How to Optimize a Perfect Ball Toss for your Child

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  • Опубліковано 3 лис 2024

КОМЕНТАРІ • 33

  • @abhishekkurup
    @abhishekkurup 2 місяці тому +27

    This is what UA-cam recommended me after I watched few videos on optimization techniques under Artificial Neural Networks

    • @jcorey333
      @jcorey333 2 місяці тому +6

      @@abhishekkurup technically, both are doing calculus optimizations 🤷‍♂️.

    • @a0fefd
      @a0fefd Місяць тому +1

      For me it was after watching projectile motion

  • @DDvargas123
    @DDvargas123 2 місяці тому +26

    Perhaps tossing it from lower than receiving height in order for the catch to occur closer to the apex of the parabola.
    But yea setting both heights equal would give that as optimum, good to see the math work out.

    • @MathTheWorld
      @MathTheWorld  2 місяці тому +10

      Thanks for sharing! If we had more time in the video, then looking to see how the height would change the velocity is a nice follow-up question. Maybe we can do that in a follow up video.

    • @atomgutan8064
      @atomgutan8064 2 місяці тому +1

      ​​​@@MathTheWorld Maybe write the velocity as a function of height and angle and then find where the gradient is 0 graphically. It would be really cool to see a 3d graph in a video of yours!

  • @wattox203
    @wattox203 2 місяці тому +18

    To optimize a perfect ball toss for your child, use a soft, lightweight ball that's easy to grip, choose a safe and open space, start at a close distance, and offer lots of encouragement and patience as they develop their skills.

    • @MathTheWorld
      @MathTheWorld  2 місяці тому +10

      Wonderful parenting advice! Probably more useful than our video.

  • @Hdtjdjbszh
    @Hdtjdjbszh 2 місяці тому +5

    Hah! It was so brilliant to see you work out that maths that every human instinctively knows. 45° -right in the middle.
    This was one of those "finding an answer vs brute force moments"
    This was an absolutely brilliant explanation of WHY.

    • @MathTheWorld
      @MathTheWorld  2 місяці тому +1

      Thanks! Yes, sometimes we do the math and find out when we get to the end that there is an easier/obvious solution. I didn't know it in this case though until I did the math. There are many situations where the optimal angle is not 45, but 60 or 120. degrees. Maybe I will do a video on those.

  • @IOSARBX
    @IOSARBX 2 місяці тому +4

    Math The World, awesome content bro

  • @pandicon3
    @pandicon3 2 місяці тому +3

    In both approaches (minimum velocity for given distance and maximum distance for given velocity) you end up with an expression containing cos(theta)sin(theta), which is 0.5*sin(2theta). So you don't even have to do any Calculus! :D To minimise the velocity, you want 0.5*sin(2theta) to be maximum, which happens when sin(2theta) is equal to 1, so at theta = 45°. Same goes for the maximum distance, there you once again want to maximise 0.5*sin(2theta). This especially helps in the first case :D

    • @MathTheWorld
      @MathTheWorld  2 місяці тому +2

      Thanks for sharing this! I actually use that strategy sometimes when I do this in class. Maybe I should have put that in the video as well. Thanks again!

    • @atomgutan8064
      @atomgutan8064 2 місяці тому

      Trig identities coming to the rescue! It is sometimes really useful and satisfying to turn a sin(x)cos(x) into sin(2x)/2 because sin(2x) is much easier to work with than sin(x)cos(x).

  • @AdityaMehendale
    @AdityaMehendale 2 місяці тому +2

    Extra points for the hydralisk!

    • @MathTheWorld
      @MathTheWorld  2 місяці тому

      Thanks! I didn't create it, but I am inspired by the person who did!

