of real numbers donot match with complex numbers complex numbers have different rules and we are using algebra of real numbers.

  • @deadpeng
    @deadpeng 5 років тому

    RIP. Even though you did not succeed the very last time.

  • @geekjokes8458
    @geekjokes8458 5 років тому

    Do we have anh updates on this? Is his proof ok?

  • @V2024-t5s
    @V2024-t5s 6 років тому

    Thanks for sharing~
    But the slides are too small..

  • @ARmy2510
    @ARmy2510 5 років тому

    I can't read the slides. I can't understand is this even worth time. What am I doing here?

  • @sunkhirous
    @sunkhirous 6 років тому

    Roots are S = 0 +- i(2pik- pi)/ lnP^2^n , P is prime

  • @aditya95sriram
    @aditya95sriram 6 років тому

    For those looking for the slides: www.dropbox.com/s/jnwtl0m3e64ca5v/rh-slides.pdf
    (compiled images obtained from the other stream at hitsmediaweb.h-its.org)

  • @adityamukherjee1679
    @adityamukherjee1679 6 років тому +23

    I know you all are excited about this Chinese people, but how about not flooding the comment section with '666 sofa.' BTW, what do you all think about this proof?

    • @fahtfakcarl7695
      @fahtfakcarl7695 6 років тому +4

      hello world
      In China when you get to places early, you get to sit on a sofa... 666 means "fucking yay!"

    • @mbkn5h
      @mbkn5h 6 років тому +1

      I'm a Chinese but maybe not an average one. I don't really understand the proof... I'm not even sure if I fully understand RH... More explanation is needed.
      Apart from that. I think this is big. Whoever has the courage to do the work and stand out to claim it worths respect. If his proof is correct then even more respect.
      With that said, I don't think this proof will have a big impact in our daily life. I guess most of the people are already taking RH as granted, right?
      I heard some people say this proof may lead to the destruction of RSA-based encryption, which I guess is BS.

    • @vanity_.
      @vanity_. 6 років тому

      So a big bunch of chinese were blended here like us? wow

    • @mbkn5h
      @mbkn5h 6 років тому

      @Tudor Șarpe That's great info. Thanks so much. I became very interested in encryption recently.

    • @mbkn5h
      @mbkn5h 6 років тому

      @源无 Like who? I see u have an ID of 2 Chinese chars.

  • @AlbertvonBolsdädt
    @AlbertvonBolsdädt 6 років тому

    I think, his рroof of Riemann conjecture is apparently wrong. But I hope, that instead - my opinion is wrong )

  • @ArunJayapal
    @ArunJayapal 6 років тому +2

    what is the euler hamilton formula?

    • @randomrant3886
      @randomrant3886 6 років тому

      www.google.com/amp/s/www.geeksforgeeks.org/mathematics-euler-hamiltonian-paths/amp/

    • @ArunJayapal
      @ArunJayapal 6 років тому

      Not sure if this is the correct reference. I think those are related to graph theory rather than quaternions...

    • @bhavishya3553
      @bhavishya3553 6 років тому

      Arun Jayapal yep, that link is wrong, this is closer math.stackexchange.com/questions/41574/can-eulers-identity-be-extended-to-quaternions

  • @mbkn5h
    @mbkn5h 6 років тому +6

    Why are u guys all complaining about Chinese people, when there are even more Korean comments?

  • @alexanderealley9992
    @alexanderealley9992 3 роки тому

    The answer to the Riemann Hypothesis is Infinity.
    Infinity times infinity equals infinity to the power of infinity.
    Infinity squared equals infinity to the power of infinity.
    If 2 is a prime then so is infinity.
    You are all welcome.

    • @arthurb.d.s2841
      @arthurb.d.s2841 2 роки тому +1

      ?

