Thanks for your words of appreciation Subscribe and Share my channel , I want to help as many students as I can so I request you to share my UA-cam channel as much as possible with your friends , classmates and everyone you know so that I can help them to score better in their exams.
BUYILE XOLILE Zulu I am happy to know that my videos are helping you, Please support my channel by sharing my channel with all your friends and everyone you know . Also Subscribe to my channel and click on bell icon so that you get notified immediately as soon as I upload any new video. Hit on like button it really motivated me to make more and more such video for YOU. Thanks
shubham:- Encryption of WORLD is ZRUOG sir first time i have seen this method and in a simplest way u explained each and every part of this topic TYSM for this explaination sir.
CR Numb Thanks for your words of appreciation Subscribe and Share my channel , I want to help as many students as I can so I request you to share my UA-cam channel as much as possible with your friends , classmates and everyone you know so that I can help them to score better in their exams.
Glad to hear that, I want my channel to reach every student so that I can help them to score better in their exams, so share my channel with your friends , classmates , and Subscribe and Click on bell icon so that you stay connected with me
I am glad to know that my UA-cam channel is helping you, help me to reach as many students as I can so that I can help as many students as I can to score better in their exams.
akshay bahadurkar I am happy to know that you are liking my UA-cam channel videos.Subscribe and Share my channel , I want to help as many students as I can so I request you to share my UA-cam channel as much as possible with your friends , classmates and everyone you know so that I can help them to score better in their exams.
Sapna Chirag Subscribe and Share my channel , I want to help as many students as I can so I request you to share my UA-cam channel as much as possible with your friends , classmates and everyone you know so that I can help them to score better in their exams.
Usama Awan I am happy to know that you are getting help from my youtube channel.Subscribe and Share my channel , I want to help as many students as I can so I request you to share my UA-cam channel as much as possible with your friends , classmates and everyone you know so that I can help them to score better in their exams.
No but soon I will upload videos, meanwhile stay connected by subscribing to my UA-cam channel and also click on Bell icon so that you can get notified whenever I upload video related to Fiestel Structure
mouli mlsn172 thanks for your words of appreciation, I want to reach more and more students like you and help them to score better in their exams so I request you to share my UA-cam channel with your friends, classmates and everyone you know so that I can help them. Thanks
Akash Kumar Please watch all other videos also in Information Security Playlist, there are many videos, soon I am going to upload more videos, Stay connected by subscribing to my UA-cam channel and click on bell icon so that you can get notified whenever I upload any new video, Share my channel with your classmates, friends and everyone you know so that I can help them to score better in their exams. Thanks
I am very happy to know that my videos are helping you, Support my channel by sharing my channel link to everyone you know, also tell them to subscribe and click on bell icon so that they get notifications whenever i upload any new video, I am sure you might have already subscribed to my channel, if not then subscribe it and also click on bell icon. Thanks
swm7f Thanks . I am happy to know that you are liking my videos.Subscribe and Share my channel , I want to help as many students as I can so I request you to share my UA-cam channel as much as possible with your friends , classmates and everyone you know so that I can help them to score better in their exams.
Rani Singh Happy to Help you, Subscribe and Share my channel , I want to help as many students as I can so I request you to share my UA-cam channel as much as possible with your friends , classmates and everyone you know so that I can help them to score better in their exams.
m bashir abdulhadi I am very happy to know that my channel is helping you, I also need your support to help my channel to reach maximum number of students in this world, so that they can also get benefit of my UA-cam channel, To support my channel Share my channel with all your friends and everyone you know, To get all the updates about my new videos Subscribe to my UA-cam channel SR COMPUTER EDUCATION and also click on the bell icon so that you get notified as soon as upload any new video, Thanks
ok, thank you sir I will do as you say but i want to have your java program tutorials if it is available, thank you once more from muhammad bashir abdulhadi
m bashir abdulhadi Thanks for sharing my videos, Java program tutorials will be uploaded after some time, rightnow my focus is on topics included in Security related subjects. Hit on the bell icon so that you can get notified whenever I upload any new video.
m bashir abdulhadi Absolutely right, share my videos with your classmates , friends and everyone you know so that they can also get help from UA-cam channel. See you soon with my next video
hey maria , I am happy to know that you liked my video, i am sure getting valuable information from youtube channel, i want to reach as many students as i can you can help me by sharing my videos and my channel link with your classmated and everyone you know so that i can help them to score better in their exams, also subscribe to my channel and click on bell icon so that you can get notified whenever i upload any new video. Thank you.
Nandam Neeraj I am sure my UA-cam channel is helping you to learn freely about Information Security subject, If you have not subscribed to my channel then I highly recommend you to subscribe to my channel and also click on bell icon so that you get notified whenever I upload any new video, I want my channel to reach every student like you so I request to share my channel with your friends , relatives and everyone you know so that they can also get benefit of my channel . If you liked my videos please hit like button it really motivates me to make more and more such useful and informative videos for YOU. Thanks
hi, why exactly are we using Mod ?? what help does mod does?? i know it gives us remainder but is it because z being the last alphabet with index 25, if we need to cipher x we would have done 23 + 3= 26, since there is nothing in the 26th place, we need to re-enter the loop starting from A . so 26 mod 26 gives us 0 which is index of A. I guess this is the only reason for A to start from 0 and the answer to why we use modulo method in this cipher............... is there any other reason then kindly explain??
anil kumar I am happy to know that you are liking my videos, I want to reach as many students as I can , so I request you to share my channel with your friends, classmates and everyone you know so that I can help them to score better in their exams . Subscribe to my channel and also click on bell icon so that you can get notified whenever I upload any new videos. Thanks
I am happy to know that you are liking my UA-cam channel .Subscribe and Share my channel , I want to help as many students as I can so I request you to share my UA-cam channel as much as possible with your friends , classmates and everyone you know so that I can help them to score better in their exams.
