Best SQL Mock Interview | SevenMentor Training

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[@pallavikumathekar6573]

Informative 👍

[@SevenMentor]

Thanks 🙂

[@bhagyashripatil1628]

Great 👍

[@SevenMentor]

Thank you 👍

[@KiranVerma-xf9dz]

Very Informative!

[@SevenMentor]

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[@abulhasanath1021]

Sound is not clear enough to understand everything,

[@SevenMentor]

ok

[@deepikakharola7470]

Nice information

[@SevenMentor]

Thank you for your Feedback.

[@sravansra-1845]

The background noise is so high that we cannot hear a clear voice.

[@deepaverma1919]

Good one!

[@SevenMentor]

Thank you for your Feedback.

[@Surekha_joshi]

Select* from employee
Order by salary;

[@SevenMentor]

ok

[@RahulBhosle-x9e]

great one

[@SevenMentor]

Thank you for your Feedback.

[@subhasmitapanda6254]

Wow it's great.

[@SevenMentor]

Thank you for your Feedback.

[@saurabhyevale7012]

Good one 👍👍👍

[@SevenMentor]

Thank you for your Feedback.

[@sahilmoraskar]

She has given wrong statement. (Show name having starting with r)
Select name from student where name like '%r';. (This is right statement)

[@SevenMentor]

ok

[@shrinivas126]

hi,
name starts with r
select * from student
where name like 'R%';
whatever you've given that holds for name ends with r

[@shubham_paliwal]

The correct query to fetch all the names starting with R is :-
SELECT name
FROM student
WHERE name LIKE "R%"
% is a wildcard which matches any number of characters after it, so we use r in the starting of the regex pattern.
Also, please note that by default, the LIKE operator in SQL is usually case-sensitive, so create the regex according to the type of case you have standardized for storing the names in the data, like Title Case, etc.
Thanks.

[@amansrivastava2691]

it 's great but its easy question

[@SevenMentor]

ok Thank You.

[@amalpeters]

Interview will be like this means ,so many peoples will be selected and got offer but real time interview is not like this.

[@SevenMentor]

ok

[@sbmori4913]

nice mam