carbocations and rearrangements

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  • Опубліковано 18 лис 2024

КОМЕНТАРІ • 41

  • @6x886
    @6x886 4 роки тому +3

    These people are real heroes. For making education free for all.

  • @johnmandrake8829
    @johnmandrake8829 8 років тому +19

    Mann..bless you for creating these vids and helping us all

  • @BallyBoy95
    @BallyBoy95 12 років тому +12

    Thank you sooooooooooo much!
    You saved me getting £25 for Chem Tuition just for this one topic lol. ;D
    Really helpful, great vid.

  • @crystalshanshuo
    @crystalshanshuo 12 років тому +8

    This is super helpful!!! Thank you for making it so clear! :D

  • @onlyvoocals
    @onlyvoocals 2 місяці тому +1

    What about reactivity of Carbocation?

  • @shaaa..n4263
    @shaaa..n4263 3 роки тому +2

    This helps me understand JEE BASICS . THANKS a lot 😍 Khan's acedemy

    • @ayushpandey8963
      @ayushpandey8963 11 місяців тому

      bhaha right , after completing the syllabus i just wanted to revisit everything in depth and this is the right content!

  • @ermiasbelachew9921
    @ermiasbelachew9921 3 роки тому +1

    thank you very much because I understood how rearrangement occurs and why

  • @ForgottenBathory7
    @ForgottenBathory7 8 років тому +4

    How do I choose between shifting the CH3 or the H in a particular molecule?Can I shift any of them all the time?

    • @jahanzebbutt8472
      @jahanzebbutt8472 8 років тому +2

      notice how in the example for the methyl shift he had a quaternary carbon which donated a methyl group to the Carbo cation but in the hydride shift he had a tertiary carbon which donated a hydride. just remember that a quaternary carbon has four CARBONS attached to it and a tertiary carbon has 3 CARBONS attached to it. so if we have a tertiary carbon then it will be bonded to 3 carbons and a hydrogen. if we have a quaternary carbon then there will be no hydride shift because there will be no hydrogens on the carbon due to the carbon already being bonded to 4 carbons. hope this helps

    • @poorasslawstudent
      @poorasslawstudent 7 років тому +3

      After an entire paragraph you never answered her question so I will: A tertiary carbon will donate its lone proton (H) before it donates one of its Me groups. That's all you had to say. I used to be against so many prereqs but it's like science majors don't know how to read & write.

    • @glom9995
      @glom9995 7 років тому +1

      R Foutz brutal

    • @PandaBearBeast
      @PandaBearBeast 7 років тому +4

      Honestly, when I was first learning this stuff I would have preferred their answer over yours because it's more detailed and helps you to visualize it. I'm assuming that you're a science major as well and that's great that you know how to read and write, but you don't have to act like an arrogant jerk and be rude to someone that was just trying to help.

    • @kevorkdanayan4791
      @kevorkdanayan4791 4 роки тому

      @@PandaBearBeast @r John 's answer is more to the point. that person called @Jahanzeb Butt didn't answer the question. He just explained the difference between a quaternary and a tertiary carbon. But the questions is whether a hydride or alkyl shift happens from a tertiary carbon to a carbon bearing the the formal charge.

  • @prameshwarlalsaini5872
    @prameshwarlalsaini5872 6 років тому

    sir I need so more examples stability of carbonation,carboantion
    and free redical.so,where I get this.
    tell me some kind of website and any book

  • @muhammadzubair7396
    @muhammadzubair7396 2 роки тому

    Thanks a bunch 🤩

  • @EXOL_1485
    @EXOL_1485 2 роки тому

    Thank you for this

  • @d3niseS
    @d3niseS 12 років тому +1

    so helpful! Thank you!

  • @Liquoricilicious
    @Liquoricilicious 9 років тому +1

    So will this always happen if it CAN happen in a mechanism?

    • @ManuAnand97
      @ManuAnand97 9 років тому +5

      Yes. Always. Various questions are formed on this concept where the student fails to identify the hydride & methyl shifts and form a wrong product.

  • @kavyagujjari9119
    @kavyagujjari9119 2 роки тому

    thank you so much!!

  • @poojapancholi5337
    @poojapancholi5337 8 років тому +1

    so helpful thank u so much

  • @thenomadicprofessor6696
    @thenomadicprofessor6696 7 років тому +1

    Do the shifts require energy?

    • @pawanprakash4131
      @pawanprakash4131 7 років тому

      yes, it requires Energy

    • @stargazer4023
      @stargazer4023 7 років тому

      Very little - the rearrangements are usually very rapid even when the reaction mixture is cooled below room temperature.

  • @Toronto2245
    @Toronto2245 10 років тому +1

    Bravo!

  • @Shenaz6
    @Shenaz6 10 років тому

    Very helpful, thank you.

  • @liang2201
    @liang2201 10 років тому

    good video. helpful. Thank you so much.

  • @TheElise1203
    @TheElise1203 12 років тому +3

    Great video! Was completely lost as to how to determine the rearrangement! Thanks!

  • @omageprosper9673
    @omageprosper9673 3 роки тому

    Pls how do we know when to do a methyl shift and when to do a hydride shift

  • @guneetkaur__
    @guneetkaur__ 4 роки тому

    Thnx

  • @parthjariwala6569
    @parthjariwala6569 4 роки тому

    so clutch

  • @adithyapatil4346
    @adithyapatil4346 3 роки тому

    ❤️❤️

  • @khaledragheb6503
    @khaledragheb6503 6 років тому

    Thanks but the shifts arent for as so im out betchessss.

  • @tatianaalanana5537
    @tatianaalanana5537 8 років тому

    thanks 😍😍😍😘😘😘😘😂😂

  • @p4blo90
    @p4blo90 8 років тому

    👏👍

  • @tteedghihh
    @tteedghihh 10 років тому +2

    I'm smarter than all of you. Just sayin.