Maulik Prajapati 1)Caesar cipher Encryption of WORLD:ZRUOG Decryption of ZRUOG: WORLD 2)Vernum cipher Encryption of WORLD:JQSED Decryption of JQSED: WORLD 3)Vigenere cipher Encryption of HELLO:JEONO Decryption of JEONO:HELLO 4)Play fair cipher Encryption of COMPUTER: UNNLEACS Decryption of UNNLEACS:COMPUTER 5)Adjoint of 3*3 matrix -47:05 -99:05 -216:18 6)Rail fence Encryption of SECURITY:SCRTEUIY Decryption of SCRTEUIY:SECURITY 7)Rail fence 3 depth Encryption of WORLD HELLO:WDLOLHLORE decryption of WDLOLHLORE:WORLDHELLO
I am very much glad to hear from you that my videos are helping you. If you think my channel is helping then share my channel link among your friends in whatsapp and facebook group so that they can also get benefit of my channel. Stay Connected Stay Secured
I am happy to know that my channel is helping you, please share my channel with everyone you know so that i can reach maximum number of viewers. Thanks
key used is 3 in caesar cipher , to know which encryption is used can be known only through cryptanalysis. Share and Subscribe my UA-cam channel so that I can reach maximum number of students and help them to score better in their exams.
Cipher text for WORLD = ZRUOG Decryption for ABC is XYZ Where value of is A is already solved in the video The value for B is 1-3 = -2 mod 26 which is equal to 24 = Y And the value for C is 2-3 = -1 mod 26 which is equal to 25 = Z
zari sikander Thanks a lot for word of appreciation , Yes your answer for encryption of Caesar Cipher is absolutely correct . I am going to upload many useful videos in upcoming days , so to get notification of my new uploaded video , click on bell icon after subscribing to my channel, I want my videos to be viewed by every student like you so that they can also get benefit of my UA-cam channel , I request you to share my channel with your classmates, friends and everyone you know. Thanks
Thanks zari sikander , I am sure you will get lot of learning from my channel, I have playlist which includes videos about computer and Internet security I strongly recommend you to watch all videos so that you can remain secure online . Thanks
Nawdeep Sharma I am glad to know that you are liking my UA-cam channel video content.I am sure my UA-cam channel is helping you to learn freely about Information Security subject, If you have not subscribed to my channel then I highly recommend you to subscribe to my channel and also click on bell icon so that you get notified whenever I upload any new video, I want my channel to reach every student like you so I request to share my channel with your friends , relatives and everyone you know so that they can also get benefit of my channel . If like my videos please hit like button it really motivates me to make more and more such useful and informative videos for YOU. Thanks
Sahil Vig Subscribe and Share my channel with your classmates , friends and everyone you know so that I can reach maximum number of students and help them to score better in their exams. Thanks
Manuela Mag Yes usually its fixed Key =3 , but in exam if key is given then you have to take given key.Thanks for your words of appreciation Subscribe and Share my channel , I want to help as many students as I can so I request you to share my UA-cam channel as much as possible with your friends , classmates and everyone you know so that I can help them to score better in their exams.
Default key for Caesar is 3, but in many books you will find key value which may b different , you can take different key, actually that cipher is called Shift Cipher
I am happy to know that you are getting valuable information from my UA-cam channel, I want to reach as many students as I can and help them to score better in their exams, so I request to Subscribe and Share my UA-cam channel with everyone you know so that I can help them to score better in their exams.
Name : jansari srushti pravinkumar Hello sir I learnt about caesor cipher techniques : the encryption and the decryption techniques. I must say their is a understandable video sir Thank you for suggesting sir.
I am happy to know that you liked my video, i am sure getting valuable information from youtube channel, i want to reach as many students as i can you can help me by sharing my videos and my channel link with your classmates and everyone you know so that i can help them to score better in their exams, also subscribe to my channel and click on bell icon so that you can get notified whenever i upload any new video. Thank you. You can easliy get the answer to your question by completely watching my video again.
vasu m Please elaborate and explain your doubts properly again I am not able to understand what's your actual doubt. Subscribe and Share my channel , I want to help as many students as I can so I request you to share my UA-cam channel as much as possible with your friends , classmates and everyone you know so that I can help them to score better in their exams.
vyas bhakti Your answer is absolutely correct, If you think my UA-cam channel is helpful to you then I request you to Share my UA-cam channel with everyone you know so that I can reach maximum number of students and help them to score better in their exams.
