@@drpeyam Holy shit, you made this 7 months ago? Wow discipline man! If it's not too intrusive, may I ask how many days of extra content do you usually have unlisted?
First multiply both sides by log (-2/√3·cos x) to clear the fraction, then use the identity b log(x) = log(x^b) to clear the square root. Next, factor 2-2sinx as 2(1-sinx) and use the identity log(a x) = log(a) + log(x). Move the constants to one side, and the trig functions to the other. A few more identities should get you to sin(x) = 1/2
@@ronaldjensen2948 Hello I don't know whether I 'm missing sth or not but log2+log(1-sinx)=log(4/3cos^2) then log(4/3cos^2) -log(1-sinx)= log(4/3cos^2 /1-sinx) which brings us 4/3 cos^2*(1-sinx) isn't it like that? Isn't cos^2*(1-sinx) in the denominator and then doesn't it bring (1-sinx)^2*(1+sinx) where is my mistake I couldn't cancel out 1-sinx factors
@@sadececansu9 Try moving everything to one side so you have log(...)-log(...) = 0 Then combine all the logs on the lhs so: log(...) = 0 Then raise to the e to clear the logs: (...) = 1 All trig from there
This explains why I don’t have a math PhD.
You could probably figure this stuff out. It’s the kind of thing that you do in an undergraduate real analysis course.
Just an excuse
But u have a PhD in integration hahaha
I want to have PhD in horseshoe mathematics .
Same here!! 😆
Undoubtedly Dr Peyam has a passion to teach, dedicating himself to achieving his goal . This is very appreciated !❤
I was attracted with your Quadratic eqn videos from INDIA
Thanks for this interesting battle. Liked it!
Prove it if you want to be thorough, but the envelope functions say it all.
Thanks! It was a very good class!
You make math enjoyable! Thank you!
Really fascinating!
Speaking of continuity, can you make a video on bump function and its properties, please?
Two "Peyam" xD
6:02
in 4:07 why X^2 is multiplied by 1?
Oh because |sin(anything)|
@@drpeyam thank you sir.
This week on "Epic Math Battles of Histora-wy."
Wait.
This video was uploaded 5 hours ago then how it has comments from past 7 months?
🤔
Magic
@@drpeyam you are mathemagician 🙏
6:15 WTF
Dr peyam can i use this channel for jeee🥰🥰
why is this unlisted?
Because
@@drpeyam Holy shit, you made this 7 months ago? Wow discipline man! If it's not too intrusive, may I ask how many days of extra content do you usually have unlisted?
@PBJ A whole year lol
At 6:56,why we want sin(1/Xn)=1
To simplify things
@@drpeyam thanku sir...
Your way of teaching is awesome
Hello, Peyam. As a curiosity, do you know which constant is the Erdos-Borwein constant?
@@pbj4184 That's not what a troll is.
@@musik350 Yes sorry, I think I had an misunderstanding
But can u make it entertainin'! thats another skill to learn. :) magician style!
Why don't you also use pokéball like your friend??
Cool!!!
Can you helpme with this equation?
log (2-2sinx) / log (-2/√3·cos x) = 2
First multiply both sides by log (-2/√3·cos x) to clear the fraction, then use the identity b log(x) = log(x^b) to clear the square root. Next, factor 2-2sinx as 2(1-sinx) and use the identity log(a x) = log(a) + log(x). Move the constants to one side, and the trig functions to the other. A few more identities should get you to sin(x) = 1/2
@@ronaldjensen2948 Yes, but i'm solved graphical, there not solutions.
Sorry by my english
@@gabrielalem123 Good point. All the solutions are extraneous since they lead to division by zero
@@ronaldjensen2948 Hello I don't know whether I 'm missing sth or not but log2+log(1-sinx)=log(4/3cos^2) then log(4/3cos^2) -log(1-sinx)= log(4/3cos^2 /1-sinx) which brings us 4/3 cos^2*(1-sinx) isn't it like that? Isn't cos^2*(1-sinx) in the denominator and then doesn't it bring (1-sinx)^2*(1+sinx) where is my mistake I couldn't cancel out 1-sinx factors
@@sadececansu9 Try moving everything to one side so you have log(...)-log(...) = 0
Then combine all the logs on the lhs so:
log(...) = 0
Then raise to the e to clear the logs:
(...) = 1
All trig from there