Gas Stoichiometry Problems

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  • Опубліковано 27 січ 2025

КОМЕНТАРІ • 145

  • @TheOrganicChemistryTutor
    @TheOrganicChemistryTutor  Рік тому +6

    Gas Laws - Free Formula Sheet: bit.ly/3TOMhhb
    Gas Laws - Video Lessons: www.video-tutor.net/gas-laws.html

  • @callensorensen5574
    @callensorensen5574 Рік тому +51

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  • @walidhossain4836
    @walidhossain4836 7 років тому +307

    i have always been intimidated by Stoichiometry. Now,i decided to start freshly in order to get an A this time. Your channel is very helpful. Thank you so much. I have learned a lot from your videos. :)

  • @emilyparmenter8284
    @emilyparmenter8284 5 років тому +198

    Im failing chem and this helped me out alot to understand everything we've learned. Thank you so much.

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      @ericrodriguez6155 3 роки тому +6

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      @SC-xw5zl 3 роки тому

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  • @sayukumar7577
    @sayukumar7577 3 роки тому +12

    You were meant to teach and I’m so glad you do. Chemistry has never been clearer to me.

  • @georgesadler7830
    @georgesadler7830 10 місяців тому +3

    Professor Organic Chemistry Tutor, thank you for an outstanding explanation of Gas Stoichiometry Problems at STP in AP/General Chemistry. In Chemistry, conversions are tied to Stoichiometry problems from start to finish. This is an error free video/lecture on UA-cam TV with the Organic Chemistry Tutor.

  • @davidlallouz3090
    @davidlallouz3090 4 роки тому +7

    you have the most soothing voice its the only thing pushing me forward in chem

  • @strugsi
    @strugsi 3 роки тому +65

    Small reminder: He's using the ideal gas constant for ATM and L. That is why it's 0.082057366080960 L⋅atm⋅K−1⋅mol−1 and not 8.31446261815324 J⋅K−1⋅mol−1. Since the 2019 redefinition of SI base units, both NA and k are defined with exact numerical values when expressed in SI units.

    • @zetashangu
      @zetashangu Рік тому +1

      🤓

    • @xin8339
      @xin8339 Рік тому

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    • @snowecaddel9454
      @snowecaddel9454 Рік тому

      Thank you :)

    • @RapotatoGAMING
      @RapotatoGAMING Рік тому

      no one cares and this is not relevent for basic stoichiometry. nerd.

    • @jeffreywang4801
      @jeffreywang4801 9 місяців тому

      @@zetashanguthis is why ur here watching a chemistry practice video

  • @dagmwitmelkamu9470
    @dagmwitmelkamu9470 3 роки тому +2

    the thing i love about you is you always come up with different examples and sol thanks a lot for being here to help us out

  • @rovertronic
    @rovertronic 5 років тому +12

    Thank you! Appreciate you doing it slow and in an understanding way.

  • @DOAU
    @DOAU 6 років тому +62

    **NOTE** For the C3H8 problem, do you think it's important to mention that you can convert directly from Liters to Mole/Mole ratio ONLY if Temperature and Pressure are constant? I'm assuming that you are assuming that T&P are constant. If the problem doesn't mention that T&P are constant, then you have to use Ideal Gas Law twice.

    • @masonc975
      @masonc975 5 років тому +8

      If no change in T or P is stated or hinted at then they are assumed to be constant.

    • @schrodingersgunna6390
      @schrodingersgunna6390 2 роки тому +2

      Idk

  • @han.jisung-s_cheesecake
    @han.jisung-s_cheesecake 25 днів тому +1

    You are the best, keep the work you are saving everyone's grades

  • @merkive
    @merkive 5 років тому +23

    thanks to you i passed my chemistry exam, IN FACT I DID BETTER THAN I THOUGHT, thanks man

  • @sahilkatta8490
    @sahilkatta8490 4 роки тому +24

    This helped so much thank you... my chem teacher doesn't know how to teach so I use u to learn

  • @kerstine8227
    @kerstine8227 4 роки тому +4

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  • @Orygiri
    @Orygiri 4 роки тому +17

    I learn infinitely better from you than the nonexistent teachings of my teacher.

