You are A Scholar, one of the Greatest Instructors of Applied Mathematical Engineering Physics in the WORLD. The Ivy league Engineering, Physics Instructors, Professors use 'obfuscation/confusion' through writing ideal theoretical equations on books and writing cryptic formulas on whiteboards, blackboards. Thank You for all these videos.
I don't know why I haven't said it sooner but THANK YOU! Your videos have helped me immensely so many times in the last 2 years. I don't want to bash any of my teachers but some are not easy for me to follow. You are so incredibly clear and concise. The part that you added at the end (about power consumption) really helped me wrap my head around how zeners work.
Hello sir, all your videos are really helpful. Didn't know how easy physics is until I came across your channel. Everything just gets inside my head when I watch your videos. You are really a great teacher. Your explanation is so clear and I am confidently able to any sum. I just don't know how to show my gratitude so thought of typing this thanks a million. 😀😀😀
Great video. It really helped me to understand the relationships between current, voltage, resistance and the zener diode. It answered some questions of mine about the voltage near the zener diode and about load resistors.
I was taught that the correct term is "potential divider" rather than "voltage divider". However, I think my teacher was really just splitting hairs because everyone calls them "voltage divider" all over the interweb. Good video 👍
Sir, I have a question on 16:02 you said that as the "R(load) Increased it began to draw more current from the ckt, and theres less avalable current to flow from the zener diode." shouldn't it be as the Rl decreased, it will draw more current since it would take the path of least resistance.
You are correct, when you say the load increases you refer to the current not the resistance, so when the load increases it means that it draws more current, so Rl should be less, Rl is refered to as the load resistance.
@ 28:16 this assumes that the breakdown voltage of the zener diode is exactly at 0mA for regulation , which is not true in reality since there has to be some leakage current and minimum current(I min) to "turn on" the zener diode as a regulator. Therefore at 0mA, it's a voltage divider circuit that's regulating 12V, so the actual % efficiency is really the heat dissipated from Rs relative to the heat dissipated from RL(assuming heat from RL is for useful work to external load). P(Rs) = I^2 * Rs P(RL) = I^2 * RL % efficiency = RL/Rs ≈ 75% efficiency
Great video, really informative, but you have a mistake when calculating efficiency. With Rs = 1k and RL = 747 ohms, Rs dissipates 15.92 Watts, while the RL dissipates 12 Watts. While it is true that your Zener diode did not lose any power, your overall efficiency is just 43%, since the load only consumed 43% of the total power into the system.
I'm sorry but you're also wrong. P=VxI PRs=VRs x IRs= 15.92V x 0.01592A= 0.2534W. PRl= VRl x IRl= 12V x 0.01592A= 0.191W. Circuit total consumption is: V x I = 27.92 x 0.01592A = 0.444W from witch 0.2534W is lost at voltage regulation resistor; so circuit efficiency is 43%, yes.
My Major was Electronic Instrumentation some thirty years ago and I learned this among many other things. What I had forgotten since then ....this video brought back to recall. Good job. But what I didn't realize were the currents between RS and RL would be different during its op; somehow that just doesn't seem right. When the Zener falls (drops) out RS & RL current is the same....am I not correct?
at 16:02, you said as RL increased, it began to draw more current from the circuit, but isn't it supposed to draw less current? also at 16:15, you said When we increased RL, Iz decreases so Vz decreases, but aren't Vz and Vout supposed to be same? Because they are the voltage across the same two points? And here, in the observation table, we see that when we decrease RL, then Vout decreases as well, but isn't it supposed to be the opposite? Isn't it supposed to increase?
Great video, however is there one where RL is a variable resistor and explains how current or voltage may cause change throughout the circuit when added or removed
now my head is swimming with impedance matching for maximum power transfer ,Thevenizing transformer impedance reflection ! Oh no! 🤪🤪It's been 40 years since I studied this stuff!
Please , can you do a video for a bidirectional TVS(transient voltage suppression) diode ? Here , the DC supply is 24olts, while the inductive load resistance is 300ohms across the TVS. But the line resistance ranges(50 to 1000ohms). What rated TVS can run along with the inductive load which operates at a minimum voltage of 19volts ?
How can the output voltage stay the same? Wouldn't it just bypass the z diode? Is a diode acting as a traffic stopper? Like the speed limit is 10mph(voltage) for z diode and even if the output voltage was supposed to be the voltage of the battery the electrones cannot pass through the wire with higher speed, because diode 10mph speed slows them down?
