How To Verify Stefan's Law | Engineering Physics

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  • Опубліковано 10 лис 2024

КОМЕНТАРІ • 138

  • @abcxyz12321
    @abcxyz12321 3 роки тому +37

    Itna accha to College ka sir o nahi samjate hai , love u sir

    • @RohitGuptaPhysics
      @RohitGuptaPhysics  3 роки тому +7

      Thanku.....please subscribe and share 🙂

    • @abcxyz12321
      @abcxyz12321 3 роки тому +1

      @@RohitGuptaPhysics ok sir

    • @munnasah8140
      @munnasah8140 2 роки тому +1

      LogT and LogP kase nikla

    • @HELLO-td3do
      @HELLO-td3do 2 роки тому +2

      Bhai mere college ke sir ne bola apne aap padhkr aao fir apne aap kro practical... Bade ho gayer ho ab apne aap krne ki aadat dalo... Jb mene yr video dekhi muje lga kash ye sir mere teacher hote 😊

    • @RohitGuptaPhysics
      @RohitGuptaPhysics  2 роки тому

      From scientific calculator.

  • @aratrikchakrabarti3082
    @aratrikchakrabarti3082 Рік тому +11

    This really made my practical understanding easy. Very well explained. Thank you sir.❤️❤️

    • @RohitGuptaPhysics
      @RohitGuptaPhysics  Рік тому

      Welcome, your appreciation means a lot....please subscribe and share 😊

  • @anilchouhan5161
    @anilchouhan5161 2 роки тому +1

    Sir super btate asa bsc karte wha college me b ase nhi btate 🙏🙏aap ase hi mehnat krte rahiye hmara support h

  • @harshchauhan5360
    @harshchauhan5360 Рік тому +4

    Thank you so much , ak baari me sara samajh agya , bhagwan apko tarikki de ❤️

  • @vanshguleria9425
    @vanshguleria9425 Рік тому +2

    Wow . My head hurts because I read from a wrong file earlier and I was so confused .that file did not explain the Rg calculation corrctly . Thanks for clearing confusions

    • @RohitGuptaPhysics
      @RohitGuptaPhysics  Рік тому +1

      Thanku so much, your appreciation means a lot......please subscribe and share 😊

  • @sohaibazhar1
    @sohaibazhar1 2 роки тому +3

    Great video.
    From where can I find the table of "Rt/Rt0 vs temperature for tungsten filament"
    Kindly share the link.

    • @RohitGuptaPhysics
      @RohitGuptaPhysics  2 роки тому +2

      If I am not wrong, it relates to the thermistor property of a sensor.. and it varies based on the coefficient alpha based on the material of the sensor.. you just check on the internet about that thermistor material property. Most probably you will get these values.

  • @sulekhagupta4833
    @sulekhagupta4833 2 роки тому +5

    Sir could you please suggest which practical book you have used for this experiment. 😀 Nice video.

  • @intrepid18
    @intrepid18 6 місяців тому +2

    Sir , why did you dont wrote each value of I as a multiple of 10^-3 as its in milli ampere so to make dimensionally correct resistance as ohm we should convert it ?

    • @RohitGuptaPhysics
      @RohitGuptaPhysics  6 місяців тому +1

      In this kit, we got the voltmeter in volts and ammeter in ampere. So, no further conversion needed.

  • @snehapaul8365
    @snehapaul8365 Рік тому +2

    Sir graph se stefan constant ka value kaise nikale??? Actually humare syllabus main" to determine the value of stefan constant "hain

    • @RohitGuptaPhysics
      @RohitGuptaPhysics  Рік тому

      Antilog of y-intercept should be calculated for Stefan's constant.

    • @snehapaul8365
      @snehapaul8365 Рік тому +1

      @@RohitGuptaPhysics aapke graph main kitna hain y- intercept???

    • @RohitGuptaPhysics
      @RohitGuptaPhysics  Рік тому +1

      @@snehapaul8365 We didn't take the reading of y intercept here because of no need......You can calculate stefans constant in your experiment by using formula, Log P = Log (σES) + αLogT
      Where P = Power
      σ = Stefans Constant
      E = Emissivity of cathode surface
      S = Surface area of Cathode
      α = Slope from the graph
      T = Temperature

  • @tejaswipratap5340
    @tejaswipratap5340 2 роки тому +2

    this is called explanation............no words sir......just tnx

  • @SunainaGupta-kk4ve
    @SunainaGupta-kk4ve 10 місяців тому +1

    Excellent explanation sir. Thanks sir

  • @Shiv_prasad_46
    @Shiv_prasad_46 11 місяців тому +1

    Stephen laws clear you sir very thanks much for you

  • @swastikbiswas9579
    @swastikbiswas9579 Рік тому +6

    Extremely well explained sir!!!! Really made the experiment clear and easy to me !!❤️🙂

