f'(x) drops degree of polynomial by 1 and removes the constant. So, x^5 and 64 come from f(x). Adding the middle terms, we get f(x) = x^5 + A x^4 + B x^3 + C x^2 + D x + 64 Only f(x) + f'(x) affect coefficient of x^4 = A x^4 + 5 x^4 = 0 therefore, A = -5, hence f(x) = x^5 - 5 x^4 + B x^3 + C x^2 + D x + 64 Next for coefficient B of x^3 in f(x) + f'(x) + f''(x), we get, 5.4 x^3 + 4A x^3 + B x^3 = 0 => B = -20 + 20 = 0, so no x^3 term in f(x) = x^5 - 5 x^4 + C x^2 + D x + 64 Next for coefficient C of x^2 in f(x) + f'(x) + f''(x), we get, 4.3.A x^2 + 3B x^2 + C = 0 => C = -12A = 60, leading to f(x) = x^5 - 5 x^4 + 60 x^2 + D x + 64 Next for coefficient D of x in f(x) + f'(x) + f''(x), we get, D x + 60 2x + 0 => D = -120, leading to f(x) = x^5 - 5 x^4 + 60 x^2 -120 x + 64 But f(1) = 1 - 5 + 60 -120 + 64 = 125 - 125 = 0, it's a 0/0 limit. So, f'(1)/(x-1)' = f'(1)/1 = f'(1) is the solution value of the limit. f'(x) = 5 x^4 - 20 x^3 +120 x - 120, so f'(1) = 5 - 20 + 120 - 120 = -15 *Answer* (1)
I also did this, it will take 5-6 minutes, the instructor came up with a solution that required less number of steps and calculation. But noticing that the equation is similar to a geometric sum and coming up with the instructor's solution itself probably takes more time.
Sir we can also see that the entire given expression has no other term other than x^5 So f(x) ka x^4 shld cancel with differentiation of x^5, so aise bhi solve kar sakte hai
@@Yyujbsingh1979 multiply numerator in 3rd step RHS by (1-D⁶). Since f is a fifth degree polynomial, that's same as multiplying it by 1. 1-D³ cancels out. You get (1-D)(1+D³)(x⁵+65). (1-D)(x⁵+65) = x⁵+65 - D(x⁵+65) = x⁵-5x⁴+64. Remember we are not multiplying anything by D here, things behave similar to multiplication but (1-D)(x⁵+65) is not multiplying (x⁵+65) by anything.
That's the good analysis of that fx at step 3 when you convert f triple dash x to a fn ,but sir is it valid for any polynomial whether the leading co efficient is not one??
Leading coefficient is definitely 1, as x^5 + 64 term is there in the question. And f triple dash (x) toh quadratic h so it doesnt affect leading coefficient of f(x)
questions questions questionsssssssssss , if every pyq of last 15 years is done , then do advanced , if advanced is done , to engineering 1st year , then 2nd year then 3rd year then 4th year then ms then phd then reserach and invent something learn coding shake ur ass
Degree of f is 5. So degree of f''' is 2. Look carefully at the below equation (he derived this in the video) f(x) = x⁵+5x⁴+64 + f'''(x) f'''(x) contributes nothing to the 5th, 4th and 3rd power terms on the RHS above (as it is a quadratic). This implies that the coefficient of x⁵ in f(x) is 1, coefficient of x⁴ in f(x) in -5 and the coefficient of x³ in f(x) is 0. To get f'''(x) you only need these 3 coefficients of f(x) (can you see why?).
sir same procedure hum 1st step mein: original equation ko differentaite karke f' f'' f''' mein ja sakte hai, phir jo aapne kiya woh karke direct f' nikal sakte hai f' = __ + ___ + ___ ... f'''' bana sakte hai, ye isliye kiya taki, ek step bach jaye, hame chahiye toh kaise bhi f' hi na LH rule se clear pata chal raha
mtlb ab google mea bhi GOD OF MATHEMATICS FOR IIT JEE SEARCH KRO TOAA HAMARE PYARE MOHIT TYAGI SIR KA NAME ATA HAI LOVE YOU SIR KYA MST SAMJAYA NTA WALO NEA SOCHA BHI NHI HOGA KI AISE BHI HO JAYEGA TURANT, 😂 LOVE YOU SIR❤
Sir i have solve Ms Chauhan book for organic chemistry for jee adv and have also clear my doubts for most of the doubt questions but sir among those 3000+ questions there i were some kind of 10-20 questions in which my doubts were not clear so sir should I solve the whole book again or just move on to coaching materials that is typically provided for jee adv after my mains please sir can you ask NS SIR and tell me😢🙏🙏
Dear Student, The 𝐏𝐫𝐚𝐯𝐞𝐞𝐧 𝐁𝐚𝐭𝐜𝐡 𝐟𝐨𝐫 𝐃𝐫𝐨𝐩𝐩𝐞𝐫𝐬 will be launched after the board exams. Please stay connected with us. As soon as it is launched, we will make an announcement. For more information and updates, feel free to contact us at +91 74109 00908 Thank you! Team Competishun
Aila Jaddu !! yeh to mujhe bhi samjh aagya itna easy se😁😁
"yeh to mujhe bhi samjh aagya" kehna kya chahte ho?
