Algebra 2 Section 3 4 Linear Programming

Поділитися
Вставка
  • Опубліковано 5 лют 2025

КОМЕНТАРІ • 8

  • @notmerkyy
    @notmerkyy 2 роки тому

    Extremely helpful, was sick when we went over this in class and this is helping me make sense of it so much! Still working 10 years later haha

  • @pricciixxjoseph1910
    @pricciixxjoseph1910 5 місяців тому

    Thank you so

  • @ethanos__
    @ethanos__ 2 роки тому

    For the vetinary medicine one, for 20v + 40s < 420, why did u substitute in zeros but in the problems before you put them in the form: y = x + n

    • @hardyvac
      @hardyvac  2 роки тому

      In the previous example I rewrote the equations in y=mx+b form. I still used (0,0) to determine shading.

    • @ethanos__
      @ethanos__ 2 роки тому

      I mean when you're trying to figure out what the coordinates are

    • @ethanos__
      @ethanos__ 2 роки тому

      Like at 2:15 you changed it to slope intercept form, but at 12:05 you sub in zeros

    • @hardyvac
      @hardyvac  2 роки тому

      @@ethanos__ y=Mx+b (or slope intercept form) is used to graph the boundary line. Plugging in (0,0) is done to determine which side of the line to shade.

  • @alialabbad1861
    @alialabbad1861 7 років тому

    Thank you