  • @Keintara04
    @Keintara04 3 роки тому +1

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    @laservik5718 2 роки тому

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  • @Alaska23
    @Alaska23 5 років тому +4

    Very helpful vid! Understood it better than when my teacher taught it. :)

  • @ShelterMarumbei
    @ShelterMarumbei 4 місяці тому

    Thank you so much we are learning a lot .I was blank on these .it's now clear

  • @ifarove
    @ifarove Рік тому +2

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    Thank you a lot man

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    @obi-wankenobi7324 3 роки тому +5

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    @lilimimi1483 2 роки тому +1

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    @patriotz6127 2 роки тому

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  • @mattfulache
    @mattfulache 3 роки тому +1

    thanks for this video, helped me!

  • @baharosman1416
    @baharosman1416 5 років тому +1

    Congratulations 1M subscriber

  • @nabyongal2040
    @nabyongal2040 Рік тому

    This has been really helpful thanks a lot

  • @imconfused801
    @imconfused801 3 роки тому +1

    thank you so very much! i fell asleep during the introduction of gas stoich in my chem class and now im super lost, haha...

  • @geurrilla2448
    @geurrilla2448 3 роки тому +1

    thanks so much, this stumped me

  • @z3nits098
    @z3nits098 2 роки тому

    Thank u so much ur so better than my gen chem teacher

  • @NEILSHILOHMORALES
    @NEILSHILOHMORALES 2 роки тому +1

    this really helps me a lot

  • @harrietkasozi8536
    @harrietkasozi8536 4 місяці тому +1

    Can you just get the moles of argon by saying if one mole is 22.4dm^3 then 2.5 moles of argon are 2.5 times 22.4 which is 56dm^3 thanks😊😊

  • @lindisamathabela3192
    @lindisamathabela3192 3 роки тому

    This is so helpful! Thank you🌷

  • @theintellectual8811
    @theintellectual8811 2 роки тому

    🥰🥰🥰🥰organic chemistry tutor 😻😻😻

  • @baharosman1416
    @baharosman1416 5 років тому

    Congrats for 1M subscribers

  • @capybara9472
    @capybara9472 6 років тому +1

    Great video!!! helped me a lot

  • @aliciapark523
    @aliciapark523 2 роки тому +1

    appreciate your video!

  • @servantofgod9679
    @servantofgod9679 2 роки тому +168

    I hope you guys have an amazing day! Don't forget, JESUS LOVES YOU! :)

    • @راكانالغامدي-و1ع
      @راكانالغامدي-و1ع Рік тому +17

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      @Momo-wb1gc Рік тому

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      @RayyanIdris Рік тому +9

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      @Natimor_1 Рік тому

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    • @4oresk1nner
      @4oresk1nner 11 місяців тому

      @@راكانالغامدي-و1عwhat is bro yappin abt

  • @baharosman1416
    @baharosman1416 5 років тому +4

    PV=nRT
    U can also use this
    For the first question....

  • @tweetybirdy6383
    @tweetybirdy6383 13 днів тому

    My class use Kpa and not atm. Would that affect anything? For example in the first equation in the video.

  • @saitchychan6955
    @saitchychan6955 3 роки тому

    I need to study becauce im failing chem with this topic, thank you for shredding some light because i'm on the tip of giving up.

  • @cicileyhaslem7879
    @cicileyhaslem7879 5 років тому +2

    So helpful! Thank you!

  • @shahvez.2610
    @shahvez.2610 6 років тому +14

    Just asking but isn’t it 245 mL of HCl not 245 L, so wouldn’t that affect the number of moles you get for HCl which changes things? Just a concept check

    • @sahijrandhawa5480
      @sahijrandhawa5480 2 роки тому

      You have to have your answer in L, not mL so, you would have to do the conversion from mL, to L. Which is what he did.

