Complex Analysis MCQs - 3 | Mathematical Sciences | Unacademy Live - CSIR UGC NET | Gajendra Purohit

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  • Опубліковано 5 гру 2024
  • In this class, Gajendra Purohit will discuss the Revision Of Complex Analysis Through MCQs Part-3 for CSIR NET Mathematics. This session would be helpful for aspirants preparing for the CSIR-UGC NET exam. Learners at any stage of their preparations will be benefited from the class. The class will be covered in Hindi and notes will be provided in English.
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КОМЕНТАРІ • 11

  • @iamvk2226
    @iamvk2226 4 роки тому

    y(x) = λ integration 0 to 1 (e^-|x-t|) y(t) dt. 0

  • @abubakarawan3449
    @abubakarawan3449 4 роки тому

    Thanks sir for this video

  • @paultare8861
    @paultare8861 4 роки тому +1

    At 7:02 it has to be non isolated?

  • @rainathomas6695
    @rainathomas6695 3 роки тому +1

    First question me woh limit point of zeroes kaise hua? Humne sirf denominator term ko 0 se equate kiya na?

  • @heenagupta915
    @heenagupta915 4 роки тому +2

    Sir but limit point of pole is non isolated singularity hoti h na

  • @rehanarshadarshad3980
    @rehanarshadarshad3980 4 роки тому

    Unbounded

  • @laxmividyaclasses9770
    @laxmividyaclasses9770 4 роки тому

    IF f(z) is an entire function from c to c.
    If f(n) =0 for all positive integers n,then f is constant or not?
    If f(1/n)=0 for all positive integers n, then f is constant or not?
    Is there any theorem for this?

  • @soumyadipsarkar5078
    @soumyadipsarkar5078 3 роки тому +2

    in problem 5 u r talking trash...u r saying that louville theorem says...constant entire functions are bounded........no!!!! bounded entire functions are constant...

    • @keerthanat1749
      @keerthanat1749 Рік тому

      its a contrapositive statement , not constant implies not bounded entire func

  • @rehanarshadarshad3980
    @rehanarshadarshad3980 4 роки тому

    C