Mujhe pahle science achhi nhi lagti thi but jab se aapke video dekha hai padha hai mujhe science me specially physics me bahut interest aa rha hai . Thank you sir . Thank you WiFi study.
Neeraj sir u are the each Nd every question is solved easily Becs of Ur concepts ..u have explained such a fabulous way..I don't have words 4 it..questions are awesome
Bahut hi badiya tha sir...actually..maine late attend kiya sir classes..but ye revision se..smjh aa raha hai last moment ke liye ye better option hai..
U=14 hi hoga. Bcz displacement (-ve) nhi (×)hoga upper direction me. Velocity,displacement upper me(+ve) But downwards me both (-ve) hoga. But "MIND it" gravity both direction me(-ve) hoga.
Hw answer..... V= u + at... Initial u= 14 m/sec....and final velocity, v= 0....so Time= -u/-g ,-14/-9.8 = 1.42 g value negative because ..upward direction or Dawn ward direction , g value always negative....because of sign conversation..... Thank you sir...
Nice exploration (specially every option explain and discuss the concept at instant question) ..as compared to all wifi study teacher....... Thanku sir
As per me it's best class of WiFi study , it's not mean other classes are not best but that's all are good . This class contains new numeric questions which I like 👌👌👍
Yes your class is very fruitful thanks sir for this class & best teaching way 👍👍👍👍👍👍👍
Mujhe pahle science achhi nhi lagti thi but jab se aapke video dekha hai padha hai mujhe science me specially physics me bahut interest aa rha hai . Thank you sir . Thank you WiFi study.
सर मैंने wifi study 4 दिन पहले ज्वाइन किया ,,सर बहुत जानकारी मिल रही है।सर बहुत बहुत धन्यवाद,,,,
Thank you Neeraj sir.... Bahut Acchi class rahi sir💞💞💞💞💞💞💞
SHANDAAR, ZINDABAAD, JABARDAST CLASS NEERAJ SIR...KAFI KUCH YAAD AA GAYA JO PYSCHO TEST KI WAJAH SE BHOOL GYA THA....THANK YOU SO MUCH
Neeraj sir u are the each Nd every question is solved easily Becs of Ur concepts ..u have explained such a fabulous way..I don't have words 4 it..questions are awesome
Thank you wifi study for your hard work .... Really enjoyed this revision course...Plz continue..😊
Sir aap Bahut Achha badate Ho, because ur teaching skill are superb🎩
😁
👕👍Great!
👖
Yes sir.. bahut maja aya..N kafi beneficial class h..Apka koi jawab nahi..Thanks wifi
Bahut hi badiya tha sir...actually..maine late attend kiya sir classes..but ye revision se..smjh aa raha hai last moment ke liye ye better option hai..
Thank you very much sir.... Bahut badhiya padhate hai aap
H.w. ans v=u +at at highest point v=0 and u =-14 as body go upwards. And a =9.8 ans will be 1.42
U=14 hi hoga. Bcz displacement (-ve) nhi (×)hoga upper direction me.
Velocity,displacement upper me(+ve)
But downwards me both (-ve) hoga.
But "MIND it" gravity both direction me(-ve) hoga.
@@ShubhamVishwakarmaDANAV initial velocity 0 heh jb formula m put karoge toh -14 = 9.8t hoga
Yes, bro. I solve above.^ . Tx..
बहुत मजा आया सर।thanks,। कोई भी चैप्टर मत छोड़िएगा।🙏🙏🙏🙏🙏
Very very....... Good class sir ji maja aa gaya all question ban gaye hai thank you so much 🙏🙏
Thankyou sir..!
Loved this class.. you're great.
formula is v=u +at, v=0, u=-14,g=9.8 after solve ,t=1.42
21/21....धन्यवाद सर...आपके एक्सपलेशन का कोई जवाब नही.
Sir bahut badiya...ek num padhate ho..har chiz ko baar baar explain krte ho..thanks you sir
Hw answer..... V= u + at...
Initial u= 14 m/sec....and final velocity, v= 0....so
Time= -u/-g ,-14/-9.8 = 1.42
g value negative because ..upward direction or Dawn ward direction , g value always negative....because of sign conversation..... Thank you sir...
HW ans 1.43 sec... Maza aa gya sir... aese he qustns lattee rahiya...
Bahut aatcha laga sir ji
H.W question solved by 2 types.
1st- v=u-gt
2nd- h=10m. Then h=ut-1/2gt^2
Thanks sir for ur efforts & knownlege🙏🙏🙏🙏🙏🙏🙏
H.w answer v=u+at
U= -14, v=0
t= 1.42 second ans
14 not-14
Sir ur explanation is awesome... Thnx for doing best 👍
WiFi k sabhi team ko Mera namshkar .etni achhi choch k liyi 📝📝🙏🙏
Sir ap se bdkr koi nhi mene sir apki puri som aur fm ki bhi class dekhi thi super sir jitni tarif kro km h
sir sare question & ans dil me bsa liye ☺☺☺
Awesom class sir.......mja aa gya. Exam hone tk ese hi session lao physics ka 1 bi que miss nhi ho skta fir
Sir bahut jyada mazza aaya aur aab confidence v badh raha h thanks
Thank u sir
U are the best teacher for physics
Nice exploration (specially every option explain and discuss the concept at instant question) ..as compared to all wifi study teacher.......
