Expand f(x)=x^2 as a Fourier series in (0,2π). | Fourier series | Lec321

[@AbdulRahman-du1rr]

Thank you for the explanation
Your explanation is great

[@dipakmahato781]

Explanation is very good❤ from Nepal.
One simple mistake in (a nut) in formula.

[@noorbanu794]

Mam Bernoullis rule was not correct😊

[@MathsPulseChinnaiahKalpana]

Hi Noorbanu!
If u and v are functions of x, then Bernoulli's rule will be integral udv=uv-u'v1+u"v2.... here u',u",...aresuccessive derivatives of u and v1,v2.. are successive integrals of dv...
You can also use some other formula if there is a possibility. It is not incorrect!
Thank you!

[@Rohith_202]

Thanks you mam for your explanation...

[@DURGAMSAGAR-iw7ts]

Mam ur god mam ur god...😻🙏

[@Prashantwagh-u3g]

Mata Rani you are teaching great🎉

[@MathsPulseChinnaiahKalpana]

😊

[@mcnstein646]

Wonderful breakdown. Thank you very much!

[@aakashsuresh2566]

why have you considered 2pi(^2) as 4pi in first sum and 4pi square in second sum