Shreeyut Koirala Efficient way is the brute force attack, trying all possible 26 alphabets. If you think my channel is helping you then share my channel link among your friends in whatsapp and facebook group so that they can also get benefit of my channel. I strongly recommend you to watch my Ethical Hacking series videos, this videos will help you to be secured on the Internet from Hackers, share this videos with your family members , relatives and friends so that they can also stay secure on the Internet.
Rightnow I am covering comman topics which will be helpful for students to understand topics in clearly and easily, I will surely try to cover the topic you mentioned in near future. Stay Connected Stay Secured.
syed sabeer Subscribe and Share my channel with your classmates , friends and everyone you know so that I can reach maximum number of students and help them to score better in their exams. Thanks
The ciphertext Fn juu uxen lahycxpajyqh! has been generated with the Caesar cipher. Determine the key and the plaintext! So how can I find the key number ???
Az Durjoy Good Question , in this question you have to manually check each letter for example start with A =0 then B =1 ,when you get some proper readable and understandable plain text then you can confirm that substituted alphabet number is key
Az Durjoy There is no other way around , you have to check it manually , but by certain assumptions and guess you can come to solution easily, Watch my Monoalphabetic Cipher videos you will find solution for this question more quickly, I will be happy to help you if you have any doubts , Subscribe and Stay Connected
I am sure you will also like my other videos on my channel, Share it with your friends and relatives so that they can also get some useful informations
Pravin Tiwari I am happy to know that you are get help from UA-cam channel, I want to help as many student as possible, you can help me by sharing my channel with everyone you know. Soon many videos are going to be uploaded so SUBSCRIBE to my channel , and also click on bell icon so that you can notified whenever I upload any new video. Thanks
Thnank you so much for sharing and taking the time to explain. Do you know whar is the logic of descripting c=(15p+13)mod26... Where the answer is p=7c+13... How did they found p ?
ymazal mazal you have use mathematical concepts to solve this kind of problem, use linear algebra concepts.Subscribe and Share my channel , I want to help as many students as I can so I request you to share my UA-cam channel as much as possible with your friends , classmates and everyone you know so that I can help them to score better in their exams.
I am happy to hear that my videos are helping you, Share this UA-cam with everyone you know so that they can also get benefit of this channel. Hit Like button if you liked the video and share it as much as possible. Thank You
caesar me usually key=3 hota he, agr alg key hoga to exam me diya hoga. I am happy to know that you liked my video, i am sure getting valuable information from youtube channel, i want to reach as many students as i can you can help me by sharing my videos and my channel link with your classmates and everyone you know so that i can help them to score better in their exams, also subscribe to my channel and click on bell icon so that you can get notified whenever i upload any new video. Thank you.
Saima Khan Subscribe and Share my UA-cam Channel with your classmates , friends and everyone you know so that I can reach maximum number of students and help them to score better in their exams. Thanks
Pilot Nur I am glad to know that my UA-cam channel is helping you. Please subscribe to my channel and also click on bell icon so that you can get notified whenever I upload new video.I want to help as many students as I can so I request you to share my channel with your friends , classmates and everyone you know so that I can help them to score better in their exams.
Akash Shukla Thanks a lot , I am happy to know that my videos are helping you, i want my channel to reach each and every student like you, so i request you to share my channel with your Facebook friends, whatsapp group and everyone you know so that they can also learn from my UA-cam channel freely. Thanks
Amir Kazami I am happy to know that my UA-cam channel is helpful to you, You can support my channel by sharing my channel with everyone you know, so that they can also get benefit of my UA-cam channel . Thanks
Firoz bhai Kardar Thanks for your words of appreciation Subscribe and Share my channel , I want to help as many students as I can so I request you to share my UA-cam channel as much as possible with your friends , classmates and everyone you know so that I can help them to score better in their exams.
Subscribe and Share my channel , I want to help as many students as I can so I request you to share my UA-cam channel as much as possible with your friends , classmates and everyone you know so that I can help them to score better in their exams.
Goutham Nayaka Follow the instruction in my video you will be able to solve this question easily. Subscribe to my UA-cam channel to stay updated about my latest videos.
Jay Shah Yes I am going to upload it soon, meanwhile please share my videos with your friends, classmates and everyone you know so that I can reach maximum number of students and help them to score better in their exams. Thanks
+N Z B Royals I am glad to hear that you liked my video on ceaser, i am sure you will also like other videos on my like , watch them and if you have any doubt I will be happy to solve, Support my channel by sharing my channel link with your classmates and everyone else. Thank you , see you soon in next video
Decrypt of "vapgsw{yrggurqvorpnfg}" n the key is 13 Can I get the final Answer for dis sir plz...............I'll compare what I did is crrt or not can u plzzz answer dis sir plzzzzzz
key value is usually taken as 3 in Caesar cipher examples, it is default value, if some other value is given in exam take that value. Share and Subscribe to my UA-cam channel so that I can reach and help as many students as possible.