  • @남윤재-k7o
    @남윤재-k7o 5 років тому +1

    Your channel is very helpful thank you so much I got 95 on the test after I watch this

  • @ompatel4990
    @ompatel4990 3 роки тому +2

    the 1 mole of gas = 22.4L is that true for all gasses or just argon?

    • @corecube7721
      @corecube7721 3 роки тому +2

      ALL GASES

    • @ompatel4990
      @ompatel4990 3 роки тому

      @@corecube7721 dope thanks lol stupid question ik thanks again

    • @corecube7721
      @corecube7721 3 роки тому +2

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  • @Anonim-bj5tc
    @Anonim-bj5tc 3 роки тому +1

    THANK YOU ✊😆🙏

  • @davidrenteria9585
    @davidrenteria9585 2 роки тому

    This is amazing!

  • @beanenita9840
    @beanenita9840 5 років тому +1

    Thanks a lot 💕

  • @johamad5148
    @johamad5148 Рік тому

    why do you use the ideal gas equation when solving for the mg3n2 equation? why can't we just say that 4.7L of ammonia is equal to the moles as in 4.7mol since the moles are equal to litres in gases please help

  • @thyl7466
    @thyl7466 4 роки тому

    Can u help? I have a problem like the last two example. What if, after the reaction, we were asked to find the pressure but is also said that we should neglect the volume of the product. Should I just remove the V from the formula?

  • @yupei7757
    @yupei7757 7 років тому +1

    "One type of sunburn occurs on exposure to UV light of wavelength in the vicinity of 325nm. a) What is the energy of a photon of this wavelength? b) What is the energy of a mole of these photons? c) How many photons are in a 1.00mJ burst of this radiation? d) These UV photons can break chemical bonds in your skin to cause sunburn, a form of radiation damage. If the 325nm radiation provides exactly the energy to break an average chemical bond in the skin, estimate the average energy of these bonds in kJ/mol."

    • @yupei7757
      @yupei7757 7 років тому

      Can you explain these types of questions please? I tried doing them and ending up getting the right answers but it's only because I kept plugging in numbers to try it out but I still don't understand the concept or what the original equation should be

    • @toriquiroga9429
      @toriquiroga9429 5 років тому

      These questions are the reason I hate chemistry. I would never need to know this information, I would just wear sunscreen. A bunch of fooey if you ask me.

    • @couragecrusader7649
      @couragecrusader7649 4 роки тому

      Thats a tough question is that higher level chemistry?!?!?!?

  • @acelatte3905
    @acelatte3905 4 роки тому

    U R MY HERO!!

  • @sahijrandhawa5480
    @sahijrandhawa5480 2 роки тому +2

    This chemistry video tutorial explains how to solve gas stoichiometry practice problems at STP and not at STP. Did you mean STAP for the last one?

  • @LunarBase-mz3vl
    @LunarBase-mz3vl Рік тому

    24:10 isn’t 0.0821?

  • @Chance-u4h
    @Chance-u4h 7 місяців тому

    thank you a again all though it was kind of tough i made it work.

  • @AlchemistAH
    @AlchemistAH 2 роки тому

    but i think that formula is V=n*24 is it wrong

  • @SeaTurtle-nl3he
    @SeaTurtle-nl3he 3 роки тому

    wow good job

  • @meiganavery8407
    @meiganavery8407 5 років тому

    thank you so much

  • @throwabone9005
    @throwabone9005 2 роки тому +1

    My teacher literally didn’t teach us that 1 mol = 22.4L so I’ve been sitting here wondering how I have 1487.39582824 mol of N2…….