@@mandar_desai34 He is editor not a student
@@mandar_desai34 hes the editor but sir ka explanation itna accha tha unhe bhi samajh aaya
@Kookie437e Yes Ryt
f'(x) drops degree of polynomial by 1 and removes the constant. So, x^5 and 64 come from f(x). Adding the middle terms, we get f(x) = x^5 + A x^4 + B x^3 + C x^2 + D x + 64
Only f(x) + f'(x) affect coefficient of x^4 = A x^4 + 5 x^4 = 0 therefore, A = -5, hence f(x) = x^5 - 5 x^4 + B x^3 + C x^2 + D x + 64
Next for coefficient B of x^3 in f(x) + f'(x) + f''(x), we get, 5.4 x^3 + 4A x^3 + B x^3 = 0 => B = -20 + 20 = 0, so no x^3 term in f(x) = x^5 - 5 x^4 + C x^2 + D x + 64
Next for coefficient C of x^2 in f(x) + f'(x) + f''(x), we get, 4.3.A x^2 + 3B x^2 + C = 0 => C = -12A = 60, leading to f(x) = x^5 - 5 x^4 + 60 x^2 + D x + 64
Next for coefficient D of x in f(x) + f'(x) + f''(x), we get, D x + 60 2x + 0 => D = -120, leading to f(x) = x^5 - 5 x^4 + 60 x^2 -120 x + 64
But f(1) = 1 - 5 + 60 -120 + 64 = 125 - 125 = 0, it's a 0/0 limit. So, f'(1)/(x-1)' = f'(1)/1 = f'(1) is the solution value of the limit.
f'(x) = 5 x^4 - 20 x^3 +120 x - 120, so f'(1) = 5 - 20 + 120 - 120 = -15 *Answer* (1)
Beautiful. This is the right explanation.
I also did this, it will take 5-6 minutes, the instructor came up with a solution that required less number of steps and calculation.
But noticing that the equation is similar to a geometric sum and coming up with the instructor's solution itself probably takes more time.
Sir we can also see that the entire given expression has no other term other than x^5
So f(x) ka x^4 shld cancel with differentiation of x^5, so aise bhi solve kar sakte hai
Done but by coefficient wallah method🎉🎉🎉🎉
This is under aod+lcd
Sir please bring this type of videos for phys and chem
Super genius solution, These kind of lines of thinking given in the class separates Mohit sir from rest teachers
Goat
Operator method D = d/dx
(1+D+D^2) f = x^5+64
f = {1/(1 - D^3 } (1- D) (x^5+64)
f = (1+D^3)(x^5+64 - 5x^4)
f = (x^5 - 5x^4 +64)+D^3 (x^5 - 5x^4+64}
f = x^5 - 5x^4+64+60 x^2 - 120x
can u explain the last third line how did it become (1+d^3)?
Wow this is a very impressive approach to solving this entire class of problems using sum of Geometric series.
@@Yyujbsingh1979
multiply numerator in 3rd step RHS by (1-D⁶). Since f is a fifth degree polynomial, that's same as multiplying it by 1. 1-D³ cancels out. You get (1-D)(1+D³)(x⁵+65). (1-D)(x⁵+65) = x⁵+65 - D(x⁵+65) = x⁵-5x⁴+64.
Remember we are not multiplying anything by D here, things behave similar to multiplication but (1-D)(x⁵+65) is not multiplying (x⁵+65) by anything.
That's the good analysis of that fx at step 3 when you convert f triple dash x to a fn ,but sir is it valid for any polynomial whether the leading co efficient is not one??
Leading coefficient is definitely 1, as x^5 + 64 term is there in the question. And f triple dash (x) toh quadratic h so it doesnt affect leading coefficient of f(x)
खूबसूरत ❤
Sir what to do besides mocks in these 19 days?
