Drawing and Interpreting a Histogram - ua-cam.com/video/Yo3oVsGzffY/v-deo.html All of Statistics in 30 minutes - ua-cam.com/video/UK3vRw1MKps/v-deo.html Everything you need for a grade 6-9 in your maths GCSE - ua-cam.com/video/o9VuZhCqR2U/v-deo.html If anyone would like to support the channel you can buy me a coffee here: www.buymeacoffee.com/gcsemathstutor New Discord Link: discord.gg/nRMtgr5AWA 👑 Check out the new shop here: the-gcse-maths-tutor.myspreadshop.co.uk/ Thank you for all of your support! 😁🙏🏼
i think you have a made a mistake in calculating the median because after adding all the values from frequency tables answer is 81 not 80 so our person will lie in 41 place not 40.5 . plz check and if i am wrong let me know
@@jamsi1066 its a method(formula - ((n+1)/2) )of finding the mean as if u add 1 u will gte the median try it on a list of numbers and you will understand what it means
you are right but i think he meant to keep the total frequency 80 but made a mistake and made it 81. so you are correct but he just went into auto pilot mode lol
Hello! i was wondering if your next video's can continue to cover the Edexcel IAS pure maths? you've blessed us with chap 1-3 and i was wondering if you can continue the rest of the chapters asap
Sure! I posted chapter 4 a few days ago and chapter 5 will be live this weekend! I also posted the entire AS Pure curriculum here: ua-cam.com/video/UiKVBshIOv4/v-deo.html warning: it’s 7 hours long! 😁🙏🏼
Hi sir! Thanks so much for the vid it really aided my understanding of the topic but (probably me being stupid) on the median question I got 81 not 80 as the total and therefore got 108.33333..... as an answer. Just wondering if I'm being daft or if it was just a small mistake in the video?
Hello TGMT, I'm a great fan of your videos. When a histogram question asks for an ESTIMATE of the median, should we ALWAYS follow the correct method by adding 1 to the frequency and dividing by 2? I've watched other GCSE maths videos covering histograms and some just go ahead and do a simple division (n/2) to find the median and 1/4 of n and 3/4 of n (instead of n+1) to find the lower and upper quartiles. Their argument is that the use of the word 'estimate' allows candidates to skip the formal approach....Would appreciate your comments. Certainly for some (maybe not all) exam boards, either approach appears to score the same marks.
@@zayankhattak7834 bro im gonna wake up at 6 and revise again, mans getting like 4 hrs of sleep 😭😭. But it'll be worth it, after today I dont have to do maths for a good few months, thats bless
half term revision did not go as planned and im here cramming for maths p2 which is tmrw (i went to comments to check if i wasnt going crazy bcs i got 81 instead of 80)
I'm now moved to a a more higher set in maths which is set 1. Ur the reason why i did well in my first maths assessment of year 10 before october half term. I used ur videos as revision. Thank u so much sir for everything. Keep on making awesome videos. When i'm doing GCSE exams and mock exams then i will use ur videos as revision. In year 7 i was in set 3 and in year 8 i was in set 2. Thank u so much sir 😁😁🙏
Wow that’s such incredible progress! It goes to show how much can be achieved when you put your mind to it and want it enough, keep going with your hard work you should be super proud of yourself! Please do keep in touch and let me know how you get on leading up to your exams 😁🙏🏼
I've never seen this thing before and never come across it in all the past papers I've already done (the median part). Is this GCSE maths (aqa higher)?
When AQA gives out the advance information for the GCSE Content this year, please may you make a video going through summaries of the topics in the higher exam, that would be really helpful.