  • @jeremydavis3631
    @jeremydavis3631 Місяць тому +1

    I think I've spotted an error, although it happens to have no effect on the optimal angle. In the derivation around 4:30, you write that x(t) = 3. But that's 3 feet, and the equation for y uses 9.8 meters per second squared as the gravitational acceleration. You should either use 1 meter for x(t) or use 32 feet per second squared for the acceleration.
    Or, to earn a sticker for your nerd helmet, treat x(t) as an unknown constant and prove that its value doesn't affect the optimal angle. 😉

  • @alejo_324
    @alejo_324 2 місяці тому +1

    Great video! Very interesting too. It feels nice to be able to understand everything you did. I guess that's what the first semester of college does haha.
    BTW I think there's a mistake at 5:48, instead of pi/2 it should be pi/4, right?

  • @jcorey333
    @jcorey333 2 місяці тому +2

    I'm sure there's math involved in the velocity of the mallet hitting the marimba.
    I remember you talking about this forever ago. It's a rare father who can show his love by doing math lol.

    • @MathTheWorld
      @MathTheWorld  2 місяці тому +2

      Dang! I can't remember that. I must be getting old.

    • @alexschwartz4412
      @alexschwartz4412 2 місяці тому +1

      There's a lot of math within music itself. I'm the wrong person to ask to explain why, but something to do with how the sounds mix well at certain frequencies

  • @ksastrophy
    @ksastrophy Місяць тому

    Sin(Th)cos(Th) = ½sin(2Th), which is easier to find max or min.

  • @Petch85
    @Petch85 2 місяці тому +4

    Well....
    I somehow feel like it would be better to throw it a little higher than 45 deg. Yes the ball would move faster, but the kid would also have more time predicting where the ball will go.
    Also I feel like it is easier to catch a ball that falls vertical than a ball that flyes horizontal. And a steeper angle also helps with this.
    But how to find out if 55 deg or 75 deg are better than 45 deg?
    I guess we would have to test this on thousands of children 🤔. Someone should really get on that. Just think of all the dads and older brothers that are thouing balls at kids at random angles, without knowing the optimal angle. 😂

    • @MathTheWorld
      @MathTheWorld  2 місяці тому +3

      Great points. This is where math modeling can break down. When I made the assumption that "easiest to catch" would be "least velocity" then the math leads to one answer, but changing the assumption about what would be easiest to catch leads to a possibly different answer. In math modeling, we often start with basic assumptions (which lead to basic models) and see what we can learn before moving to more complex models. I think you are right with the idea that actual data could be used to improve on our results.

    • @Petch85
      @Petch85 2 місяці тому +2

      @@MathTheWorld Yes the assumptions dictates the solution. But as an engineer you will always start with a simple model and build up from there. There are lots to learn from simple models.
      But if we say low speed makes it easier and long time makes it easier, then we have to choose how we weight speed and time and then it is pretty clear that we choose what is "optimal" by choosing the weight between speed and time.
      And now the problem is what is the optimal weight and no math in the world can solve that problem 😂

  • @xandermylle2537
    @xandermylle2537 2 місяці тому +3

    No, throw the ball from infinitely far down but just hard enough so that it’s vertical velocity is zero when it reaches your sons hands, since it will take infinitely long to reach your son the horizontal velocity will be zero therefore even your son could catch it ;)

  • @kaaristotelancien3005
    @kaaristotelancien3005 2 місяці тому

    why Gravity Vector is divided by 2 ?

    • @yiannchrst
      @yiannchrst 2 місяці тому

      x=1/2gt^2

    • @ziiirozone
      @ziiirozone 2 місяці тому +2

      a = g thus v = t * g + v0 thus x = t^2 / 2 *g + t v0 + x0, it's because the integral of the integral of a constant is the constant multiplied by t^2

    • @kaaristotelancien3005
      @kaaristotelancien3005 2 місяці тому +1

      @@ziiirozone ahok, g is the second derivative of x

    • @ziiirozone
      @ziiirozone Місяць тому

      @@kaaristotelancien3005 exactly 👍

  • @esm_75
    @esm_75 Місяць тому

    It's a great and exciting channel, I hope my channel will reach this success.