[@lucaszapata]

easy, quick, and well explained. This is the way most of the tutorials should be. Thanks a lot

[@wbreslyn]

Glad it helped!
- Dr. B

[@aviedits_in]

Bro why (OH) is in bracket...plzz explain 🙏 I didn't get this...

[@BotBananaYT]

@@aviedits_in OH is a radical called hydroxide with 1 valency. A radical is an ion consisting of a group of ions with a single charge. Eg: sodium hydroxide NaOH or Ca(OH)2(OH is in bracket because calcium has 2 valency and when you do criss cross valency method, OH will get 2 valency. OH in sodium has only 1 valency hence, no bracket is needed because sodium and hydroxide have 1 valency and doing criss cross method will cancel the 1's) . You can think radicals as elements when writing chemical equation. But, note that they aren't elements. Sorry for late reply.

[@BotBananaYT]

@@deathshot9234 both radical and polyatomic ions are appropriate terms.

[@AminaMahamud-y8o]

U didn't balance a equation u balanced my life

[@christanaatral3252]

My teacher sovle this in different way,but this way is easy to me. Thanks for this method sir

[@bhabishyarajmainali5709]

You are a Lifesaver with these quick and short videos

[@gainthui2332]

I learned how to balance a chemical equation from watching all ur helpful videos.. Thank u so much sir.. btw stay safe❤️

[@wbreslyn]

Glad to hear that!

[@Zaddy459]

You have not a shirt 😂 bro 😅

[@tranglethuy1194]

thank you very much Dr. B now I thoroughly understood this chemical equation!

[@wbreslyn]

Glad it was helpful!
--- Dr. B

[@AIZEN_7773]

Thank u sir👍
Love from India
💤

[@wbreslyn]

You're welcome!

[@chilam8955]

When calcium carbonate mix with water in a clear glass and let it rest for few hours, I see clear liquid on top and cloudy liquid at bottom of glass. Someone had told me that clear liquid a form of Ca(OH)2 which is lime water, is it correct? If it's correct, that means the above reaction in this video is reversible reaction, isn't it? Thanks.

[@poorvanchalarmystore]

thankyou so much sir , your all videos are very helpful for us ..btw a lot of love from india..❤

[@wbreslyn]

Thanks for the kind words!

[@sparkleangels6714]

This explanation helps me lot .Now I can balance the equations thanks

[@shashisvine2902]

It's really helpful for me as this too easy to learn by this teacher

[@wbreslyn]

This teacher thanks you!

[@RP-rb1fb]

Dr B, Your'e a legend!
Thanks!!

[@wbreslyn]

You're welcome!

[@hisyamzakaria5879]

Remove the thumbnails at the end of the video.

[@flavyadavid1178]

Thanks u for ur teaching today is my science exam ❤❤❤❤

[@wbreslyn]

All the best on your exam!

[@flavyadavid1178]

@@wbreslyn thanks sir🙇🙇

[@Avinashsingh-lz3ey]

@@flavyadavid1178 what is difference between carbon and carbonate

[@garvarora9833]

Thank you very much sir for this wonderful video. Thanks thanks thanks...

[@wbreslyn]

You are most welcome! --- Dr. B

[@gyanbano736]

Sir, if this is already balence, why we need to do that again?

[@wbreslyn]

We don't. for this reaction people have trouble because they count up the oxygen atoms incorrectly. So this video is mostly to help them see where they went wrong.
--- Dr.B

[@gyanbano736]

@@wbreslyn thank you for the explanation

[@pragatiblink4789]

@@wbreslyn thanks for explaining

[@muthuramalingamramalingam2698]

Thank you so much, your all video is very useful...

[@wbreslyn]

You are most welcome!

[@dodonick8326]

Thanks so much I have a problem an am really good with that now 🙏💯

[@wbreslyn]

No problem 👍

[@chin_z1]

Thank you when i really needed this.

[@maansipandey1434]

👍👍👍👍very easiest way to balance the equation 💗

[@Maniacs1771]

Nice video..very helpful.pls upload more videos

[@wbreslyn]

Thank you, I will!

[@punamkumari6540]

Thanqq it's very helpful for me🙏

[@wbreslyn]

Welcome 😊

[@amitrajyaguru319]

Haydred lime ko jyada naram kese karate hai? Edibale use liye

[@afreenmaqsood2721]

Thank god I found your channel.