@@yes-kc4mt my teacher always taught me not to add the 1 as this is grouped data and therefore an appoximation. My textbook also doesn't add it so if this comes up in a test I won't add it. Just ask your teacher if youre unsure though
this so use full I have an exam tomorrow and trust me I forgot how to do this so thanks all your vids are good you explain better than my school teacher
Hey to find the mean i did a faster a way i added the frequency divided it by which gives 40.5 i then did 40.5-29 which gives us 11.5. I then did 5/18*11.5 which gives us 3.194 I then add it on to 105 to give 108.194
for the question at 12:10 : - Find the upper quartile by adding 1 to the total frequency, dividing it by 4, then multiplying it by 3 = 18 - If we go 18 in => we reach the 25 and 30 bound section as (4+4+6+5 = 19) - The frequency for 25 and 30 is 5, when we reach it (4+4+6 = 14) we're at 14 - So we only go 4 more instead of using the full 5 - So this is 4/5 in aka 80%/0.8 - We multiply the difference of 25 and 30 (30-25=5) which is 5 by 0.8 which equals 4 - 25+4= 29 is the estimate for the upper quartile
Look up averages from a table. We don't have the exact value for the amount of cars with that stopping distance. So we use a midpoint of the class as an estimate to work out the total frequency which we can use to divide by the frequency.
Hi im from Namibia and i will be writing gcse maths next week and because of covid we missed more than 8 months of school and now im stressed because i need to understand all this material at once Any advice please
You can download my checklist on the website and just start working through each topic, hopefully you will find that a good proportion you will know and identify exactly which topics you need to work on! You could also look through my “entire gcse videos” and identify them that way too! Just get to work on as many topics as you can, make lots of notes, practice a few past papers and repeat this after you identify the topics you need to work on! Hope this helps 🙏🏼🙏🏼
Hi sir, for the median calculations, why do we need to add one to the total frequency? Since in another paper with histogram questions, the answer only used the total frequency/2 instead of frequency + 1 divided by 2 (Corbett maths paper)
The starting grounds of it for sure! I guess it’s in a similar fashion to how we do area under a curve at GCSE and how that then links into Integration at A level! 😁🙏🏼
i think he made a mistake adding it up because if you add the frequency it totals to 81. Then he should've added a 1 to the 81=82 then divide it by 2 = 41 and the median would've been the 41th value (then you continue from there). I think so
Are histograms a contrived thing to create GCSE questions? I never understood the point of them, they don't show anything in a simple way, you can't even read off relative amounts or even get a quick estimate since all the bars are different widths - What's the point of them.....
Yes it’s a new topic! Previously you just had to draw and interpret histograms which you can find in the description but under the new curriculum working out averages such as the median we’re added in new 😁🙏🏼
to find an estimate for the upper quartile, you divide the value by 4 then times it by 3 it would look like n+1/4 X 3 then follow the rest of the steps...
Drawing and Interpreting a Histogram - ua-cam.com/video/Yo3oVsGzffY/v-deo.html
All of Statistics in 30 minutes - ua-cam.com/video/UK3vRw1MKps/v-deo.html
Everything you need for a grade 6-9 in your maths GCSE - ua-cam.com/video/o9VuZhCqR2U/v-deo.html
If anyone would like to support the channel you can buy me a coffee here: www.buymeacoffee.com/gcsemathstutor
New Discord Link: discord.gg/nRMtgr5AWA 👑
Check out the new shop here: the-gcse-maths-tutor.myspreadshop.co.uk/
Thank you for all of your support! 😁🙏🏼
i think you have a made a mistake in calculating the median because after adding all the values from frequency tables answer is 81 not 80 so our person will lie in 41 place not 40.5 . plz check and if i am wrong let me know
You are such a blessing thank you for all of your hard work 😊
Thank you so much! 😁🙏🏼
In 6:15 the total count of frequency is 81 not 80 so if you add 1 it will be 82
why do u add 1
@@jamsi1066 its a method(formula - ((n+1)/2) )of finding the mean as if u add 1 u will gte the median try it on a list of numbers and you will understand what it means
you are right but i think he meant to keep the total frequency 80 but made a mistake and made it 81. so you are correct but he just went into auto pilot mode lol
lol i was thinking that but i thought i was wrong a does that affect the answer tho?
not since it was an estimate question
@@yaseen8827
I forgot to tell you I got an A in my Igsce you saved me completely You are the best tgmt
Hello! i was wondering if your next video's can continue to cover the Edexcel IAS pure maths? you've blessed us with chap 1-3 and i was wondering if you can continue the rest of the chapters asap
Sure! I posted chapter 4 a few days ago and chapter 5 will be live this weekend! I also posted the entire AS Pure curriculum here: ua-cam.com/video/UiKVBshIOv4/v-deo.html warning: it’s 7 hours long! 😁🙏🏼
@@TheGCSEMathsTutor thank you so much! your amazing
@@bbyrhf9319 No problem at all! Thank you for the kind words 😁🙏🏼
Hi sir! Thanks so much for the vid it really aided my understanding of the topic but (probably me being stupid) on the median question I got 81 not 80 as the total and therefore got 108.33333..... as an answer. Just wondering if I'm being daft or if it was just a small mistake in the video?