Q1. sir I have a doubt that while experimented with using a key higher than 26 on a Caesar cipher, I have had some very interesting results. That encryption works fine, but when I attempt to decrypt the encrypted message, I am unable to decrypt the message why sir??? Q2. On which base we choose the key please tell the reason how we get to know which key to use during the cipher encryption??? Ans : world=zruog We would like to say that you’re the best teacher we could ever have dreamed of studying with you. Thank you for your support and inspiration! FROM : VINEET MEHTA CE-5B 166330307120
janak kamble On your request I had upload Columnar Cipher video , watch it and if you have any doubt then let me know by commenting your question below that video so I can solve it . Share this video with your classmates and friends so that they can also clear all their doubts about columnar cipher encryption and decryption.
maham ali your answer is absolutely correct. Please subscribe to my channel and also click on bell icon so that you can get notified whenever I upload new video.I want to help as many students as I can so I request you to share my channel with your friends , classmates and everyone you know so that I can help them to score better in their exams.
Pooja A Please watch the video completely without skipping even a second, your question is already answered in the video. If you still have any doubt then let me know I would be happy to help you
Zayn Ch I had already explained this video, watch complete video, Subscribe and Share my channel with your classmates , friends and everyone you know so that I can reach maximum number of students and help them to score better in their exams. Thanks
Pritesh Patil This video has 31555 views and you are the first and the only one to say this, I had explained fundamentals of this technique which is the base for all other encryption technique.
Mohit Yadav I am glad to hear from you that my videos are helpful to you , If you are new to my channel then subscribe to my channel and also click on the bell icon so that you can get notified whenever I upload any new video , I am sure there are other students also who are in need of such useful and informative videos, so I request you to share this videos with everyone you know , this will help me to make my channel reachable to every student, so that they can also get benefit of my UA-cam channel.
Thank you so much, better than my university professor, cheers all the way from Australia
students need this type of explanation...tq sir hats off to you
Thanks for your words of appreciation
Subscribe and Share my channel , I want to help as many students as I can so I request you to share my UA-cam channel as much as possible with your friends , classmates and everyone you know so that I can help them to score better in their exams.
@@SRCOMPUTEREDUCATION sure sir tq
Thank you especially with negative value. Now I understand and will be writing my exam tomorrow with confidence.
BUYILE XOLILE Zulu I am happy to know that my videos are helping you, Please support my channel by sharing my channel with all your friends and everyone you know . Also Subscribe to my channel and click on bell icon so that you get notified immediately as soon as I upload any new video. Hit on like button it really motivated me to make more and more such video for YOU. Thanks
shubham:-
Encryption of WORLD is ZRUOG
sir first time i have seen this method and in a simplest way u explained each and every part of this topic TYSM for this explaination sir.
keep uploding this type of video sir...thankyou for this video
Thank you Sir for Explaining each of these clear and easy to understand :)
CR Numb Thanks for your words of appreciation
Subscribe and Share my channel , I want to help as many students as I can so I request you to share my UA-cam channel as much as possible with your friends , classmates and everyone you know so that I can help them to score better in their exams.
Diploma Sem 5 ke bad
Ab BE sem 7 me Vapis apka videos dekhne aya hu 😅🫶🙌👍
Great sir 🙏
Clear and understandable sir thank you
Glad to hear that, I want my channel to reach every student so that I can help them to score better in their exams, so share my channel with your friends , classmates , and Subscribe and Click on bell icon so that you stay connected with me
V good explanation thank you sooo much
I am glad to know that my UA-cam channel is helping you, help me to reach as many students as I can so that I can help as many students as I can to score better in their exams.
@@SRCOMPUTEREDUCATION can you please make a video on topic confusion and diffusion in network security along with solved example
if Caesar cipher technique is applied twice on the plaintext ( SECURITY) The key will be 6 right??
No its not like that key is fixed for caesar cipher , key is 3 , shift cipher is variation of caesar cipher in which you can take any key value
Encryption of WORLD = ZRUOG
THANK YOU SIR UPLOADING VIDEO TO UNDERSTANDING EASILY
IT 5 ADITYA PANCHAL
Dhruvpatel
1.)
Encryption:-
P=WORLD--c= ZRUOG
Decryption:-
ZRUOG===WORLD
2.)
P=dhruv c= gkuxy
Thank you sir 👍🏻
Ty so much sir for explaining in easiest way
akshay bahadurkar I am happy to know that you are liking my UA-cam channel videos.Subscribe and Share my channel , I want to help as many students as I can so I request you to share my UA-cam channel as much as possible with your friends , classmates and everyone you know so that I can help them to score better in their exams.
Well done! Great explanation good job
Sapna Chirag Subscribe and Share my channel , I want to help as many students as I can so I request you to share my UA-cam channel as much as possible with your friends , classmates and everyone you know so that I can help them to score better in their exams.
Great Sir ! It helped me alot to understand this concept
Usama Awan I am happy to know that you are getting help from my youtube channel.Subscribe and Share my channel , I want to help as many students as I can so I request you to share my UA-cam channel as much as possible with your friends , classmates and everyone you know so that I can help them to score better in their exams.
hi did you explain
Feistel Block Cipher Encryption?