[@JD-59]

Is this a reversible reaction?

[@wbreslyn]

I don't think it would be easy to reverse...

[@lordram123]

Brilliant explanation

[@nacimah8357]

what is the ionic equation for this reaction?

[@shaleengaming6329]

Your videos are satisfying

[@wbreslyn]

Glad you like them!

[@FarooqTak]

Is this endothermic or exothermic

[@vinaykrishnakumar8666]

Is it a reversible change sir? Please help sir.

[@wbreslyn]

I don't think it would be easily reversed. But this article might explain a bit further:
arxiv.org/ftp/arxiv/papers/0801/0801.0460.pdf
- Dr. B

[@alexandery8508]

What about the middle reaction ( CaO+H2O ).
How can i consider away that if it is given?
Is not that a "huge" problem?

[@daskirtika05]

Really sir thank you so much for this necessary vedio 🙏

[@rehanabinu5283]

Thank you sir. I see Bangladesh

[@ergunkoc2207]

After trying to balance
C4H10 + Ca(OH)2 -> H2O + CaCO3
I gave up because I couldn’t find a solution / I couldn’t balance it... :/ Could someone help me on that?
Thanks.

[@wbreslyn]

I'm not sure that reaction actually happens in the real world. I'd probably look at an online balancer since it looks like a pain to balance...
en.intl.chemicalaid.com/tools/equationbalancer.php?equation=C4H10+%2B+O2+%2B+Ca%28OH%292+%3D+CaCO3+%2B+H2O
--- Dr. B

[@christinakumar6417]

Their's no 'C' on the product side as per the law of conservation of mass it's mass will neither be destroyed nor be created

[@superfast1986]

@@christinakumar6417 there is a c in co3 right side

[@christinakumar6417]

@@superfast1986 ohk I'm really sorry 😅😔 I misunderstood that , my mistake. sorry 😔
Nd thank u

[@superfast1986]

@@christinakumar6417 no problem😃😃

[@sruthisurendra6674]

My chemistry exam is tomorrow and I still don't think I can answer all these equations. Any last minuter's tips pls

[@wbreslyn]

Give these a try! --- Dr. B
• How to Balance Chemical Equations: ua-cam.com/video/zmdxMlb88Fs/v-deo.html
• Practice Balancing: ua-cam.com/video/Qci7hiBy7EQ/v-deo.html

[@elliehague5278]

thank you, these videos are super helpful

[@wbreslyn]

You're very welcome!

[@rajnishbelbase3539]

but what is exact answer to be written in balance equation without table plz reply

[@ramesharamesha8490]

This video helped me so much

[@amuthakamalesh7641]

Sir In the product side carbon has 3 atoms and in reaction side , carbon has 1 atom, then your equation is wrong .

[@wbreslyn]

I only see one C atom on each side. If you mean CaCO3, it has one Ca, one C, and three O atoms. Take a look at this video:
Coefficients & Subscripts: ua-cam.com/video/wGNgY2XoYPs/v-deo.html

[@milobedford5423]

How would you write this out then? please respond asap

[@wbreslyn]

You mean as a word equation?
Ca(OH)2 is Calcium hydroxide.
CaCO3 is calcium carbonate.
It pays to know you polyatomic ions!
ua-cam.com/video/vepxhM_bZqk/v-deo.html
--- Dr. B

[@bencymonachan5672]

How did oh get 2 subscripts??

[@shlokgameryt8572]

Thank you sir 😊😊

[@wbreslyn]

You are most welcome!

[@sheetalpandey7303]

Thank you :)

[@kavitadwivedi2601]

Bro you are awesome 👌👊👊👊👊

[@himanshujakhal2224]

Thanks

[@gamerzytsupportme7415]

Nyc explanation

[@codexspeedstar7841]

thank u

[@tazeeenashmi7710]

thank you sir

[@rehanabinu5283]

I like your vedio

[@JitendraDhakrey-hv5vs]

Where do you live in country

[@JitendraDhakrey-hv5vs]

Which country do you live in

[@moramidas3059]

Thanks to help 😊😊😊😊😊

[@wbreslyn]

Welcome 😊

[@pragatiblink4789]

THANKYOU SO MUCH 😊👍

[@r.d.gamers8525]

Thank you

[@Zunaira4868]

Thanks bro

[@kajalpreetkaur82]

thq this is very helpful 😊😀😁

[@wbreslyn]

Most welcome 😊

[@kajalpreetkaur82]

@@wbreslyn 😊😊😊u are great

[@subodhraj8145]

Thanks sir

[@adnpro717]

Thank you so much 😊

[@wbreslyn]

No problem! --- Dr. B

[@adnpro717]

@@wbreslyn sir do you have instagram account?