  • @lalitkonar4945
    @lalitkonar4945 Рік тому +2

    Sir when you explain to calculate K
    Then your ans is 789.7 for 3.9 (Rt/R○) but when i calculate for 3.9 then (100÷0.6)×0.1 = 14.666.... then 500+ 14.6666.... = 514.66
    Sir i don't understand my mistakes please explain me

    • @RohitGuptaPhysics
      @RohitGuptaPhysics  Рік тому +3

      Nothing is wrong......please convert the temperature from Celsius to Kelvin by adding 273.15

    • @lalitkonar4945
      @lalitkonar4945 Рік тому +1

      @@RohitGuptaPhysics yes..Now I understand 👍

  • @arghasreepalit24
    @arghasreepalit24 2 роки тому +1

    But sir Stefan constant ki observed value nikal ne ke liye woh formula pe log p and log t ka value kya hoigi ???
    Please help kijiye na sir

    • @RohitGuptaPhysics
      @RohitGuptaPhysics  2 роки тому

      Please watch the whole video then you will understand.

  • @abcxyz12321
    @abcxyz12321 3 роки тому +2

    Sir book may alpha bita se resistance ka relationship o konsa kam may aya ga ??
    Rt = 1+ at+bt² ea kon se kam ....??

    • @RohitGuptaPhysics
      @RohitGuptaPhysics  3 роки тому +2

      Normally we use this formula 👇
      R = R०[1 + a(T - T०)]
      Where,
      R = Conductor resistance at temperature “T”
      R०= Conductor resistance at reference temperature T०, usually 0°C.
      a = Temperature coefficient of resistance for conductor material.
      T = Conductor temperature in degrees.

    • @abcxyz12321
      @abcxyz12321 3 роки тому +1

      @@RohitGuptaPhysics ok sir

  • @intrepid18
    @intrepid18 Рік тому +2

    Very well explanation

  • @washimakram7381
    @washimakram7381 Рік тому +1

    Sir 273 ya 273.15 krenge plus?

  • @mr_affan15
    @mr_affan15 2 роки тому +2

    Thanks for table calculations

  • @AdityaSingh-uz1lj
    @AdityaSingh-uz1lj 2 роки тому +2

    Thank you very much but sir hamare college me to instruments me galvanometer aur miliammeter diye uska kya kaam h

    • @RohitGuptaPhysics
      @RohitGuptaPhysics  2 роки тому

      Milliammeter is ok and that galvanometer can be converted in to a voltmeter by connecting a high resistance in series connection within it.

    • @AdityaSingh-uz1lj
      @AdityaSingh-uz1lj 2 роки тому +1

      @@RohitGuptaPhysics oo

  • @Nxt_Jod_23
    @Nxt_Jod_23 Рік тому +2

    Thnx for so much help❤✌🏻

  • @sutapachakrobarty5272
    @sutapachakrobarty5272 Рік тому +1

    Thank you sir for beautiful explanation

  • @zehrafatima6030
    @zehrafatima6030 Рік тому +3

    How we taken log P and log T

    • @RohitGuptaPhysics
      @RohitGuptaPhysics  Рік тому

      I already explained.....Please watch the whole video to understand.

  • @aswhanibanerjee
    @aswhanibanerjee 2 роки тому +2

    The slope m I am getting 2.3 is it correct

  • @jyotirawat9344
    @jyotirawat9344 Рік тому +1

    Thank you so much sir great job 😊🧡but it's a request please don't use subtitles your voice is already clear its distracting me and many time incorrect

    • @RohitGuptaPhysics
      @RohitGuptaPhysics  Рік тому +1

      Thanks a lot, your appreciation matters to me 😊......UA-cam auto generated subtitles are not accurate.....you may turn off it by clicking cc button on the video.

    • @jyotirawat9344
      @jyotirawat9344 Рік тому +1

      @@RohitGuptaPhysics 😅😅thanks again sir

    • @RohitGuptaPhysics
      @RohitGuptaPhysics  Рік тому

      Welcome.....please subscribe and share 😊

  • @vanshchauhan9367
    @vanshchauhan9367 2 роки тому +1

    Sir, what is the EMF of the battery

    • @RohitGuptaPhysics
      @RohitGuptaPhysics  2 роки тому

      In this experiment, we used ac supply with voltage regulator in the kit.

  • @MDASIF-im9sn
    @MDASIF-im9sn 2 роки тому +1

    Thnku plz update more video on experiments

    • @RohitGuptaPhysics
      @RohitGuptaPhysics  2 роки тому

      Welcome.....please subscribe and share. Check this playlist 👇🏻
      Physics | भौतिकी: ua-cam.com/play/PLE9-jDkK-HyofhbEubFx7395dCTddAWnj.html

  • @Vns_girl
    @Vns_girl Рік тому +1

    Please explain Stefan's constant experiment 🙏

    • @RohitGuptaPhysics
      @RohitGuptaPhysics  Рік тому

      Antilog of y-intercept should be calculated for Stefan's constant.......You can calculate stefans constant in your experiment by using formula, Log P = Log (σES) + αLogT
      Where P = Power
      σ = Stefans Constant
      E = Emissivity of cathode surface
      S = Surface area of Cathode
      α = Slope from the graph
      T = Temperature