No but soon I will upload videos, meanwhile stay connected by subscribing to my UA-cam channel and also click on Bell icon so that you can get notified whenever I upload video related to Fiestel Structure
Thank sir,u are awesome plz keep doing more
mouli mlsn172 thanks for your words of appreciation, I want to reach more and more students like you and help them to score better in their exams so I request you to share my UA-cam channel with your friends, classmates and everyone you know so that I can help them. Thanks
Very nice
Upload more about 5th sem security
Akash Kumar Please watch all other videos also in Information Security Playlist, there are many videos, soon I am going to upload more videos, Stay connected by subscribing to my UA-cam channel and click on bell icon so that you can get notified whenever I upload any new video, Share my channel with your classmates, friends and everyone you know so that I can help them to score better in their exams. Thanks
Good job sir. Keep it up.
I am very happy to know that my videos are helping you, Support my channel by sharing my channel link to everyone you know, also tell them to subscribe and click on bell icon so that they get notifications whenever i upload any new video, I am sure you might have already subscribed to my channel, if not then subscribe it and also click on bell icon. Thanks
you are the best
swm7f Thanks . I am happy to know that you are liking my videos.Subscribe and Share my channel , I want to help as many students as I can so I request you to share my UA-cam channel as much as possible with your friends , classmates and everyone you know so that I can help them to score better in their exams.
Superbbbbbbb lecture sir......
Rani Singh Happy to Help you, Subscribe and Share my channel , I want to help as many students as I can so I request you to share my UA-cam channel as much as possible with your friends , classmates and everyone you know so that I can help them to score better in their exams.
Encryption:- ZRUOG
Decryption:- WORLD
Thanks Sir.🙏
Well done sir, it is well explanatory.. thank you.
m bashir abdulhadi I am very happy to know that my channel is helping you, I also need your support to help my channel to reach maximum number of students in this world, so that they can also get benefit of my UA-cam channel, To support my channel Share my channel with all your friends and everyone you know, To get all the updates about my new videos Subscribe to my UA-cam channel SR COMPUTER EDUCATION and also click on the bell icon so that you get notified as soon as upload any new video, Thanks
ok, thank you sir I will do as you say but i want to have your java program tutorials if it is available, thank you once more from muhammad bashir abdulhadi
and the world is zruog
m bashir abdulhadi Thanks for sharing my videos, Java program tutorials will be uploaded after some time, rightnow my focus is on topics included in Security related subjects. Hit on the bell icon so that you can get notified whenever I upload any new video.
m bashir abdulhadi Absolutely right, share my videos with your classmates , friends and everyone you know so that they can also get help from UA-cam channel. See you soon with my next video
very clear very nice, thank you :)
hey maria , I am happy to know that you liked my video, i am sure getting valuable information from youtube channel, i want to reach as many students as i can you can help me by sharing my videos and my channel link with your classmated and everyone you know so that i can help them to score better in their exams, also subscribe to my channel and click on bell icon so that you can get notified whenever i upload any new video. Thank you.
super video to learn the concept
Thankyou
Nandam Neeraj I am sure my UA-cam channel is helping you to learn freely about Information Security subject, If you have not subscribed to my channel then I highly recommend you to subscribe to my channel and also click on bell icon so that you get notified whenever I upload any new video, I want my channel to reach every student like you so I request to share my channel with your friends , relatives and everyone you know so that they can also get benefit of my channel . If you liked my videos please hit like button it really motivates me to make more and more such useful and informative videos for YOU. Thanks
hi, why exactly are we using Mod ?? what help does mod does?? i know it gives us remainder but is it because z being the last alphabet with index 25, if we need to cipher x we would have done 23 + 3= 26, since there is nothing in the 26th place, we need to re-enter the loop starting from A . so 26 mod 26 gives us 0 which is index of A. I guess this is the only reason for A to start from 0 and the answer to why we use modulo method in this cipher............... is there any other reason then kindly explain??
Avi Roy , Yes you are absolutely correct, Share my UA-cam channel with everyone you know so that I can help them to score better in their exams
Thank you sir
Gud explanation thanq sooooo much
anil kumar I am happy to know that you are liking my videos, I want to reach as many students as I can , so I request you to share my channel with your friends, classmates and everyone you know so that I can help them to score better in their exams . Subscribe to my channel and also click on bell icon so that you can get notified whenever I upload any new videos. Thanks
very nice thank u sir
I am happy to know that you are liking my UA-cam channel .Subscribe and Share my channel , I want to help as many students as I can so I request you to share my UA-cam channel as much as possible with your friends , classmates and everyone you know so that I can help them to score better in their exams.
awesome sir.
Thank you sir, thank you so much
Saved my day sir.
I have been looking for the case when result is negative, nobody solve it except you.
THANK YOU MAN.
Maulik Prajapati
1)Caesar cipher
Encryption of WORLD:ZRUOG
Decryption of ZRUOG: WORLD
2)Vernum cipher
Encryption of WORLD:JQSED
Decryption of JQSED: WORLD
3)Vigenere cipher
Encryption of HELLO:JEONO
Decryption of JEONO:HELLO
4)Play fair cipher
Encryption of COMPUTER: UNNLEACS
Decryption of UNNLEACS:COMPUTER
5)Adjoint of 3*3 matrix
-47:05
-99:05
-216:18
6)Rail fence
Encryption of SECURITY:SCRTEUIY
Decryption of SCRTEUIY:SECURITY
7)Rail fence 3 depth
Encryption of WORLD HELLO:WDLOLHLORE
decryption of WDLOLHLORE:WORLDHELLO
thanks, it help me alot.
