Patrick, I've followed you for years finding your videos helpful as I attempted to conquer first elemental algebra, then calculus and now probabilities. Please know that your presentations are timeless and of high quality and I image students are still viewing them. Once exposed to "patrickJMT' videos they become associated with easily interpreted versions of highly complex theorems. Be proud of your contribution - and thank you.
Dude, you rock. I find it admirable that you would offer services like this for free. Thanks for helping me with the understanding of this elementary probability concept
I think it's because we are looking for the probability that event A (one blue marble) AND event B (another blue marble) both occur. If the two events were not dependent (say we replace the blue marble), then we would add the two probabilities (look up the Union Rule of Probability)
(continuation from my last question) I don't know if I should treat this is as an independent or dependent event. Can you show how to do this problem? There are 12 doughnut holes in a box. 5 are chocolate, 4 are plain, and 3 are jelly-filled. If three doughnut holes are removed at random, what’s the probability of removing all three that are jelly-filled? These are the answers to choose from: 1/288, 1/220, 1/3, 1/4, 117/220 Thanks!
so I have a question....what do i do when i have three events that are dependent on each other? ie i have S: 10 red marbles and 6 blue marbles so what is the probability that I get 1 red and 2 blue marbles if i select three marbles randomly? I worked out first taking a red , then a blue with the reduced total sample space and finally a second blue with reduced blue and reduced total sample space. but then this could happen in 3 sequences, do i * the results together or + results?
No. Intuitively, independent events are events where knowing about one tells you nothing about the other e.g. if you flip a coin and roll a die, then if I roll the die, and see it's a 6, that tells me nothing about whether the coin will show heads or tails. Mutually exclusive events are events which are impossible to both happen at the same time e.g. for a single flip of a fair coin, the events of getting a heads and tails cannot both happen. You'll either get heads or tails.
Hi Patrick, I was wondering if you could help me with some GRE probability problems that I came across since you are great at the whiteboard explanations. This is one of the problems that was posted.
Dude you rock! Awesome work! I actually understand probability now! Thanks dude! For sure now I will pass my maths test! Keep Up The Good Work! =] =] =] =] =]
i have question teacher :) ok y did u say at the probability of pick red ball it is 9/19 why u didnt say it is 10/19 ?? becoz if he is gonna pick a blue one so the remaings will be 10 red and 9 blue and the total will be 19 so the probability of getting a red one will be 10/19 thx i hope u answer asap :)
I don't understand why it's alright to simplify the first probability statement. If you multiply 19 by 20 you get 380 which would make the answer 9/380. This does not reduce to 9/38 which makes it a completely different answer than if you had not reduced.
on the first draw, you may get a 10 blue marbles out of 20 marbles out there right? and on the second draw, you can get 9 blue out of 19 remaining marbles right? what if on the first draw, I got a red marble. so it will affect the 2nd draw right? my solution on this problem is 10/20*9/19+10/20*10/19=1/2
Yeah, but well, he's working you know, assuming that the first one would be blue. As he said "If we draw the first one and it was blue, what is the probability that we'll get a blue one again in the second time?"
You're amazing! I'm so happy to know that I'm not the only one who's so passionate about fitness that I kinda feel I do nothing other than that in my life xD much live and respect, keep inspiring !
Thanks, was just thinking about that and youtube to the rescue. As always. Though, you got it all mixed up. It's obviously blue/red rings of some sort! Hehe.
If you do not draw a blue marble on the 1st try, the probability of drawing 2 blue marbles becomes 0. That is why you assume you are successful the 1st time when finding the probability.
Patrick, I've followed you for years finding your videos helpful as I attempted to conquer first elemental algebra, then calculus and now probabilities. Please know that your presentations are timeless and of high quality and I image students are still viewing them. Once exposed to "patrickJMT' videos they become associated with easily interpreted versions of highly complex theorems. Be proud of your contribution - and thank you.
perfect! i did not know if anyone is really even watching the probability videos...
Dude, you rock. I find it admirable that you would offer services like this for free. Thanks for helping me with the understanding of this elementary probability concept
patrick you are my 105 mathamatics teacher. Since my real one sucks lol, ty your style of teaching is very easy to follow.
@Jarrodmontelius ha, hope it is going well!
no problem! glad to help!
I think it's because we are looking for the probability that event A (one blue marble) AND event B (another blue marble) both occur. If the two events were not dependent (say we replace the blue marble), then we would add the two probabilities (look up the Union Rule of Probability)
wonderful, glad to help
(continuation from my last question)
I don't know if I should treat this is as an independent or dependent event. Can you show how to do this problem?