    • @alexanderealley9992
      @alexanderealley9992 2 роки тому

      @@arthurb.d.s2841 All numbers are comprised of Primes but not all numbers are comprised of non-Primes. Primes make up the building blocks of infinity. They are telling the other numbers what to do. People are looking at numbers and infinity incorrectly. Infinity is Prime so case closed on the Hypothesis.
      all the non-zeros have the same point of origin as does infinity so all of them are going to be in the same place just on an endless line. You are never going to find one that doesn’t share this behavior with every other prime.

  • @LaureateForum
    @LaureateForum  6 років тому

    This video is also available on another stream:
    hitsmediaweb.h-its.org/Mediasite/Play/35600dda1dec419cb4e99f706197a3951d
    On this side you can choose between the slides and the video (buttons on the right side)

  • @bipulkumarjaiswal4699
    @bipulkumarjaiswal4699 5 років тому +2

    I solved riemann hypithesis

    • @diegohp93
      @diegohp93 3 роки тому

      Bruh you can't even spell it properly cm'on...

  • @NO-yx6yl
    @NO-yx6yl 5 років тому

    thank god that's the easy solution. money is still on the table.

  • @ronaldalbertozunigarojas4926
    @ronaldalbertozunigarojas4926 6 років тому

    Is there any chance to get Sir Michael F. Atiyah's Presentation?

    • @nahidhkurdi6740
      @nahidhkurdi6740 6 років тому

      A youtube link to the slides
      ua-cam.com/video/oe4Jo4i3w_w/v-deo.html

  • @cheneyphindx3894
    @cheneyphindx3894 6 років тому +1

    官方网站链接,看的比较清楚www.heidelberg-laureate-forum.org/blog/video/lecture-monday-september-24-2018-sir-michael-francis-atiyah

  • @BakingScienceTraveller
    @BakingScienceTraveller 6 років тому

    So exciting!

  • @yutonggao3323
    @yutonggao3323 6 років тому

    his accent reminds me of my computer architecture class instructor

  • @MrMatirafi
    @MrMatirafi 6 років тому +17

    "simple proof"

    • @xxxpirlo
      @xxxpirlo 6 років тому +5

      actually it's really simple, taking into account that this is one of the most difficult problems that exists

    • @AmbientMorality
      @AmbientMorality 6 років тому +6

      Too simple. As in it doesn't work, unfortunately.

    • @xxxpirlo
      @xxxpirlo 6 років тому +2

      I'm a mathematician but I work on dynamical systems so don't know a lot about this, however I don't find any evident problem with the reasoning, so please can you elaborate a little bit more about why you think is a flawed proof?

    • @1998bigkiller
      @1998bigkiller 6 років тому

      xxxpirlo check the details about the Todd function. There are things to clarify there. I do not think the proof works.

    • @xxxpirlo
      @xxxpirlo 6 років тому

      Where can I check them please ?

  • @galas062
    @galas062 4 роки тому

    do we really need the side bar on the video...?

    • @LaureateForum
      @LaureateForum  4 роки тому

      The lecture videos are uploaded from our Newsroom and there the viewer can alternate screens between the speaker and presentation.
      www.newsroom.hlf-foundation.org/newsroom/lectures/video/lecture-the-riemann-hypothesis.html
      We opt for the main screen to be the presentation but the videos cannot be uploaded without a sidebar.

  • @enlongchiou
    @enlongchiou 6 років тому +2

    -e^(3.1415926..*i)=1 is sum of zero of zeta function 1-ll(p-1)/p=1 when it get infinite large,it's vector's sum plus it's imagine function is 2*3.1415926... which appear in fine structure constant 1/137.036=e^2/(4*3.14*(8.85*10^-12)*c*(h/(2*3.14))), if zero of zeta function are not all on line x=1/2 then not equal to 1, result is that it do not have 2*3.14, deduce fine structure constant will not be same as we saw today, this is his connection.

  • @Vincent-Andrew
    @Vincent-Andrew 6 років тому +4

    有幸见证这个时刻!