I got 81 too! i think he made a mistake adding them up :)
He made a mistake it’s 81
I got 108.3333 as well , is it correct though?
@@thepocketsofpolly145 I'm 3 months late but yes
Hello TGMT, I'm a great fan of your videos. When a histogram question asks for an ESTIMATE of the median, should we ALWAYS follow the correct method by adding 1 to the frequency and dividing by 2? I've watched other GCSE maths videos covering histograms and some just go ahead and do a simple division (n/2) to find the median and 1/4 of n and 3/4 of n (instead of n+1) to find the lower and upper quartiles. Their argument is that the use of the word 'estimate' allows candidates to skip the formal approach....Would appreciate your comments. Certainly for some (maybe not all) exam boards, either approach appears to score the same marks.
6:07 the total is meant to be 81
Yeah, so he was meant to do 81+1 divided by 2 which is 41. With that answer, his median should've been 108.3 recurring
@@Anyting9OnTopGrrr Yes and i see you're here revising for the exam in a few hrs too😭
@@zayankhattak7834 bro im gonna wake up at 6 and revise again, mans getting like 4 hrs of sleep 😭😭. But it'll be worth it, after today I dont have to do maths for a good few months, thats bless
@@Anyting9OnTopGrrrImma probs pull an all nighter and nap for an hr. Least u dont have business exam too today like me
@@zayankhattak7834 its 4AM FAM 4AM IM FUCKED
half term revision did not go as planned and im here cramming for maths p2 which is tmrw (i went to comments to check if i wasnt going crazy bcs i got 81 instead of 80)
I'm now moved to a a more higher set in maths which is set 1. Ur the reason why i did well in my first maths assessment of year 10 before october half term. I used ur videos as revision. Thank u so much sir for everything. Keep on making awesome videos. When i'm doing GCSE exams and mock exams then i will use ur videos as revision.
In year 7 i was in set 3 and in year 8 i was in set 2.
Thank u so much sir 😁😁🙏
Wow that’s such incredible progress! It goes to show how much can be achieved when you put your mind to it and want it enough, keep going with your hard work you should be super proud of yourself! Please do keep in touch and let me know how you get on leading up to your exams 😁🙏🏼
bro litch EXACT same thing w me
what did u get
FOR HOMEWORK I LITERALLY HAD THE SAME EXACT QUESTION FOR MEAN. thank you so much for this video!!!!
I've never seen this thing before and never come across it in all the past papers I've already done (the median part). Is this GCSE maths (aqa higher)?
When AQA gives out the advance information for the GCSE Content this year, please may you make a video going through summaries of the topics in the higher exam, that would be really helpful.
That’s the plan! 😁🙏🏼🙏🏼
@@TheGCSEMathsTutor edexcel too please
6:07 Total is 81 not 80.
This videos are so helpful, especially for mocks. You are a life saviour, thanks for the help with the engaging videos.
So glad you are enjoying them! Let me know how you get on 😁🙏🏼
hello, if they asked for the upper quartile would you treat it the same way as the lower one ?
Upper quartile would be 3/4
@@hjqp 3/4 of the total add up?
@@mymusicbook7364 so when you divide it by 4 the first time you would times it by 3 to get the upper quartile
total is 81 so median is 41 as you add 1 and my median is 108.3rd
I’m doing GCSE statistics, so surprised that they added Linear Interpolation to the GCSE Maths curriculum
Nobody cares
@@jasmingaming921 ?
@@jasmingaming921who hurt u
how would you find the upper quartile and the interquartile range?
upper quartile = 3/4 i think you then use the similar way used to work out LQ; not 100% sure though
What would you do for the upper quartile
Divide the total by 4/3 or just add the lower quartile to the median
I have a question here 14:36, why are we adding 1 to 23 to calculate the median?