  • @DueflikyGaming
    @DueflikyGaming 5 років тому

    Just gonna go ahead and point out that Standard Pressure is no longer expressed in atm. As of 1982 STP is defined by IUPAC as exactly 1.00 bar , 273.15 K. As a result 22.4 L / 1 mol is no longer valid. Since the standard unit is bar and not atm 22.4 L becomes 22.7. So, 1 mol of gas at STP = 22.7 L

    • @ctrlz9372
      @ctrlz9372 3 роки тому +3

      tf man

    • @seaweedaf
      @seaweedaf Рік тому

      i dunno, mcat still uses 22.4 but the numbers are so similar, pretty sure the difference is negligible unless you're a physical chemist..

  • @forbiddenotaku467
    @forbiddenotaku467 5 років тому

    Thank you

  • @giemarbebernaldez2369
    @giemarbebernaldez2369 6 років тому

    i don't understand the 6th problem, how come HCl is the limiting when Zn has the lesser value of moles?

  • @richphero106
    @richphero106 3 роки тому

    God bless you!

  • @kalebparkinson5248
    @kalebparkinson5248 3 роки тому +1

    Short cuts tend to not help people. I would strongly suggest using Idea Gas Laws and staying consistent in your methods vs. taking shortcuts.

  • @metangel3566
    @metangel3566 2 роки тому

    for #2 at 6:36

  • @anilsharma-ev2my
    @anilsharma-ev2my 4 роки тому

    We can use the direct current from Dynamo to hydrogen making and reuse the hydrogen again and again so we go further in lesser fuel
    Please do the math over it

  • @JoeSchmo69420
    @JoeSchmo69420 2 місяці тому

    thx babe ❤❤

  • @thanishiajoanna79
    @thanishiajoanna79 2 роки тому

    The complete combustion of a tank of petrol produced 219 kg of carbon dioxide gas:
    a. What volume of carbon dioxide is produced when measured at STP?
    b. What mass of oxygen is used by a car in burning a tank of petrol? You may assume that
    for every 1.00 L of carbon dioxide produced, 1.00 L carbon dioxide produced, 1.00 L of
    oxygen is consumed.
    pls help me with this guys!!!!

    • @Rotnoc473
      @Rotnoc473 2 роки тому

      I may be a little late, but you need to use moles to solve these problems. For a., convert 219kg of into mols of C02, which is approximately 4976.141786 mols. You then use PV=nRT by plugging in the values at STP and the amount of mols you have, solving for V. this will look like: V=((4976.1418)(0.08206)(273))/1. This will equal: 111477.4192L, accounting for significant figures you should get: 111,000L CO2.
      For b, I'm not sure that this problem is solvable. You would need to know the chemical reaction, and whether or not you can assume STP. If there is no more information then possibly: LCO2=LO2 will be an acceptable answer. For practice I will assume the chemical reaction is gaseous Octane reacting with excess 02 to produce carbon dioxide and water. The balanced chemical reaction should go as follows: C8H12(g) + 11O2(g) -> 8CO2(g) + 6H2O(g) I will also assume the gasses are at STP and the volume of the petrol tank is 50.0L, and I will be solving for the mass of CO2 produced. First we need to solve for the mols of Octane, to do this you need to plug in the information stated with the equation n=(PV)/(RT).
      This should look like: n= ((1)(50))/((0.08206)(273)). n = 2.2319mol Octane. now multiply the mol ratio of Octane to CO2, which is 8/1 by the mols of Octane we have, which is:
      8*2.2319= 12.85524mol CO2. Now we can convert the mols into grams by doing 17.85524mol CO2 * 44.01g/mol CO2 =785.809g CO2, applying significant figures the answer should be: 786g CO2. For a challenge lets assume that the combustion reaction of 1mol of Octane takes place in an enclosed chamber of 1.00L at 100.C which is being pumped with excess O2, which will then be removed when the reaction is finished. What would the pressure of the reacted compounds in the chamber be? to solve this we need to divide mol ratio of Octane used and Octane in the reaction (this is 1/1, if the coefficient of Octane was, for example: 4, and there was still 1 mol of octane actually reacted then the ratio would be 4/4. this removes the coefficient Infront of Octane, I'm not sure how to explain this any better so hopefully this will do). You then divide the products mol ratios by the amount divided by the Octane. This is a really bad way of explaining it so hopefully the view of the balanced chemical equation will help: 1/1C8H12 + 11O2 -> 8/1CO2 + 6/1 H2O. you then take the products mols and plug it into PV=nRT, solving for P. This should look like: P = ((8+6)(0.08206)(373))/1 = 428.5173atm produced. Accounting for significant figures you should get 429atm produced.
      For b I should should clarify that the problems I did I did not derive from the information given, I simply took the premise to show different ways that you can use gas stoichiometry to solve problems. it would not be possible to derive these problems from the information given, so I made up some information to be able to do the problems I did. I know that I am late to answering you question, which I did so more to help myself in understand gas stichometry then to teach it, so I hope that you now have an answer and understand you original question. I also hope you at least partially understood my explanations. I should also clarify that the problems I did are most likely harder than what you would see on any test of yours, I am in AP chem, and that is were I derived these problems from, so if they felt way too hard then do not worry too much. If you take one thing away from this response then it should be that moles are the key to stoichiometry, and chemistry at that. If you can familiarize yourself with moles then you will have familiarized yourself with stoichiometry. Good luck on your future chemistry endeavors.