    • @vanity_.
      @vanity_. 6 років тому

      没错

    • @beau-payage
      @beau-payage 6 років тому

      Andrew Macvoy Vincent 他的证明很可能是错的,只是大家不忍心指出他的错误

    • @vanity_.
      @vanity_. 6 років тому

      Yu Li 不见得是错的,只是他的todd函数还未被证实而已,它的定义还比较模糊。若有朝一日todd被其它数学家们认可了,那么他就证明成功了。

    • @ziyingxu6111
      @ziyingxu6111 6 років тому

      前排围观

    • @beau-payage
      @beau-payage 6 років тому

      源无 我个人对此不乐观

  • @superman15212
    @superman15212 6 років тому

    The slides need to be at least 2 times the size

    • @LaureateForum
      @LaureateForum  6 років тому

      This video is also available on another stream:
      hitsmediaweb.h-its.org/Mediasite/Play/35600dda1dec419cb4e99f706197a3951dplayFrom=13826&autoStart=false&popout=true
      If you open the link, in the upper right-hand corner you will see a few icons:
      · Select the middle icon ‘Slide by Slide’
      · Then select the last icon - ‘Swap media elements’

  • @zirkjalheim
    @zirkjalheim 6 років тому +1

    Todd ALL the things!

  • @sabrebar.2669
    @sabrebar.2669 6 років тому +12

    Where can we find the paper ?

    • @mounirbensalem5692
      @mounirbensalem5692 6 років тому +2

      drive.google.com/file/d/17NBICP6OcUSucrXKNWvzLmrQpfUrEKuY/view

    • @mounirbensalem5692
      @mounirbensalem5692 6 років тому +2

      you can find the paper here

    • @AsSa-yz8tk
      @AsSa-yz8tk 6 років тому

      @@mounirbensalem5692
      اشكرك صديقي
      بس هل تعتقد ان حله صحيح اعتقد ان هنالك حلقه مفقوده

    • @mounirbensalem5692
      @mounirbensalem5692 6 років тому +5

      We should wait for the review of specialized mathematicians, because this is not the first time a math professor claims that he solved the conjecture. The different thing this time is that Prof. Atiyah is a field medal and Abel prize awarded mathematician. So let's wait and see.. I've heard several mathematicians saying that we still don't have the required math to solve this conjecture but who knows what will happen with this attempt ..

    • @AsSa-yz8tk
      @AsSa-yz8tk 6 років тому +1

      @@mounirbensalem5692
      Thank a lot

  • @hugopereira1438
    @hugopereira1438 6 років тому

    I don't understand this method and maybe somebody can help me with this.
    As I understand, the proof is about applying the Todd function to the zeta function. The question is, If you apply the Todd function to the prime zeta function or even any Dirichlet series then you also can prove that any of those functions have no zeros in the right half critical strip. Right?! The problem is that those functions have zeros on that strip.

    • @AmbientMorality
      @AmbientMorality 6 років тому +1

      Hugo Pereira yes, that’s one of the flaws with this proof.

    • @suesheification
      @suesheification 6 років тому

      Damn you smart people

    • @primenumbers2383
      @primenumbers2383 6 років тому

      If you find a new rule for prime numbers than you can see 83% of zeroes for zeta function are true. So RH isn't true.

  • @이찬호-u1h8i
    @이찬호-u1h8i 5 років тому

    You tried Michael Atiyah

  • @ocidity
    @ocidity 3 роки тому +1

    you are the reason my wife left

  • @flashdoom
    @flashdoom 6 років тому

    very elegant

  • @rubenscabral2657
    @rubenscabral2657 3 роки тому

    Hello I'm Brazil Riemann's formula all non-prime automatically you find the primes 3+3+3+3+... to infinity and 7+7+7+... to infinity after the perfect squares odd of 9×9.11× 11.13×13... the three

  • @konradtomkow875
    @konradtomkow875 6 років тому

    The lecture slides.. literally the most important thing in the lecture are way too small..

