This is interesting, and it's a clever solution if the number happens to be 27 or some other number that conveniently fits the form of a^a. Other examples might be 1=1^1, 4=2^2, 64=4^4, etc. But how can this be solved for any general number that might not fit that pattern? Suppose the number was 19 instead of 27?
Whoa what a lesson👍👍👍😉
Good evening sir thanks for the help
You always make me sir
Good morning sir,how are you today
This is interesting, and it's a clever solution if the number happens to be 27 or some other number that conveniently fits the form of a^a. Other examples might be 1=1^1, 4=2^2, 64=4^4, etc. But how can this be solved for any general number that might not fit that pattern? Suppose the number was 19 instead of 27?
Good morning, following
Thanks sir this Tracy from mayuge have learnt more
Good morning sir
Thanks for the informative video but that concept of a to power a is equal to b to power b is just hard to understand
good work teacher but at the last i saw a mistake that what if the 27 would have been 8 will you get the correct answer using the formula a^a=B^b
What if a=2 & b=5? Can your comparisons work? I doubt if this is true
❤ you are a good teacher
I want to join u Sir
Morning sir are we done with 2023 paper
Its coming
Good morning
Mmmm it's bad 😮😮...but thanks sir for your help....
Where did the three come from?
Good morning sir
Please make more