3 is the maximum number of total outfits you can make (that is taking the "a third as many shoes" to mean 3 pairs) . the maximum number of combinations of outfits however is 486. but you can only make 3 at any one time.
At the title card (0.01), my answer is d)486. With 9 pair of pants, 3 pair of shoes, and 18 shirts, it's simple multiplication: 9 * 3 * 18 = 486. To break it down further, for each pair of pants, you could make 3 "starter sets" with different shoes, so 27 "starter sets." Then, for each of those 27, you could make 18 different complete outfits, so 27 * 18 = 486. (Of course, you could get even MORE "outfits" depending on gender and season by forgoing the shirt, the shoes, or both!)
It seems that the fundamental counting principle was stored in my brain somewhere because I got it. I even checked with my own diagram tree to make sure and saw that it worked. And now I know my "ways" for the next similar test coming my "way".
As long as you pick which assumes that the TWO shoes out of the three for each outfit, the number is the same as taking 3 pairs of shoes a pair at a time (3 different selections). It gets more interesting if you have 4 pairs (4 selections), vs 4 shoes taken two at a time (6 selections). That might make things interesting. Of course this assumes that left and right shoes are interchangeable (which might not be the case). Something to ponder. Of course if you have three shoes, where you have two left, and right, you get only TWO combinations. In that case the answer would be 324, not 486. Assuming you don't have two left feet!!
9 pants 18 shirts 1) If you meant 1/3 as many shoes 9 pants x 18 shirts x 3 pairs => 162 x 3 = 486 2) If you meant 3 shoes If two are left and one right or if two are right and one left => 162 x 2 = 324 If all three are left or if all three are right => 162 bare-foot outfits
Question: Does the order of the m and n values matter? In the original question, it was 9 pants, 3 shoes and 18 shirts. What if I did 18 shirts, 9 pants and 3 shoes to get to an answer?
This assumes every outfit must contain one and ONLY one shirt, pants, and pair of shoes. An outfit could contain anywhere from nothing but a pair of shoes for travel to the tropics, all the way to 18 shirts, 9 pants, and 3 pairs of footwear if you're in Antarctica.
You make some good points, but if this was a nudist colony, then the answer would be the "null answer" or undefined. Because nudists don't wear clothes.
The answer is 324. That's 9 x 18 pants / shirts combination time 2 pair combinations of shoes. It say a third as many SHOES, which is THREE SHOES to make 2 pair combinations. 9 x 18 x 2 = 324. And this assumes there is ONE shoe of one side and two of the other. NOW, if there had been "a third as many" PAIRS of SHOES....
When I was a kid (about 55 years ago), during the spring or fall I liked to wear a long sleeve flannel shirt under a short sleeve pull over sweat shirt. It was warm and my arms were more free.
I am assuming that the chap is 2 legged, in which case you should write PAIRS of shoes ( or is that not necessary on your side of the pond?!!) So we simply have 486 different outfits available!! :o
Clearly you know nothing about fashion! The very idea that any pair (!) of shoes would match with any particular pair of pants-or matching (!) shirts… sheesh! Einstein’s head would explode. [Surely you know the famous equation: Wear under (T over P over LS + RS) = Phew…] I think that covers everything… (oh no, there’s a remainder: socks!)
got it 486, simple multiplication. thanks for the fun.
You haven;t listed enough items to make a single outfit. Not where I live anyway.
3 is the maximum number of total outfits you can make (that is taking the "a third as many shoes" to mean 3 pairs) . the maximum number of combinations of outfits however is 486.
but you can only make 3 at any one time.
At the title card (0.01), my answer is d)486.
With 9 pair of pants, 3 pair of shoes, and 18 shirts, it's simple multiplication: 9 * 3 * 18 = 486.
To break it down further, for each pair of pants, you could make 3 "starter sets" with different shoes, so 27 "starter sets."
Then, for each of those 27, you could make 18 different complete outfits, so 27 * 18 = 486.
(Of course, you could get even MORE "outfits" depending on gender and season by forgoing the shirt, the shoes, or both!)
It seems that the fundamental counting principle was stored in my brain somewhere because I got it.
I even checked with my own diagram tree to make sure and saw that it worked.
And now I know my "ways" for the next similar test coming my "way".
What is an outfit?
Who says I can't put different shoes on? Let's say it's Halloween. Then my choices triple at least, right?