I am very much glad to hear from you that my videos are helping you.
If you think my channel is helping then share my channel link among your friends in whatsapp and facebook group so that they can also get benefit of my channel.
Stay Connected Stay Secured
I like you, great video bro
I am happy to know that my channel is helping you, please share my channel with everyone you know so that i can reach maximum number of viewers. Thanks
Now when you are given like MXLMRO, XLIVIJSVIMIBMWX and you are told key is less than 5 how do you solve this one
what is the given key?
@@SRCOMPUTEREDUCATION They said the key is less than 5
Then take key = 3
Thank you. What is the key is not known also how would you determine the type of encryption that was used that is transposition, caeser or xor?
key used is 3 in caesar cipher , to know which encryption is used can be known only through cryptanalysis. Share and Subscribe my UA-cam channel so that I can reach maximum number of students and help them to score better in their exams.
Cipher text for WORLD = ZRUOG
Decryption for ABC is XYZ
Where value of is A is already solved in the video
The value for B is 1-3 = -2 mod 26 which is equal to 24 = Y
And the value for C is 2-3 = -1 mod 26 which is equal to 25 = Z
Assalam O Alaikum!!!
Sir the "world" is encrypted into "ZRUOG".
your way of teaching is very eary to understand..
hope we will see more
zari sikander Thanks a lot for word of appreciation , Yes your answer for encryption of Caesar Cipher is absolutely correct . I am going to upload many useful videos in upcoming days , so to get notification of my new uploaded video , click on bell icon after subscribing to my channel, I want my videos to be viewed by every student like you so that they can also get benefit of my UA-cam channel , I request you to share my channel with your classmates, friends and everyone you know. Thanks
i have done this...thanks a lot
Thanks zari sikander , I am sure you will get lot of learning from my channel, I have playlist which includes videos about computer and Internet security I strongly recommend you to watch all videos so that you can remain secure online . Thanks
yeah sure
aMAZING eXPLANATION
Nawdeep Sharma I am glad to know that you are liking my UA-cam channel video content.I am sure my UA-cam channel is helping you to learn freely about Information Security subject, If you have not subscribed to my channel then I highly recommend you to subscribe to my channel and also click on bell icon so that you get notified whenever I upload any new video, I want my channel to reach every student like you so I request to share my channel with your friends , relatives and everyone you know so that they can also get benefit of my channel . If like my videos please hit like button it really motivates me to make more and more such useful and informative videos for YOU. Thanks
Bansi from CE 5A
Encryption of world =ZRUOG
It's interesting sir
Is it asks in example for exam ?
Hello sir, Yash is here
Encryption=zruog
Decription=world
Thank you bhaiya😊
Sahil Vig Subscribe and Share my channel with your classmates , friends and everyone you know so that I can reach maximum number of students and help them to score better in their exams. Thanks
hello, firstly i would like to thank you for your lesson. I have a question... Is the key always 3? If not, how it is chosen?
Manuela Mag Yes usually its fixed Key =3 , but in exam if key is given then you have to take given key.Thanks for your words of appreciation
Subscribe and Share my channel , I want to help as many students as I can so I request you to share my UA-cam channel as much as possible with your friends , classmates and everyone you know so that I can help them to score better in their exams.
@@SRCOMPUTEREDUCATION tell with viva point of view...if they ask if key is always 3 should I say yes or no???
Default key for Caesar is 3, but in many books you will find key value which may b different , you can take different key, actually that cipher is called Shift Cipher
good man
I am happy to know that you are getting valuable information from my UA-cam channel, I want to reach as many students as I can and help them to score better in their exams, so I request to Subscribe and Share my UA-cam channel with everyone you know so that I can help them to score better in their exams.
Name : jansari srushti pravinkumar
Hello sir
I learnt about caesor cipher techniques : the encryption and the decryption techniques. I must say their is a understandable video sir
Thank you for suggesting sir.
what is the cipher text of dead zone plsss replyy
I am happy to know that you liked my video, i am sure getting valuable information from youtube channel, i want to reach as many students as i can you can help me by sharing my videos and my channel link with your classmates and everyone you know so that i can help them to score better in their exams, also subscribe to my channel and click on bell icon so that you can get notified whenever i upload any new video. Thank you. You can easliy get the answer to your question by completely watching my video again.
sir i have a doubt our lecture teached 2nd method which u have if possible we can do that also or not plzz conform it
vasu m Please elaborate and explain your doubts properly again I am not able to understand what's your actual doubt. Subscribe and Share my channel , I want to help as many students as I can so I request you to share my UA-cam channel as much as possible with your friends , classmates and everyone you know so that I can help them to score better in their exams.
Hello world
khoor zruog
thank you sir
vyas bhakti Your answer is absolutely correct, If you think my UA-cam channel is helpful to you then I request you to Share my UA-cam channel with everyone you know so that I can reach maximum number of students and help them to score better in their exams.
except using force attack, how do you find the key of a cypher text that is very short and has words greater than 4 letters
can you make a very clear lesson on frequeeency analysis
Shreeyut Koirala Efficient way is the brute force attack, trying all possible 26 alphabets.