    • @Vns_girl
      @Vns_girl Рік тому +1

      @@RohitGuptaPhysics thanks

    • @RohitGuptaPhysics
      @RohitGuptaPhysics  Рік тому

      @@Vns_girl Welcome......please subscribe and share 😊

    • @saritadevi7072
      @saritadevi7072 Рік тому

      Sir how to calculate this.. can't understand plz help me out

    • @RohitGuptaPhysics
      @RohitGuptaPhysics  Рік тому

      @@saritadevi7072 Antilog of y-intercept should be calculated for Stefan's constant.......You can calculate stefans constant in your experiment by using formula, Log P = Log (σES) + αLogT
      Where P = Power
      σ = Stefans Constant
      E = Emissivity of cathode surface
      S = Surface area of Cathode
      α = Slope from the graph
      T = Temperature

  • @shashank.m.rdronepiolet4712
    @shashank.m.rdronepiolet4712 2 роки тому +1

    Tummorw my exam useful vedio thanks sir

    • @RohitGuptaPhysics
      @RohitGuptaPhysics  2 роки тому

      Welcome.....please subscribe and all the best for your exams👍🏻

  • @artistprudential
    @artistprudential Рік тому +1

    Thank you bhai 💞

  • @shalinichaudhary2690
    @shalinichaudhary2690 2 роки тому +2

    Very nice and good explanation 🙂🙂

  • @varshamalhotra813
    @varshamalhotra813 3 роки тому +3

    Thanks for this effort.

  • @vidhisood7661
    @vidhisood7661 2 роки тому +2

    Very well explained

  • @Sai_Dheeraj15
    @Sai_Dheeraj15 Місяць тому +1

    Thank you so much sir!! You saved my life sir, even a single subscribe is wont enough for you

  • @Idontnocrea
    @Idontnocrea 2 роки тому +1

    How we get logP and logT from graph for calculation????

    • @RohitGuptaPhysics
      @RohitGuptaPhysics  2 роки тому

      Please watch the whole video then you would come to know.

    • @Idontnocrea
      @Idontnocrea 2 роки тому

      Log P= log(€.sigma.s) +nlogt
      For calculate Stephen con how we get the value of logP and logT from graph for use this formula
      🙏 Please replay

    • @RohitGuptaPhysics
      @RohitGuptaPhysics  2 роки тому

      @@IdontnocreaIn the graph, antilog of intercept value in Log P (y-axis) is stefan's constant.

  • @soumyadipbanerjee6744
    @soumyadipbanerjee6744 2 роки тому +2

    Very nice explanation ❤️❤️

  • @adilsafi7424
    @adilsafi7424 2 роки тому +1

    Thankyou so much sir ❤️

  • @arvindkushwaha6927
    @arvindkushwaha6927 Рік тому +1

    Thanks sir 🙏🙏

  • @abcxyz12321
    @abcxyz12321 3 роки тому +1

    Thank you so much sir

  • @saritadevi7072
    @saritadevi7072 Рік тому

    Sir log P and Log 10 ka value kaise nikalenge

  • @intrepid18
    @intrepid18 Рік тому +2

    I got my answers

  • @kodikalapudi3855
    @kodikalapudi3855 Рік тому

    Sir please send experiment notes

  • @kaimurcollection2699
    @kaimurcollection2699 2 роки тому +1

    Thnku sir

  • @sujalpanchal7030
    @sujalpanchal7030 4 дні тому +1

    🎉🎉🎉

  • @tanishqgaming8601
    @tanishqgaming8601 2 роки тому

    smaj to nahi aya fir bhi mast

  • @physicslovers6046
    @physicslovers6046 2 роки тому

    First reading of voltage must be 0.625
    🧐

  • @kashishagarwal8191
    @kashishagarwal8191 2 роки тому +2

    I got slope 4.2

  • @abcxyz12321
    @abcxyz12321 3 роки тому +1

    ❤❤❤❤❤❤❤❤❤❤❤

  • @jaatcreations9554
    @jaatcreations9554 2 роки тому +1

    Weins law bhi isse he hota h

  • @devvratsahu282
    @devvratsahu282 Рік тому +1

    Thank you sir.....

  • @pushpendrapal8279
    @pushpendrapal8279 2 роки тому +1

    Thank you very much sir

  • @Aanya2020
    @Aanya2020 Рік тому +1

    Thanks sir

  • @debanjanpurkait2047
    @debanjanpurkait2047 Рік тому +1

    Thank you sir.

  • @sakshinagwan414
    @sakshinagwan414 Рік тому +1

    Thanku so much sir 😊

  • @rishavkumar_Pandit
    @rishavkumar_Pandit Рік тому +1

    Thanks sir

  • @AnchalSingh-to7pm
    @AnchalSingh-to7pm 6 місяців тому +1

    Thanks sir 🙏