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make life even easier by using the roots to do the multiplying : 2 * ( x + ( 1 / 2 ) ) * ( x + 5 ) ( x - 5 ) = 2 * [ x^3 + ( 5 - 5 + 1 / 2 ) * x^2 + [ ( 1 / 2 ) * ( 5 - 5 ) + 5 * ( - 5 ) ] * x + ( 1 / 2 ) * 5 * ( - 5 ) ] so this makes 2 * [ x^3 + ( 1 / 2 )x^2 - 25x - 25 / 2 ] = 2x^3 + x^2 - 50x - 25
Thank you....but is that really simpler?
@@MathsWithJay this can be extended to any number of factors.
HIII !!Thank you so much for your explanation!!Can you please help with this : A= 2^0+2^1+2^2+.....+2^49+2^50
See ua-cam.com/video/ErfSfea0Mh0/v-deo.html
that is (2^51) - 1
make life even easier by using the roots to do the multiplying : 2 * ( x + ( 1 / 2 ) ) * ( x + 5 ) ( x - 5 ) = 2 * [ x^3 + ( 5 - 5 + 1 / 2 ) * x^2 + [ ( 1 / 2 ) * ( 5 - 5 ) + 5 * ( - 5 ) ] * x + ( 1 / 2 ) * 5 * ( - 5 ) ]
so this makes 2 * [ x^3 + ( 1 / 2 )x^2 - 25x - 25 / 2 ] = 2x^3 + x^2 - 50x - 25
Thank you....but is that really simpler?
@@MathsWithJay this can be extended to any number of factors.
HIII !!
Thank you so much for your explanation!!
Can you please help with this :
A= 2^0+2^1+2^2+.....+2^49+2^50
See ua-cam.com/video/ErfSfea0Mh0/v-deo.html
that is (2^51) - 1