I subscribed your channel bro
@@hrishikeshdas3390 i discontinued 2 years ago
questions questions questionsssssssssss , if every pyq of last 15 years is done , then do advanced , if advanced is done , to engineering 1st year , then 2nd year then 3rd year then 4th year then ms then phd then reserach and invent something learn coding shake ur ass
Eat and sleep peacefully
@saitama9733 My life is sorted now
He is an amazing teacher 🙏
You're Great Sir🙏🙏🙏
sir this is really helpful ...it would be great if you could continue this series...would really appreciate it
👍
Beautiful solution sir
supper kool,keep going Sir
Thanku sir is question ko long method se krta the pehle
Perfect maths teacher ! Still looking for a better solution !
nice solution sir
Thanks sir❤❤❤
Sir Lh rule can be applied only if it is 0/0 or infinity/infinity?
@@KarthikNT-ii1ik yes
it's used when 0/0 form is there
GOD OF MATHEMATICS
Sir i am little confused how did you just find f```(x) at last step . Could we really do like this
Question dekh usme highest power 5 hain to who fx ka term hoga
Aise smj ki sir ne f(x) vale eqn ko 3 baar diff kiya and since f'''(x) ek quad thi, 3 baar diff karne par vo vanish ho gyi and f'''(x) aa gaya on lhs
Esa samjho ki Fx ko 3baar aur diif kar toh f''''''x wala term aayega whoh toh 0 hoga then f'''x ka value nikal jayega
Degree of f is 5. So degree of f''' is 2.
Look carefully at the below equation (he derived this in the video)
f(x) = x⁵+5x⁴+64 + f'''(x)
f'''(x) contributes nothing to the 5th, 4th and 3rd power terms on the RHS above (as it is a quadratic). This implies that the coefficient of x⁵ in f(x) is 1, coefficient of x⁴ in f(x) in -5 and the coefficient of x³ in f(x) is 0. To get f'''(x) you only need these 3 coefficients of f(x) (can you see why?).
sir,please bring such type of short vedio
Beautiful
Wonderful sir...
Good trick sir❤
Wonderful
EXTREMELY beautiful......well i first tried the question myslef and did the lengthy way and thought i was doing it "beautifully" 😆
sir same procedure hum
1st step mein: original equation ko differentaite karke f' f'' f''' mein ja sakte hai, phir jo aapne kiya woh karke
direct f' nikal sakte hai
f' = __ + ___ + ___ ... f'''' bana sakte hai, ye isliye kiya taki, ek step bach jaye, hame chahiye toh kaise bhi f' hi na LH rule se clear pata chal raha
If Mathematics is a world, then our Mohit sir is God.❤❤❤😊😊😊
Impressive 😍
mtlb ab google mea bhi GOD OF MATHEMATICS FOR IIT JEE SEARCH KRO TOAA HAMARE PYARE MOHIT TYAGI SIR KA NAME ATA HAI LOVE YOU SIR KYA MST SAMJAYA NTA WALO NEA SOCHA BHI NHI HOGA KI AISE BHI HO JAYEGA TURANT, 😂 LOVE YOU SIR❤
Mein toh maths stream wala bhi nahi hu fir bhi samjh aa gaya 🙂
Well done sir
Sir i have solve Ms Chauhan book for organic chemistry for jee adv and have also clear my doubts for most of the doubt questions but sir among those 3000+ questions there i were some kind of 10-20 questions in which my doubts were not clear so sir should I solve the whole book again or just move on to coaching materials that is typically provided for jee adv after my mains please sir can you ask NS SIR and tell me😢🙏🙏
Thoda logically soch jo tu bol raha h😂
Yeh toh express solutions h 😅
Which chapter?
Limits and derivative
- of f'(1) hoga na?
to fir 15 aayega
Well explained sir ❤
Sir board exam ke bad
dropper online batch 2026 exam ke liye kab aeyaga
Dear Student,
The 𝐏𝐫𝐚𝐯𝐞𝐞𝐧 𝐁𝐚𝐭𝐜𝐡 𝐟𝐨𝐫 𝐃𝐫𝐨𝐩𝐩𝐞𝐫𝐬 will be launched after the board exams. Please stay connected with us. As soon as it is launched, we will make an announcement. For more information and updates, feel free to contact us at +91 74109 00908
Thank you!
Team Competishun
1st comment sir
It took me 15 to 20 min solve on my own
Solved it normally but it is too lengthy to do it in exam
Wow
#editor ye 2022 ka question hai 2023 ka nhi 😊
#askcompetishun sir make a video padne mein maan kaise lage
O bhaisahab
What a observation!!
Simply Marvelous
Sir when CATS 2 are launching?
Dear Student,
CATS-II batch will be launched after January. For more information, please feel free to contact us at 8888000021.
-Team Competishun
Arnab Goswami in parallel universe 😂
Sir cats 😢😢
God of mathematics 🫡
First comment
First