Thank you very much, in fact your explanation in this video really helped me. Please can you help me with this question: Without a step down transformer, I rectified 220 AC voltage to 8 DC Voltage using voltage divider and I wanted to use 5 v Zener diode to regulate the 8v, I have tried all connections (I mean circuit) but its not giving me the 5 v, Please why is it so and does it mean I cannot use a Zener diode with such voltage divider? I will be grateful for your response on this
In the real world Volt and ampere of R-load is Fix, and Zd is have impedance (For 12 Volt, Impedace = +/- 5 Ohm), and Zd have tolerance to accept i, as max power allowed ( for this, +/ - 0.25 watt), P = (id²).z., thus id not must be zero ampere. Hence the variable that must be arranged is Vs (batteray), and Rs can random fixed as product suggested. When Vs is also must be fixed than we can use comparing- op amp and bjt (or even mosfed) beside diode Zener.
I am having issues with problems i am facing I am asked to find the value of RS in order to find values of other components in the circuit but i am only given source voltage the Zener Voltage and wattage and the Load resistance how would I find these values of RS
Why does the Zener stop voltage from going from Battery + through Rs directly to the load ? What and How does that work? Wouldn't it be better if it were in series with Rs and the + output? Why is it is parallel ?
a ver good explanation video. For the selection Rl resistor if my input supply is not constant i.e solar panel is connected to the output then the value of my resistor will keep on changing. my max voltage through solar panel is 22.3 V and i am using a 3.3 V zener diode as i require voltage of 3.3 V to the mosfet for my application through phototransistor. can any one help me with this
If the (Rs) resistor's power consumption it taken account the output power percentage would be roughly 16%. it's so inefficient. Also I figured out that the internal resistor of the source is about 290 ohms which again has decreased the output power. (on 26':26")
organic chem i dont understand the graph of x! can you please make a video on the graph of x!???? plz also how exactly does a zener diode work? and will it still work if the input voltage is like 3k but it was designed to limit voltage to 1v?
Pretty good. Last point on design was ass backwards as you would want to design for the lower load resistance which will draw more than a higher one but no big deal. I despise whole number names being used to describe decimal values though. 12.15 is NOT twelve point fifteen. It's twelve point one five. Still. Decent video.
how did i landed here ... obviously not all zener diodes are the same to put it simple (not totally right) they are dependent on the area of the junction and the voltage is a weak function of current usually a logarithmic one with slight adjustments that it what makes a diode a diode
Final Exams and Video Playlists: www.video-tutor.net/
He just takes his time to simplify the concept, even when it's complex. I'm really happy having such a good teacher
One of the best Zener diode videos ive run across in 10 years
You are A Scholar, one of the Greatest Instructors of Applied Mathematical Engineering Physics in the WORLD. The Ivy league Engineering, Physics Instructors, Professors use 'obfuscation/confusion' through writing ideal theoretical equations on books and writing cryptic formulas on whiteboards, blackboards. Thank You for all these videos.
Everytime I search something be it advanced maths - statistics - elec stuff - chem you seem to have it all. i applaud you good sir
I don't know why I haven't said it sooner but THANK YOU! Your videos have helped me immensely so many times in the last 2 years. I don't want to bash any of my teachers but some are not easy for me to follow. You are so incredibly clear and concise. The part that you added at the end (about power consumption) really helped me wrap my head around how zeners work.
How does he learn all those things and explain to us? It’s just amazing
I wanna know how he knows so fucking much lol hes a genius
Bachelor or master in engineering
@@Undertakerfan700 My hard guess is either a masters or phD in electrical engineering? But then idek lol
@@Bravo_L I bet the organic chemistry turor loves science and math. That's why he doesn't get tired studying it haha. Unlike me lmaoo
I want to know the same thing he's a walking calculator
Hello sir, all your videos are really helpful. Didn't know how easy physics is until I came across your channel. Everything just gets inside my head when I watch your videos. You are really a great teacher. Your explanation is so clear and I am confidently able to any sum. I just don't know how to show my gratitude so thought of typing this thanks a million. 😀😀😀
seconded!
Very helpful Sir, thanks.
To be honest, This man is a legend!
Great video. It really helped me to understand the relationships between current, voltage, resistance and the zener diode. It answered some questions of mine about the voltage near the zener diode and about load resistors.
Thank you Sir : Love from Sri Lanka 🇱🇰
at 16:10 he was mean R(L) decrease rather than increase. This way it make sense according with data from the chart
The explanation is perfect and clear. Thank you for the video which solves many problems in my mind.
