Big Data Interview | Mock | Problem Solving | Technical Round | Pyspark , SQL
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1.1st qstn, the join condition should be like
ON e.manager_id = m.id
WHERE e.sal > m.sal
So you can match the manager id first nd check for the manager's id coming as emp id which will give the proper answer i gss
2. Also 2nd qstn we can do
order by count(ord_no) desc limit 1
Which will fetch the cust no who placed largest no.of orders in general
Correct me if I'm wrong
Dear team..missing your videos of mock interview..pls do upload ❤
I think the join condition in the solution for the first question should be employee(e1).managerid = employee(e2).id.
correct
In real life coalesce is used while writing/saving the data in storage location in single partion while repartition is used to achieve parallelism that will use worker node properly
GroupByKey and reduceByKey both used on rdd level
As per me, we can do the second question with below :
with t1 as (
select customer_number,count(*) as count from orders group by customer_number)
select t1.customer_number from t1 where t1.count = (select max(count) from t1)
first one
Select name from salary_table as a where salary>(select salary from salary_table where id =a.managerid)
not cool second sql question answer is wrong and if interview went wrong at least you can put the correct answe at the end of video this will help full for others it is not like just posting the thing.
1st question ans is wrong. i guess
This is not upto the mark interview. Answers are wrong for sql query.
Is this the standard difficulty of questions? I'm almost a fresher and trying for first switch. And it doesn't seems right as question are pretty easy.
Hi Brother currently I am doing job in TCS and i am BCA graduate and I am thinking that after I will complete 2 year in tcs I will take Leave without pay for 2 year and I will do Full time MCA. Its that right way I am going or wrong way . Please suggest me what to do or esle I will go with Part time MCA ??
with c as(select e.*,m.salary as manager_salary,m.name as manager_name
from employees_prac e left join employees_prac m
on e.managerid=m.id where e.salary-m.salary>0)
select name from c;
My solution