Image Formation By Convex lenses | Best Demonstration of All Cases | Physics | Grade 8-12

#convexlens#raydiagrams#Demonstrations
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Image Formation By Concave Mirror | Grade 7-12 | Physics Demonstration
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[@augijyotbali2131]

Best explanation sir, we don't need 3 hours lectures but lifetime understanding

[@patrickmburu3028]

It is best

[@revathiscsreekanth867]

Thank Sir, for the detailed explanation.. Much easier to understand with a practical demo... Timely help. 🙏

[@MakeMeScientific]

You are welcome

[@ASHISHKUMAR-hv3cl]

Really helpful for our practical 🙏🙏 😊 thanks so much 💗 sir ji 💗🙏🙏

[@CivilEngineeringForum]

this is the best youtube channel for physics

[@rujutakulkarni9961]

a perfect video to learn in a short period of time !!!!

[@kakarsabir9198]

What a great effort, Best explanation,more power to you🌹

[@MakeMeScientific]

Thanks a lot 😊

[@sciencepracticals1624]

Doing a great job for students. Good 👍

[@hetjoshi6014]

Sir Nice video.Very Nicely explained image formed by convex lense

[@ramakrishnatoopurani5157]

Best teach ever ❤❤

[@সত্যেরউন্মোচন-ন৪ম]

Thank you so much sir ❤️🙂☺️. This video is very useful for me. Thank you so much.lm from Bangladesh 🇧🇩🇧🇩🇧🇩🇧🇩

[@AvniDiwan-tu3wh]

This video was very helpful!! Thankyou so much.

[@binitanarayanmishra7917]

Sir thanks so much for the explanation , it was a lifeline for me in my practicals 😊

[@CivilEngineeringForum]

Superb demo
Thank you it was very useful

[@beardedbotanist8662]

thank you sir you are best teacher in the world

[@TQM237]

You're a called teacher ❤️

[@sikandar3192]

Thank you so much sir this help me a lot ☺️ for my exams 📚📖👌👍👍

[@nggameingdunia8154]

Best explanation sir
Saw 100s of video but didn't understand anything

[@MakeMeScientific]

Glad to hear that

[@aryanthakkkar2640]

Fabulously Made sir....30k soon

[@funnywithtalkingtom8938]

I had easily understood Sr ...Very thanks

[@devbratpaliwal1040]

Sir जब हम कोई rule पढ़ते हैं तो उसमें जो proportionality constant आता है उसकी value kese find ki jati hai

[@MakeMeScientific]

Thanks for watching the video. Most of the constants in physics are calculated by experiments like acceleration due to gravity constant is calculated by Simple pendulum method. G gravitational constant is calculated by Cavendish method

[@devbratpaliwal1040]

@@MakeMeScientific thank you sir

[@chakmadhunu6323]

Wow great explanation 🙂🙂

[@panneerselvam9279]

❤Great sir

[@cook4me818]

Nalla avatharanam

[@geofferyromany4634]

Thank you. Now to watch again.

[@RupinderKaur-jj2hq]

Bestest

[@amithaks7486]

Thank u so much so informative

[@nidhi.rathiii]

what we have to move? lens or screen?for different readings?

[@MakeMeScientific]

ua-cam.com/video/6ki0GmxoY6A/v-deo.html
please watch this

[@actiontoperfection13]

Please make more videos if possible it really helps

[@bikkikuriakose3557]

Here in the last case, the focal length was around 20 cm. What will happen if the lens is placed very closer to the screen?

[@MakeMeScientific]

Focal length always remain constant

[@sciencepracticals1624]

The image will be on the side of the object. It will be large and erect as shown. Remove screen and place your eye in the place of screen to see its image

[@sciencepracticals1624]

Well tried but 1.keep the object. Candle is the source of light
2. Screen should be upright perpendicular to the table

[@seetalaxmi4061]

You have to show the adjustment of the screen to get the image but not directly keeping the screen at that point

[@MakeMeScientific]

Ok
thanks for watching

[@IsaacNewton.]

Nice....wahi na....

[@trending1360]

There is an error by mistake (see 0:11) 5th point. It should be "Height measured below the principle axis is Negative "

[@MakeMeScientific]

Noted with thanks

[@rojigalla7925]

Thank u so much sir new here but understood

[@arya-qy7hc]

Kya ulta msg jane se brain pr frk pdega

[@MakeMeScientific]

Optic nerve carries signal to brain and brain converts it to straight image

[@shatoshia]

Tx it helped me

[@ChinmayJain-bq8yb]

outstanding experiment sir

[@MakeMeScientific]

Thank you! Cheers!

[@rashmipal96]

Sir your explanation is wonderful..

[@Scienceendeavour]

Very good demo

[@kartikey_pandey_bjym]

Thank you sir

[@kanvapatelamchi]

Thank you

[@skullcrush3r437]

I enjoyed 😅

[@suryanshsingh874]

Nice video

[@sabavaths5996]

Nice sir

[@ashishmj230]

what a big and beautiful house sir i think you are rich

[@MakeMeScientific]

Not at all dear. 550sq feet 2bhk

[@ashishmj230]

@@MakeMeScientific sir do you work on a school

[@soulgaming2471]

Op

[@whyyoulooking4944]

My real question is how to measure image length :)

[@MakeMeScientific]

You mean height of the image. It can be roughly measured with scale on screen. Or by applying magnification formula you can calculate
ua-cam.com/video/6ki0GmxoY6A/v-deo.html

[@omkargangwar5651]

If u=-10cm
F=-20cm
V=?
ACCORDING TO YOUR 1ST CASE

[@MakeMeScientific]

-6.66cm

[@noorfatimajamal2393]

Image of an Object at focal point should be virtual not real

[@MakeMeScientific]

Incorrect

[@noorfatimajamal2393]

In book “physics matters GCE o levels edition 4 , chap 12 , lenses , it is mentioned that object at focal point make virtual image however when I performed an experiment myself its not that way . Image formed is real.

[@Dhyaneshwar-um6ln]

If when placed at F1 the image is at infinity then what are we seeing at the screen?

[@MakeMeScientific]

Infinity means very long distance compared to the focal length of the lens so if the focal length is 10 cm a distance of 200 m can be considered as infinity

[@Dhyaneshwar-um6ln]

@@MakeMeScientific but the reflected rays seems to never meet!

[@vaishnavisoni4106]

Best explaining thankyou sir for this vedio

[@ashishjadhav8765]

Bhai ye 20cm convex lens kaha se kharide aur ha ye kitne ki aati hay

[@MakeMeScientific]

Amazoan se

[@Mika-d4h]

Nice

[@MakeMeScientific]

Thanks

[@recipesvideos1401]

Best explanation👍

[@MakeMeScientific]

Thank you 🙂

[@shivanishukla2155]

Nice video, but sir I have one doubt that will there be image formed in lens in every case without screen??

[@MakeMeScientific]

Yes it will but to see the image screen should be placed, or else the image will be in air and cant be seen by human eye

[@shivanishukla2155]

@@MakeMeScientific thank you sir 🙏