So decision trees can be used only when there are only 2 possible outcomes because otherwise finding the complementary probabilities would not be possible
A box contains the following three coins. I. A fair coin with head on one face and tail on the other face. II. A coin with heads on both the faces. III. A coin with tails on both the faces. A coin is picked randomly from the box and tossed. Out of the two remaining coins in the box, one coin is then picked randomly and tossed. If the first toss results in a head, the probability of getting a head in the second toss is Plz help solve this question using Bayes Theorem
Thank you ma'am.....u r the best 💕
Better explained than my $ 8k decision theory course at my university
Thank you, prof!
video 27:45 how to get E(income)=7169 for node 1?
Thank You Ma'am, ...... 🎉🎉
P(fw) and P(fC) in tha tree has been wrongly mentioned, it should in otherway
So decision trees can be used only when there are only 2 possible outcomes because otherwise finding the complementary probabilities would not be possible
thanks a lot you are great
A box contains the following three coins.
I. A fair coin with head on one face and tail on the other face.
II. A coin with heads on both the faces.
III. A coin with tails on both the faces.
A coin is picked randomly from the box and tossed. Out of the two remaining coins in the box, one coin is then picked randomly and tossed. If the first toss results in a head, the probability of getting a head in the second toss is
Plz help solve this question using Bayes Theorem
How 6620.2 comes?
I think it is 6749.90
Calculate :
0.48×7169=3441.12
0.52×6361.5=3308.78
E(Income)=3441.12+3308.78=6749.90
thanks :)
Ur supposed to prune the lines that aren’t the best decision
But Somewhere The maths of values is not right. The one after determining the probabilities, ..... !!!