Oops, I think there is a mistake at the end there Mr Hegarty, part (a). You used the "n-1(d)" from part B forgetting that n has changed from 14 to 8. So 8-1=7; 7(1000)=7000; therefore S8= 4[30,000+7000]= £141,000 if I'm not wrong :)
This is wrong once a salary of £25,000 is reached there are no more increases in £1000 every year so when n=11 his maximum salary has reached £25,000. After this £15,000 is increased each time. So for part b, it should be S11 + (15,000x3).
Oops, I think there is a mistake at the end there Mr Hegarty, part (a). You used the "n-1(d)" from part B forgetting that n has changed from 14 to 8. So 8-1=7; 7(1000)=7000; therefore S8= 4[30,000+7000]= £141,000 if I'm not wrong :)
Hamzah413 148,000**
4x(30000+7000) is 148000 btw
But, doesn't he reach his maximum salary after 10 years, so it's S10 + 4(25000)?
Madame Corgi He reaches his maximum on the 11th year, which is included, don’t get confused with the n-1 rule
295000 guys for b
Hello, great videos! Just another comment: I think the link to this video is missing from your website.
What the hell everything is wrong ._.
part b is wrong its 295 000
Cmon fix up lol
This is wrong once a salary of £25,000 is reached there are no more increases in £1000 every year so when n=11 his maximum salary has reached £25,000. After this £15,000 is increased each time. So for part b, it should be S11 + (15,000x3).
Iqra Zuberi lmao nah son, it stays at £25000. I suggest he quits if it goes back to £15000..shit job
So s11 + 3(25000)