    • @thanishiajoanna79
      @thanishiajoanna79 2 роки тому

      @@Rotnoc473 Thank you so much... 🥺

  • @oliviarichardson7570
    @oliviarichardson7570 3 роки тому

    this doesnt work, becuase for PV= nRT doesnt the pressure have to be in kpa, which would make it 101.3 not 1 atm

  • @coldchickennoodles5575
    @coldchickennoodles5575 8 місяців тому

    What is the volume of 7.6g of argon at RTP? guys I'm failing tomorrow 😭

  • @anilsharma-ev2my
    @anilsharma-ev2my 4 роки тому

    We can printed the biological molecules by using an atom a day so we got living molecules in few days and artificial petrol fact9 become possible for whole universe

  • @bable480
    @bable480 10 місяців тому

    Sobbinggggggg😭😭

  • @ayfmlol9725
    @ayfmlol9725 3 роки тому

    Finals tommorow : (

  • @JacobKuriakose-sb3me
    @JacobKuriakose-sb3me Рік тому +1

    Im pretty sure number 1 is wrong because its supposed to be2.5 mols but he puts 1 mold and also he didint solve the whole equation for number 1

  • @синиякрыса
    @синиякрыса 4 роки тому +2

    5 + 5 = 55

  • @nx_0
    @nx_0 4 роки тому +1

    2020 people

  • @rachelharrison6191
    @rachelharrison6191 7 місяців тому +1

    the way none of these set ups for the problems got me the right answers for my chemistry worksheets….do better thanks !

  • @harmanbaidwan1713
    @harmanbaidwan1713 9 місяців тому

    if you were carti, it would be easier to understand, but aight bruh

  • @nikalei723
    @nikalei723 Рік тому

    BENETTE

  • @psych7656
    @psych7656 3 місяці тому

    help

  • @renllybacolina2755
    @renllybacolina2755 4 роки тому

    Stem pa more

  • @777domingo8
    @777domingo8 2 роки тому

    i hatte this

  • @Wlf-lp1mq
    @Wlf-lp1mq 5 років тому

    The answer you gave to the first problem is wrong.You needed to plug the 56L into the problem to get the actual answer of 1.000593

  • @prospectagu8693
    @prospectagu8693 3 роки тому

    you don't explain well

  • @Zhelfilms
    @Zhelfilms 5 років тому

    Gggrrrrr... I'm not interested

  • @baharosman1416
    @baharosman1416 5 років тому +3

    Congratulations 1M subscriber

  • @vincentzulu7066
    @vincentzulu7066 2 роки тому

    Thank u very much

  • @Thv-ri3fl
    @Thv-ri3fl 4 роки тому

    Thank you