If you think my channel is helping you then share my channel link among your friends in whatsapp and facebook group so that they can also get benefit of my channel.
I strongly recommend you to watch my Ethical Hacking series videos, this videos will help you to be secured on the Internet from Hackers, share this videos with your family members , relatives and friends so that they can also stay secure on the Internet.
Rightnow I am covering comman topics which will be helpful for students to understand topics in clearly and easily, I will surely try to cover the topic you mentioned in near future.
Stay Connected Stay Secured.
Thank you! Sir
syed sabeer Subscribe and Share my channel with your classmates , friends and everyone you know so that I can reach maximum number of students and help them to score better in their exams. Thanks
The ciphertext Fn juu uxen lahycxpajyqh! has been generated with the Caesar cipher. Determine the key and the plaintext!
So how can I find the key number ???
Az Durjoy Good Question , in this question you have to manually check each letter for example start with A =0 then B =1 ,when you get some proper readable and understandable plain text then you can confirm that substituted alphabet number is key
@@SRCOMPUTEREDUCATION but it takes so long time. Is there any short calculation?
Az Durjoy There is no other way around , you have to check it manually , but by certain assumptions and guess you can come to solution easily, Watch my Monoalphabetic Cipher videos you will find solution for this question more quickly, I will be happy to help you if you have any doubts , Subscribe and Stay Connected
Name : : Jal Patel
Encryption : ZRUOG
Decryption : Computer
Thank you sir
Nice video
I am sure you will also like my other videos on my channel, Share it with your friends and relatives so that they can also get some useful informations
Thanku so much sir...we need a staff like u in our clg☺️
Pravin Tiwari I am happy to know that you are get help from UA-cam channel, I want to help as many student as possible, you can help me by sharing my channel with everyone you know. Soon many videos are going to be uploaded so SUBSCRIBE to my channel , and also click on bell icon so that you can notified whenever I upload any new video. Thanks
for , plain text=WORLD the cipher text is = ZRUOG
Caesar cipher is for decrypting the cipher text na?
No its not only decryption, caesar cipher is one algorithm used to encrypt and decrypt both.
Thnank you so much for sharing and taking the time to explain. Do you know whar is the logic of descripting c=(15p+13)mod26... Where the answer is p=7c+13... How did they found p ?
ymazal mazal you have use mathematical concepts to solve this kind of problem, use linear algebra concepts.Subscribe and Share my channel , I want to help as many students as I can so I request you to share my UA-cam channel as much as possible with your friends , classmates and everyone you know so that I can help them to score better in their exams.
Thank you!! 😁
I am happy to hear that my videos are helping you, Share this UA-cam with everyone you know so that they can also get benefit of this channel. Hit Like button if you liked the video and share it as much as possible.
Thank You
sir .key given hogi question m ya khud se leni h .. how to select a key?
caesar me usually key=3 hota he, agr alg key hoga to exam me diya hoga. I am happy to know that you liked my video, i am sure getting valuable information from youtube channel, i want to reach as many students as i can you can help me by sharing my videos and my channel link with your classmates and everyone you know so that i can help them to score better in their exams, also subscribe to my channel and click on bell icon so that you can get notified whenever i upload any new video. Thank you.
+SR COMPUTER EDUCATION thank u sir
sonam nader Meanwhile please share my UA-cam channels with your classmates and everyone you know so that I can help maximum number of students. Thanks
sir if we have C=7p+3 so what will
we do?
you cannot have value like this
Thank you sir :)
Saima Khan Subscribe and Share my UA-cam Channel with your classmates , friends and everyone you know so that I can reach maximum number of students and help them to score better in their exams. Thanks
Thanks bro
Pilot Nur I am glad to know that my UA-cam channel is helping you. Please subscribe to my channel and also click on bell icon so that you can get notified whenever I upload new video.I want to help as many students as I can so I request you to share my channel with your friends , classmates and everyone you know so that I can help them to score better in their exams.
very helpfull
Akash Shukla Thanks a lot , I am happy to know that my videos are helping you, i want my channel to reach each and every student like you, so i request you to share my channel with your Facebook friends, whatsapp group and everyone you know so that they can also learn from my UA-cam channel freely. Thanks
thank u so much
Amir Kazami I am happy to know that my UA-cam channel is helpful to you, You can support my channel by sharing my channel with everyone you know, so that they can also get benefit of my UA-cam channel . Thanks
CE5A jay desai
supperb explaination sir
tnku sir
Firoz bhai Kardar
Thanks for your words of appreciation
Subscribe and Share my channel , I want to help as many students as I can so I request you to share my UA-cam channel as much as possible with your friends , classmates and everyone you know so that I can help them to score better in their exams.
Sir gtu exam ni under badha alphabet mate method paper ma dekhadvi pdse keh ek alphabet mate dekhadine ne biju badha oraly kri daiye to marks kapse
Bdha btavana , bau var nai lage , calculation na marks hoy che, jo 2 mark ma puchay to direct lkhi sko
thanx sir
thnq sir
Subscribe and Share my channel , I want to help as many students as I can so I request you to share my UA-cam channel as much as possible with your friends , classmates and everyone you know so that I can help them to score better in their exams.
How to encrypt "8AM" when key=F using caeser cipher?
