Mujhe pahle science achhi nhi lagti thi but jab se aapke video dekha hai padha hai mujhe science me specially physics me bahut interest aa rha hai . Thank you sir . Thank you WiFi study.
Neeraj sir u are the each Nd every question is solved easily Becs of Ur concepts ..u have explained such a fabulous way..I don't have words 4 it..questions are awesome
Bahut hi badiya tha sir...actually..maine late attend kiya sir classes..but ye revision se..smjh aa raha hai last moment ke liye ye better option hai..
U=14 hi hoga. Bcz displacement (-ve) nhi (×)hoga upper direction me. Velocity,displacement upper me(+ve) But downwards me both (-ve) hoga. But "MIND it" gravity both direction me(-ve) hoga.
Hw answer..... V= u + at... Initial u= 14 m/sec....and final velocity, v= 0....so Time= -u/-g ,-14/-9.8 = 1.42 g value negative because ..upward direction or Dawn ward direction , g value always negative....because of sign conversation..... Thank you sir...
Nice exploration (specially every option explain and discuss the concept at instant question) ..as compared to all wifi study teacher....... Thanku sir
Mujhe pahle science achhi nhi lagti thi but jab se aapke video dekha hai padha hai mujhe science me specially physics me bahut interest aa rha hai . Thank you sir . Thank you WiFi study.
Thank you very much sir.... Bahut badhiya padhate hai aap
Yes your class is very fruitful thanks sir for this class & best teaching way 👍👍👍👍👍👍👍
सर मैंने wifi study 4 दिन पहले ज्वाइन किया ,,सर बहुत जानकारी मिल रही है।सर बहुत बहुत धन्यवाद,,,,
Bahut aatcha laga sir ji
Neeraj sir u are the each Nd every question is solved easily Becs of Ur concepts ..u have explained such a fabulous way..I don't have words 4 it..questions are awesome
SHANDAAR, ZINDABAAD, JABARDAST CLASS NEERAJ SIR...KAFI KUCH YAAD AA GAYA JO PYSCHO TEST KI WAJAH SE BHOOL GYA THA....THANK YOU SO MUCH
Yes sir.. bahut maja aya..N kafi beneficial class h..Apka koi jawab nahi..Thanks wifi
Bahut hi badiya tha sir...actually..maine late attend kiya sir classes..but ye revision se..smjh aa raha hai last moment ke liye ye better option hai..
Very very....... Good class sir ji maja aa gaya all question ban gaye hai thank you so much 🙏🙏
Great Effort
Thank you Neeraj sir.... Bahut Acchi class rahi sir💞💞💞💞💞💞💞
Thank you wifi study for your hard work .... Really enjoyed this revision course...Plz continue..😊
Sir bahut badiya...ek num padhate ho..har chiz ko baar baar explain krte ho..thanks you sir
formula is v=u +at, v=0, u=-14,g=9.8 after solve ,t=1.42
H.W question solved by 2 types.
1st- v=u-gt
2nd- h=10m. Then h=ut-1/2gt^2
Sare concept yad aa rhe h thankq sir
H.w. ans v=u +at at highest point v=0 and u =-14 as body go upwards. And a =9.8 ans will be 1.42
U=14 hi hoga. Bcz displacement (-ve) nhi (×)hoga upper direction me.
Velocity,displacement upper me(+ve)
But downwards me both (-ve) hoga.
But "MIND it" gravity both direction me(-ve) hoga.
@@ShubhamVishwakarmaDANAV initial velocity 0 heh jb formula m put karoge toh -14 = 9.8t hoga
Yes, bro. I solve above.^ . Tx..
Thank you sir super session bahut kuch sikhne ko mila n bahut mza bhi aae 👍
Thanks sir for ur efforts & knownlege🙏🙏🙏🙏🙏🙏🙏
Thankyou sir..!
Loved this class.. you're great.
awesome👍👍👍👍👍👍
HW ans 1.43 sec... Maza aa gya sir... aese he qustns lattee rahiya...
Sir aap Bahut Achha badate Ho, because ur teaching skill are superb🎩
😁
👕👍Great!
👖
sir sare question & ans dil me bsa liye ☺☺☺
WiFi k sabhi team ko Mera namshkar .etni achhi choch k liyi 📝📝🙏🙏
Sir bahut jyada mazza aaya aur aab confidence v badh raha h thanks
Thanks q Niraj sir Bhut acha laga lec.
