Painted Cubes II How Many Faces Painted? II Cubes Painted & Cut II Rule to Solve All Cube Problems

[@chhatarpurbranch2676]

Short , sweet and to the point.

[@anangel-y3x]

good simple explanation. Thank you

[@pmakatikun]

preparing for ntse this helped me a lot thnks a lot

[@ultronxx8166]

nice teaching love u sir

[@pavanpujari2307]

Very very very very very very very very fantastic

[@lakshya_13]

nice

[@RiteshRandhir13]

This is super helpful, Sir. Thank you very much.

[@avyaan-aaryahisandeepjajaw4743]

Very nice concept n trick ..thanks sir

[@sumitroy003]

Just outstanding sir, cleared all my doubts

[@harikabunnyharikabunny2923]

Please explain this question a solid cube of 4 inches has been painted red green black one pair of opposite faces it has been then cut into 1 inch cubes questions
1) how many cubes have no faces painted
2) how many cubes have three faces painted
3)how many cubes have only four faces painted
4) how many cubes have only one face painted
Please say like these problems and say answer sir

[@athulk7626]

1) 8
2) 8
3) 0
4) 24

[@shouryagoyal3314]

Jo formula btaya h usi se karna h, n=4 hoga iss case me

[@Shiv-cj9cv]

It helped me to solve SSC-CGL previous year questions 🙏🙏 thankyou

[@kalaicheluva8850]

Simple and clear....

[@sumitsrivastava3685]

great explanation sir......thank u

[@nandininandini4136]

It is very helpful sir 👍

[@chaitalimehta8439]

very helpful... Thank you sir

[@chow3439]

It was helpful

[@soumil5065]

343 cubes of similar size are arranged in a form of bigger cube abd kept at the cornor of a room, all the exposed sides are painted then how many cubes have atleast 2 sides painted?

[@stormplayzop223]

Thank you sir, this video is very helpful.

[@saurabhsinghjadaun5172]

Thankyou sir. Can add
Number of total cuts=(N-1)×3
Number of surfaces painted four side =0 as these types of questions also have been asked in some exams 👍

[@jairadhamadhav21]

Your starting was very good about the concept of cutting along the length .. this was not told by any teacher in any video

[@jamunavenkatesh4921]

Excellent sir!!

[@سارا-ف7ي]

thank youuuuu🌸🌸

[@preetisingh1874]

Nicely explained

[@saurabhchoudhary5142]

Very nice concept... Thank you Sir

[@sandunigunasekara2012]

Thank u very much sir. I m from Sri Lanka.

[@rajnishkaur8736]

Very helpful video

[@akaSuri15]

Thanks a lot sir 😄...I hope this will help me in CUET UG

[@MUKESHKUMAR-pc7mv]

Very very helpful ☺️👍

[@pardhupuli6099]

Good class❤

[@randomstuff7764]

Whose here because of online classes

[@gift537]

Thank you Sir it was very helpful but how did you work out the formula?

[@AmitYadav-mr6dc]

Who's here after recommended by The Pundits?

[@Anilkumar-iv7oh]

Really glorious. Sir

[@desifauzi-oz8ol]

One vedio lecture and all doubts are cleared
Teacher always must be like SURESH SIR
Wonderful explanation in short time......👌👌👌

[@sureshaggarwal]

Thanks a lot for the kind words

[@vivekagrawal6375]

Awesome sir ...❤️

[@learningdirections2577]

There is not a single doubt left when I watch your video sir….. you are really my mentor…. Thanks for sharing amazing ideas with students👏🏻👏🏻👏🏻👏🏻👏🏻👏🏻👏🏻👏🏻👏🏻👏🏻👏🏻👏🏻👏🏻👏🏻👏🏻

[@Ashish-2874]

👍

[@sahithisarvani1214]

Very helpful..thank u

[@GagandeepKaur-do2rq]

thanku so much sir...best explanation 👌🙏

[@amitv.l.s7305]

Thank you sir It was very helpful for my aptitude exams😊😊😊😊

[@adventureadda7953]

Well explained sir👏

[@arushibasotra8461]

Very helpful

[@mansichauhan8724]

Very good explanation 👍🙏.... thanks alot 😊

[@lakshya_13]

Nice VDO

[@pavanpujari2307]

Kidar se Ho aap

[@strivingforexcellency]

Tq sir
Nice information

[@iliyasbasha6664]

Thank you sir for very simple and clear lecture

[@aanchalgupta2107]

Thank you so much sir! For explaining it in simplest form.😊

[@yahatabia8865]

Thank you so much🙆🏻‍♀️

[@suryaprakash3266]

Nice sir

[@prisha5455]

Sir thanks for the trick

[@hsaniva1]

Thank You 🙂

[@paritosh2338]

Nice video 👍

[@sathishjeeva1650]

Sir how the formulas constructed??
Please make a video for that..