    • @LaureateForum
      @LaureateForum  6 років тому

      This video is also available on another stream:
      hitsmediaweb.h-its.org/Mediasite/Play/35600dda1dec419cb4e99f706197a3951dplayFrom=13826&autoStart=false&popout=true
      If you open the link, in the upper right-hand corner you will see a few icons:
      · Select the middle icon ‘Slide by Slide’
      · Then select the last icon - ‘Swap media elements’

  • @scin3759
    @scin3759 6 років тому

    Honestly, even if many of us are very fond of Michael, it would be much more productive to be seeing the slides rather than Michael delivering the lecture.

    • @LaureateForum
      @LaureateForum  6 років тому

      This video is also available on another stream:
      hitsmediaweb.h-its.org/Mediasite/Play/35600dda1dec419cb4e99f706197a3951dplayFrom=13826&autoStart=false&popout=true
      If you open the link, in the upper right-hand corner you will see a few icons:
      · Select the middle icon ‘Slide by Slide’
      · Then select the last icon - ‘Swap media elements’

  • @primenumbers2383
    @primenumbers2383 6 років тому

    R. H isn't true. I can show that by find a general rule for prime number. This rule shows most of the zeros on the critical line are close from the zeros of a new rule and the rest of the zeros for zeta function aren't existed at a new rule. Furthermore, l can find the factorization for any integer number by using the new rule

    • @TimHaloun
      @TimHaloun 6 років тому

      OK show us

    • @modhartorki2756
      @modhartorki2756 6 років тому

      l have practical method to find prime factors for any integer number. So l can't publish the new rule . But lm ready to show a calculation example to find prime factors for any numbers is consist of 15 digits by using Excel. Also l can spacify any number is prime or not. See this video
      ua-cam.com/video/toc-9cTM_pQ/v-deo.html

    • @AmbientMorality
      @AmbientMorality 6 років тому

      modhar: There is a sub-exponential algorithm for integer factorization, General Number Field Sieve. There is a polynomial-time algorithm for deterministic primality testing as well (AKS Primality test). Therefore, primality testing is not NP-hard, and integer factorization may or may not be. Regardless, your Excel algorithm almost certainly runs in exponential time or a relatively fast-growing sub-exponential time. It's definitely not faster than GNFS and very likely significantly slower than QFS or ECM.
      15 digits is tiny. You should be able to factor 60-70 digit numbers in a few seconds with modern efficient techniques.

    • @primenumbers2383
      @primenumbers2383 6 років тому

      I used the Excel on the classical computer. But we can track prime factors for lage numbers on quick computer by using a new rule. In computer science, it is not known exactly which complexity classes of integer factorization because
      there is no proof to show that this problem into Np-complete. But we can show that this problem into Np-
      complete by the new rule to make a reduction for integer numbers and use the decision answer to identify
      the 97% of the composite number at straightforward and the rest of this Percentage needs polynomial time. And we can easily track the prime factors for this composite
      number. This method also leads to show that P=NP.

  • @노진호-h4f
    @노진호-h4f 6 років тому

    성지순례~

  • @supergsx
    @supergsx 6 років тому

    You NEED to re-release this and replace the two screens. The slides are so important!!!
    Please?

  • @guren1484
    @guren1484 6 років тому

    "Nobody in the front."

  • @이찬호-u1h8i
    @이찬호-u1h8i 5 років тому

    Sorry atiyah and Wiles

  • @gingdry
    @gingdry 6 років тому

    It seems like RH is not yet proved/ cannot be proved right now, but has anyone tired to prove RH itself is wrong? or it has logical fallacy mathematically?

    • @obinator9065
      @obinator9065 6 років тому

      They try everything, proving it, disproving it, but we only found some complex numbers which come pretty close, ζ(1/2+14.1347i) for example.

    • @夏苏安
      @夏苏安 6 років тому

      Proving wrong is “easy”,just need an example XD.

  • @vanity_.
    @vanity_. 6 років тому +1

    Finally !!