Hi Partha, In the graph on the left the peak appears at shorter wavelengths. It is, therefore, at higher energy than the one on the right. Recall that a molecule captures a photon and tends to lose some of the energy before releasing it. Consequently, the emitted photon will be at lower energy and longer wavelengths than the photon that was absorbed. So, the curve on the left (at shorter wavelengths) is the excitation (or absorption) spectrum and the curve on the right is for the emission spectrum. (There is another mechanism that involves the arrangement of solvent around the molecule in the ground state and the excited state that causes the emitted photon to appear at longer wavelengths, but the trend is the same--the emission peak appears at longer wavelengths.)
@@garymabbott4064 Dear Dr Gary, Thank you so much. I recently switch to this field and this video and the explanation really helped me. I added you in Linkedin for future reference. Stay safe.
very nice and clear video, can you please make video for Kinetics too?
Hi, can you help me please
How can I use synchronous spectrum in this device?
Hi I have doubt. The last graph you got where the graphs are overlayed. Is the left one emission and right one is excitation? Please help
Hi Partha,
In the graph on the left the peak appears at shorter wavelengths. It is, therefore, at higher energy than the one on the right. Recall that a molecule captures a photon and tends to lose some of the energy before releasing it. Consequently, the emitted photon will be at lower energy and longer wavelengths than the photon that was absorbed. So, the curve on the left (at shorter wavelengths) is the excitation (or absorption) spectrum and the curve on the right is for the emission spectrum. (There is another mechanism that involves the arrangement of solvent around the molecule in the ground state and the excited state that causes the emitted photon to appear at longer wavelengths, but the trend is the same--the emission peak appears at longer wavelengths.)
@@garymabbott4064 Dear Dr Gary, Thank you so much. I recently switch to this field and this video and the explanation really helped me. I added you in Linkedin for future reference. Stay safe.
@UCYeHob4LdDaJ18vMkdaZozg
I'm sorry, but I retired recently. I don't have any plans to make any more videos on fluorescence.