[@rajatsachdeva2196]

How that 12 and 6 came, in case of 2 and 1 side painted

[@nayanmenon1767]

It was very helpful...Thank you very much sir

[@drpriyandarshan6925]

Sir tq tq so much my 10yrs of doubt this simply solved

[@srh6678]

thanks it was very helpful 🤓🤓for @yk7

[@yashxxwanth]

yes i am a nerd

[@ashwinimurthy8733]

Sir, I was blank wrt this topic. Thankyou so much 🙏🏼🙏🏼🙏🏼...was very helpful

[@rajatkotiya7486]

Very helpful 👌☺🙂👏😀😊👌☺🙂

[@maturusaicharan3970]

Sir please explain about how many circles in more circles

[@harikabunnyharikabunny2923]

Yes sir please explain

[@digvijaykumar43]

Well explained👌👌

[@lg4854]

Thnks

[@RAJIVKUMAR-bi3et]

Genius.fantastic

[@raghavra6539]

Thank You Sir💥

[@palaktikoria4958]

Helpful 👍

[@parasbellani2851]

Thank u very much sir... loved ur shortcut ❣❣

[@Acreus_the_wandering_pagan]

What to do in case of a much larger cube broken into few small and few large cubes

[@anjalilalwani5167]

Can u please explain how these formula came ( (n-2)×12 etc)

[@Shreya-oy6zc]

@@nazrulhuda9 no sahi hai ye

[@yatharthmahoar6154]

If you visualize it then it would be easy for you to understand
Ans: cubes which are 2 faces colour are on edge except two at corners which have 3 colour so to remove them we subtract 2 (n-2) for each edge and there are 12 edges so we multiply by 12 and we get formula (n-2)×12

[@yatharthmusical9987]

@@yatharthmahoar6154
Yes, you are correct

[@deku_xD]

😂2 min silence for those who use this, formula is wrong

[@sharp_as_tack]

Nice 👍

[@sureshaggarwal]

Thank you! Cheers!

[@myflutemelody800]

Thank u sir plz upload more vdos

[@NishaSingh-ss8oo]

Thank you sir nice explaination

[@dikshitrishi574]

Sir Please Explain same Concept in case of Cuboid.
Hearty Request

[@SH-pc4xt]

3 colored sides = 8, 2 colored sides = 4*(a+b+c-6), 1 colored side = 2*[(a-2)*(b-2)+(b-2)*(c-2)+(a-2)*(c-2)], 0 colored side = (a-2)*((b-2)*(c-2) these apply only when each side is cut.

[@dwitikrishnapradhan5093]

Thank you very much Sir

[@ArshDeep-yc1wu]

Thank you sir

[@satwikagunishetty5819]

good explained

[@varshamalpani8921]

who liked this videos tricks and formulas like

[@sumandevi2866]

Sir tusi to great

[@amirsyed7891]

Tophu kubul karo xD

[@karthikeyabarnala8024]

Tq sir it is very usefull

[@divyabharahtiperiasamy9413]

If we have all side painted then how to solve it sir

[@user-vv4kv2ch1p]

@@divyabharahtiperiasamy9413 all the sides can be painted only if there is only 1 cube

[@bhubaneswarvibes5]

Best

[@bran0942]

Thanks sir it's very clear

[@srimanthn8001]

Sir please make a videos on permutations & combinations

[@sureshaggarwal]

Sure....keep watching

[@kvar3263]

Best 😍👌

[@sidharthprabhakar1716]

Sir, could you please esplain this question - A cube of side 5 cm is painted on all its side. If it is sliced into 1 cubic centimeter cubes, how many 1 cubic centimeter cubes will have exactly one of their sides painted. Thank You

[@ajmiyair1225]

I think the answer is 34. I am not sure. I used the equation[n-2]^2*6. but I am confused with the statement '1 cubic cm'

[@yugantt207]

we need for 1 side painted, hence the formula which will be used should be (n-2)*12 = (5-2)*12 = 3*12 = 36

[@souravsaha6273]

54ans

[@sivapriyahaasinichitta6952]

Total no. of cubes = 125
Let n=5
No. Of cubes with one side painted= (n-2)^2 * 6
= 3^2 * 6 = 54
Hope it helps!🙃

[@zaiikim01]

Using the formula, we get 54.

[@rajnisekhri9275]

Very useful and very easy
Thanks 🙏

[@asifhasan9227]

Thank you sir that was easy to understand

[@niveditabhagwat13]

Thankyou sir 😇✨ it’s a great one

[@ravikiranvepa7892]

How to calculate if only few faces are painted ?

[@revathymohandas1872]

Thanks alot sir

[@nivedhan7325]

Thqqq u sooo much for wonderful lecture I understood very well thqqqqq u sir

[@ArushiSharma14]

Thank you so muchfor this trick.🙏🙏🙏

[@amardyutibasu5901]

But what if adjacent faces are painted??

[@AnkitKumar-bv7yg]

You should have explained using a cube diagram

[@shravanimore8581]

Thank you soo much Sir🙏🙏..
It was really helpful...🙏🙏

[@gauthambedari1348]

Tq sir

[@sureshaggarwal]

Hey friends....
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Pay through paytm or googlepay 9896369963 or paypal on mail ID [e-mail] and send a screenshot on this number WhatsApp.
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[@Bilwa329]

Thank u sir......

[@sureshaggarwal]

Do share the links with your WhatsApp groups and contacts

[@mradesh7752]

Sir direction sense batoe

[@edulakantisaritha3029]

Awesome

[@sweetyshining8613]

Thanks

[@raviarora4749]

Sir will u stream today?

[@sureshaggarwal]

Yes 8 PM

[@bgansh6343]

Please upload more video

[@rakeshgoud7574]

TanQ sir