Best presentation I have seen. Keep it simple works best. Great Job Sir!
I was taught that the correct term is "potential divider" rather than "voltage divider". However, I think my teacher was really just splitting hairs because everyone calls them "voltage divider" all over the interweb. Good video 👍
It's the same thing.
Voltage is just a short for the difference between 2 potential voltages
Outstanding explanation of how zener diods works! Thanks a lot! 👍🏻👍🏻
Thank you so much i love watching and learning from your tutorials, i like the way you clearly explain everything,
The best zener video ever!
Thank you so much for making these videos! Learned a lot!
Sir, I have a question on 16:02 you said that as the "R(load) Increased it began to draw more current from the ckt, and theres less avalable current to flow from the zener diode." shouldn't it be as the Rl decreased, it will draw more current since it would take the path of least resistance.
You are correct, when you say the load increases you refer to the current not the resistance, so when the load increases it means that it draws more current, so Rl should be less, Rl is refered to as the load resistance.
@@vashtalelq thanks for the clarification
Absolutely amazing explanation. Thank you so much for this wonderful video I learned so much!
Thanks. just came across your channel. Some very useful learning resources 👍
@ 28:16 this assumes that the breakdown voltage of the zener diode is exactly at 0mA for regulation , which is not true in reality since there has to be some leakage current and minimum current(I min) to "turn on" the zener diode as a regulator. Therefore at 0mA, it's a voltage divider circuit that's regulating 12V, so the actual % efficiency is really the heat dissipated from Rs relative to the heat dissipated from RL(assuming heat from RL is for useful work to external load).
P(Rs) = I^2 * Rs
P(RL) = I^2 * RL
% efficiency = RL/Rs ≈ 75% efficiency
Nice educational description of a zener diode, I managed to lower 16v to 5 volt for a bluetooth module on my preamplifier, cheers.
Cant give you enough thanks until each one of us subscribe and like all your videos even those which we didnt watch ❤
Amazing you are a pro teacher thanks
Finalement, une explication claire! Merci!
I’m not in college anymore, but if I found his videos in college.. I probably would have cried and laughed spontaneously.
Great video, really informative, but you have a mistake when calculating efficiency. With Rs = 1k and RL = 747 ohms, Rs dissipates 15.92 Watts, while the RL dissipates 12 Watts. While it is true that your Zener diode did not lose any power, your overall efficiency is just 43%, since the load only consumed 43% of the total power into the system.
I'm sorry but you're also wrong. P=VxI PRs=VRs x IRs= 15.92V x 0.01592A= 0.2534W. PRl= VRl x IRl= 12V x 0.01592A= 0.191W. Circuit total consumption is: V x I = 27.92 x 0.01592A = 0.444W from witch 0.2534W is lost at voltage regulation resistor; so circuit efficiency is 43%, yes.
My Major was Electronic Instrumentation some thirty years ago and I learned this among many other things. What I had forgotten since then ....this video brought back to recall. Good job. But what I didn't realize were the currents between RS and RL would be different during its op; somehow that just doesn't seem right. When the Zener falls (drops) out RS & RL current is the same....am I not correct?
Thanks for the diode name!
Clear explanation! Thank you! Subscribed
Thanks for efficient lecture 🙏
Great Video.....👍👍👍
at 16:02, you said as RL increased, it began to draw more current from the circuit, but isn't it supposed to draw less current?
also at 16:15, you said When we increased RL, Iz decreases so Vz decreases, but aren't Vz and Vout supposed to be same? Because they are the voltage across the same two points? And here, in the observation table, we see that when we decrease RL, then Vout decreases as well, but isn't it supposed to be the opposite? Isn't it supposed to increase?
Awsome explanation
Thank you it was really helpful 👍🏻
Check the last comment about using the higher RL value to choose an ideal Rs. If the RL drops, the zener will stop regulating. Otherwise, great video.
Great video, however is there one where RL is a variable resistor and explains how current or voltage may cause change throughout the circuit when added or removed
Priceless video.
Our lord and saviour 🙏 thank youuuuuu💖💖
I hope you will contuine to post helpful videos
thanks for very informing video.
how did you get the Vout of (12..05 or 12.03)v. .
Sir thank you so much for your help ❤ 🙏 😊
now my head is swimming with impedance matching for maximum power transfer ,Thevenizing transformer impedance reflection ! Oh no! 🤪🤪It's been 40 years since I studied this stuff!