As long as you pick which assumes that the TWO shoes out of the three for each outfit, the number is the same as taking 3 pairs of shoes a pair at a time (3 different selections). It gets more interesting if you have 4 pairs (4 selections), vs 4 shoes taken two at a time (6 selections). That might make things interesting. Of course this assumes that left and right shoes are interchangeable (which might not be the case). Something to ponder.
Of course if you have three shoes, where you have two left, and right, you get only TWO combinations. In that case the answer would be 324, not 486. Assuming you don't have two left feet!!
It also doesn't say what the outfit must consist of, a very hot day at the beach pants (I guess this means trousers?) Would do.
9 pants
18 shirts
1) If you meant 1/3 as many shoes
9 pants x 18 shirts x 3 pairs => 162 x 3 = 486
2) If you meant 3 shoes
If two are left and one right or if two are right and one left => 162 x 2 = 324
If all three are left or if all three are right => 162 bare-foot outfits
Question: Does the order of the m and n values matter? In the original question, it was 9 pants, 3 shoes and 18 shirts. What if I did 18 shirts, 9 pants and 3 shoes to get to an answer?
Multiplication is commutative. So the answer is the same.
This assumes every outfit must contain one and ONLY one shirt, pants, and pair of shoes. An outfit could contain anywhere from nothing but a pair of shoes for travel to the tropics, all the way to 18 shirts, 9 pants, and 3 pairs of footwear if you're in Antarctica.
You make some good points, but if this was a nudist colony, then the answer would be the "null answer" or undefined. Because nudists don't wear clothes.
@@terry_willisROFL - TOO TRUE. I presumed a deserted tropical island.
9X3X18=486
12
The answer is 324. That's 9 x 18 pants / shirts combination time 2 pair combinations of shoes. It say a third as many SHOES, which is THREE SHOES to make 2 pair combinations. 9 x 18 x 2 = 324. And this assumes there is ONE shoe of one side and two of the other. NOW, if there had been "a third as many" PAIRS of SHOES....
If you only have 3 shoes, this severely limits your outfits. You didn’t say 3 pairs. A mathematician should be precise.
Hello karen
It goes without saying that the three shoes were a right ballet slipper, a left high heel, and a right flip-flop.
@@thatcherdavis8939yep. You can tell from the way the question mark is depicted that those shoes are correct
Totally agree. I made the same point before I read your comment. Badly worded question.
972 outfits if you don't match your shoes. 1458 outfits if you consider left shoe and right shoe mismatches distinct outfits.
My daughter likes to wear 2 shirts long sleeve under short sleeve.
When I was a kid (about 55 years ago), during the spring or fall I liked to wear a long sleeve flannel shirt under a short sleeve pull over sweat shirt. It was warm and my arms were more free.
None that I'd want to be seen in public weari.... Oh! You mean trousers!
It's a question of permutations, right?
18 shirt *9 pants * 3 shoes = logically this work, but mathematically, have forgotten the permutation and combination concept ✌
I am assuming that the chap is 2 legged, in which case you should write PAIRS of shoes ( or is that not necessary on your side of the pond?!!) So we simply have 486 different outfits available!! :o
This is fun. I am not good at math, but that was simple😊 I missed it, but now I know why
9+(9/3)+(9x2)=9+3+18=30
As written, only 1 outfit.
Thank you 😊
I didn’t calculate, I eliminated to reach “D”.
(9)^2=81 {81+9}=90 {90•2}=180
{9•3}=27 {27•2}=54
So .. that's 9 pairs of pants (or trousers) 3 pairs of shoes and 18 shirts.
9 x 3 x 18 = 486
So that's 486 different outfits.
So the question is what's 9 times 3 times 18. I did the math by hand and got 486.
If you had said unique outfits I would have understood.
I can’t even do this problem, I barely know the very basics because of a learning disability
thanks
This is like a genetics problem, I don’t think the question was clear.
The answer is 9 x3 x 18 = 486 😊
a) 30
Thanks,
A third as many shoes is three shoes . one pair and an odd one . badly worded question.
Poorly worded, not badly.
486 combo's
d) 486
👍 got 486
D
Clearly you know nothing about fashion! The very idea that any pair (!) of shoes would match with any particular pair of pants-or matching (!) shirts… sheesh! Einstein’s head would explode.
[Surely you know the famous equation:
Wear under (T over P over LS + RS) = Phew…]
I think that covers everything… (oh no, there’s a remainder: socks!)
d) 486