AC Load Line of BJT Amplifier Circuit
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- Опубліковано 22 лип 2024
- The load line for a BJT amplifier indicates the range of allowable values for collector current and collector-emitter voltage. It is useful for predicting at what point clipping on the output would occur in the circuit.
Outro Song Credit: Enter the Tesla Machine by Tri-Tachyon (CC BY 4.0)
David Williams
www.elen.ca
Thanks David! I learned so much from your videos! Great review material!
Finally someone have more detailed explanation thanks buddy
Excellent video that leads to a great understanding of how transistors do their thing when amplifying AC signals. Another way to bias without all the math is to hook up your oscilloscope and run a sinusoid through the circuit to check for clipping and min/max levels. Also, a spectrum analyzer clearly reveals harmonic distortions.
Very Nice explanation.
Excellent explanation!! I finally understand it!
Thanks man, it was helpful.
nice explanation
it's helpful for me, thank you so much.
Glad to hear that
What is that re in ac model ?😥
god bless you!!!
Hi David, @7:43 Can you please explain it in a bit more detail why you can use the Icq in place of the AC collector current?
I have the same question. Thanks in advance!
Nevermind, it's actually explained in the example video at 5:00. Because ic can swing down from the DC Q point to 0mA (when there is no collector current), the magnitude of ic is equal to the DC current Q value found before. Beyond this, we would have clipping, and therefore distortion of the incoming AC signal. Hope this helps!
@@jasonw.2232legend
Doubling isnt good there can be saturation constraints also which may reduce the Vp-p if the emitter voltage is considerably high
nice
At @2:53 the guy seemed to indicate that the resistor "re" was part of the actual transistor and that the transistor "E" point was on the other side, below said resistor. Is this an error right? (Those who are more familiar with this stuff may glide over such a trivial detail, but I'm hanging on to every detail to trying to follow😅). Thanks
re is part of the model of the transistor while RE is the external resistor that is part of the circuit
finally a video where it isn't someone trying to explain this stuff with a thick indian accent
a little confusing with the way you draw your ac Vce i keep mistaking it for the root symbol. But otherwise...amazing job with the expliantion!
I'm glad you got something from my explanation, but sorry about my v's. I needed a way to distinguish upper case from lower case V's, but I think my hand just can't make a very convincing lower case v.
Why is Vce = ic Rload and not Vce = - Ic Rload?
It's negetive actually see in diagram the slope is negetive
Why is Ic=Vcc/(Rc+Re) not Ic=Vcc/Rc? I thought Re is in another current?
@glyn hodges honestly I don't get it 😂