Goutham Nayaka Follow the instruction in my video you will be able to solve this question easily. Subscribe to my UA-cam channel to stay updated about my latest videos.
Sir please DES & AES ke bhi video banaie it is very important in BE.
Jay Shah Yes I am going to upload it soon, meanwhile please share my videos with your friends, classmates and everyone you know so that I can reach maximum number of students and help them to score better in their exams. Thanks
sohini patel
encryption:-
plain text=computer
key=3
chiper text=frpsxwhu
decryption:-
chiper text=frpsxwhu
key=3
plain text=computer
Super
+N Z B Royals I am glad to hear that you liked my video on ceaser, i am sure you will also like other videos on my like , watch them and if you have any doubt I will be happy to solve, Support my channel by sharing my channel link with your classmates and everyone else.
Thank you , see you soon in next video
Can you gave me notes pics
N Z B Royals I have not prepared any notes , but you make notes by watching my videos , r u a diploma or degree engineering student?
Decrypt of "vapgsw{yrggurqvorpnfg}" n the key is 13
Can I get the final Answer for dis sir plz...............I'll compare what I did is crrt or not can u plzzz answer dis sir plzzzzzz
Simple text (world)=ciphertext(Zruog)
Where is encryption and decryption system used nowdays
How will u find the key value plse tll me
key value is usually taken as 3 in Caesar cipher examples, it is default value, if some other value is given in exam take that value. Share and Subscribe to my UA-cam channel so that I can reach and help as many students as possible.
Very nice 👌👌👌👌👌👌👌👌 very nice explain 👌👌👌👌👌👌👌👌👌👌👌👌👌👌👌👌💻💻💻💻💯💯💯💯💯💯💯
Q1. sir I have a doubt that while experimented with using a key higher than 26 on a Caesar cipher, I have had some very interesting results. That encryption works fine, but when I attempt to decrypt the encrypted message, I am unable to decrypt the message why sir???
Q2. On which base we choose the key please tell the reason how we get to know which key to use during the cipher encryption???
Ans : world=zruog
We would like to say that you’re the best teacher we could ever have dreamed of studying with you. Thank you for your support and inspiration!
FROM : VINEET MEHTA
CE-5B
166330307120
Nisarg(512)The encryption of world is ZRUOG.Thank You.
ii. Simple Columnar Transposition Techniques with four columns. Order is 3,2,4,1
....
...
plz explain me sir
janak kamble I am going to upload Columnar Transposition video as soon as possible.
janak kamble On your request I had upload Columnar Cipher video , watch it and if you have any doubt then let me know by commenting your question below that video so I can solve it .
Share this video with your classmates and friends so that they can also clear all their doubts about columnar cipher encryption and decryption.
Thank you sir...
world=ZRUOG ? correct me if m wrong
maham ali your answer is absolutely correct. Please subscribe to my channel and also click on bell icon so that you can get notified whenever I upload new video.I want to help as many students as I can so I request you to share my channel with your friends , classmates and everyone you know so that I can help them to score better in their exams.
Name : jansari Srushti pravinkumar
I tried 2 example
1. P=World : c= ZRUOJ
2.P= Srushti : C= VUXVKWL
the encryption of "hello world" is "KHOOR ZRUOG" - Nandpal Mohit
How we got 14 by decrypting (10-15)mod 26
Pooja A Please watch the video completely without skipping even a second, your question is already answered in the video. If you still have any doubt then let me know I would be happy to help you
@@SRCOMPUTEREDUCATION sir this question is from my notes not in ur vedio could u tell me that how we got 14.i tried by ur way I got 21
Comment the exact question , I will definitely help you to get your doubts solved.
what if the key is 26 or higher?
Zayn Ch I had already explained this video, watch complete video, Subscribe and Share my channel with your classmates , friends and everyone you know so that I can reach maximum number of students and help them to score better in their exams. Thanks
Name: Nitav Antani
Encryption = ZRUOG
Decryption = WORLD
Thank you sir
hello sir Anjali here the encryption of hello world is khoor zruog
The concept is simple but you made it too complex !
Pritesh Patil This video has 31555 views and you are the first and the only one to say this, I had explained fundamentals of this technique which is the base for all other encryption technique.
I don't understand the xyz sum
Hello Sir ,
I am Bhavin Panchasara
WORLD
ENCRYPTION : ZRUOG
DECRYPTION: WORLD
Kishan Patel
Ce 5
Encryption :zruog
Decreption :world
Name: Thakor Nikita Ben Rameshji
I tried 2 example
1.p=world :c=ZRUOJ
2.p=Nikita :c=QLNLWD
Neel Shah
CE-5C
Encryption: ZRUOG
Decription: WORLD
Satyam darji
Encryption:zruog
Decryption:word
hello sir ,Mahima here
hello= khoor
world =zroug
Cipher text for WORLD is ZRUOG
Thank you very much sir
Mohit Yadav I am glad to hear from you that my videos are helpful to you , If you are new to my channel then subscribe to my channel and also click on the bell icon so that you can get notified whenever I upload any new video , I am sure there are other students also who are in need of such useful and informative videos, so I request you to share this videos with everyone you know , this will help me to make my channel reachable to every student, so that they can also get benefit of my UA-cam channel.