A box contains the following three coins. I. A fair coin with head on one face and tail on the other face. II. A coin with heads on both the faces. III. A coin with tails on both the faces. A coin is picked randomly from the box and tossed. Out of the two remaining coins in the box, one coin is then picked randomly and tossed. If the first toss results in a head, the probability of getting a head in the second toss is Plz help solve this question using Bayes Theorem
Thank you ma'am.....u r the best 💕
thanks a lot you are great
Better explained than my $ 8k decision theory course at my university
video 27:45 how to get E(income)=7169 for node 1?
Thank You Ma'am, ...... 🎉🎉
thanks :)
How 6620.2 comes?
I think it is 6749.90
Calculate :
0.48×7169=3441.12
0.52×6361.5=3308.78
E(Income)=3441.12+3308.78=6749.90
A box contains the following three coins.
I. A fair coin with head on one face and tail on the other face.
II. A coin with heads on both the faces.
III. A coin with tails on both the faces.
A coin is picked randomly from the box and tossed. Out of the two remaining coins in the box, one coin is then picked randomly and tossed. If the first toss results in a head, the probability of getting a head in the second toss is
Plz help solve this question using Bayes Theorem
But Somewhere The maths of values is not right. The one after determining the probabilities, ..... !!!