[@danieladan1734]

You are the Best.. thenkyou for... 💋😉!

[@wbreslyn]

You're welcome 😊

[@harminderpal3622]

Thanku u help alot

[@kukutusu497]

Thank you Sir!!!!!

[@wbreslyn]

Most welcome!

[@saniyamaliksaniyamalik1552]

Thank you soo much

[@wbreslyn]

Welcome 😊

[@paominlienhaokip9884]

Ty again

[@simmidevi1773]

Thanks❤🙏

[@sleekke280]

Wait if Ca(OH)2+co2-------> CaCo3+H2O
But
CaO+co2----->CaCo3+H2O

[@comrademonke5934]

thx man

[@wbreslyn]

Yw!

[@abhijeet7456]

I didn't understand because the left hand side its co2 and in right its co3

[@smitasinghai8521]

Thanks buddy

[@marikasarton262]

which ones are solids, gases, aqueous etc???

[@wbreslyn]

Let's see. Ca(OH)2 would be a aqueous in this equation for the CO2 to react. The CO2 is a gas. CaCO3 isn't very soluble so most of it would be a solid (see Solubility Rules: ua-cam.com/video/zffVKN6tm7k/v-deo.html ) and H2O is a liquid. --- Dr.B

[@jdjdjndndnd9409]

we can't write all this stuff in exam...can u tell another way

[@wbreslyn]

I find that after practice you don't need to write as much and can sometimes do them by just writing coefficients. But to be sure you've got the equation balanced correctly you do need to accurately count. Maybe just do a small table and only write the elements on the left side? I'm not aware of a more condensed way that that. --- Dr. B

[@psyadavpsyadav3397]

Please name the reactions also

[@auroraantheia8537]

Thank god bruh why does the answer key here says 2Ca(OH)2 + 2CO2 → 2CaCO3 + 2H2O? Ok nvm it's the same thing but multiplying 2 was unnecessary why'd they do that lol

[@a.t.l.a.s8501]

Great

[@wbreslyn]

Thanks!

[@abhi_shek4yt]

Bro it's already balanced. Then what

[@codexspeedstar7841]

wow

[@masoomkhan390]

good reaction

[@wbreslyn]

Indeed! --- Dr. B

[@exolblinkmy8152]

Thank you very much

[@namastenepal1456]

Thankksssssssss

[@wbreslyn]

You are welcome!

[@superfast1986]

I made that silly mistake 😂 not counting o

[@wbreslyn]

It's only silly if you make it more than once (maybe twice)! Otherwise it's just learning.
- Dr B

[@superfast1986]

@@wbreslyn Sir is there any way on which I can ask my doubt to you except comment

[@akshayparihar2115]

Sir please increase your voice in the video

[@khoibui8587]

khác gì cân bằng đâu sao phải lm khó v

[@Binodbhusal973]

😊

[@wbreslyn]

Thanks!

[@neetaspirant258]

😇🤗

[@wbreslyn]

😎

[@chaitalipistolwala8633]

Can u explain why

[@wbreslyn]

Probably not very quickly. But this article looks promising:
pubmed.ncbi.nlm.nih.gov/23734593/

[@woodyd6745]

помогите

[@khoibui8587]

tôi đéo h

[@ramesharamesha8490]

This video helped me so much

[@kumarkl5529]

Thanks

[@arshadraza287]

thanks❤

[@wbreslyn]

You're welcome 😊

[@jyotiray9610]

Thanks

[@mastertailor6326]

Thankyou

[@wbreslyn]

You’re welcome 😊

[@BhupinderSingh-nz9op]

Thanks

[@wbreslyn]

Welcome!

[@ffworldfreefire7588]

Thanks

[@wbreslyn]

You're welcome!