Can You Use Lambert's W Function?

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[@mbmillermo]

I solved it "by inspection". Basically, doing what you did but skipping the W(). Just write ln4 as 2ln2 = ln2*e^ln2, and you can see that the answer is x = ln2. Many of your problems work that way, but then I'm always wondering "is that the only solution" -- I can hear your voice in my head when I say that!

[@SyberMath]

😁

[@thorinpalladino2826]

Not sure you need some special function.
X*e^X= ln4 can be rewritten in exponential notation as e^(X*e^X)=4
or (e^X)^e^X=4
or (e^X)^e^X=2^2
So e^X=2
X=ln2

[@tsar_asterov17]

Hey that would be right yeah! That's pretty cool. I guess he wanted to just use it as an example to show the lambert W function, which is a very cool function.

[@saliryakouli1260]

Maybe not for this equation but you need it for other equation that can't be solved otherwise

[@dr.rolandzagler8831]

Hello,
in yt there are a few videos which are dealing with the so-called „g(log)-function (e^x=zx). It is said that the g(log) method can be used instead of the „W Lambert function“, but for the g(log) function no results of calculations are shown, neither by Wolfram Alpha, nor by the function curve itself. It would please me, if you gave me some detailed informations of the status of g(log) 😇.
THX very much. Roland

[@SidneiMV]

x = W(2ln2) = ln2

[@BlaqRaq]

I almost forget to like (already subscribed).

[@SyberMath]

you must be. You write good comments

[@rakenzarnsworld2]

x = ln2

[@mathswan1607]

x=ln 2

[@saliryakouli1260]

x=w(ln(4))

[@trojanleo123]

x = ln2

[@user-ii5ge1to9l]

x=ln2