Caution Do not attempt to implement or use the information, unless you are experienced and skilled with respect to such subject matter, and competent in handling AC mains. There are better ways to accomplish the same task.
Thank you so much for your explanation, sir. Could you please explain why are you using a 220ohm resistor in series with the dropping capacitor? It would be amazing.
This makes me quit electronics... It feels like I don't have time for this even tho I enjoy it very much and very thing I learn I feel it's a bonus but for what ? I don't really make money with this or just rarely...
1/6.28×60×5000 1/2185440 0.46uf U r getting this value But when I multiply 1/6.28×60×5000 I'm getting 1/1884000 5.307uf How is this,y your values r not matching ,can u explain me
Thank you so much for your explanation, sir. Could you please explain why are you using a 220ohm resistor in series with the dropping capacitor? It would be amazing.
Best explanation on UA-cam about this circuit design. THANX!!!!!!!!!!!!!!!!!!!!!!!
excellent explanation sir. thank u very much
😃ur calculations are really prefect
Great video. Thank you 🙏 and have a good day!
Rectified 120vac is around 170 volts. That should resolve your issue of the current being 40% higher than calculated. Great video, though!
hi, shouldn't you use Vin = (120 x under root 2 ) - 4 because Vin = Vp and Vp = Vrms x under root 2?
Caution
Do not attempt to implement or use the information, unless you are experienced and skilled with respect to such subject matter, and competent in handling AC mains. There are better ways to accomplish the same task.
where to get those electric protection gloves ?
good work flow. thank you
Thank you so much for your explanation, sir. Could you please explain why are you using a 220ohm resistor in series with the dropping capacitor? It would be amazing.
Check out my inrush current resistor video
Why didnt you add this 1M bleeder resistor to your impedance calculations?
its large enough to not have an impact
nice vid, sir
how do you obtain the C value of the voltage stabilizer cap in parallel with the output load?
Thanks I'll do a vidio on smoothing capacitors
Check out My Smoothing capacitor video.
Hi, I like to know how to calculate the capacitor value for dc ac inverters in first stage capacitor. can you pls help me?
Thanks for subscribing. A quick design approach is to do it empirically.
i cant work out how you got z l am getting 5829, what am i doing wrong
Link to my notes: drive.google.com/file/d/1zhAqlCOMKdRjzQkZ2-d-O9HkAX1Q5Nii/view?usp=sharing
Z= √(〖220〗^2+〖3,902〗^2 ) Z= √(48400+15225604) Z=√15274004 Z = 3,908
@@ke6chris thanks got it
This makes me quit electronics... It feels like I don't have time for this even tho I enjoy it very much and very thing I learn I feel it's a bonus but for what ? I don't really make money with this or just rarely...
1/6.28×60×5000
1/2185440
0.46uf
U r getting this value
But when I multiply
1/6.28×60×5000 I'm getting
1/1884000
5.307uf
How is this,y your values r not matching ,can u explain me
its 5800 not 5000
Power loss = 120.6V x 0.028A = 3.3768W - 0.064W (LED) = 3.3128 watts
Your diagram should be magnify for better viewing
Link to diagram: drive.google.com/file/d/1zhAqlCOMKdRjzQkZ2-d-O9HkAX1Q5Nii/view?usp=sharing
Thank you so much for your explanation, sir. Could you please explain why are you using a 220ohm resistor in series with the dropping capacitor? It would be amazing.
To limit inrush current