Well, I guess that if you hold the temperature constant on the left side; you'd already call it dG(T). And that must be independent from the other side of equality because you named it that way. Same thing for the right side.
1) There are many ways: increase the pressure, decrease the temperature, increase the concentration, etc 2) Keep watching the next few videos and this is discussed. In particular, try this one: ua-cam.com/video/EsVV3hxl_8Q/v-deo.html
I'm not sure what yo'ure asking. Perhaps: is it **possible** to set up a constant-entropy system? Yes, it is. Any process that is both adiabatic (δq = 0) and reversible will be isentropic (dS = 0). (Recall the Clausius Theorem, dS = δq_rev / T. ua-cam.com/video/e3YynS_D5z0/v-deo.html ) So, to set up an isentropic process, just insulate your system well to make sure it doesn't exchange heat with the surroundings, so it will be adiabatic. And then make sure any changes happen very slowly, so that the system remains in equilibrium, so it will be reversible.
That's a good suggestion, I'll add it to the list. Briefly: you would usually measure the temperature change for the mixing of the components, get the enthalpy of mixing via calorimetry (ua-cam.com/video/ieb92-5YVpo/v-deo.html), then use the definition of partial molar enthalpy = ∂H/∂n|_T,P,nⱼ to get the partial molar enthalpy.
Thank you for this video.. I was struggling to understand from where did the relations of different thermodynamic functions with respect to chemical potential came.
prepping for my PhD entrance exams and these have been a life saver thank you so much!!
Great to hear that, thanks. Good luck on your exams
Thank you so much for creating all of these videos! They are extremely helpful!
My pleasure. I'm glad you found them useful
why is it possiblbe to hold the entropy constant on one side and the temperature on the other side, shouldnt I do the same on both sides?
Well, I guess that if you hold the temperature constant on the left side; you'd already call it dG(T). And that must be independent from the other side of equality because you named it that way. Same thing for the right side.
Prof,
Q1) How do increase increase the chemical potential
2) How does the chemical potential depend on T and number density
1) There are many ways: increase the pressure, decrease the temperature, increase the concentration, etc
2) Keep watching the next few videos and this is discussed. In particular, try this one: ua-cam.com/video/EsVV3hxl_8Q/v-deo.html
Sir where are you teaching? In which country?
I'm in the United States
@@PhysicalChemistry
Sir you are teaching which grade students
@@chemistrybysaadanwar This PC?hem course material is for undergraduate students, mostly 3rd- and 4th-year.
@@PhysicalChemistry you have excellent teaching skills 👍💯
@@chemistrybysaadanwar Thanks, I appreciate that
You saved my semester.
You had to put in all of the work, so you should take the credit for your own semester
Can we increase the chemical potential by increasing the number density and deceasing the temperature?
Regards
Yes, that's right
im starving more lectures of you! it would be great pleasure if it is possible to upload more than one video every day
I'm glad you're eager to learn more, and I'm working on them as fast as I can.
@@PhysicalChemistry it is because of you. thanks alot prof🌹🌹🌹
Do we have a constant entropy system?
I'm not sure what yo'ure asking. Perhaps: is it **possible** to set up a constant-entropy system? Yes, it is.
Any process that is both adiabatic (δq = 0) and reversible will be isentropic (dS = 0). (Recall the Clausius Theorem, dS = δq_rev / T. ua-cam.com/video/e3YynS_D5z0/v-deo.html )
So, to set up an isentropic process, just insulate your system well to make sure it doesn't exchange heat with the surroundings, so it will be adiabatic. And then make sure any changes happen very slowly, so that the system remains in equilibrium, so it will be reversible.
Sir can you upload how to estimate partial molar enthalpy experimentally for binary components in lab
That's a good suggestion, I'll add it to the list.
Briefly: you would usually measure the temperature change for the mixing of the components, get the enthalpy of mixing via calorimetry (ua-cam.com/video/ieb92-5YVpo/v-deo.html), then use the definition of partial molar enthalpy = ∂H/∂n|_T,P,nⱼ to get the partial molar enthalpy.
Thank you for this video.. I was struggling to understand from where did the relations of different thermodynamic functions with respect to chemical potential came.
You're welcome. This topic is definitely brushed over a little too quickly in most textbooks.
@@PhysicalChemistry Do you have a forum for resolution of doubts?
@@vaibhavraj6512 Not aside from these comments
Thankyou so much.
OMG 😍💋 💝💖❤️