Thank you 🍒
Please , can you do a video for a bidirectional TVS(transient voltage suppression) diode ?
Here , the DC supply is 24olts, while the inductive load resistance is 300ohms across the TVS. But the line resistance ranges(50 to 1000ohms). What rated TVS can run along with the inductive load which operates at a minimum voltage of 19volts ?
I love you man. thanks
thank you for sharing
How can the output voltage stay the same? Wouldn't it just bypass the z diode? Is a diode acting as a traffic stopper? Like the speed limit is 10mph(voltage) for z diode and even if the output voltage was supposed to be the voltage of the battery the electrones cannot pass through the wire with higher speed, because diode 10mph speed slows them down?
Hi, need an immediate response, is there any way or is it possible for us to limit or store the energy loss that from this regulator??
How exactly do you calculate Vout? Because im trying to do this with a Vin of 16v
THANK U THANK U AND THANK U AGAIN!!
Thank you very much, in fact your explanation in this video really helped me. Please can you help me with this question: Without a step down transformer, I rectified 220 AC voltage to 8 DC Voltage using voltage divider and I wanted to use 5 v Zener diode to regulate the 8v, I have tried all connections (I mean circuit) but its not giving me the 5 v, Please why is it so and does it mean I cannot use a Zener diode with such voltage divider? I will be grateful for your response on this
In the real world Volt and ampere of R-load is Fix, and Zd is have impedance (For 12 Volt, Impedace = +/- 5 Ohm), and Zd have tolerance to accept i, as max power allowed ( for this, +/ - 0.25 watt), P = (id²).z., thus id not must be zero ampere. Hence the variable that must be arranged is Vs (batteray), and Rs can random fixed as product suggested.
When Vs is also must be fixed than we can use comparing- op amp and bjt (or even mosfed) beside diode Zener.
Thank you so much!!!
30:35 you should go with lower value of RL I think !!!!!???
I am having issues with problems i am facing I am asked to find the value of RS in order to find values of other components in the circuit but i am only given source voltage the Zener Voltage and wattage and the Load resistance how would I find these values of RS
Why does the Zener stop voltage from going from Battery + through Rs directly to the load ? What and How does that work? Wouldn't it be better if it were in series with Rs and the + output? Why is it is parallel ?
at 16.07 you said as Rl increases the current will also increase ?
i think that was an error
what is the maximum input voltage for safe operation of zener diode?
So if Im using a battery of less than 12v I dont require a Zener diode or any diode in the circuit?
Can you leave a link for the Zener you used? Thanks
a ver good explanation video. For the selection Rl resistor if my input supply is not constant i.e solar panel is connected to the output then the value of my resistor will keep on changing. my max voltage through solar panel is 22.3 V and i am using a 3.3 V zener diode as i require voltage of 3.3 V to the mosfet for my application through phototransistor. can any one help me with this
If the (Rs) resistor's power consumption it taken account the output power percentage would be roughly 16%. it's so inefficient. Also I figured out that the internal resistor of the source is about 290 ohms which again has decreased the output power. (on 26':26")
Is diode zener "suck" that voltage. I mean where the remaining voltage go?
achraf into the series resistor
I think the energy is just dissipated as heat i.e wasted. Hence the bit about efficiency at the end.
organic chem i dont understand the graph of x! can you please make a video on the graph of x!???? plz also how exactly does a zener diode work? and will it still work if the input voltage is like 3k but it was designed to limit voltage to 1v?
Amazing
Pretty good. Last point on design was ass backwards as you would want to design for the lower load resistance which will draw more than a higher one but no big deal. I despise whole number names being used to describe decimal values though. 12.15 is NOT twelve point fifteen. It's twelve point one five.
Still. Decent video.
thank you!!!!
Der wiederstand ist zu klein fuer die belastung
Thanks 😘
Thanks
10:40 15:10 17:50 19:10
Small mistake @ 4'40 : for RS = 10K Iz = 0.639mA :-)
12:23
11:30
15:35
how did i landed here ... obviously not all zener diodes are the same to put it simple (not totally right) they are dependent on the area of the junction and the voltage is a weak function of current usually a logarithmic one with slight adjustments that it what makes a diode a diode
how can someone know this much😂😂😂😂😂 he must be related to isaac newton
👍👍👍
Nein Song
Apka electric oqatay is nizam pa fail hain 10 15 sal ma apko sab kuch mil jai ga
Ac or dc