Sir super se uper hai ye class
Aap bahut acche paidte hai
Very nice
Sir ur explanation is awesome... Thnx for doing best 👍
21/21....धन्यवाद सर...आपके एक्सपलेशन का कोई जवाब नही.
Bahot mjja aaya sir..... thankuuu...
Sir ap se bdkr koi nhi mene sir apki puri som aur fm ki bhi class dekhi thi super sir jitni tarif kro km h
Hw answer..... V= u + at...
Initial u= 14 m/sec....and final velocity, v= 0....so
Time= -u/-g ,-14/-9.8 = 1.42
g value negative because ..upward direction or Dawn ward direction , g value always negative....because of sign conversation..... Thank you sir...
Thanks
बहुत मजा आया सर।thanks,। कोई भी चैप्टर मत छोड़िएगा।🙏🙏🙏🙏🙏
H.w answer v=u+at
U= -14, v=0
t= 1.42 second ans
14 not-14
Awesom class sir.......mja aa gya. Exam hone tk ese hi session lao physics ka 1 bi que miss nhi ho skta fir
Thank u sir
U are the best teacher for physics
Nice exploration (specially every option explain and discuss the concept at instant question) ..as compared to all wifi study teacher.......
Thanku sir
Class bhut achi thi ....thanks sir
Bilkul sir ese hi lage rahiye hum apke sath h
Sir esi type je video or banayiye plz
Neeraj sir Aapke bareme kahne ke liye शब्द nhi h u r great sir thank you so much
Total correct ; tq sir.....
Jbrdst......blast session rahta h aapka sir g
Hw-1.43sec
HW ANS v=u+at u=14m/s highest pt pe final velocity v=0 g=-10m/s^2 and is 1.4sec or when g=-9.8m/s^s ans is 1.42sec
Nice cls sir 👍👍👍👍👍✌✌✌✌
Class achh lag ra he or re call bi ho raha he thanks sir
Super energy aaya sir. Thank you
I love the way u teach..awesome session by Neeraj Sir.
this is honest online class....good work bro...
class bahot achi thi aade sahi nikle qution
Good knowledgeable lecture thank you so much
Thanking you sir , you are best teacher of physics love u
1.43
Super sir
hats off to you sir...
you're the heart and soul of wifistudy...
Tum Muslim ho
Bht achha lga class.....
Bhuut mza aaya sir ji🙏🙏🙏😎😎
Thanks you sir
Thanx sir its Helpful for me😊🙏
Shakshi Sharma kaisa hua exam
Sir Maja aa gya. You are real sir.
Bahut bdiya quetion h sir
Mza aa gya sir ji
Thank you sir,,,
Maja aa gya question karke,,,
Sir bhut badiya sir bhut maza aaya
Bahut achhi class thi sir
An-1.42 second
C
Sir ap ka Cina word bahut acha lgta hai
Best teacher of physics neerj sir..
Thank u sir..seriously bhut mjaaa aaya sir
Bahut mazaa aaya sir... 1 No
U=14m/s, v=0, a= - 9.8, t=?
V=u+at
t=14/9.8
ans= 1.43 sec
Bahut Maja aaya
Sir ji aapne bhut acha kraya mja aa gya question ka level bhi bhut acha tha sir ji class ka time change kra do pls 👍👍👍👍👍👍
Bahut badhiya sir
1.43 sec use law of motion Equation 14/9.8
मजा आ गया सर्
रोजाना ऐसे ही प्रश्न लाइये
answer is 1.42 sec from v=u+at .nice session sir thank you .
sir bahut achi class lagi
Thnx sir saare questions bn rhe h
Thank you very much sir ... Class bahut achi thi maza aa gya .HW ans 1.43
1.43 sec
V=u + at formula se aa jayega
bhahut achha sir
Bahut fayda huwa sir
Bohot Maja aaya sir
Thank you..
Answer 1.43 sec , u= 14 m/s , v= 0 , g = - 9.8 m/s2 , v = u + at
One of the best teacher.
Thnks sir.. Really nice class.
Sir very good explanation
Very nice sir...it's useful
Best teacher of WiFi study...
You have to solute sir and lv u sir
Fantastic class sir....
Thank you sir for the sessions
Superb sir thank you
Ur classes are very interesting.. N i really enjoy n learn at the same time... Thnku so much neeraj sir
thank you sir💐💐💐💐💐💐💐💐💐💐💐💐💐💐💐💐💐💐
thank you neeraj sir..
Sir mock test Dekha maine physics k bht easy questions h y level to CMA cbt2 k liye v h aadhe questions ISI s ho kayenge