Thank you
formula to find the median is (n + 1)/2
@@mahika21 MAHIKA STOP APPEARING EVERYWHERE WTF
@@mahika21 but this is grouped data so the median is just n/2
@@_epe2590 so do we add the 1 or not cuz I found another vid that didn't add 1, but this guy does
@@yes-kc4mt my teacher always taught me not to add the 1 as this is grouped data and therefore an appoximation. My textbook also doesn't add it so if this comes up in a test I won't add it. Just ask your teacher if youre unsure though
thanks so much finally understand
this so use full I have an exam tomorrow and trust me I forgot how to do this so thanks all your vids are good you explain better than my school teacher
So glad to hear it’s useful, best of luck on your exam let me know how it goes 🤞🏼 thank you for the kind words!
Hey to find the mean i did a faster a way i added the frequency divided it by which gives 40.5 i then did 40.5-29 which gives us 11.5. I then did 5/18*11.5 which gives us 3.194 I then add it on to 105 to give 108.194
Hi! i was just wondering how you would go about solving the upper quartile in a histogram? thanks :))
you find the lower quartile and times it by three
sence the lower quartile is 1/4 and the upper quartile is the 3/4
@@rerala9052 thats not how it works
for the question at 12:10 :
- Find the upper quartile by adding 1 to the total frequency, dividing it by 4, then multiplying it by 3 = 18
- If we go 18 in => we reach the 25 and 30 bound section as (4+4+6+5 = 19)
- The frequency for 25 and 30 is 5, when we reach it (4+4+6 = 14) we're at 14
- So we only go 4 more instead of using the full 5
- So this is 4/5 in aka 80%/0.8
- We multiply the difference of 25 and 30 (30-25=5) which is 5 by 0.8 which equals 4
- 25+4= 29 is the estimate for the upper quartile
@@chaska8144why do you always add 1 because ive seen other people solve these problems and they dont +1
how many marks approximately would this median question be please? :)
4 marks at least
Our teacher hasn't taught us this. Only drawing + interpreting histograms.
6:04 the frequency sum is 81 not 80
So is the median actually 41?
82/2 = 41
Do you get marks if you use the interpolation method from statistics gcse to calculate the averages
How do u find upper quartile ?
our teacher told us to not add 1 to find the position of the median for histograms or cumulative frequency graphs
In GCSE maths exams, when it has appeared, you have been allowed the marks for either approach 👍🏼
Hello sir, for the last question why did you find the midpoint instead of doing what you did for the previous question?
Look up averages from a table. We don't have the exact value for the amount of cars with that stopping distance. So we use a midpoint of the class as an estimate to work out the total frequency which we can use to divide by the frequency.
Hi im from Namibia and i will be writing gcse maths next week and because of covid we missed more than 8 months of school and now im stressed because i need to understand all this material at once
Any advice please
You can download my checklist on the website and just start working through each topic, hopefully you will find that a good proportion you will know and identify exactly which topics you need to work on! You could also look through my “entire gcse videos” and identify them that way too! Just get to work on as many topics as you can, make lots of notes, practice a few past papers and repeat this after you identify the topics you need to work on! Hope this helps 🙏🏼🙏🏼
@@TheGCSEMathsTutor okay thabk u so much love to all
@@marthamathew how'd it go?
Thank you so so so much !! This was really helpful and I actually understand exactly what to do now ❤
Do people doing AQA maths need to know this?
I’ll miss the intro song after gcses
6:12 You do realize that the sum of the frequencies is 81, not 80 - right?!
So the median would be the (81+1)/2= 82/2= 41st Number
Hi sir, for the median calculations, why do we need to add one to the total frequency? Since in another paper with histogram questions, the answer only used the total frequency/2 instead of frequency + 1 divided by 2 (Corbett maths paper)
Why did you add 1 while dividing it by 2 6:10
why do you add 1 when calculating mean / lower quartile?
17:27 Can we figure out what the upper quartile is, too?
18:22 Can't we use the expected value formula?
No.
Ok, why not? I thought that the expected value was the mean.
Damn, they’ve added linear interpolation into GCSE? 🤯
Well, still good for Stats and Mechanics at A-Level this video. Thanks!