There are 12 doughnut holes in a box. 5 are chocolate, 4 are plain, and 3 are jelly-filled. If three doughnut holes are removed at random, what’s the probability of removing all three that are jelly-filled? These are the answers to choose from: 1/288, 1/220, 1/3, 1/4, 117/220
Thanks!
I got 100% for my previous test after I watched your videos . Thank you. I hope you help us more!
Thanks to this video, I finally understand the meaning of P(A and B)=P(A)*P(B|A)
wow i wish you were my teacher! every video is soo helpful! thank you!!
so I have a question....what do i do when i have three events that are dependent on each other? ie i have S: 10 red marbles and 6 blue marbles so what is the probability that I get 1 red and 2 blue marbles if i select three marbles randomly?
I worked out first taking a red , then a blue with the reduced total sample space and finally a second blue with reduced blue and reduced total sample space. but then this could happen in 3 sequences, do i * the results together or + results?
I don't know if this means anything to you, but you are a 100 times better than my UCLA math professor.
No.
Intuitively, independent events are events where knowing about one tells you nothing about the other e.g. if you flip a coin and roll a die, then if I roll the die, and see it's a 6, that tells me nothing about whether the coin will show heads or tails.
Mutually exclusive events are events which are impossible to both happen at the same time e.g. for a single flip of a fair coin, the events of getting a heads and tails cannot both happen. You'll either get heads or tails.
Hi Patrick, I was wondering if you could help me with some GRE probability problems that I came across since you are great at the whiteboard explanations. This is one of the problems that was posted.
Is dependent event the same as mutually exclusive event?
Dude you rock!
Awesome work!
I actually understand probability now!
Thanks dude!
For sure now I will pass my maths test!
Keep Up The Good Work!
=] =] =] =] =]
Thank you so much for these videos! You are helping me a lot this semester.....
Yeah I'm watching them. I'm taking math for the liberal arts and we are doing probability right now so they are helping a lot.
thanks Patrick this very helpful, keep the good work!
Thank you so very very much!!!!! I really appreciate you putting these videos up!!!!!!! :)
hahaha Jarrods, Professor Fray was my teacher as well as Miss Spicer! but Patrick is my king!!!!
Thank you for this, a lot of help, really.! More power!
Very, very helpful! Thank you!
I've been watching so many videos, but this is actually the first one I understand completely. Thank you very much for what you do.
i have question teacher :)
ok y did u say at the probability of pick red ball it is 9/19 why u didnt say it is 10/19 ??
becoz if he is gonna pick a blue one so the remaings will be 10 red and 9 blue and the total will be 19 so the probability of getting a red one will be 10/19
thx i hope u answer asap :)
if < then dependant?
The percentage is 23.68% ( 9/38 x 100 = 23.68 % )
I don't understand why it's alright to simplify the first probability statement. If you multiply 19 by 20 you get 380 which would make the answer 9/380. This does not reduce to 9/38 which makes it a completely different answer than if you had not reduced.
on the first draw, you may get a 10 blue marbles out of 20 marbles out there right? and on the second draw, you can get 9 blue out of 19 remaining marbles right? what if on the first draw, I got a red marble. so it will affect the 2nd draw right? my solution on this problem is 10/20*9/19+10/20*10/19=1/2
We only take an event into consideration which is asked in the question. So we won't include the probability of getting a red marble.
I wish you were my teacher...
Yeah, but well, he's working you know, assuming that the first one would be blue.
As he said "If we draw the first one and it was blue, what is the probability that we'll get a blue one again in the second time?"
so if P(A)*P(B|A) = P(A)*P(B), then they're independant?
You're amazing! I'm so happy to know that I'm not the only one who's so passionate about fitness that I kinda feel I do nothing other than that in my life xD much live and respect, keep inspiring !
you are god.... sent from heaven to spread wisdom to people on earth :D
Life saver!!! thanks man! much love
Why don't we add the two probability....why do we multiply them ?? Sum of probability is 1
if > then what?
Thank you, thank you!!
THANK YOU SO MUCH!!!!
Thank you!!
5:04
did he just flip us off?
Yes, your country is a leading intellectual nation.
Thanks, was just thinking about that and youtube to the rescue. As always.
Though, you got it all mixed up. It's obviously blue/red rings of some sort! Hehe.
ops! i got confused!! : )
Thnx dude God bless u
OMG you are awesome!
1/12 + 1/11 + 1/10 = 0.274.. = 27.4% ?
it would be 10:20 x 10:19
10 blue
19 total
شكراً
thank you
its actually 90/380
If you do not draw a blue marble on the 1st try, the probability of drawing 2 blue marbles becomes 0. That is why you assume you are successful the 1st time when finding the probability.