@@notknown42 Actually no. To say a graph is Eulerian is to say the graph has an Euler tour. An euler tour exists only if every vertex has even degree. If the graph has 2 vertices of odd degree, then there exists an euler trail (open euler tour), but not an euler tour. Hope this helps.
This is the most clear explanation and well explained solution I found on internet.
yeah, indeed
yep
Hello, I am from Brazil, and your classes really helps me to understand the problem! Thank you.
Brazil will win Fifa wc 22 😊
thank you prof, you really explain those problems really good!
Best Lecture on this topic, thank you very much !!
excellent lecture..thanks for releasing lectures
Which is the name of the second algorithm? Thanks
Excellent presentation
Excellent Video
Is this problem needs to satisfy the triangle inequality ?
Wouldn't a graph be Eulerian if it had at most 2 vertices of odd degree?
Yes, would be a eulerian
@@notknown42 Actually no. To say a graph is Eulerian is to say the graph has an Euler tour. An euler tour exists only if every vertex has even degree. If the graph has 2 vertices of odd degree, then there exists an euler trail (open euler tour), but not an euler tour. Hope this helps.
Semi Eulerian
Thank you Sir
Woww😍
Thanks for the lesson! Excelente!
Good video but 115+215=330 not 340
Thanks,good video
was a bit slow and at 21:30 (stopped watching then) im sure it should say 330 not 340 but thanks anyway.
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