The starting grounds of it for sure! I guess it’s in a similar fashion to how we do area under a curve at GCSE and how that then links into Integration at A level! 😁🙏🏼
may i ask why you added 1 to 80 before you divided it by 2
i think he made a mistake adding it up because if you add the frequency it totals to 81. Then he should've added a 1 to the 81=82 then divide it by 2 = 41 and the median would've been the 41th value (then you continue from there).
I think so
@@haneensuliman9399 correct
@@haneensuliman9399 that still doesn't explain why you do it though
@@t.p_yourhouse it's basically a way to find te midpoint. U always add one and divide by two to find the midpoint
How about the upper quartile ??
I don’t really understand here😰
Matrix 1:24
Are histograms a contrived thing to create GCSE questions? I never understood the point of them, they don't show anything in a simple way, you can't even read off relative amounts or even get a quick estimate since all the bars are different widths - What's the point of them.....
Hi, at 14:16 when calculating IQR why was cumulative freq not done before? would you not have done 2 over 8 opposed to 2 over 4 ?
sorry 16:14 not 14:16
what about IQR?
Man this is so hard
Thank you.
So for the higher quartile are we adding 1 to the total frequency and dividing that by 4 like the lower quartile?
Yeah or no??
no we:
- Add 1 to the toala frequency
- Divide it by 4
- Then multiply it by 3
This is the same thing as dividing the total frequency by 4/3
good stuff
Mate, there are 81 cars, not 80. How can 4 even numbers plus one odd equal an even number?
Will this be a topic that could come up in the 2022 GCSE Paper?
most likely, got my mock tommorow and this is in the mock
@@thegreatgojousatoru5846 Thanks for letting me know,
@@enlightenedsoul8897 btw im doing AQA dont know if it will be on the other exam boards
@@enlightenedsoul8897 Yes! It will definitely appear in Paper 3 !
You got the first mean estimate wrong its 112.5
why do you add 1 to the total frequency?
To find the midpoint. U add one and divide by two, like every time u do that
Why do we add 1 to an even number to get median?
why do you add one?
He made a mistake. You only add one if the number isn't even.
how many marks would these questions be worth?
4-5, there is only a couple of such questions but they make up like 20-30% of ur grade on that paper so it matters a lot
at 16:27 why do u have to do 5+5
hi this video was so helpful, do you mind explaining when you use n+1/2 or n/2 for the median is there a reason for the difference? thankyou!!
There is not
too hard
It's very easy
thank you!!
Anyone know what exam boards this covers?
edexcel i think
Is this a new GCSE topic
It’s not new no unfortunately it’s been around always in the specification!! It comes under types of charts in statistics!!
Yes it’s a new topic! Previously you just had to draw and interpret histograms which you can find in the description but under the new curriculum working out averages such as the median we’re added in new 😁🙏🏼
@@GCSEALevelMaths it is new 😁👍🏼
@@GCSEALevelMaths bro thought he was him
@@skerpy8145 😂
💀☠💀
Tough topic right.. 🫠
@@TheGCSEMathsTutor very much but I'm determined to understand it😔🧐
@@grim9970 you’ve got this 🫡
18:11
HI! Why do you have to add 1 to the total?
it is a rule
theres got to be an easier way to all this.
why did you divide 24 by 4 instead of 2?
Because it’s inter quartile range
Whatevwr the answer to that is you have to add it to median to get the upper q or you minus it from the number to let lower q
Maths paper 3 tmrw 😣😣
Paper 1 tomorrow 😭😭
@@jen_sen8508 good luck!! the relief once you finish the last paper is incomparable, regardless of how you think you’ve done
@@jen_sen8508 maths paper 2 tomorrow !!
how do you find the upper quartile using this method?
get your median by doing n+1/2 or n/2, then multiply that by (3/4). After that just carry on as normal
@@sangobhogal578 ahh thank you, what would you do for IQR?
@@embaaa2542 do the value you get for upper quartile - the value you get for lower quartile
@@sangobhogal578 what do you mean carry on as normal then just do class it lies on divided by then times by class width and add on class width?
@@aysen5061 exactly that yes
I have found it
to find an estimate for the upper quartile,
you divide the value by 4
then times it by 3
it would look like n+1/4 X 3
then follow the rest of the steps...
can i not find the mean by multiplying the mid point by the frequency then divide that by the total number of things
sigma fx divided by sigma x 💀
is this aqa or edexcel?