Thanku sir
Thank you sir super session bahut kuch sikhne ko mila n bahut mza bhi aae 👍
Sir super se uper hai ye class
Aap bahut acche paidte hai
Sare concept yad aa rhe h thankq sir
Bilkul sir ese hi lage rahiye hum apke sath h
Neeraj sir Aapke bareme kahne ke liye शब्द nhi h u r great sir thank you so much
Nice session sir thanku thanku thanku sir
hats off to you sir...
you're the heart and soul of wifistudy...
Tum Muslim ho
Jbrdst......blast session rahta h aapka sir g
Thank you very much sir ... Class bahut achi thi maza aa gya .HW ans 1.43
awesome👍👍👍👍👍👍
I love the way u teach..awesome session by Neeraj Sir.
Great Effort
As per me it's best class of WiFi study , it's not mean other classes are not best but that's all are good . This class contains new numeric questions which I like 👌👌👍
Thanx sir its Helpful for me😊🙏
Shakshi Sharma kaisa hua exam
1.43
Super sir
HW answer
t = 14/9.8 = 1.428 sec
Option ( B ) 👌👌👌
Thanks q Niraj sir Bhut acha laga lec.
Class achh lag ra he or re call bi ho raha he thanks sir
1.43 sec use law of motion Equation 14/9.8
HW ANS v=u+at u=14m/s highest pt pe final velocity v=0 g=-10m/s^2 and is 1.4sec or when g=-9.8m/s^s ans is 1.42sec
Thanking you sir , you are best teacher of physics love u
Nice cls sir 👍👍👍👍👍✌✌✌✌
Class bhut achi thi ....thanks sir
Ultimate sir ....Thoda km pdao sir Bht classes leni pd rhii h aajkl...Rest ni milta...
this is honest online class....good work bro...
You have to solute sir and lv u sir
Fantastic class sir....
Bahut achhi class thi sir
An-1.42 second
C
Total correct ; tq sir.....
Bhuut mza aaya sir ji🙏🙏🙏😎😎
Thank you sir,,,
Maja aa gya question karke,,,
class bahot achi thi aade sahi nikle qution
Mza aa gya sir ji
Sir Maja aa gya. You are real sir.
Aaj mene first time apki class li h ...I m really satisfied
Best teacher of physics neerj sir..
Bahot mjja aaya sir..... thankuuu...
Thanku so much sir...
U=14m/s, v=0, a= - 9.8, t=?
V=u+at
t=14/9.8
ans= 1.43 sec
Best teacher of WiFi study...
Bht achha lga class.....
Hw-1.43sec
Question on time 22:50
unit= watt×hour/1000 (kwh)
Or Amp.×volt×hour/1000 (kwh)
Sir ji aapne bhut acha kraya mja aa gya question ka level bhi bhut acha tha sir ji class ka time change kra do pls 👍👍👍👍👍👍
Bahut mazaa aaya sir... 1 No
20 out of 21 are correct thanks sir for quick revision
Hw 1.43
One of the best teacher.
Good knowledgeable lecture thank you so much
मजा आ गया सर्
रोजाना ऐसे ही प्रश्न लाइये
answer is 1.42 sec from v=u+at .nice session sir thank you .
Answer 1.43 sec , u= 14 m/s , v= 0 , g = - 9.8 m/s2 , v = u + at
1.43 Ans hoga HW question ka sir..becoz highest point pe V=0 ho jayega then t=14/9.8 equals to 1.43.
8 M ki bdhaiya team ko 🤗
Thank u sit
Super energy aaya sir. Thank you
20/21sir, nice session🙏🙏😂
Hw1 B) 1.43s
Thank u sir..seriously bhut mjaaa aaya sir
Sir esi type je video or banayiye plz
@wifistudy Sahil Sir, Neeraj Sir, Puneet Sir and Arun Sir are your best teachers.
My every question is *RIGHT*
Total correct sir g
Sir bhut badiya sir bhut maza aaya
Thanks you sir
sir bahut achi class lagi
excellent efforts sir..but sad to see some couple of dislikes even after this wonderful sessions
Bohot Maja aaya sir
Thank you..
thank you sir💐💐💐💐💐💐💐💐💐💐💐💐💐💐💐💐💐💐
Hw answer v=u+at, u=-14, v=0, a=9.8 then after putting all the value in formula ans t=1.42s
Bahut fayda huwa sir