How to find derivative of arcsine x (sine inverse x) by first principles

[@cosmosXverse]

Very well explained.. I watch 5-6 vd on this topic. But this one is the the the best video. Thanks a lots sir ❤️❤️❤️

[@NumberX]

Thanks for your feedback.

[@erarvindverma4]

A reliable institute of success

[@holyshit922]

Using double angle identity we can reduce limit (1 - cos(h))/h to limit sin(h)/h
1 - cos(h) = cos^2(h/2)+sin^2(h/2) - (cos^2(h/2) - sin^2(h/2))
1 - cos(h) = 2sin^2(h/2)
So we have less limits to remember

[@nityanandmaurya5165]

Thanku sir ❤❤❤❤

[@gpratapkumarpatro2475]

Sir make videos like this.... it helps me alot and keep making videos on inverse of a function and difficult qs of I. F

[@NumberX]

Sure. Thanks.

[@jan-willemreens9010]

... The correct title is "How to find derivative of ..... by first principleS", instead of first principle. With "s"! Additionally I found your presentation very clear and well-structured, and last but not least very pleasant to watch! Thank you very much for your math efforts, Jan-W

[@NumberX]

Thanks for your valuable suggestions.

[@eleazaralmazan4089]

This is beautiful! Thank you very much!

[@Pure_Masculinity]

Absolutely amazing 👏

[@NumberX]

Thank you.

[@HeyKevinYT]

Very elegant process and good explanation 👍

[@NumberX]

Thanks a lot 😊

[@MdTauhid-iw1hd]

Very good

[@jhampatlaunda]

Great concept sir thanks

[@tophustler3616]

Why you assumed the range of y from -90° to 90°?

[@victormanuel3127]

Thanks very much

[@aaratigupta1282]

Very long

[@aaratigupta1282]

Use sinc _sind to short